Description

This mock test of Test: Dynamics Of SHM for Class 11 helps you for every Class 11 entrance exam.
This contains 10 Multiple Choice Questions for Class 11 Test: Dynamics Of SHM (mcq) to study with solutions a complete question bank.
The solved questions answers in this Test: Dynamics Of SHM quiz give you a good mix of easy questions and tough questions. Class 11
students definitely take this Test: Dynamics Of SHM exercise for a better result in the exam. You can find other Test: Dynamics Of SHM extra questions,
long questions & short questions for Class 11 on EduRev as well by searching above.

QUESTION: 1

Potential energy of a particle with mass m is U=k[x]^{3} , where k is a positive constant. The particle is oscillating about the origin on x-axis. If the amplitude of oscillation is a, then its time period, T is

Solution:

QUESTION: 2

The dimensions and unit of phase constant Φ is

Solution:

QUESTION: 3

If the reference particle P moves in uniform circular motion, its projection along a diameter of the circle executes

Solution:

QUESTION: 4

The equation of motion of a particle is x= 3cos(0.45t+π/4)m. Its maximum acceleration is

Solution:

QUESTION: 5

If the sign in equation F = -kx is changed what would happen to the motion of the oscillating body?

Solution:

QUESTION: 6

Choose the correct time period of the function sin ωt + cos ωt

Solution:

QUESTION: 7

The velocity and acceleration amplitudes of body executing simple harmonic motion is

Solution:

QUESTION: 8

At what distance from the mean position would the K.E of a particle in simple harmonic motion be equal to its potential energy?

Solution:

Let say from some distance x, the KE = PE and as total energy must be conserved and TE = -½ kA^{2}

Thus we get 2PE = ½ kA^{2}

Thus we get 2kx^{2} = kA^{2}

We get x = A / √2

QUESTION: 9

What is the maximum Kinetic energy and minimum potential energy of a harmonic oscillator with amplitude 0.03m, force constant 4×10^{5} N/m and total mechanical energy of 230 J.

Solution:

QUESTION: 10

A particle starts S.H.M. from the mean position. Its amplitude is A and time period is T. At the time when its speed is half of the maximum speed, its displacement y is

Solution:

### SHM Module

Doc | 9 Pages

### Damped SHM

Video | 12:32 min

### Simple Harmonic Motion(SHM)

Doc | 23 Pages

### Velocity in SHM - Oscillations

Video | 08:26 min

- Test: Dynamics Of SHM
Test | 10 questions | 10 min

- Test: Dynamics Of Rotational Motion
Test | 10 questions | 10 min

- SHM MCQ Level - 1
Test | 30 questions | 30 min

- SHM Practice Level - 1
Test | 30 questions | 60 min

- Fluid Dynamics MSQ
Test | 10 questions | 45 min