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Test: Introduction To Determinants - JEE MCQ


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10 Questions MCQ Test Mathematics (Maths) for JEE Main & Advanced - Test: Introduction To Determinants

Test: Introduction To Determinants for JEE 2024 is part of Mathematics (Maths) for JEE Main & Advanced preparation. The Test: Introduction To Determinants questions and answers have been prepared according to the JEE exam syllabus.The Test: Introduction To Determinants MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Introduction To Determinants below.
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Test: Introduction To Determinants - Question 1

Order of a matrix [ 2 5 7 ] is:

Detailed Solution for Test: Introduction To Determinants - Question 1

The order of matrix is defined by (row × column). The follwing matrix has 1 row and 3 columns. So, the correct option is (d) i.e 1×3.

Test: Introduction To Determinants - Question 2

The value of 

Detailed Solution for Test: Introduction To Determinants - Question 2

To find the determinant we have to cross mutliply the elements and then subtract it.
cos2θ - (-sin2θ) = 1

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Test: Introduction To Determinants - Question 3

If  , then the value of |2A| is same as​:

Detailed Solution for Test: Introduction To Determinants - Question 3

Due to the rule if a square matrix is of order n x n then, |kA| = kn |A|.

Test: Introduction To Determinants - Question 4

Value of the determinant 

Detailed Solution for Test: Introduction To Determinants - Question 4

(a2 + b2)×1 - (2a) × b
= a2 +b2 - 2ab
= (a - b)2

Test: Introduction To Determinants - Question 5

​If , then the value of x is:

Detailed Solution for Test: Introduction To Determinants - Question 5

As value of both determinants are equal
∴ (1×1) - (1×1) = 4x - 2
0 = 4x-2.
4x = 2.
x = 2/4 = 1/2

Test: Introduction To Determinants - Question 6

​is equal to

Detailed Solution for Test: Introduction To Determinants - Question 6

Determinant = [(a2 + b2).1 - (-2ab)]
= (a+b)2

Test: Introduction To Determinants - Question 7

If , then the value of x is  ​

Detailed Solution for Test: Introduction To Determinants - Question 7

As the value of both determinants are equal,
∴ 1 = x2
x = ±1

Test: Introduction To Determinants - Question 8

 , then the value of x is​

Detailed Solution for Test: Introduction To Determinants - Question 8

8-6 = 4x-2x
⇒ x = 1

Test: Introduction To Determinants - Question 9

The value of  is​

Detailed Solution for Test: Introduction To Determinants - Question 9

Δ = 1/2 [2(1-8) -7(1-10) +1(8-10)]
= 47/2

Test: Introduction To Determinants - Question 10

Detailed Solution for Test: Introduction To Determinants - Question 10

9(2x+5) - 3(5x+2) = 0
18x+45-15x-6 = 0
3x = -39
x = -13

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