Description

This mock test of Test: Circles- 2 for Class 9 helps you for every Class 9 entrance exam.
This contains 25 Multiple Choice Questions for Class 9 Test: Circles- 2 (mcq) to study with solutions a complete question bank.
The solved questions answers in this Test: Circles- 2 quiz give you a good mix of easy questions and tough questions. Class 9
students definitely take this Test: Circles- 2 exercise for a better result in the exam. You can find other Test: Circles- 2 extra questions,
long questions & short questions for Class 9 on EduRev as well by searching above.

QUESTION: 1

AB is a chord of a circle with radius ‘r’. If P is any point on the circle such that ∠APB is a right angle , then AB is equal to

Solution:

QUESTION: 2

In the given figure, AC is a diameter of the given circle and ∠BCD = 75^{o}. Then, ∠EAF−∠ABC is equal to

Solution:

QUESTION: 3

The region between chord and either of the arc is called

Solution:

QUESTION: 4

P is a point on the diameter AB of a circle and CD is a chord perpendicular to AB. If AP = 4 cm and PB = 16 cm, the length of chord CD is

Solution:

QUESTION: 5

Arc ABC subtends an angle of 130^{o} at the centre O of the circle. AB is extended to P. Then ∠CBP equals :

Solution:

QUESTION: 6

Chords AB and CD intersect at right angles. If ∠BAC = 40^{o}, then ∠ABD is equal to

Solution:

QUESTION: 7

In the given figure, O is the centre of the circle. ∠OAB and ∠OCB are 40^{o} and 30^{o} respectively. Then, the measure of ∠AOC is

Solution:

(Angle at the centre is double the angle at the circumference subtended by the same chord)

QUESTION: 8

In the given, AB is side of regular five sided polygon and AC is a side of a regular six sided polygon inscribed in the circle with centre O. AO and CB intersect at P, then ∠APB is equal to

Solution:

QUESTION: 9

In the given figure, if ∠AOB = 80^{o} and ∠ABC = 30^{o} , then ∠CAO is equal to

Solution:

2ACB=AOB

ACB=40

CAB+ACB+ABC=180

CAB=180-70

CAB=110

since,OA=OB(radius)

OAB=OBA

AOB+OAB+OBA=180

2OBA=100

OBA=50

CAO=CAB-OBA=110-5O

CAO=60^{o}

QUESTION: 10

In the figure, O is the centre of eh circle and ∠AOB = 80^{o}. The value of x is :

Solution:

QUESTION: 11

In the given figure if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then CD is equal to

Solution:

QUESTION: 12

If ∠OAB = 40^{o}, then the measure of ∠ACB is

Solution:

QUESTION: 13

Chords AD and BC intersect each other at right angles at point P. ∠DAB = 35^{o}, then ∠ADC is equal to

Solution:

QUESTION: 14

In the given figure, AB is a diameter of the circle APBR. APQ and RBQ are straight lines. If ∠A = 35^{o} and , then the measure of ∠PBR is

Solution:

QUESTION: 15

In the figure, O is the center of the circle. If ∠OAB = 40^{o}, then ∠ACB is equal to :

Solution:

QUESTION: 16

X is a point on a circle with centre O. If X is equidistant from the two radii OP, OQ, then arc PX : arc PQ is equal to

Solution:

QUESTION: 17

BC is a diameter of the circle and ∠BAO = 60^{o} . Then ∠ADC is equal to

Solution:

QUESTION: 18

What fraction of the whole circle is minor arc RP in the given figure ?

Solution:

QUESTION: 19

In the given figure, AD is the diameter of the circle and AE = DE. If ∠ABC = 115^{o}, then the measure of ∠CAE is

Solution:

QUESTION: 20

In the figure, if ∠DAB = 60^{o}, ∠ABD = 50^{o}, then ∠ACB is equal to :

Solution:

QUESTION: 21

If ABCD is a cyclic trapezium in which AD ║ BC and ∠B = 60^{o}, then ∠BCD is equal to

Solution:

QUESTION: 22

In the given figure, O is the centre of the circle and ∠AOC = 130^{o}. Then ∠ABC is equal to

Solution:

360^{o} - 130^{o} =230^{o}

Therefore, angle ABC =1/2reflex angle AOC

Angle ABC =1/2 230^{o}

So, angle ABC =115^{o}

QUESTION: 23

In the given circle, O is the centre and ∠BDC = 42^{o}. Then, ∠ACB is equal to

Solution:

In ∆ BDC and ∆ BAC

Angle BAC = BDC

(angle made on same segment BC)

Since ABC is making right angle (90)

So,

In ∆ABC

ABC +BAC+ACB=180

(angle sum property of triangle)

90+42+ACB=180

ACB=180-132

ACB=48^{o}

QUESTION: 24

AOB is the diameter of the circle. If ∠AOE = 150^{o}, then the measure of ∠CBE is

Solution:

QUESTION: 25

In the given figure, a circle is centred at O. The value of x is :

Solution:

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