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JEE Main Mock - 7 (Previous Pattern)


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90 Questions MCQ Test JEE Main & Advanced Mock Test Series | JEE Main Mock - 7 (Previous Pattern)

JEE Main Mock - 7 (Previous Pattern) for JEE 2022 is part of JEE Main & Advanced Mock Test Series preparation. The JEE Main Mock - 7 (Previous Pattern) questions and answers have been prepared according to the JEE exam syllabus.The JEE Main Mock - 7 (Previous Pattern) MCQs are made for JEE 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main Mock - 7 (Previous Pattern) below.
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JEE Main Mock - 7 (Previous Pattern) - Question 1

The frequency for which a 5 μF capacitor has a reactance of 1/1000 ohm is given by

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 1 Given:C=5uf Xc=1/1000. Xc=1/wc=1/1000 ,, wc=10002πf=1000/5u =200*10^6= F=100/π M Hz
JEE Main Mock - 7 (Previous Pattern) - Question 2

If the instantaneous current in a circuit is given by: I = 2cos(ω t + φ)A, then r.m.s. value of the current is

JEE Main Mock - 7 (Previous Pattern) - Question 3

When the speed of electrons increases, then the value of its specific charge

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 3 Because these electrons are losing energy.
JEE Main Mock - 7 (Previous Pattern) - Question 4

In which of the following systems will the radius of the first orbit (n = 1) be minimum

JEE Main Mock - 7 (Previous Pattern) - Question 5
To see first 20 lines of Balmer series distinctly, minimum resolving power of instrument should be
JEE Main Mock - 7 (Previous Pattern) - Question 6

A ball weighing 10 g hits a hard surface vertically with a speed of 5 ms⁻1 and rebounds with the same speed. The ball remains in contact with the surface for 0.01 s. The average force exerted by the surface on the ball is

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 6
Since, F=P/T

where, P= change in momentum and T = total time

F= ( mv1 - mv2 )/T

F= { 0.01[5-(-5)]}/0.01

F=10 N
JEE Main Mock - 7 (Previous Pattern) - Question 7

A dipole of dipole moment p̅ is placed in uniform electric field E̅, then torque acting on it is given by

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 7 Torque=p×E.

It is due to the reason that torque is a vector quantity .therefore we use a cross product to measure the torque acting on the body
JEE Main Mock - 7 (Previous Pattern) - Question 8

In a certain 0.1m3 of space, electric potential is found to be 5V throughout. The electric field in this region is

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 8 Consider there is sphere of volume 0.1m3 now since it is in space it is a hollow sphere so electric field inside it will be zero now this was the easy method u can also do it by taking a sphere and deriving values. 
JEE Main Mock - 7 (Previous Pattern) - Question 9

A ball of mass 0.25 kg attached to the end of a string of length 1.96 m is moving in a horizontal circle. The string will break if the tension is more than 25 N. What is the maximum speed with which the ball can be moved?

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 9

Given,
Length of String, l = 1.96m
Mass of Ball, m = 0.25 Kg
Maximum Tension of String, Tmax = 25 N
Let the speed of the balls is v m/s
In the horizontal circular motion of the ball tension in the string is balanced by the centrifugal force (mv2/l) and hence the maximum tension in the string will be for the maximum speed of the ball (since m and l are fixed)
Therefore,

Therefore, maximum speed of the ball will be 14 m/s

JEE Main Mock - 7 (Previous Pattern) - Question 10

A ball of mass m strikes elastically a wall at an angle of 30º with velocity ν. The change in momentum is

JEE Main Mock - 7 (Previous Pattern) - Question 11

A current passing through a circular coil of two produces a magnetic field of 8 T at its centre. The coil is then rewound, so as to have four turns and current is passed through it is doubled. Now magnetic field at the centre of the coil will be

JEE Main Mock - 7 (Previous Pattern) - Question 12

The following figure shows a logic gate circuit with two inputs A and B and the output C. The voltage waveforms of A, B and C are as shown below.

The logic circuit gate is

JEE Main Mock - 7 (Previous Pattern) - Question 13

Sixty four spherical rain drops of equal size are falling vertically through air with a terminal velocity 1.5 m-s⁻1 If these drops coalesce to form a big spherical drop, then terminal velocity of big drop is

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 13 There is a general formula for calculating the velocity of big drop which is formed by the number of smaller drops The terminal velocity of bigger drop be v' The terminal velocity of smaller drop be v The total no.of smaller drop is 64(n) v'=v×n^2/3 v'=1.5×(64)^2/3 v'=24m/s
JEE Main Mock - 7 (Previous Pattern) - Question 14

An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically at a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 14
First resolve the motion is 2 components 1st horizontal and 2nd vertical .
1st vertical component :-

As there is no velocity in the vertical direction so in Italy velocity there will be zero but the gravitational force is acting in that direction so the accleration in the vertical direction will be g(10)m/s^2
Apply equation of motion here and u will get the time i.e about 19.79sec .
Then we have no acceleration in the horizontal direction so simply 
Velocity[horizontal] =distance /time 
Hence distance will be 3.3km approx 
JEE Main Mock - 7 (Previous Pattern) - Question 15

In the following question, a Statement of Assertion (A) is given followed by a corresponding Reason (R) just below it. Read the Statements carefully and mark the correct answer-
Assertion(A): When charges are shared between two bodies, there occurs loss of energy.
Reason(R): In case of sharing of charges, conservation of energy fails.

JEE Main Mock - 7 (Previous Pattern) - Question 16

In the following question, a Statement of Assertion (A) is given followed by a corresponding Reason (R) just below it. Read the Statements carefully and mark the correct answer-
Assertion(A): For refraction in a plane surface v can be used for the light moving from μ1 to μ2.
Reason(R): for light getting into a medium of index μ2 from μ1.

JEE Main Mock - 7 (Previous Pattern) - Question 17


Number of particles emitted in the reaction is

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 17 The mass number differs by 4 so 1 Alpha, and atomic number differs by 1 so one electron.
JEE Main Mock - 7 (Previous Pattern) - Question 18
For a gas, if the ratio of specific heats at constant pressure and volume is γ, then the value of degree of freedom is
JEE Main Mock - 7 (Previous Pattern) - Question 19
The moment of inertia of a uniform disc about an axis passing through its centre and perpendicular to its plane is 1kg - m2. It is rotating with an angular velocity 100 radians/second. Another identical disc is gently placed on it so that their centres coincide. Now these two discs together continue to rotate about the same axis. Then the loss in kinetic energy in kilo joules is
JEE Main Mock - 7 (Previous Pattern) - Question 20
Faraday is the unit of
JEE Main Mock - 7 (Previous Pattern) - Question 21
The penetration of light into the region of geometrical shadow is called
JEE Main Mock - 7 (Previous Pattern) - Question 22
Huygen's wave theory of light can not explain
JEE Main Mock - 7 (Previous Pattern) - Question 23
A metal wire of linear mass density 9.8 g/m is stretched with a tension of 10 kg wt between two rigid supports 1 metre apart. The wire passes at its middle point between the poles of a permanent magnet and it vibrates in resonance when carrying an alternating current of frequency n. The frequency n of alternating source is
Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 23
The wire vibrates because of the magnetic force on it. When the alternating current completes one cycle, the wire completes one oscillation and hence the frequency of oscillation of the wir is the same as the frequency of the alternating current (n). Therefore we have

n = (1/2L)√(T/m) where L is the length of the segment of the wire betweenetween the supports, T is the tension and ‘m’ is the linear density (mass per unit length) of the wire. Substituting for L, T and m we have

n = (1/2)√[(10X9.8)/(9.8X10–3 )] = 50 Hz.
JEE Main Mock - 7 (Previous Pattern) - Question 24
When a star moves away from earth, the spectrum of the star shifts towards higher wavelength side. This is due to
JEE Main Mock - 7 (Previous Pattern) - Question 25
Which of the following will give maximum ions in solution ?
Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 25 A) has 2 ions :- K+& (I3)- , b) & d) have 3 ions , While FeCl3 has 4 ions :- 1Fe+³ and 3 Cl- So (c) has maximum number of ions
JEE Main Mock - 7 (Previous Pattern) - Question 26

According to the Bohr model, electrons of quantum number n = 4 in excited hydrogen atoms can undergo transitions to lower energy states in different ways and give rise to photons of discrete frequencies. How many discrete frequencies are possible in this case?

JEE Main Mock - 7 (Previous Pattern) - Question 27

A parallel plate capacitor with air between the plates has a capacitance of 9 pF. The separation between its plates is 'd' . The space between the plates is now filled with two dielectrics. One of the dielectrics has dielectric constant K1 = 3 and thickness d 3 while the other one has dielectric constant K2 = 6 and thickness. 2d 3 Capacitance of the capacitor is now

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 27

JEE Main Mock - 7 (Previous Pattern) - Question 28

The angular speed of an engine wheel making 90 revolutions per minute is

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 28 Angular speed=2π × n =2π×(1.5rps)=3 rad/s
JEE Main Mock - 7 (Previous Pattern) - Question 29

The resistivity of a wire depends on its

JEE Main Mock - 7 (Previous Pattern) - Question 30

An electron moves in a circular orbit with a uniform velocity v. It produces a magentic field B at the centre of the circle. The radius of the circle is proportional to

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 30

JEE Main Mock - 7 (Previous Pattern) - Question 31

Two identical conducting spheres, each of radius R, carry charges +Q and -Q/2 respectively. When the distance between their centres is d(d > 2R), the attractive force between them is F. The spheres are now brought into contact and then separated to the initial distance d. The force between the spheres is now

JEE Main Mock - 7 (Previous Pattern) - Question 32

3 moles of ethanol react with one mole of phosphorus tribromide to form 3 moles of bromoethane and one mole of X. Which of the following is X?

JEE Main Mock - 7 (Previous Pattern) - Question 33

When formaldehyde and KOH are heated we get,

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 33
When formaldehyde and potassium hydroxide are heated,we get methyl alcohol and formic acid, it is cannizarroo reaction. The Cannizzaro reaction, named after its discoverer StanislaoCannizzaro, is a chemical reaction that involves the base-induced disproportionation of an aldehyde. HENCE, CORRECT OPTION IS (C).
JEE Main Mock - 7 (Previous Pattern) - Question 34

Oils are converted into fats by

JEE Main Mock - 7 (Previous Pattern) - Question 35

An equilibrium mixture for the reaction
2A2B(g) ⇌ 2A2(g) + B2(g) had 0.5, 0.1 and 0.4 moles of A2B, and A2 and B2 in a two litre vessel respectively the equilibrium constant (K) is__

JEE Main Mock - 7 (Previous Pattern) - Question 36

In a reaction : A → B, the rate of reaction, increases two times, on increasing the concentration of reactants four times. Then, order of reaction is

JEE Main Mock - 7 (Previous Pattern) - Question 37

Calculate the difference between the Δ E AND Δ H for the following reaction at 2º C (in K.cal)

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 37

R = 2 cals/deg-mole
T = 27 º C = 27 + 273 = 300 º A
Δ n = No of moles of gaseous products - No of moles of gaseous reactants = 2-3=-1
Δ H = Δ E + Δ n R T
Δ H − Δ E = Δ n R T = − 1 x2 x300 = − 600 cals = − 0.6 K . c a l .

JEE Main Mock - 7 (Previous Pattern) - Question 38

Which pair of elements of atomic numbers given below will have similar chemical properties?

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 38

In the periodic table, the elements belong to the same group have similar chemical properties. Atomic number-3 (i.e. Li ) and atomic number-11 (i.e. Na ) belong to the same group (i.e. alkali metals), thus they have similar chemical properties.

JEE Main Mock - 7 (Previous Pattern) - Question 39

The art of electroplating was given by

JEE Main Mock - 7 (Previous Pattern) - Question 40

Which of the following is orgno-metalic compound?

JEE Main Mock - 7 (Previous Pattern) - Question 41

Which of the following compound gives dye test ?

JEE Main Mock - 7 (Previous Pattern) - Question 42

When HCl gas is passed through a saturated solution of common salt, pure NaCl is precipiated because

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 42
The increase in [Cl^-] brings in an increase in [ Na^+][Cl^-] which will lead for backward reaction because,
JEE Main Mock - 7 (Previous Pattern) - Question 43

The electrode potentials of half-cell reactions are: Zn → Zn2⁺ + 2e⁻ ; E = -0.76 V and Fe → Fe2⁺ + 2e⁻ ; E=0.41 V. The e.m.f. of the cell Fe2⁺ + Zn → Zn2⁺ + Fe is

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 43 Emf = Ereduction of fe - Ereduction of Zn = - 0.41V - 0.76V = -1. 17 V
JEE Main Mock - 7 (Previous Pattern) - Question 44

Which of the following will act as Lewis base, nucleophilic reagent as well as ligand in complex compound ?

JEE Main Mock - 7 (Previous Pattern) - Question 45

Sodium carbonate cannot be used in place of ammonium carbonate for the identification of the fifth group radicals . This is because the

JEE Main Mock - 7 (Previous Pattern) - Question 46

Alcoholic beverages are made of

JEE Main Mock - 7 (Previous Pattern) - Question 47

Nylon thread are made of

JEE Main Mock - 7 (Previous Pattern) - Question 48

Which effect is not reversible?

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 48 The inductive effect is an experimentally observed effect of the transmission of unequal sharing of the bonding electron through a chain of atoms in a molecule, leading to a permanent dipole in a bond. In short, alkyl groups tend to donate electrons, leading to the inductive effect.
JEE Main Mock - 7 (Previous Pattern) - Question 49

Which of the following isomers will have the highest octane number ?

JEE Main Mock - 7 (Previous Pattern) - Question 50

A solid has a structure in which in which 'W' atoms are located at the corners of a cubic lattice, 'O' atoms at the centre of edges and 'Na' atoms at the centre of the cube. The formula for the compound is

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 50

 

JEE Main Mock - 7 (Previous Pattern) - Question 51

Body-centred cubic has coordination number of

JEE Main Mock - 7 (Previous Pattern) - Question 52

The lowering in vapour pressure, caused by the addition of 100 g of surcose (molecular weight = 342) in 1000 g of water, if the vapour pressure of pure water at 25ºC is 23.8 mm of Hg, is

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 52
JEE Main Mock - 7 (Previous Pattern) - Question 53

A 0.6% solution of urea (molecular weight = 60) would be isotonic with

JEE Main Mock - 7 (Previous Pattern) - Question 54

Propan-1-ol can be prepared from propene by

JEE Main Mock - 7 (Previous Pattern) - Question 55

For a d electron,the orbital angular momentum is :

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 55

JEE Main Mock - 7 (Previous Pattern) - Question 56

Which shell would be the first to have a g sub-shell?

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 56

For g subshell, l = 4. Minimum n should be 5.

JEE Main Mock - 7 (Previous Pattern) - Question 57

Given : C + 2S→CS₂ ; ∆H = 117 KJ
C + O₂→CO₂; ∆H = -393 KJ
S + O₂→ ; ∆H = -297 KJ
The heat of combustion of CS₂ to form CO₂ and SO₂ is

JEE Main Mock - 7 (Previous Pattern) - Question 58

The equation for an overall reaction is M+ 2N → X + Y; therefore, the rate equation for this reaction is__

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 58

No concentrations of reactants and products are given at different intervals of time.

JEE Main Mock - 7 (Previous Pattern) - Question 59

The oxidation number of the central metal ion in Wilkinson's catalyst is__

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 59

Wilkinson's catalyst is [(Ph3P)3RhCl]

JEE Main Mock - 7 (Previous Pattern) - Question 60

The Beilstein test for organic compounds is used to detect

JEE Main Mock - 7 (Previous Pattern) - Question 61

The number of real solution of the equation x2 - 3∣x∣ 2 = 0 is :

JEE Main Mock - 7 (Previous Pattern) - Question 62

If 'n' is a positive integer, then n3 + 2n is divisible by

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 62
Basis Step: If n=0, then n^3+2n=0^3+ 2*0=0. So it is divisible by 3.
Induction: Assume that for an arbitrary natural number n, n^3+2n is divisible by 3.
Induction Hypothesis: To prove this for n+1, first try to express (n+1)^3+2(n+1) in terms of n^3+2n and use the induction hypothesis. Got it
(n+1)^3+2(n+1)=(n^3+3n^2+3n+1)+(2n+2){Just some simplifying}
=(n^3+2n)+(3n^2+3n+3){simplifying and regrouping}
=(n^3+2n)+3(n^2+n+1){factored out the 3}
which is divisible by 3, because (n^3+2n) is divisible by 3 by the induction hypothesis.
JEE Main Mock - 7 (Previous Pattern) - Question 63

the area of the ellipse x2/a2 + y2/b2 = 1 is

JEE Main Mock - 7 (Previous Pattern) - Question 64

The locus of the points from which the lengths of the tangents to the two circles x2 + y2 + 4x + 3 = 0, x2 + y2 - 6x + 5 = 0 are in the ratio 2:3 is a circle with centre

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 64 The length of a tangent from any point (x1,y1) to a circle S=0 is √S1.Let the point be (x,y).Thus According to Question√x^2+y^2+4x+3/√x^2+y^2-6x+5 =2/3On solving further we get,x^2+y^2+12x+7/5=0The center of this circle is (-6,0)
JEE Main Mock - 7 (Previous Pattern) - Question 65

The equation of the circle described on the common chord of the circles x2 + y2-8x + y -15 = 0 and x2+ y2 - 4x + 4y - 42 = 0 as diameter is

JEE Main Mock - 7 (Previous Pattern) - Question 66

The locus represented by |z - 1| = |z + i| is

JEE Main Mock - 7 (Previous Pattern) - Question 67

If and α is constant then the locus of z is

JEE Main Mock - 7 (Previous Pattern) - Question 68

The solution of the differential equation cos(x + y)dy = dx is

JEE Main Mock - 7 (Previous Pattern) - Question 69

If y = √(sin x + y), then dy/dx =

JEE Main Mock - 7 (Previous Pattern) - Question 70

Let f : Z → Z be defined as f x = x2 , x ∈ Z. The function f is

JEE Main Mock - 7 (Previous Pattern) - Question 71

Ajay runs a mile in 8 minutes. At this rate how long will it take him to run a 26-mile marathon?
Which of the following problems can be solved using the same arithmetic operations that are used to solve the problem above?

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 71

Ajay runs one mile in 8 minutes, so you’d have to multiply 8 by 26 to get the minutes it would take him to run the 26 miles at the same rate. The arithmetic operation used to solve this problem is multiplication.
In choice A, you’d have to divide the 220 minutes by 26 to get the time for one mile. For choice B, the total number of books would have to be divided by the number of shelves to get the books per shelf. Finally, in choice D, to find the number of baskets you’d have to divide the 500 grams by 60. But to figure out choice C, the weight of one box of crackers, 200 grams, would have to be multiplied by 100 to find the weight of all the boxes. Only in choice C would you have to multiply, as in the questions

JEE Main Mock - 7 (Previous Pattern) - Question 72

In the following question, a Statement of Assertion (A) is given followed by a corresponding Reason (R) just below it. Read the Statements carefully and mark the correct answer-
Assertion(A):The determinants are not identically equal.
Reason(R): If two rows (or columns) of a determinant are identical, then value of the determinant is zero.

JEE Main Mock - 7 (Previous Pattern) - Question 73

The system of equations x+y+z=6, x+2y+3z=10. x+2y+λz=12 is inconsistent, if

JEE Main Mock - 7 (Previous Pattern) - Question 74

In the following question, a Statement-1 is given followed by a corresponding Statement-2 just below it. Read the statements carefully and mark the correct answer-
Statement-1:
The curve is symmetric with respect to the line x = 1.
Statement-2:
A parabola is symmetric about its axis.

JEE Main Mock - 7 (Previous Pattern) - Question 75

Axis of the parabola x2 − 3 y − 6 x + 6 = 0 is

JEE Main Mock - 7 (Previous Pattern) - Question 76

A polygon has 44 diagonals. The number of its sides is

JEE Main Mock - 7 (Previous Pattern) - Question 77

A pair of dice is thrown and the numbers appearing have sum greater than or equal to 10. The probability of getting 10 is

JEE Main Mock - 7 (Previous Pattern) - Question 78

The plane XOZ divides the join of (1, -1, 5) and (2, 3, 4) in the ratio λ : 1, then λ is

JEE Main Mock - 7 (Previous Pattern) - Question 79

Which of the following is not a measure of central tendency?

JEE Main Mock - 7 (Previous Pattern) - Question 80

The equation of line passing through (c,d) and parallel to ax+by+c=0 is

JEE Main Mock - 7 (Previous Pattern) - Question 81

Angle of intersection of the curves y=4-x2 and y=x2 is

JEE Main Mock - 7 (Previous Pattern) - Question 82

The one root of the equation cos x-x+(1/2)=0 lies in the interval

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 82
JEE Main Mock - 7 (Previous Pattern) - Question 83

The projection of a along b is

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 83 The projection of a along b is (a.b/lbl)according to projection formula
JEE Main Mock - 7 (Previous Pattern) - Question 84

The unit normal vector to the line joining i-j and 2i+3j towards origin is

JEE Main Mock - 7 (Previous Pattern) - Question 85

If f'(2) = 4 and f' (1) = 2 then

JEE Main Mock - 7 (Previous Pattern) - Question 86

JEE Main Mock - 7 (Previous Pattern) - Question 87

In the following question, a Statement of Assertion (A) is given followed by a corresponding Reason (R) just below it. Read the Statements carefully and mark the correct answer-
Assertion(A):
Reason:

JEE Main Mock - 7 (Previous Pattern) - Question 88

If A is a non-singular, then adj A is

Detailed Solution for JEE Main Mock - 7 (Previous Pattern) - Question 88 Show that if A is singular, then adj A is also singular. I had been going to use the fact that if a matrix is singular, its determinant is 0, and the theorem that says that det(adj A) = [det(A)]^(n-1), but then realized that the theorem was only true if A was non-singular.
JEE Main Mock - 7 (Previous Pattern) - Question 89

If x + y = 12, then the minimum value of x2 + y2 is

JEE Main Mock - 7 (Previous Pattern) - Question 90

Consider an infinite series with first term 'a' and common ration 'r'. If it sum is 4 and the second term is 3/4, then

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