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This mock test of Test: Perpendicular From Centre To Chord for Class 9 helps you for every Class 9 entrance exam.
This contains 10 Multiple Choice Questions for Class 9 Test: Perpendicular From Centre To Chord (mcq) to study with solutions a complete question bank.
The solved questions answers in this Test: Perpendicular From Centre To Chord quiz give you a good mix of easy questions and tough questions. Class 9
students definitely take this Test: Perpendicular From Centre To Chord exercise for a better result in the exam. You can find other Test: Perpendicular From Centre To Chord extra questions,
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QUESTION: 1

A circle with centre O in which diameter AB bisects the chord CD at point E. If CE = ED = 8 cm and EB = 4 cm, the radius of the circle is

Solution:

QUESTION: 2

Two circles of radii 5 cm and 3 cm intersect at two points and the distance between their centres is 4 cm. The length of the common chord is

Solution:

QUESTION: 3

The length of chord which is at a distance of 12 cm from centre of circle of radius 13 cm is:

Solution:

QUESTION: 4

AD is a diameter of a circle and AB is chord. If AB = 24 cm, AD = 30 cm, the distance of AB from the centre of the circle is :

Solution:

QUESTION: 5

The perpendicular distance of a chord 8 cm long from the centre of a circle of radius 5 cm is

Solution:

QUESTION: 6

A, B, C and D are four points on a circle. AC and BD intersect at E such that angle BEC = 140° and angle ECD = 25°, then angle BAC is

Solution:

QUESTION: 7

The radius of a circle which has a 6 cm long chord, 4 cm away from the centre of the circle is

Solution:

QUESTION: 8

Two concentric circles are intersected by a line L at A, B, C and D. Then

Solution:

QUESTION: 9

In the figure, AD is a straight line. OP is perpendicular to AD and O is the centre of both the circles. If AO = 34 cm, OB = 20 cm and OP = 16 cm, then the length of AD is

Solution:

QUESTION: 10

Two circles of radii10 cm and 8 cm intersect and the length of the common chord is 12 cm. The distance between their centers is

Solution:

Center of circles= O and O'

Radii = 10 and 8cm

common chord= PQ

OP= 10cm

O'P = 8cm

PQ= 12cm

PL= 1/2PQ

= 1/2 x 12

= 6cm

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