What should be subtracted to x2+2x+2 to make it a perfect square?
By subtracting 1 from 2,you will get 1 that makes the whole square of (x+1)=1
If a + b = 12 and a2 + b2 = 60, the value of a3 + b3 is:
The correct option is Option C.
(a + b)² = a² + b² + 2ab
(12)² = 60 + 2ab
ab = (144 - 60)/2
ab = 84/2
ab = 42
Now,
(a + b)³ = a³ + b³ + 3ab(a+b)
(12)³ = a³ + b³ + (3 × 42 × 12)
a³ + b³ = 1728 - 1512
Therefore, a³ + b³ = 216
One of the factors of (16y2 – 1) + (1 -4y)2 is
(101)2 is equal to
(100-1)²= (100)²+(1)²+2×100×1 10000+1+200 =10201
Find the value of (9a + 10b)2
a2 + b2 + c2 – ab – bc – ca equals:
= ( a² + b² + c² - ab - bc - ca )
By multiplying it by 2 and dividing it by 2.
= 2 ( a² + b² + c² - ab - bc - ca ) ÷ 2
= ( 2a² + 2b² + 2c² - 2ab - 2bc - 2ca ) ÷ 2
= ( a² + a² + b² + b² + c² + c² - 2ab - 2bc - 2ca ) ÷ 2
= ( a² + b² - 2ab + b² + c² - 2bc + a² + c² - 2ca ) ÷ 2
= [ ( a - b )² + ( b - c )² + ( a - c )² ] ÷ 2
Now , whatever is the value of ( a - b ) , ( b - c ) and ( a - c ) but its square will be always positive, and 2 is also a positive number.
So, the sum of ( a - b )², ( b - c )² and ( a - c )² will be a positive number and if a positive number is divided by a positive number then the result is also a positive number.
So, it is a positive number,hence it can't be a negative number.
Evaluate 98 x 102.
(100+2)×(100-2). [(a+b)(a-b)=a^2-b^2
100^2 - 2^2
10000 - 4
9996
a2 + b2 is equal to
Solve the equation x2 + 6x - 7 = 0
If a - b = 3 and a2 + b2 = 29, find the value of ab.
2ab = (a2 + b2) - (a - b)2
= 29 - 9 = 20
⇒ ab = 10.
What should be added to x2+2x+0.5 to make it a perfect square?
The missing figure in the expression
(5p +…)2 = ….+ 40 pq + 16q2 are:
Factorise: x4-1
Factorise: x2– 81
What is the product of (x+a) and (x+b)?
The value of 101 x 99 is
(100+1)×(100 - 1) it is the formula of a²-b² so, (100)² -(1)² = 10000-1 = 9999.
If 2x + 3y = 12 and xy = 5, find the value of 4x2 + 9y2.
Find the value of (109)2
(99)2 is equivalent to
The expansion of (2a – 3b + 5c)2.
The expansion of (2a - 3b + 5c)² -: (2a)² + (- 3b)² + (5c)² + 2× 2a × (-3b) + 2× (-3b)× 5c + 2× 5c + 2a. = 4a² + 9b² + 25c² - 12ab - 30bc + 20ac
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