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SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - SSC CGL MCQ


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34 Questions MCQ Test SSC CGL (Tier - 1) - Previous Year Papers (Topic Wise) - SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 for SSC CGL 2024 is part of SSC CGL (Tier - 1) - Previous Year Papers (Topic Wise) preparation. The SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 questions and answers have been prepared according to the SSC CGL exam syllabus.The SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 below.
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SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 1

A and B together can complete a work in 3 days. They start together. But, after 2 days, B left the work. If the work is completed after 2 more days, B alone could do the work in    (SSC CGL 2013)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 1

(A + B)’s 2 days’ work 2/3

Time taken by A in doing 1/3 work = 2 days
∴ Time taken by A in completing the work = 6 days.

∴ B alone will complete the work in 6 days.

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 2

A and B together can complete a piece of work in 12 days, B and C can do it in 20 days and C and A can do it in 15 days. A, B and C together can complete it in    (SSC CGL 2013)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 2

(A + B)’s 1 day’s work = 1/12
(B + C)’s 1 day’s work = 1/20
(C + A)’s 1 day’s work = 1/15
On adding all three,

∴ (A + B + C)’s 1 day’s work = 1/10
Hence, the work will be finished in 10 days.

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 3

One man, 3 women and 4 boys can do a piece of work in 96 hours, 2 men and 8 boys can do it in 80 hours, 2 men and 3 women can do it in 120 hours. 5 men and 12 boys can do it in    (SSC CGL 2nd Sit. 2013)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 3

1 hr’s work of 1 man and 4 boys = 1/160
1 hr’s work of 1 man and 3 women = 1/96
1 hr work of 3 women

∴ 2 men = 3 women = 4 boys
∴ 2 men + 8 boys = 12 boys
5 men + 12 boys = 22 boys
∴ By M1 D1 = M2D2
⇒ 12 × 80 = 22 × D2

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 4

Ronald and Elan are working on an Assignment. Ronald takes 6 hours to type 32 pages on a computer, while Elan takes 5 hours to type 40 pages. How much time will they take working together on two different computers to type an assignment of 110 pages?    (SSC CGL 2nd Sit. 2013)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 4

Ronald’s 1 hour’s work = 32/6 = 16/3 pages
Elan’s 1 hour’s work = 8 pages
1 hour’s work of the both

∴ Required time

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 5

A can do a piece of work in 12 days while B alone can do it in 15 days. With the help of C they can finish it in 5 days. If they are paid ₹ 960 for the whole work. How much money A gets?    (SSC CGL 2nd Sit. 2013)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 5

Work done by A and B in 5 days

Time taken by C in doing 1/4
Work = 5 days
∴ C will complete in 20 days.

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 6

A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days  A alone can finish the remaining work?    (SSC CGL 1st Sit. 2013)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 6

Work done by B in 10 days = 10/15 = 2/3

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 7

A man undertakes to do a certain work in 150 days. He employs 200 men. He finds that only a quarter of the work is done in 50 days. The number of additional men that should be appointed so that the whole work will be finished in time is:    (SSC CGL 1st Sit. 2013)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 7

200 men do 1/4 work in 50 days.

⇒ M2 × 100 = 200 × 50 × 3 ⇒ M2 = 300
∴ Additional men = 100

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 8

If 10 men or 20 women or 40 children can do a piece of work in 7 months, then 5 men, 5 women and 5 children together can do half of the work in:    (SSC CGL  1st Sit. 2013)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 8

10 men = 20 women = 40 children
i.e. 1m = 2w = 4 c
∴ Sm  + Sw + Sch
⇒ 5 × 4 + 5 × 2 + 5 = 35

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 9

A can do a work in 20 days and B can do the same work in 30 days. In how many days can A and B together do the work?    (SSC CHSL 2013)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 9

A's 1 day's work = 1/20
B's 1 day’s work = 1/30

∴ Both A and B will finish the work in 60/5 = 12 days.

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 10

3 men and 7 women can do a job in 5 days while 4 men and 6 women can do it in 4 days. The number of days required for a group of 10 women working together, at the same rate as before, to finish the same job is:    (SSC Sub. Ins. 2013)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 10

3 × 5 men + 7 × 5 women
= 4 × 4 men + 6 ×4 women
⇒ 16 men – 15 men = 35 women – 24 women
∴ 1 man = 11 women
∴ 3 men + 7 women = 40 women
∴ M1 D1 = M2 D2
⇒ 40 × 5 = 10 × D2
⇒ D2 = 20 days

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 11

Water flows at the rate of 10 metres per minute from a cylindrical pipe 5 mm in diameter. How long it take to fill up a conical vessel whose diameter at the base is 30 cm and depth 24 cm?    (SSC Sub. Ins. 2013)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 11

Volume of water flowing from the pipe in 1 minute
= π x 0.25 x 0.25 x 1000 ccm.

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 12

A can do as much work as B and C together can do. A and B can together do a piece of work in 9 hours 36 minutes and C can do it in 48 hours. The time (in hours) that B needs to do the work alone, is:   (SSC Sub. Ins. 2013)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 12

9 hours 36 minutes

A’s 1 hours work = (B + C)’s 1 hour ’s work ...(ii)

∴ B alone will finish the work in 24 hours.

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 13

A, B and C can do a piece of work in 10, 12 and 15 days respectively. A leaves 5 days before the completion of the work and B leaves 2 days after A. The whole work lasts for    (SSC Multitasking 2013)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 13

Suppose, the work was finished in x days.
Then, A’s (x – 5) day’s work + B’s (x – 3) day’s work + C’s x day’s work = 1.

⇒ 6x – 30 + 5x – 15 + 4x = 60
⇒ 15x = 60 + 30 + 15
⇒ 15x = 105 ⇒ x = 7 days.

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 14

Two pipes A and B can fill a tank in 6 hours and 4 hours respectively. If they are opened on alternate hours and if pipe A is opened first, then the tank shall be full in    (SSC Multitasking 2013)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 14

A’s work in 1 hour = 1/6
B’s work in 1 hour = 1/4
(A + B)’s 2 hour’s work when opened alternately

 (A + B)’s 4 hour’s work when opened alternately


Now, it is A’s turn and 1/6 part is filled by A in 1 hour.
∴ Total time taken to fill the tank = (4 + 1) hrs. = 5 hrs.

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 15

A is thrice as good a workman as B and takes 60 days less than B for doing a job. The time in which they can do it together is:   (SSC CHSL 2012)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 15

If A can finish a work = x days
B will do this work = 3x days
From question, A – B = 3x – x = 60 ⇒ x = 30
A = 30 days, B = 90 days

So, A and B working together can complete work = 90/4 = 22.5 days

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 16

A can do a piece of work in 20 days which B can do in 12 days. B worked at it for 9 days. A can finish the remaining work in:   (SSC CHSL 2012)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 16

B’s 1 day work = 1/12
∴ B’s 9 day’s work = 9/12 = 3/4

∴ A can finish this work in 20/4 days = 5 days

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 17

In a fort, there was sufficient food for 200 soldiers for 31 days. After 27 days, 120 soldiers left the fort. For how many extra days will be rest of the food last for the remaining soldiers?    (SSC Sub. Ins. 2012)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 17

Ratio of new number of persons in fort : original number of persons in fort = 80 : 200 = 2 : 5
Hence the food will last for 5/2 days of the original (4 days = 31 days – 27 days)

So, extra days = 6 days

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 18

If 10 men or 18 boys can do a work in 15 days, then the number of days required by 15 men and 33 boys to do twice the work is     (SSC Sub. Ins. 2012)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 18

10 men in 15 days
⇒ 1 man can do the work in 150 days
⇒ 1 man can do twice the work in 300 days
Similarly, 18 boys in 15 days
⇒ 1 boy can do the work in 270 days
⇒ 1 boy can do twice the work in 540 days
Now, if there are 15 men and 33 boys trying to do twice the work then,

∴ It will take 9 days for 15 men and 33 boys to do twice the work.

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 19

X and Y can do a piece of work in 30 days. They work together for 6 days and then X quits and Y finishes the work in 32 more days. In how many days can Y do the piece of work alone?    (SSC CGL 2nd Sit. 2012)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 19


Now, 4/5 work is done by Y in 32 days.
∴ Whole work will be done by Y in 

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 20

Two men A and B started a job in which A was thrice as good as B and therefore took 60 days less than B to finish the job. How many days will they take to finish the job, if they start working together?   (SSC CGL 1st Sit. 2012)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 20

If time taken by A be x days, then, time taken by B will be 3x days
∴ 3x – x = 60
⇒ 2x = 60 ⇒ x = 30
Time taken by B = 90 days

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 21

If 12 men or 18 women can reap a field in 14 days, then working at the same rate, 8 men and 16 women can reap the same field in:   (SSC CGL  2012)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 21

∵ 12 men ≡ 18 women
∴ 2 men ≡ 3 women
∴ 8 men + 16 women = 28 women
∴ M1D1 = M2D2
⇒ 18 × 14 = 28 × D2

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 22

Pipe A alone can fill a tank in 8 hours. Pipe B alone can fill it in 6 hours. If both the pipes are opened and after 2 hours pipe A is closed, then the other pipe will fill the tank in    (SSC CGL 1st Sit. 2012)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 22

Part of the tank filled by both pipes in two hours


Time taken by B in filling the remaining part

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 23

A is thrice as good a workman as B and is, therefore, able to finish a piece of work in 60 days less than B. The time (in days) in which they can do it working together is    (SSC CGL 2nd Sit. 2011)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 23

If A completes the work in x days, B will do the same in 3x days.
∴ 3x – x = 60
⇒ 2x = 60 ⇒ x = 30 and 3x = 90
∴ (A + B)’s 1 day’s work

∴ A and B together will do the work in 

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 24

A work can be completed by P and Q in 12 days, Q and R in 15 days, R and P in 20 days. In how many days P alone can finish the work?   (SSC CGL 2nd Sit. 2011)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 24


Adding all three equations, 2 (P + Q + R)’s 1 day’s work

∴ P’s 1 day’s work
= Equation (iv) – equation (ii)

∴ P alone will complete the work in 30 days,
Alternate Method:
Work efficiency of P + Q : Q + R : P + R =

Working efficiency of  P+ Q + R = 
Total work unit =5 × 12 = 60
Work efficiency of P = (P + Q + R) – (Q+ R) = 6 – 4 = 2 units
Required time =60/2 = days. 

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 25

'x' number of men can finish a piece of work in 30 days. If there were 6 men more, the work could be finished in 10 days less. The original number of men is   (SSC CGL 2nd Sit. 2011)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 25

m1d1 = m2d2
x (30) = (x + 6) 20
⇒ 2x + 12 = 3x
⇒ 3x – 2x = 12
⇒ x = 12 men

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 26

X is 3 times as fast as Y and is able to complete the work in 40 days less than Y. Then the time in which they can complete the work together is   (SSC CGL 1st Sit. 2011)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 26

If X completes a work in x days then Y will do the same in 3x days.
∴ 3x – x = 40 ⇒ x = 20
∴ Y will finish the work in 60 days.

∴ Both together will complete the work in 15 days.

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 27

A and B can complete a piece of work in 8 days, B and C can do it in 12 days, C and A can do it in 8 days. A, B and C together can complete it in    (SSC CGL 1st Sit. 2011)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 27


On adding, 2 (A + B + C)’s 1 day’s work

∴ (A + B + C)’s 1 day’s work = 1/6
Hence, the work will be completed in 6 days.

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 28

A can do a work in 12 days. When he had worked for 3 days, B joined him. If they complete the work in 3 more days, in how many days can B alone finish the work?    (SSC CGL 1st Sit. 2011)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 28

According to Question,

⇒ B = 6 days

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 29

One pipe fills a water tank three times faster than another pipe. If the two pipes together can fill the empty tank in 36 minutes, then how much time will the slower pipe alone take to fill the tank?    (SSC CGL 2nd Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 29

If time taken by the pipe at faster rate to fill the tank be x minutes, then

⇒ 3x = 4 × 36
⇒ x = 48 minutes
∴ Time taken by the slower pipe
= 48 × 3  = 144 minutes  = 2 hours 24 minutes
Alternate Method:
Work efficiency of first pipe : work efficiency of second pipe = 3 : 1
Total work unit = (3 + 1) 36 = 144
Time required for slow pipe = 144/1
= 144 min
=  2 hrs 24 min.

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 30

7 men can complete a piece of work in 12 days. How many additional men will be required to complete double the work in 8 days?   (SSC CGL 2nd Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 30

M1D1W2 = M2D2W1
⇒ 7 × 12 × 2 = M2 × 8 × 1

∴ No. of additional men = 21 – 7 = 14

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 31

A can compete 1/3 of a work in 5 days and B can do 2/5 of the work in 10 days. In how many days both A and B together can complete the work?   (SSC CGL 2nd Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 31

Total time taken by A = 15 days

∴ (A + B)’s 1 day’s work

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 32

A can complete a piece of work in 18 days, B in 20 days and C in 30 days, B and C together start the work and are forced to leave after 2 days. The time taken by A alone to complete the remaining work is    (SSC CGL 1st Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 32

(B + C)’s 2 days work

∴ Time taken by A to complete this part of work

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 33

If A and B together can complete a piece of work in 15 days and B alone in 20 days, in how many days can A alone complete the work?   (SSC CGL 1st Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 33

(A + B)’s 1 day’s work = 1/15
B’s 1 day’s work = 1/20

∴ A alone will do the work in 60 days.

SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 34

If 5 men or 7 women can earn ₹ 5,250 per day, how much would 7 men and 13 women earn per day?   (SSC CGL 1st Sit. 2010)

Detailed Solution for SSC CGL Previous Year Questions: Time and Work (Pipe & Cisterns) - 3 - Question 34

5 men ≡ 7 women

Alternate Method:
5 Men = 7 women
Work efficiency of Man :  Woman = 7 : 5
Work efficiency of 5 Men = 5 × 7 = 35
Work efficiency of 7 Men and 13 Women = 7 × 7 + 5 × 65 = 114

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