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This mock test of JEE Main Mathematics Mock - 4 for JEE helps you for every JEE entrance exam.
This contains 25 Multiple Choice Questions for JEE JEE Main Mathematics Mock - 4 (mcq) to study with solutions a complete question bank.
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students definitely take this JEE Main Mathematics Mock - 4 exercise for a better result in the exam. You can find other JEE Main Mathematics Mock - 4 extra questions,
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QUESTION: 1

Points A(2,2), B(-4,-4), C(5,-8) are vertices of ∆ ABC the length of the median through C is

Solution:

QUESTION: 2

Solution:

QUESTION: 3

Let *f(x)* be a function satisfying f ′(x) = f (x) with *f(0)* = 1 and *g(x)* be a function that satisfies *f(x) + g(x) = x*^{2}, then value of integral

is equal to

Solution:

QUESTION: 4

If is a purely imaginary number, then is equal to

Solution:

QUESTION: 5

If f (x) = cos [π^{2}] x + cos [− π^{2}] x where [x] is the step function, then

Solution:

QUESTION: 6

The sum of the focal distances from any point on the ellipse 9x^{2} + 16y^{2} = 144 is

Solution:

QUESTION: 7

In the following question, a Statement of Assertion (A) is given followed by a corresponding Reason (R) just below it. Read the Statements carefully and mark the correct answer-

Assertion(A): f (x) = log x^{3} and g (x) = 3 log x are equal.

Reason(R) : Two functions f and g are said to be equal if their domains, ranges are equal and f (x) = g (x)∀ x in the domain .

Solution:

QUESTION: 8

Determinant is not equal to

Solution:

QUESTION: 9

If is continuous at x = x_{0} , then f ′ (x_{0}) is equal to

Solution:

QUESTION: 10

Solution of the differential equation

Solution:

QUESTION: 11

In the following question, a Statement-1 is given followed by a corresponding Statement-2 just below it. Read the statements carefully and mark the correct answer-

Tangents are drawn from the point (17,7) to the circle x^{2}+y^{2}=169.

Statement-1:

The tangents are mutually perpendicular.

Statement-2:

The locus of the points from which mutually perpendicular tangents can be drawn to the given circle is x^{2}+y^{2}=338.

Solution:

QUESTION: 12

If z^{2} = -i, then z is equal o

Solution:

QUESTION: 13

The sum of the digits in the unit place of all the numbers formed with the help of 3,4,5,6 taken all at a time is

Solution:

If the unit place is ‘3’ then remaining three places can be filled in 3! ways.

Thus ‘3’ appears in unit place in 3! times.

Similarly each digit appear in unit place 3! times.

So, sum of digits in unit place = 3!(3 + 4 + 5 + 6) = 18 * 6 = 108

QUESTION: 14

If θ + Φ = π/3 then sin θ . sinΦ has a maximum value at θ =

Solution:

Here, y = sin θ · sinΦ = sinθ · sin

QUESTION: 15

An unbiased coin is tossed to get 2 points for turning up a head and one point for the tail. If three unbiased coins are tossed simultaneously, then the probability of getting a total of odd number of points is

Solution:

QUESTION: 16

The probability of A = probability of B = probability of C = 1/4, P(A∩B) = P(C∩B) = 0 and P(A∩C) = 1/8, then P(A∪B∪C) is equal to:

Solution:

QUESTION: 17

If the equations x^{2}+ ba + a = 0 and x^{2} + ax + b = 0 have a common root, then a + b =

Solution:

QUESTION: 18

If a, b, c, d, e, f are in A.P., then e - c is equal to

Solution:

QUESTION: 19

If a line passes through points (4,3) and (2,λ) and perpendicular to y=2x+3, then λ=

Solution:

QUESTION: 20

The median of a set of 9 distinct observations is 20.5. If each of the largest 4 observations of the set is increased by 2, then the median of the new set

Solution:

*Answer can only contain numeric values

QUESTION: 21

If a, b are odd integers then number of integral root, of equation x^{10} + ax^{9} + b = 0 is equal to :

Solution:

Let P is a root (∈I)

**Case-I :** p is odd

p^{10} + ap^{9} + b ≠ 0

Because LHS odd

**Case-II :** p is even

p^{10} + ap^{9} + b ≠ 0

because, LHs is odd

*Answer can only contain numeric values

QUESTION: 22

If the number of distinct positive rational numbers p/q smaller than 1, where p, q ∈ {1, 2, 3 ....., 6} is k then k is :

Solution:

Out of numbers will result only 3 distinct rational numbers.

⇒ Total numbers = ^{6}C_{2} – 7 + 3 = 11

*Answer can only contain numeric values

QUESTION: 23

If two distinct chords of a parabola y^{2} = 4ax passing through (a, 2a) are bisected on the line x + y = 1, then the sum of integral values of the length of possible latus rectums is equal to :

Solution:

Any point on x + y = 1 can be taken as (t, 1–t)

The equation of chord with this as mid-point is y(1–t) –2a (x + t) = (1 – t)^{2} – 4at

It passes through (a, 2a)

So, t^{2} – 2t + 2a^{2} – 2a + 1 = 0

This should have two distinct real roots. So D > 0

⇒ a^{2} – a < 0

⇒ 0 < a < 1

So, length of latus rectum < 4 and 0 < a < 1

⇒ LR = 1, 2, 3

*Answer can only contain numeric values

QUESTION: 24

If the value of is e^{–A} then ‘A’ is :

Solution:

*Answer can only contain numeric values

QUESTION: 25

If be three vectors of magnitude √3, 1, 2, such that is the angle between is equal to:-

Solution:

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