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Test: Matrices- Case Based Type Questions- 1 - JEE MCQ


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15 Questions MCQ Test Mathematics (Maths) Class 12 - Test: Matrices- Case Based Type Questions- 1

Test: Matrices- Case Based Type Questions- 1 for JEE 2024 is part of Mathematics (Maths) Class 12 preparation. The Test: Matrices- Case Based Type Questions- 1 questions and answers have been prepared according to the JEE exam syllabus.The Test: Matrices- Case Based Type Questions- 1 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Matrices- Case Based Type Questions- 1 below.
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Test: Matrices- Case Based Type Questions- 1 - Question 1

Read the following text and answer the following questions from (1 - 5) on the basis of the same:

A manufacture produces three stationery products Pencil, Eraser and Sharpener which he sells in two markets. Annual sales are indicated below

If the unit Sale price of Pencil, Eraser and Sharpener are ₹2.50, ₹1.50 and ₹1.00 respectively, and unit cost of the above three commodities are ₹2.00, ₹1.00 and ₹0.50 respectively, then,

Total revenue of market A

Detailed Solution for Test: Matrices- Case Based Type Questions- 1 - Question 1

Total revenue of

= [2.50 x 10,000 + 1.50 x 2,000 + 1.00 x 18,000]

= [46, 000]

Test: Matrices- Case Based Type Questions- 1 - Question 2

Total revenue of market B

Detailed Solution for Test: Matrices- Case Based Type Questions- 1 - Question 2
Total revenue of market B

= [2.50 x 6,000 + 1.50 x 20,000 + 1,00 x 8,000]

= 53,000

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Test: Matrices- Case Based Type Questions- 1 - Question 3

Cost incurred in market A

Detailed Solution for Test: Matrices- Case Based Type Questions- 1 - Question 3

Cost incurred in market A

= [2.00 x 10,000 + 1.00 x 2,000 + 0.50 x 18,000]

= 31,000

Test: Matrices- Case Based Type Questions- 1 - Question 4

Profits in market A and B respectively are

Detailed Solution for Test: Matrices- Case Based Type Questions- 1 - Question 4
Cost incurred in market B

= [2.00 x 6,000 + 1.00 x 20,000 + 0.58 x 8,000]

= 36,000

Profit of market A & B = total revenue of A and B – Cost increased in market A and B

i.e., (₹15,000, ₹17,000)

Test: Matrices- Case Based Type Questions- 1 - Question 5

Gross profit in both markets

Detailed Solution for Test: Matrices- Case Based Type Questions- 1 - Question 5
Gross profit in both markets = Profit in A + Profit in B

= 15,000 + 17,000

= ₹32,000

Test: Matrices- Case Based Type Questions- 1 - Question 6

Direction: Read the following text and answer the following questions from (6 - 10) on the basis of the same:

Amit, Biraj and Chirag were given the task of creating a square matrix of order 2.

Below are the matrices created by them. A, B, C are the matrices created by Amit, Biraj and Chirag respectively.

If a = 4 and b = −2,

Sum of the matrices A, B and C, A+(B + C) is

Detailed Solution for Test: Matrices- Case Based Type Questions- 1 - Question 6

A +B+ C =

Test: Matrices- Case Based Type Questions- 1 - Question 7

(AT)T is equal to

Detailed Solution for Test: Matrices- Case Based Type Questions- 1 - Question 7

Test: Matrices- Case Based Type Questions- 1 - Question 8

(bA)T is equal to

Detailed Solution for Test: Matrices- Case Based Type Questions- 1 - Question 8

Test: Matrices- Case Based Type Questions- 1 - Question 9

AC − BC is equal to

Detailed Solution for Test: Matrices- Case Based Type Questions- 1 - Question 9

AC-BC =

Test: Matrices- Case Based Type Questions- 1 - Question 10

(a + b)B is equal to

Detailed Solution for Test: Matrices- Case Based Type Questions- 1 - Question 10
( a +b)B= (4 - 2)

Test: Matrices- Case Based Type Questions- 1 - Question 11

Direction: Read the following text and answer the following questions from (11 - 15) on the basis of the same:

Three schools DPS, CVC and KVS decided to organize a fair for collecting money for helping the flood victims. They sold handmade fans, mats and plates from recycled material at a cost of ₹25, ₹100 and ₹50 each respectively. The numbers of articles sold are given as

What is the total money (in Rupees) collected by the school DPS?

Detailed Solution for Test: Matrices- Case Based Type Questions- 1 - Question 11

The funds collected by the schools can be obtained by matrix multiplication

Funds collected by school DPS = 7000

Funds collected by school, CVC = 6125

Funds collected by school KVS = 7875

Test: Matrices- Case Based Type Questions- 1 - Question 12

Three schools DPS, CVC and KVS decided to organize a fair for collecting money for helping the flood victims. They sold handmade fans, mats and plates from recycled material at a cost of Rs. 25, Rs.100 and Rs. 50 each respectively. The numbers of articles sold are given as

What is the total amount of money (in ₹) collected by schools CVC and KVS?

Detailed Solution for Test: Matrices- Case Based Type Questions- 1 - Question 12

Total amount of money collected by school

= 6125 + 7875

= 14000

Test: Matrices- Case Based Type Questions- 1 - Question 13

What is the total amount of money collected by all three schools DPS, CVC and KVS?

Detailed Solution for Test: Matrices- Case Based Type Questions- 1 - Question 13
Total amount of money collected by all school DPS, CVC and KVS

= 7000 + 7875 + 6125

= 21000

Test: Matrices- Case Based Type Questions- 1 - Question 14

If the number of handmade fans and plates are interchanged for all the schools, then what is the total money collected by all schools?

Detailed Solution for Test: Matrices- Case Based Type Questions- 1 - Question 14

If the number of handmade fans and plates are interchanged for all the schools, then our table will look like

Let our new matrix be A

An, our sale price of articles is denoted by matrix Y

Now,
Total Revenue = Sales price x Total sales
= YA

Total amount collected by all 3 school = Rs. 7500 + 6000 + 7750
= Rs 21, 250 

Test: Matrices- Case Based Type Questions- 1 - Question 15

How many articles (in total) are sold by three schools?

Detailed Solution for Test: Matrices- Case Based Type Questions- 1 - Question 15
Total Articles sold = (40 + 25 + 35) + (50 + 40 + 50) + (20 + 30 + 40)

= 100 + 140 + 90

= 330

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