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SSC CGL Exam  >  SSC CGL Tests  >  SSC CGL Previous Year Papers  >  Test: SSC CGL Previous Year Questions: Simplification (2023-18) - SSC CGL MCQ

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - SSC CGL MCQ


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30 Questions MCQ Test SSC CGL Previous Year Papers - Test: SSC CGL Previous Year Questions: Simplification (2023-18)

Test: SSC CGL Previous Year Questions: Simplification (2023-18) for SSC CGL 2024 is part of SSC CGL Previous Year Papers preparation. The Test: SSC CGL Previous Year Questions: Simplification (2023-18) questions and answers have been prepared according to the SSC CGL exam syllabus.The Test: SSC CGL Previous Year Questions: Simplification (2023-18) MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: SSC CGL Previous Year Questions: Simplification (2023-18) below.
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Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 1
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What is the value of the given Expression?  [SSC CGL 24/07/2023 (1st shift)]

Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 1


Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 2
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The value of  is:  [SSC CGL Tier II  (29/01/2022)]

Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 2

 


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Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 3
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If ‘+’ means ‘-’, ‘-’ means ‘+’, ‘×’ means ‘÷’ and ‘÷’ means ‘×’ then the value of  is:  [SSC CGL 03/03/2020 (Morning)]

Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 3


After applying changes as per question we get

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 4
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The value of  is:  [SSC CGL Tier II (13/09/2019)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 4




= (4.6)2 + (5.4)2 − 24.84
= (4.6 + 5.4)2 - 2(4.6)(5.4) - 24.84
= 100 − 74.52 = 25.48

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 5
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The value of  is  [SSC CGL Tier II  (11/09/2019)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 5


= 22.444444…. ∞ + 11.5676767… ∞ - 33.599999… ∞
= 0.412121212…. ∞ = 

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 6
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The value of  of is :  [SSC CGL 06/06/2019 (Afternoon)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 6


Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 7
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The value of (5 + 3 ÷ 5 × 5) / (3 ÷ 3 of 6) of (4 × 4 ÷ 4 of 4 + 4÷ 4 × 4) is  [SSC CGL 06/06/2019 (Morning)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 7

(5 + 3 ÷ 5 × 5) / (3 ÷ 3 of 6 ) of (4 × 4 ÷ 4 of 4 + 4 ÷ 4 × 4)

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 8
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Find the value of   [SSC CGL Tier II  (26/10/2023)]
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Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 9
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Simplify the given expression.  [SSC CGL 17/07/2023 (1st shift)]
y + 2x - [y - (y - x + y) - (x + y) + y] - 2y.
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 9

y + 2x - [ y - (y - x + y ) - (x + y) + y] - 2y
= y + 2x − [(x − y) − x] − 2y
= y + 2x − [−y] − 2y
= y + 2x + y − 2y = 2x

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 10
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Simplify the following expression.  [SSC CGL 18/07/2023 (4th shift)]
[√25 + 12 ÷ 3 - {20 + (16 of 8 ÷ 16) - (54 ÷ 18 of 1/2)}] 
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 10

[√25 + 12 ÷ 3 - {20 + (16 of 8 ÷ 16) - (54 ÷ 18 of 1/2)}] 
[5 + 4 − {20 + (8) − (54 ÷ 9)}]
[5 + 4 − {20 + (8) − (6)}]
5 + 4 − 22 = − 13

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 11
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Simplify the following  [SSC CGL 19/07/2023 (1st shift)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 11


Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 12
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Simplify the expression 
where x = 2 and y = 3.  [SSC CGL 25/07/2023 (4th shift)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 12

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 13
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Simplify the given expression  [SSC CGL 27/07/2023 (2nd shift)]
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= (120 − 100) = 20

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 14
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Find the value of the given expression.  [SSC CGL Tier II (03/03/2023)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 14



Short Trick:-
Co - prime factors of 20 = (4 , 5)
In case of ( − ve) sign, smaller number is the right answer.

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 15
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Simplify the following.  [SSC CGL Tier II (06/03/2023)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 15

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 16
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Simplify   [SSC CGL 01/12/2022 (2nd Shift)]
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Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 17
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What is the value of 1002 - 992 + 982 - 972 + 962 - 952 + 942 - 932 + ............122 - 112?  [SSC CGL 05/12/2022 (3rd Shift)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 17

Sum of ‘n’ natural numbers = (n/2)(a + l) ….where a = first term, l = last term
1002 − 992 + 982 − 972 +........ + 122 − 112
(100 + 99 (100 − 99) + (98 + 97) (98 − 97) +........ + (12 + 11)(12 − 11)
= 100 + 99 + 98 + 97 .......... + 12 + 11
Sum = (90/2) (100 + 11) = 4995

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 18
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What is the value of
  [SSC CGL Tier II  (08/08/2022)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 18


 
= 99 × 29 + (1/99) (11 + 13 + 15 + ….67)
= 2871 + 
= 2871 + (1/99) (29 x 39)
= 2871 + (377/33) = (94743 + 377)/33 = 95120/33

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 19
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What is the simplified value of   [SSC CGL Tier II (08/08/2022)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 19

Let x = y = z = 2


= (72 - 8)/64 = 64/64 = 1

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 20
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If A =  then what is the value of A + B + C?  [SSC CGL Tier II  (08/08/2022)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 20


So, A + B + C = 

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 21
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Simplify the following expressions:  [SSC CGL 11/04/2022 (Afternoon)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 21

Put a = b = 1 and c = 0.

= 36/6 = 6
On checking the option we get only option (b) satisfies this.

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 22
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Simplify the following expression:  [SSC CGL 24/08/2021 (Evening)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 22


= -(7/4) ÷ (15/8) = -(14/15)

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 23
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The expression  is equal to:  [SSC CGL Tier II (15/10/2020)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 23



= 5(3 + 2√2)

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 24
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The value of  lies between:  [SSC CGL Tier II (16/11/2020)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 24




So, 2.236 lies between 2 and 2.5

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 25
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The value of  is equal to:  [SSC CGL Tier II (18/11/2020)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 25

 on rationalisation

⇒ 5 - 4 = 1

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 26
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The value of Is:  [SSC CGL 04/03/2020 (Afternoon)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 26

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 27
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If (√2 + √5 + √3) x k = -12 then what will be the value of k?  [SSC CGL Tier II (11/09/2019)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 27

(√2 + √5 − √3) × k = -12


= (√2 + √5 + √3) (2 − √10)

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 28
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The expression  is equal to  [SSC CGL Tier II (12/09/2019)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 28


Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 29
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The value of   is :  [SSC CGL Tier II (12/09/2019)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 29



= 153/990 = 0.1545454 ...∞ = 
Alternate method :

Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 30
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A student was asked to find the value of  His answer was 19(1/4). What is the difference between his answer and the correct answer?  [SSC CGL Tier II (13/09/2019)]
Detailed Solution for Test: SSC CGL Previous Year Questions: Simplification (2023-18) - Question 30

 

Required difference = (77/4) - (23/2) = 7(3/4)

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