JEE Exam  >  JEE Tests  >  Mock Tests for JEE Main and Advanced 2024  >  JEE Main Maths Mock Test- 2 - JEE MCQ

JEE Main Maths Mock Test- 2 - JEE MCQ


Test Description

25 Questions MCQ Test Mock Tests for JEE Main and Advanced 2024 - JEE Main Maths Mock Test- 2

JEE Main Maths Mock Test- 2 for JEE 2024 is part of Mock Tests for JEE Main and Advanced 2024 preparation. The JEE Main Maths Mock Test- 2 questions and answers have been prepared according to the JEE exam syllabus.The JEE Main Maths Mock Test- 2 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main Maths Mock Test- 2 below.
Solutions of JEE Main Maths Mock Test- 2 questions in English are available as part of our Mock Tests for JEE Main and Advanced 2024 for JEE & JEE Main Maths Mock Test- 2 solutions in Hindi for Mock Tests for JEE Main and Advanced 2024 course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt JEE Main Maths Mock Test- 2 | 25 questions in 60 minutes | Mock test for JEE preparation | Free important questions MCQ to study Mock Tests for JEE Main and Advanced 2024 for JEE Exam | Download free PDF with solutions
1 Crore+ students have signed up on EduRev. Have you? Download the App
JEE Main Maths Mock Test- 2 - Question 1

The orthocentre of the traingle whose vertices are (5, -2), (-1, 2) and (1,4) is

JEE Main Maths Mock Test- 2 - Question 2

If the equation [(k(x+1)2/3)]+[(y+2)2/4]=1 represents a circle, then k=

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 2
The given equation can be write as


=> 4k(x+1) ²+3(y+2) ²=12

on expanding wee get x² coefficient as 4k
and y² coefficient as 3
but in equation of circle x² coefficient is equal to y² coefficient

therefore 4k=3
=> k=3/4
JEE Main Maths Mock Test- 2 - Question 3

The eccentric angles of the extremities of the latus-rectum intersecting positive x-axis of the ellipse ((x2/a2) + (y2/b2) = 1) are given by

JEE Main Maths Mock Test- 2 - Question 4

If arg (z) = θ, then arg(z̅) =

JEE Main Maths Mock Test- 2 - Question 5

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 5


Hence the answer will be 1.

JEE Main Maths Mock Test- 2 - Question 6

If N N+ denotes the set of all positive integers and if f : NN+ → N is defined by f(n)    = the sum of positive divisors of (n)  then f (2k . 3), where k is a positive integer is

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 6

f(2k. 3) = The sum of positive divisors of 2k . 3 

JEE Main Maths Mock Test- 2 - Question 7

If a, b, c are different and 

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 7

Correct Answer : b

Explanation : A = {(a, a2, a3-1) (b, b2, b3-1) (c, c2, c3-1)}

=> {(a, a2, a3) (b, b2, b3) (c, c2, c3)} - {(a, a2, 1) (b, b2, 1) (c, c2, 1)} = 0

=> abc{(1, a, a2) (1, b, b2) (1, c, c2)} - {(a, a2, 1) (b, b2, 1) (c, c2, 1)} = 0

=> abc{(a, a2, 1) (b, b2, 1) (c, c2, 1)} - {(a, a2, 1) (b, b2 1) (c, c2, 1)} = 0

=> (abc-1){(a, a2, 1) (b, b2, 1) (c, c2, 1)} = 0

abc - 1 = 0

=> abc = 1

JEE Main Maths Mock Test- 2 - Question 8

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 8

JEE Main Maths Mock Test- 2 - Question 9

In the following question, a Statement of Assertion (A) is given followed by a corresponding Reason (R) just below it. Read the Statements carefully and mark the correct answer-
Assertion (A): Angle between is acute angle

Reason (R): If is acute then is obtuse then

JEE Main Maths Mock Test- 2 - Question 10

The point on the curve y = x2 which is nearest to (3, 0) is

JEE Main Maths Mock Test- 2 - Question 11

The degree of the differential equation

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 11

JEE Main Maths Mock Test- 2 - Question 12

In the following question, a Statement of Assertion (A) is given followed by a corresponding Reason (R) just below it. Read the Statements carefully and mark the correct answer-
Assertion (A): are non zero vectors then is a vector perpendicular to all the vectors a → , b → , c →
Reason (R): are perpendicular to both

JEE Main Maths Mock Test- 2 - Question 13

If i2 = -1, then the sum i + i2 + i3 + ..... upto 1000 terms is equal to

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 13
There will equal n opposite signed terms that is 500 +ve one and 500-ve one therefore it's value comes to zero.
JEE Main Maths Mock Test- 2 - Question 14

A parallelogram is cut by two sets of m lines parallel to the sides, the number of parallelogram thus formed is

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 14
Parallelogram is cut by two sets of m parallel lines to its sides.
then we have  2 sets of (m+2) parallel lines ( 2 lines of the parallelogram)
so parallelogram is formed by taking 2 lines from each set
 = m+2C2 * m+2C2
 = [(m+2)(m+1)/2 ]2
 this also include 1 original parallelogram
 so total number of new parallelogram formed is  =  (m + 2)2(m + 1)2/4
JEE Main Maths Mock Test- 2 - Question 15

If A and B are two events such that 

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 15

JEE Main Maths Mock Test- 2 - Question 16

The probability that a leap year will have exactly 52 Tuesdays is

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 16

The probability of a year being a leap year is 1/4 and being non-leap is 3/4.A leap year has 366 days or 52 weeks and 2 odd days. The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday}, Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}.So there are 7 possibiliyies out of which 2 have a Sunday. So the probability of 53 Sundays in a leap year is 2/7.

So, the probability of 52 sundays is 1-2/7 = 5/7.

JEE Main Maths Mock Test- 2 - Question 17

Product of the real roots of the equation t2x2 + ∣x∣ + 9 = 0

JEE Main Maths Mock Test- 2 - Question 18

If A.M. between two numbers is 5 and their G.M. is 4, then their H.M. is

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 18

If x, y and z respectively represent AM, GM and HM between two numbers a and b, then
y2 = xz
Here x = 5, y = 4
then 16 = 5 x z
z = 16/5

JEE Main Maths Mock Test- 2 - Question 19

If the coefficient of correlation between x and y is 0.28, covariance between x and y is 7.6, and the variance of x is 9, then the standard deviation of the y series is

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 19
N the given problem it is SD of x is 3: (or Variance of x is 9). As Variance = (Sx)^2. We know the relation : correlation coefficient (r) = Cov (x,y) / (Sx * Sy) so, 0.28 = 7.6 / (3 * Sy) From here we get the value of SD of Y : Sy = 9.05.
JEE Main Maths Mock Test- 2 - Question 20

The equation line passing through the point P(1,2) whose portion cut by axes is bisected at P, is

Detailed Solution for JEE Main Maths Mock Test- 2 - Question 20

*Answer can only contain numeric values
JEE Main Maths Mock Test- 2 - Question 21

 

If 2 tan2x – 5 sec x is equal to 1 for exactly 7 distinct values of X ∈ [0, nπ/2], n ∈ N, then the greatest value of n is


Detailed Solution for JEE Main Maths Mock Test- 2 - Question 21

2tan2x – 5sec x = 1
2 (sec2x – 1) – 5secx = 1
2sec2x – 5sec – 3 = 1
∴  cosx = 1/3

*Answer can only contain numeric values
JEE Main Maths Mock Test- 2 - Question 22

If the mean deviation of the number 1, 1 + d, ... , 1 + 8d from their mean is 205, then d is equal to


Detailed Solution for JEE Main Maths Mock Test- 2 - Question 22

*Answer can only contain numeric values
JEE Main Maths Mock Test- 2 - Question 23

The number of 5-digit numbers of the form xyzyx in which x < y is :-


Detailed Solution for JEE Main Maths Mock Test- 2 - Question 23

for z → 10 choice
for  First two x and y → 9C2 choice
Last two y and x → 1 choice
10 × 9C2 × 1= 360

*Answer can only contain numeric values
JEE Main Maths Mock Test- 2 - Question 24

If z1 and z2 are two unimodular complex numbers that satisfy z12 + z22 = 5, then  is equal to -


Detailed Solution for JEE Main Maths Mock Test- 2 - Question 24

*Answer can only contain numeric values
JEE Main Maths Mock Test- 2 - Question 25

The AM of 9 term is 15. If one more term is added to this series, then the A.M. becomes 16. The value of added term is :


Detailed Solution for JEE Main Maths Mock Test- 2 - Question 25

Sum of 9 term = 9 × 15 = 135
New sum when Mean is 16
= 16 × 10 = 160
New term = 160 – 135 ⇒ 25

357 docs|148 tests
Information about JEE Main Maths Mock Test- 2 Page
In this test you can find the Exam questions for JEE Main Maths Mock Test- 2 solved & explained in the simplest way possible. Besides giving Questions and answers for JEE Main Maths Mock Test- 2, EduRev gives you an ample number of Online tests for practice

Up next

Download as PDF

Up next

Download the FREE EduRev App
Track your progress, build streaks, highlight & save important lessons and more!