NEET Exam  >  NEET Tests  >  Chemistry Class 11  >  Test: Aromaticity & Acid Base Properties - NEET MCQ

Test: Aromaticity & Acid Base Properties - NEET MCQ


Test Description

15 Questions MCQ Test Chemistry Class 11 - Test: Aromaticity & Acid Base Properties

Test: Aromaticity & Acid Base Properties for NEET 2024 is part of Chemistry Class 11 preparation. The Test: Aromaticity & Acid Base Properties questions and answers have been prepared according to the NEET exam syllabus.The Test: Aromaticity & Acid Base Properties MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Aromaticity & Acid Base Properties below.
Solutions of Test: Aromaticity & Acid Base Properties questions in English are available as part of our Chemistry Class 11 for NEET & Test: Aromaticity & Acid Base Properties solutions in Hindi for Chemistry Class 11 course. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free. Attempt Test: Aromaticity & Acid Base Properties | 15 questions in 15 minutes | Mock test for NEET preparation | Free important questions MCQ to study Chemistry Class 11 for NEET Exam | Download free PDF with solutions
1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Aromaticity & Acid Base Properties - Question 1

Direction (Q. Nos. 1 - 10) This section contains 10 multiple choice questions. Each question has four choices (a), (b), (c), and (d), out of which ONLY ONE option is correct.

Q. Arrange the following compounds in increasing order of their basic strength.

1.

2.

3.

4.

Detailed Solution for Test: Aromaticity & Acid Base Properties - Question 1


So, correct option is A. 

Test: Aromaticity & Acid Base Properties - Question 2

In the compound below, which nitrogen is protonated first when treated with HCI?

Detailed Solution for Test: Aromaticity & Acid Base Properties - Question 2

1 is protonated because its lone pair is not involved in aromaticity and also lone pair on Nitrogen 2 will get involved in conjugation and will provide extra electron density on Nitrogen 1. Hence, Option C is correct.

Test: Aromaticity & Acid Base Properties - Question 3

Which of the following compounds is more easily oxidised to a carbonyl when treated with MnO2?

Detailed Solution for Test: Aromaticity & Acid Base Properties - Question 3

MnO2 is used for the selective oxidation of allylic and benzylic carbon and in these compounds these carbons are not very easily oxidisable.

Test: Aromaticity & Acid Base Properties - Question 4

Which among these is the simplest example for polycyclic arenes?

Detailed Solution for Test: Aromaticity & Acid Base Properties - Question 4

Naphthalene has fused ring of aromaticity and has the simplest structure when compared with other polycyclic aromatic hydrocarbons.

Test: Aromaticity & Acid Base Properties - Question 5

The compound shown below evolve hydrogen gas when refluxed with potassium metal, why?

Detailed Solution for Test: Aromaticity & Acid Base Properties - Question 5

Metals like Potassium tend to loose their own electrons and the excess electrons will complete the aromaticity of the system.Thus, Deprotonation of the above compound converts it into an aromatic anion witn 6 pi electrons.

Test: Aromaticity & Acid Base Properties - Question 6

Which compound below has maximum tendency to form a salt when treated with HBr?

Detailed Solution for Test: Aromaticity & Acid Base Properties - Question 6

Option C has maximum tendency to form a salt when treated with HBr. Due to the polarity difference and the aromatic nature of ring after generation of carbocation on Carbon of Carbonyl group. It will give an aromatic system of 6 pi electrons.

Test: Aromaticity & Acid Base Properties - Question 7

What is the correct order of increasing acidic strength of the following?

Detailed Solution for Test: Aromaticity & Acid Base Properties - Question 7

Compound I is having the highest acidic strength due to the -I effect of five CF3 substituents.

Compound II is having less acidic strength than I but more than the rest due to the extremely stable conjugate anion formed after deprrotonation.

So, Option B is correct.

Test: Aromaticity & Acid Base Properties - Question 8

How many Kekule structures exist for benzene?

Detailed Solution for Test: Aromaticity & Acid Base Properties - Question 8


Benzene has Five resonance structures. They are Two Kekule’s and Three Dewar’s structure.

Test: Aromaticity & Acid Base Properties - Question 9

How many monobromo derivatives exists for anthracene?

Detailed Solution for Test: Aromaticity & Acid Base Properties - Question 9

The correct answer is Option B. 

There are 3 monobromo derivatives exists for anthracene:
1-Chloroanthracene
2-Chloroanthracene
and 9-Chloroanthracene

Test: Aromaticity & Acid Base Properties - Question 10

7-bromo-1,3,5-cycloheptatriene exists as ionic species in aqueous solution while 5-bromo-1,3-cyclopentadiene does not ionise even in presence of AgNO3(aq) because

Detailed Solution for Test: Aromaticity & Acid Base Properties - Question 10

The correct answer is Option C.
The C-Br bond in the case of 7-bromo-1, 3, 5-cycloheptatriene is broken easily because the intermediate carbocation formed is very stable (aromatic as it contains (4n + 2)π e- ie, follows Huckle rule) while it does not break easily in the case of 5-bromo-1, 3-cyclopentadiene because carbocation formed here is highly unstable as it is antiaromatic i.e., does not follow Huckel rule. (It contains 4π electrons).
 

*Multiple options can be correct
Test: Aromaticity & Acid Base Properties - Question 11

Direction (Q. Nos. 11-15) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Q. Consider the following compounds.

The correct statement regarding properties of above mentioned compounds is/are

Detailed Solution for Test: Aromaticity & Acid Base Properties - Question 11
  • Both have all their C—C bonds of equal length due to conjugation.
  • I does not decolorises brown colour of bromine water solution but II does as The π bonds in Cyclooctatetraene (Compound II) react as usual for olefins, rather than as aromatic ring systems.
  • I is planar but II is not as it adopts a tub conformation.
  • Cyclooctatetraene shows various other addition reactions including Sulfonation.

Hence, Option A, B and D are correct.

*Multiple options can be correct
Test: Aromaticity & Acid Base Properties - Question 12

Which of the following systems are aromatic?

Detailed Solution for Test: Aromaticity & Acid Base Properties - Question 12

The correct answers are Options C and D.
Aromatic compounds are those which follow Huckel's rule i.e, they have (4n+2) π electrons, n must be an integer.
In option C, there are 5 π bonds which means 10 π electrons; so 4n+2 = 10 i.e, n= 2 which is an integer.
In option D, Nitrogen has a lone pair which contains 2 electrons therefore this compound also have 10 π electrons; so n= 2.

*Multiple options can be correct
Test: Aromaticity & Acid Base Properties - Question 13

What is true about the 1,3,5,7-cyclooctatetraene?

Detailed Solution for Test: Aromaticity & Acid Base Properties - Question 13

1-3-5-7-cyclooctatetraene it has 8 pi electrons, and like stated above, fits the criteria of 4n, to be antiaromatic. to avoid this state of anti-aromaticity (less stable then expected), it becomes non-planar, so it can be more stable then it would be in the antiaromatic state. cyclooctatetraene can do this because it can fold, however other 6 carbon compounds that have 4n electrons and are planar can not and result in an antiaromatic compound.
Potassium cyclooctatetraene is formed by the reaction of cyclooctatetraene with potassium metal:
2 K + C8H8 → K2C8H8
The reaction entails 2-electron reduction of the polyene and is accompanied by a color change from colorless to brown.

*Multiple options can be correct
Test: Aromaticity & Acid Base Properties - Question 14

What is true regarding the following compound?

Detailed Solution for Test: Aromaticity & Acid Base Properties - Question 14

The given compound will turn itself to
To gain aromaticity, it will transfer the electrons as follow:-

It is clear that the compound is heterocyclic(the ring constitutes other than C and H). Due to -ve charge on outer O atom, it has high affinity for BF3. However, NaBH4  has no reaction with this. As the compound will turn itself to latter, there is no aldehyde or ketone group present in the compound.

Test: Aromaticity & Acid Base Properties - Question 15

Organic compounds can be classified even based upon the function groups. Identify the one which is not a functional group

Detailed Solution for Test: Aromaticity & Acid Base Properties - Question 15

Isocyanide is a compound and it is not a functional group.

195 videos|337 docs|190 tests
Information about Test: Aromaticity & Acid Base Properties Page
In this test you can find the Exam questions for Test: Aromaticity & Acid Base Properties solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Aromaticity & Acid Base Properties, EduRev gives you an ample number of Online tests for practice
195 videos|337 docs|190 tests
Download as PDF

How to Prepare for NEET

Read our guide to prepare for NEET which is created by Toppers & the best Teachers
Download the FREE EduRev App
Track your progress, build streaks, highlight & save important lessons and more!