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This mock test of 28 Year NEET Questions: Kinetic Theory for NEET helps you for every NEET entrance exam.
This contains 19 Multiple Choice Questions for NEET 28 Year NEET Questions: Kinetic Theory (mcq) to study with solutions a complete question bank.
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QUESTION: 1

Two containers A and B are partly filled with water and closed. The volume of A is twice that of B and it contains half the amount of water in B. If both are at the same temperature, the water vapour in the containers will have pressure in the ratio of [1988]

Solution:

Vapour pressure does not depend on the amount of substance. It depends on the temperature alone.

QUESTION: 2

At constant volume, temperature is increased then

Solution:

As the temperature increases, the average velocity increases. So, the collisions are faster.

QUESTION: 3

A polyatomic gas with n degrees of freedom has a mean energy per molecule given by [1989]

Solution:

According to law of equipartition of energy, the energy per degree of freedom is For a polyatomic gas with n degrees of freedom, the mean energy per molecule =

QUESTION: 4

For a certain gas the ratio of specific heats is given to be γ = 1.5. For this gas [1990]

Solution:

QUESTION: 5

According to kinetic theory of gases, at absolute zero temperature [1990]

Solution:

The average kinetic energy of a gas molecular is directly eruptional to absolute temperature only; this implies that all molecular motion stops if the temperature is reduced to absolute zero.

QUESTION: 6

One mole of an ideal monoatomic gas requires 207 J heat to raise the temperature by 10 K when heated at constant pressure. If the same gas is heated at constant volume to raise the temperature by the same 10 K, the heat required is [Given the gas constant R = 8.3 J/ mol. K] [1990]

Solution:

We know that Q_{v} = nC_{v}ΔT and Q_{p }= nC_{p}ΔT

Given Qp = 207 J

QUESTION: 7

Relation between pressure (P) and energy (E) of a gas is [1991]

Solution:

QUESTION: 8

Three containers of the same volume contain three different gases. The masses of the molecules are m_{1}, m_{2} and m_{3 }and the number of molecules in their respective containers are N_{1}, N_{2 }and N_{3}. The gas pressure in the containers are P_{1}, P_{2} and P_{3 }respectively. All the gases are now mixed and put in one of these containers.The pressure P of the mixture will be [1991]

Solution:

According to Dalton’s law of partial pressures, we have P = P_{1} + P_{2} + P_{3}

QUESTION: 9

The number of translational degrees of freedom for a diatomic gas is [1993]

Solution:

Number of translational degrees of freedom are same for all types of gases.

QUESTION: 10

The temperature of a gas is raised from 27°C to 927°C.The root mean square speed is [1994]

Solution:

As temperature increases from 300 K to 1200 K that is four times, so, c_{rms} will be doubled.

QUESTION: 11

The equation of state, corresponding to 8g of O_{2} is[1994]

Solution:

8g of oxygen is equivalent to (1/4) mole.

QUESTION: 12

If C_{s} be the velocity of sound in air and C be the r.m.s velocity, then [1994]

Solution:

Velocity of sound

R.M.S. velocity of gas molecules =

QUESTION: 13

At 0 K, which of the following properties of a gas will be zero? [1996]

Solution:

At 0 K, molecular motion stops. Hence, kinetic energy of molecules becomes zero.

QUESTION: 14

The degree of freedom of a molecule of a triatomic ga s is[1999]

Solution:

No. of degree of freedom = 3 K – N where K is no. of atom and N is the number of relations between atoms. For triatomic gas, K = 3, N = ^{3}C_{2} = 3

No. of degree of freedom = 3 (3) – 3 = 6

QUESTION: 15

The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be [2004]

Solution:

[∵ PV = nRT]

QUESTION: 16

At 10° C the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110°C this ratio is: [2008]

Solution:

Let the mass of the gas be m.

At a fixed temperature and pressure, volume is fixed.

Density of the gas,

(By question)

QUESTION: 17

In the given (V – T) diagram, what is the relation between pressure P_{1} and P_{2} ? [NEET 2013]

Solution:

P_{1} > P_{2}

As V = constant ⇒ P ∝ T

Hence from V–T graph P_{1 }> P_{2}

QUESTION: 18

The amount of heat energy required to raise the temperature of 1g of Helium at NTP, from T_{1}K to T_{2}K is [NEET 2013]

Solution:

From first law of thermodynamics ΔQ = ΔU + ΔW

QUESTION: 19

In a vessel, the gas is at a pressure P. If the mass of all the molecules is halved and their speed is doubled, then the resultant pressure will be [NEET Kar. 2013]

Solution:

When mass is halved and speed is doubled then Resultant pressure,= 2 P.

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