IBM Aptitude Questions and Answers - Interview Preparation MCQ

Let’s take round figure value, then the simplification is
1782÷54+456-2345*1
= 33+456-2345
= -1856/2 = -928

25% of 800 ÷ 20 = 25*800/100*20
= 10
55-45 = 10
Therefore, forgetting value as a 10 the number should be ‘ 45 ‘

Given
The expenditure between January to June = 4200 * 6 = 25200
The expenditure between February to June = 25200 – 1200 = 24000
Therefore, The expenditure between February to July = 24000 + 1500 = 25500/6 = 4250

7x+5x = 60
Milk = 35litres, water = 25litres
10litres of mixture taken out
Milk = 35-12(7/12) = 35-7 = 28
Water = 25-12(5/12) = 25-5 = 20
28+6 : 20 = 34:20 = 17:10
Therefore, the ratio of Milk and Water after the final operation is 17:10

Let we assume x = avg price
x-14/17-x = 5/4
4x-56 = 85-5x
5x+4x = 85+56 = 141
9x = 141
x = 141/9 = 15.67
Hence, The average price of the mixture is Rs.15.67

The Simple Intrest on Rs 15000
=(15000×6×1)/100 = Rs. 900
Profit to made on Rs 30000
= 30000×10/100=Rs 3000
S.I.on Rs.15000 = 3000-900 = Rs.2100
Rate=(S.I.* 100)/(P * T)=(2100×100)/15000
=14% per annum
Therefore, the simple interest rate at which he should lend the remaining sum of money to the second friend is 14%.

x – (40/100)*x = 60x/100
40/100 at 15% p.a = 40/100 * 15/100 = 60x/1000
50/100*60x/100 = 30x/100 at 10% p.a = 30x/100 * 10/100 = 30x/1000
Balance amount = x – 40x/100 – 30x/100 = 30x/100 at 18% p.a = 18/100 * 30x/100 = 54x/1000
R = [(144x/1000)/x] * 100 = 14.4%
Therefore, the annual rate of interst is 14.4%.

LCM of 12, 15, 25 and 30 is 300
the least number of 4-digit divided by 300 is 1200

Let us assume that work completed in x days
According to given data A and C worked for all x days and B for (x-3) days. So
(1/10 + 1/15)*x + (1/12)*(x-3) = 1
Solve, x = 5 days
In 5 days, A did 5/10 = 1/2 of work
In (5-3) = 2 days, B did 2/12 = 1/6 of work
So total by A and B = (1/2 + 1/6) = 2/3
Therefore, the total work done by A and B together is 2/3.

Let we assume that the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.
Then, 4x – 3x = 1000
x = 1000.
B’s share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.
Therefore, the share of the B is Rs. 2000.

Given that
A+B+C in 1h = 1/6
A+B+C in 2h = 2/6 = 1/3
Remaining = 1-1/3 = 2/3
A+B in 6hrs = 2/3
A+B in 1hr = 2/18
C alone to fill the cistern = 1/6 – 2/18 = 3-2/18 = 1/18
Therefore, the time taken by C alone to fill the cistern was 18 hours.

We assume that pipe A is opened first
Total= 30, A = 30/6 =1/5, B = 30/5 =1/6
In 2 hrs = 5+6 =11
In 4hrs = 22
Remaining = 30-22 =8
1hr Pipe A = 8-5= 3,Remaining B = 3*1/6 = 30min
Therefore, the time taken in order to fill the tank was 5hrs 30min

X(1/20+1/30) +(16-x)1/20 = 1
5x/60+16-x/20 =1
5x+48-3x/60 =1
2x+48 = 60
2x=12
X=12/2 = 6
Hence it is proved.

According to the given data
Total profit required = Rs.(42 x 18) = Rs.756
Profit on 22 sarees = Rs. (460 + 144) = Rs. 604
Profit on 20 sarees = Rs. (756 – 604) = Rs. 152
Average profit on these sarees = Rs.(152/20) = Rs. 7.60.
Hence it is proved.

Let us assume that the market price of each pen is Rs. 1.
Then, C.P. of 40 pens = Rs. 36.
S.P. of 40 pens = 99% of Rs. 40 = Rs. 39.60.
Therefore, the percentage of profit = [3.60/36 x 100]% = 10%.
Hence it is proved.

let the fraction is (p-4)/p
now, (p -4 + 15)/(p-4) = 6
we get p = 7
Therefore, fraction = 3/7

Let first number N1 = D*a + 7
and second number N2 = D*b + 9
N1 + N2 = (a+b)*D + 16
Remainder is 4
Therefore, D will be 12

a + (20/100)*b = (150/100)*b
a:b = 13:10
Therefore, the ratio between the first and second number is 13:10.