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Class 10 Exam  >  Class 10 Tests  >  Physics for Class 10  >  Case Based Questions Test: Electricity - 2 - Class 10 MCQ

Case Based Questions Test: Electricity - 2 - Class 10 MCQ


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15 Questions MCQ Test Physics for Class 10 - Case Based Questions Test: Electricity - 2

Case Based Questions Test: Electricity - 2 for Class 10 2024 is part of Physics for Class 10 preparation. The Case Based Questions Test: Electricity - 2 questions and answers have been prepared according to the Class 10 exam syllabus.The Case Based Questions Test: Electricity - 2 MCQs are made for Class 10 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Case Based Questions Test: Electricity - 2 below.
Solutions of Case Based Questions Test: Electricity - 2 questions in English are available as part of our Physics for Class 10 for Class 10 & Case Based Questions Test: Electricity - 2 solutions in Hindi for Physics for Class 10 course. Download more important topics, notes, lectures and mock test series for Class 10 Exam by signing up for free. Attempt Case Based Questions Test: Electricity - 2 | 15 questions in 30 minutes | Mock test for Class 10 preparation | Free important questions MCQ to study Physics for Class 10 for Class 10 Exam | Download free PDF with solutions
Case Based Questions Test: Electricity - 2 - Question 1
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Find out the following in the electric circuit given in the figure. Answer the questions:

Effective resistance of two 8 Ω resistors in the combination.

Detailed Solution for Case Based Questions Test: Electricity - 2 - Question 1
1/R = 1/8 + 1/8 = 2 / 8

R = 4Ω

Case Based Questions Test: Electricity - 2 - Question 2
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Find out the following in the electric circuit given in the figure. Answer the questions:

Power dissipated in 4 Ω resistor

Detailed Solution for Case Based Questions Test: Electricity - 2 - Question 2
Power dissipated in 4Ω = P P = VI = 4V × 1A = 4 watt
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Case Based Questions Test: Electricity - 2 - Question 3
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Find out the following in the electric circuit given in the figure. Answer the questions:

Current flowing through a 4 Ω resistor.

Detailed Solution for Case Based Questions Test: Electricity - 2 - Question 3
Current flowing through the circuit = Current flowing through 4 Ω Equivalent resistance of the circuit = 4Ω + 4Ω = 8Ω

Current flowing in the circuit = V /R = 8V/8Ω = 1A

Case Based Questions Test: Electricity - 2 - Question 4
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Find out the following in the electric circuit given in the figure. Answer the questions:

Difference in reading of ammeter A1 and A2
Detailed Solution for Case Based Questions Test: Electricity - 2 - Question 4

There is no difference in the readings of ammeters A1 and A2 as same current flows through all elements in a series curcuit.

Case Based Questions Test: Electricity - 2 - Question 5
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Find out the following in the electric circuit given in the figure. Answer the questions:

Potential difference across 4 Ω resistor
Detailed Solution for Case Based Questions Test: Electricity - 2 - Question 5
Potential difference across 4Ω = V1 V1= IR1

V1 = 1A × 4Ω = 4V

Case Based Questions Test: Electricity - 2 - Question 6
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Two conductors A and B of resistances 5 Ω and 10 Ω respectively are first joined in parallel and then in series. In each case the voltage applied is 20 V. Answer the questions:

In which arrangement will the current through A and B be the same ?
Case Based Questions Test: Electricity - 2 - Question 7
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Two conductors A and B of resistances 5 Ω and 10 Ω respectively are first joined in parallel and then in series. In each case the voltage applied is 20 V. Answer the questions:

Draw the circuit diagram to show connection when A and B are joined in parallel?
Detailed Solution for Case Based Questions Test: Electricity - 2 - Question 7
Correct circuit diagram
Case Based Questions Test: Electricity - 2 - Question 8
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Two conductors A and B of resistances 5 Ω and 10 Ω respectively are first joined in parallel and then in series. In each case the voltage applied is 20 V. Answer the questions:

Equivalent resistance in series combination is:
Detailed Solution for Case Based Questions Test: Electricity - 2 - Question 8
5 + 10 = 15 Ω
Case Based Questions Test: Electricity - 2 - Question 9
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Two conductors A and B of resistances 5 Ω and 10 Ω respectively are first joined in parallel and then in series. In each case the voltage applied is 20 V. Answer the questions:

Equivalent resistance in parallel combination is:
Detailed Solution for Case Based Questions Test: Electricity - 2 - Question 9

(ii) The voltage across A and B will be the same in a parallel arrangement.

(iii) Current in A and B will be same in a series arrangement.

Case Based Questions Test: Electricity - 2 - Question 10
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Two conductors A and B of resistances 5 Ω and 10 Ω respectively are first joined in parallel and then in series. In each case the voltage applied is 20 V. Answer the questions:

Q. In which combination will the voltage across the conductors A and B be the same ?
Detailed Solution for Case Based Questions Test: Electricity - 2 - Question 10
(i) Voltage across A and B will be the same in parallel arrangement.

Fig. Parallel arrangement

Case Based Questions Test: Electricity - 2 - Question 11
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Study the circuit shown in which three identical bulbs B1, B2 and B3 are connected in parallel with a battery of 4.5 V. Answer the questions:

Q. What will happen to the other two bulbs if the bulb B3 gets fused ?
Case Based Questions Test: Electricity - 2 - Question 12
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Study the circuit shown in which three identical bulbs B1, B2 and B3 are connected in parallel with a battery of 4.5 V. Answer the questions:

How many resistors of 88 W are connected in parallel to carry 10 A current on a 220 V line:
Detailed Solution for Case Based Questions Test: Electricity - 2 - Question 12

Equivalent resistance,= 1 / Rp = n / 88

Rp = 88 / n

V = IR

R = 88 / n

88 /n = 220 / 10

n= 4 resistors

Case Based Questions Test: Electricity - 2 - Question 13
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Study the circuit shown in which three identical bulbs B1, B2 and B3 are connected in parallel with a battery of 4.5 V. Answer the questions:

If the wattage of each bulb is 1.5 W, how much readings will the ammeter A show when all the three bulbs glow simultaneously.
Detailed Solution for Case Based Questions Test: Electricity - 2 - Question 13
When the bulbs are in parallel, wattage will be added (4.5 W) and the ammeter reading would be,

Case Based Questions Test: Electricity - 2 - Question 14
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Study the circuit shown in which three identical bulbs B1, B2 and B3 are connected in parallel with a battery of 4.5 V. Answer the questions:

Find the statement which does not justify parallel connection:
Detailed Solution for Case Based Questions Test: Electricity - 2 - Question 14
There is a path of flow of electrons through each resistor. So there are several paths.
Case Based Questions Test: Electricity - 2 - Question 15
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Study the circuit shown in which three identical bulbs B1, B2 and B3 are connected in parallel with a battery of 4.5 V. Answer the questions:

Find the total resistance of the circuit:
Detailed Solution for Case Based Questions Test: Electricity - 2 - Question 15
Ammeter reading = 1.0A

V = 4.5V

R = V/I

= 4.5 = 4.5 Ω

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