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QUESTION: 1

Identify the pair whose dimensions are equal.

[AIEEE 2002]

Solution:

The dimensions of torque and work are [ML^{2}T^{-2}]

QUESTION: 2

The physical quantities not having same dimensions are

[AIEEE 2003]

Solution:

Planck's constant (in term of unit)

(h) = j-s

= [ML^{2}T^{-2}][T]

= [ML^{2}T^{-1}]

Momentum (p) = kg-ms^{-1}

=[M][L][T^{-1}] = [MLT^{-1}]

QUESTION: 3

Dimensions of where symbols have their usual meaning, are

[AIEEE 2003]

Solution:

As we know that formula of velocity is

QUESTION: 4

Which one of the following represents the correct dimensions of the coefficient of viscosity?

[AIEEE 2004]

Solution:

By Newton's formula

QUESTION: 5

Out of the following pairs, which one does not have identical dimensions ?

[AIEEE 2005]

Solution:

I = mr^{2}

∴[I] = [ML^{2}]

and = moment of force =

∴ = [L][MT^{-2}]=[ML^{2}T^{-2}]

QUESTION: 6

The 'rad' is the correct unit used to report the measurement of

[AIEEE 2006]

Solution:

'rad' is used to measure biological effect of radiation.

QUESTION: 7

Which of the following units denotes the dimensions [ML^{2}/Q^{2}], where Q denotes the electric charges ?

[AIEEE 2006]

Solution:

Magnetic energy

[L→ inductance, i → current]

Energy has the dimension = [ML^{2}T^{-2}]

Equate the dimension, we have

QUESTION: 8

A body of mass m = 3.513 kg is moving along the *x*-axis with a speed of 5.00 ms^{-}^{1}. The magnitude of its momentum is recorded as

[AIEEE 2008]

Solution:

m = 3.513 kg and v = 5.00 ms^{-1}

So momentum, p = mv = 17.565 As the number of significant digits in m is 4 and in v is 3, so p must have 3 (minimum) significant digits.

Hence, p = 17.6 kg ms^{-1}

QUESTION: 9

The dimensions of magnetic field in M, L, T and C (coulomb) is given as

[AIEEE 2008]

Solution:

We know that F = q v B where q is charge, v is velocity and B is magnetic field.

Hence we get B = F / q v

Therefore [B] = [F] / [q] [v]

= MLT^{-2} / C.LT^{-1}

= MCT^{-1}

QUESTION: 10

In an experiment the angles are required to be measured using an instrument. 29 divisions of the main scale exactly coincide with the 30 divisions of the vernier scale. If the smallest division of the main scale is half-a-degree (= 0.5°), then the least count of the instrument is

[AIEEE 2009]

Solution:

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