In two right triangles, one side and an acute angle of one are equal to the corresponding side and angle of the other, then ΔABC ≅ ΔDEF by the criterion
In ΔABC if ∠A = ∠B, then
In the given figure, AB = AC and ∠ACD = 105°, ∠BAC will be
Angle acb = 75 ( linear pair) Ab= Ac hence angle B= angle c in triangle ABC angle a+B+c= 180. angle B+ c = 150 hence angle c a= 30
PQR is a triangle in which PQ = PR and S is any point on the side PQ. Through S, a line is drawn parallel to QR and intersecting PR at T. then
The altitude of an equilateral triangle of side a to any of its other sides from the opposite vertex is
In an isosceles right angled triangle, the measures of the acute angles are
In ΔABC if AB = BC then:
Pick out the incorrect statement
The altitudes of a triangle are the line segments drawn from each side of the triangle to the angle opposite that side, such that the line segment is perpendicular to the side it is drawn from. In an isosceles triangle, only the altitudes of the legs of equal length in the triangle are congruent.
If the bisector of the exterior vertical angle of a triangle is parallel to the base, then it is
In PQR, PQ = PR and R = 65°, then P = ?
By using the theorem,If two sides of a triangle are equal then the opposite angles to the sides are equal.
⇒ if PQ=PR then ∠Q=∠R
in triangle PQR,
⇒ ∠P+∠Q+∠Q=180° (∵∠Q=∠R)