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QUESTION: 1

A frequency distribution is defined as

Solution:

QUESTION: 2

The class mark of class interval 60 – 70 will be

Solution:

class mark = [lower class interval + upper class interval]/2

= (60+70)/2

= 130/2

= 65

(if the intervals are of uniform width)

QUESTION: 3

The consecutive class marks of a data having continuous class intervals having class width as 5, have a gap of ________ between them.

Solution:

QUESTION: 4

Number of runs scored by a cricket player in 25 innings are as follows:

26, 35, 94, 48, 82, 105, 53, 0, 39, 42, 71, 0, 64, 15, 34, 67, 0, 42, 124, 84, 54, 48, 139, 64, 47.

The number of centuries scored by him is

Solution:

QUESTION: 5

If the class marks in a frequency distribution are 19.5, 26.5, 33.5, 40.5 then the class corresponding to the class mark 33.5 is:

Solution:

QUESTION: 6

A curious 12^{th} class student wants to know and collect the data regarding the percentage of students who got grade A1 in Mathematics during the last 10 years in Board examinations. This collected data is known as

Solution:

Secondary data refers to data that was collected by someone other than the user. Common sources of secondary data for social science include censuses, information collected by government departments, organisational records and data that was originally collected for other research purposes.

QUESTION: 7

Class size for the following distribution: 0 – 0.25, 0.25 – 0.50, 0.50 – 0.75 is

Solution:

QUESTION: 8

Three coins were tossed thirty times. Each time the number of heads occurring was noted as follows:

0, 1, 2, 2, 1, 2, 3, 1, 3, 0

1, 3, 1, 1, 2, 2, 0, 1, 2, 1

3, 0, 0, 1, 1, 2, 3, 2, 2, 0

The frequency distribution table for the given data will be

Solution:

QUESTION: 9

Class mark of a class interval U-L is

Solution:

QUESTION: 10

In the following data, the number of class intervals, (by inclusive method), and taking 4 as the magnitude of class intervals will be

31, 23, 19, 29, 22, 20, 16, 10, 13, 34

38, 33, 28, 21, 15, 18, 36, 24, 18, 15

12, 30, 27, 23, 20, 17, 14, 32, 26, 25

18, 29, 24, 19, 16, 11, 22, 15, 17, 10

Solution:

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