Test: Dynamics of Rotational Motion - NEET MCQ

# Test: Dynamics of Rotational Motion - NEET MCQ

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## 10 Questions MCQ Test Topic-wise MCQ Tests for NEET - Test: Dynamics of Rotational Motion

Test: Dynamics of Rotational Motion for NEET 2024 is part of Topic-wise MCQ Tests for NEET preparation. The Test: Dynamics of Rotational Motion questions and answers have been prepared according to the NEET exam syllabus.The Test: Dynamics of Rotational Motion MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Dynamics of Rotational Motion below.
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Test: Dynamics of Rotational Motion - Question 1

### Kinetic energy of a rolling object is the

Detailed Solution for Test: Dynamics of Rotational Motion - Question 1

If an object is rolling without slipping, then its kinetic energy can be expressed as the sum of the translational kinetic energy of its center of mass plus the rotational kinetic energy about the center of mass.

Test: Dynamics of Rotational Motion - Question 2

### A rotating machine is maintained at a uniform angular speed of 150 rad s-1, with a torque of 100 Nm. The power is

Detailed Solution for Test: Dynamics of Rotational Motion - Question 2

Power = torque × angular velocity
P = 100 × 150
P = 15000 W
P = 15KW

Test: Dynamics of Rotational Motion - Question 3

### If we apply Newton’s First Law to torque then the statement will be

Detailed Solution for Test: Dynamics of Rotational Motion - Question 3

Newton's First Law for Rotation: an object at rest tends to remain at rest, and an object that is spinning tends to spin with a constant angular velocity, unless it is acted on by a nonzero net torque or there is a change in the way the object's mass is distributed.

Test: Dynamics of Rotational Motion - Question 4

A torque of 20 Nm is applied to a flywheel of mass 10 kg and radius of gyration 50 cm. The resulting angular acceleration is:

Test: Dynamics of Rotational Motion - Question 5

In case of couples, which statement is not true?

Detailed Solution for Test: Dynamics of Rotational Motion - Question 5

When two forces of equal magnitude opposite in direction and acting along parallel straight lines, then they are said to form a couple. The perpendicular distance between the two force forming a couple is called the arm of the couple.

‘Couple’ are the types of forces acting clockwise or anti-clockwise. We can only balance them by two forces minimum.

Test: Dynamics of Rotational Motion - Question 6

A rigid body is rotating about an axis. Different particles are at different distances from the axis. Which of the following is true?

Detailed Solution for Test: Dynamics of Rotational Motion - Question 6

In the fixed axis rotation we see that every point on the body has two components of velocity, one in the radial direction and one in the tangential direction. The resultant of these velocities is not the same for any two points lying in the plane of the body.
Any two points on the radial line have the radial acceleration directed towards the center of equal magnitude and the tangential acceleration of equal magnitude as well. Thus option B is correct.
All the particles lying on the curved surface of a cylinder whose axis coincides with the axis of rotation have the same speed but different velocities.

Test: Dynamics of Rotational Motion - Question 7

To maximize torque on a lever, which of the following will not help?

Test: Dynamics of Rotational Motion - Question 8

Kinetic Energy of a rotating body i.e. Rotational Kinetic Energy can be converted to various forms of energy they are

Detailed Solution for Test: Dynamics of Rotational Motion - Question 8

Take an example where the system is attached with spring and the spring is attached to a wall, if you rotate the system that system has KE and spring will also rotate with that system and thus spring will start to compress which will create PE in it and heat will obviously be generated.

Test: Dynamics of Rotational Motion - Question 9

A 2 m rod of mass 1 kg rotates at an angular speed of 15 rad/s about its ends. Then K.E. is

Detailed Solution for Test: Dynamics of Rotational Motion - Question 9

Given,
l=2m
m=1kg
ω=15rd//s
K.E.=1/2I ω
=1/2x(ml2/3) ω2
=1/2x(1x4/3)(15)2
=150J

Test: Dynamics of Rotational Motion - Question 10

An object is in combined rotational and translational motion. Its K.E. is

Detailed Solution for Test: Dynamics of Rotational Motion - Question 10

Total kinetic energy =

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