IBPS PO Mains Mock Test - 7 - Bank Exams MCQ

2) Ekta is sitting second to the right of Lalita.

3) Mohit and Trikesh sit opposite to each other.

4) Trikesh is not an immediate neighbour of Lalita.

5) Bala sits second to the left of Mohit.

6) Kajal sits second to the left of Ekta.

7) Immediate left neighbours of Lalita are facing the opposite direction.

8) Trikesh faces outside of the centre.

9) Harsh sits immediately to the left of Trikesh. (This eliminates case 2)

10) Kajal and Harsh are facing the same direction as that of Ekta.

Thus, Harsh and Kajal are the immediate neighbours of Trikesh.

2) Ekta is sitting second to the right of Lalita.

3) Mohit and Trikesh sit opposite to each other.

4) Trikesh is not an immediate neighbour of Lalita.

5) Bala sits second to the left of Mohit.

6) Kajal sits second to the left of Ekta.

7) Immediate left neighbours of Lalita are facing the opposite direction.

8) Trikesh faces outside of the centre.

9) Harsh sits immediately to the left of Trikesh. (This eliminates case 2)

10) Kajal and Harsh are facing the same direction as that of Ekta.

Thus, Lalita and Harsh are immediate neighbours of Bala is true.

2) Ekta is sitting second to the right of Lalita.

3) Mohit and Trikesh sit opposite to each other.

4) Trikesh is not an immediate neighbour of Lalita.

5) Bala sits second to the left of Mohit.

6) Kajal sits second to the left of Ekta.

7) Immediate left neighbours of Lalita are facing the opposite direction.

8) Trikesh faces outside of the centre.

9) Harsh sits immediately to the left of Trikesh. (This eliminates case 2)

10) Kajal and Harsh are facing the same direction as that of Ekta.

Thus, Ekta is immediate to the left of Sunil.

2) Ekta is sitting second to the right of Lalita.

3) Mohit and Trikesh sit opposite to each other.

4) Trikesh is not an immediate neighbour of Lalita.

5) Bala sits second to the left of Mohit.

6) Kajal sits second to the left of Ekta.

7) Immediate left neighbours of Lalita are facing the opposite direction.

8) Trikesh faces outside of the centre.

9) Harsh sits immediately to the left of Trikesh. (This eliminates case 2)

10) Kajal and Harsh are facing the same direction as that of Ekta.

Thus, two persons sit between Kajal and Mohit when counted anticlockwise from Mohit.

2) Ekta is sitting second to the right of Lalita.

3) Mohit and Trikesh sit opposite to each other.

4) Trikesh is not an immediate neighbour of Lalita.

5) Bala sits second to the left of Mohit.

6) Kajal sits second to the left of Ekta.

7) Immediate left neighbours of Lalita are facing the opposite direction.

8) Trikesh faces outside of the centre.

9) Harsh sits immediately to the left of Trikesh. (This eliminates case 2)

10) Kajal and Harsh are facing the same direction as that of Ekta.

All of them are facing outside the centre except Mohit.

Thus, Mohit is different from others.

We have:

• The one who likes BMW is three persons senior to Rohan.
• Rohan neither likes Toyota nor Ford.
• Kabir promotes the one who likes BMW but doesn’t like Toyota.

That means, in case (1) Rohan is designated as a clerk, and Kabir is designated as ED, in case (2) Rohan is designated as a clerk, and Kabir is designated as CMD.

Based on the above given information we have:

Again, we have:

• Three persons are designated between Shweta and the one who likes Maruti.
• The number of persons designated between the one who likes Maruti and Rohan is one less than the number of persons senior to Ankita.

That means, in case (1) the one who likes Maruti is designated as AGM, case (2) gets eliminated.

Based on the above given information we have:

Case (2) is not valid as Three persons are designated between Shweta and the one who likes Maruti.

Again, we have:

• Not more than one person is designated between the one who likes Honda and Lalit.
• Lalit is two persons senior to the one who likes Ford.

That means, in case (1) Kabir likes Honda, and Lalit likes BMW, in case (1a) Ankita likes Honda, and Lalit likes BMW.

Based on the above given information we have:

Again, we have:

• Mohit gets promoted by the one who likes Fiat and is immediately senior to the one who likes Tata.
• Neither Kabir nor Ankita likes Fiat.

That means, in case (1) Shweta likes Fiat, and Mohit likes ford, case (1a) is not valid.

Based on the above given information we have:

Case (1a) is not valid as Kabir doesn’t like Toyota.

We have:

• The one who likes BMW is three persons senior to Rohan.
• Rohan neither likes Toyota nor Ford.
• Kabir promotes the one who likes BMW but doesn’t like Toyota.

That means, in case (1) Rohan is designated as a clerk, and Kabir is designated as ED, in case (2) Rohan is designated as a clerk, and Kabir is designated as CMD.

Based on the above given information we have:

Again, we have:

• Three persons are designated between Shweta and the one who likes Maruti.
• The number of persons designated between the one who likes Maruti and Rohan is one less than the number of persons senior to Ankita.

That means, in case (1) the one who likes Maruti is designated as AGM, case (2) gets eliminated.

Based on the above given information we have:

Case (2) is not valid as Three persons are designated between Shweta and the one who likes Maruti.

Again, we have:

• Not more than one person is designated between the one who likes Honda and Lalit.
• Lalit is two persons senior to the one who likes Ford.

That means, in case (1) Kabir likes Honda, and Lalit likes BMW, in case (1a) Ankita likes Honda, and Lalit likes BMW.

Based on the above given information we have:

Again, we have:

• Mohit gets promoted by the one who likes Fiat and is immediately senior to the one who likes Tata.
• Neither Kabir nor Ankita likes Fiat.

That means, in case (1) Shweta likes Fiat, and Mohit likes ford, case (1a) is not valid.

Based on the above given information we have:

Case (1a) is not valid as Kabir doesn’t like Toyota.

We have:

• The one who likes BMW is three persons senior to Rohan.
• Rohan neither likes Toyota nor Ford.
• Kabir promotes the one who likes BMW but doesn’t like Toyota.

That means, in case (1) Rohan is designated as a clerk, and Kabir is designated as ED, in case (2) Rohan is designated as a clerk, and Kabir is designated as CMD.

Based on the above given information we have:

Again, we have:

• Three persons are designated between Shweta and the one who likes Maruti.
• The number of persons designated between the one who likes Maruti and Rohan is one less than the number of persons senior to Ankita.

That means, in case (1) the one who likes Maruti is designated as AGM, case (2) gets eliminated.

Based on the above given information we have:

Case (2) is not valid as Three persons are designated between Shweta and the one who likes Maruti.

Again, we have:

• Not more than one person is designated between the one who likes Honda and Lalit.
• Lalit is two persons senior to the one who likes Ford.

That means, in case (1) Kabir likes Honda, and Lalit likes BMW, in case (1a) Ankita likes Honda, and Lalit likes BMW.

Based on the above given information we have:

Again, we have:

• Mohit gets promoted by the one who likes Fiat and is immediately senior to the one who likes Tata.
• Neither Kabir nor Ankita likes Fiat.

That means, in case (1) Shweta likes Fiat, and Mohit likes ford, case (1a) is not valid.

Based on the above given information we have:

Case (1a) is not valid as Kabir doesn’t like Toyota.

We have:

• The one who likes BMW is three persons senior to Rohan.
• Rohan neither likes Toyota nor Ford.
• Kabir promotes the one who likes BMW but doesn’t like Toyota.

That means, in case (1) Rohan is designated as a clerk, and Kabir is designated as ED, in case (2) Rohan is designated as a clerk, and Kabir is designated as CMD.

Based on the above given information we have:

Again, we have:

• Three persons are designated between Shweta and the one who likes Maruti.
• The number of persons designated between the one who likes Maruti and Rohan is one less than the number of persons senior to Ankita.

That means, in case (1) the one who likes Maruti is designated as AGM, case (2) gets eliminated.

Based on the above given information we have:

Case (2) is not valid as Three persons are designated between Shweta and the one who likes Maruti.

Again, we have:

• Not more than one person is designated between the one who likes Honda and Lalit.
• Lalit is two persons senior to the one who likes Ford.

That means, in case (1) Kabir likes Honda, and Lalit likes BMW, in case (1a) Ankita likes Honda, and Lalit likes BMW.

Based on the above given information we have:

Again, we have:

• Mohit gets promoted by the one who likes Fiat and is immediately senior to the one who likes Tata.
• Neither Kabir nor Ankita likes Fiat.

That means, in case (1) Shweta likes Fiat, and Mohit likes ford, case (1a) is not valid.

Based on the above given information we have:

Case (1a) is not valid as Kabir doesn’t like Toyota.

a) Words are arranged in ascending dictionary order, from the right end one at a time in each step.

b) The largest number is reversed and one is added to it and then placed at the left end one at a time in each step, moving the previously placed number towards right.

So the given input can be analyzed as follows,

Applying the same rule on the given input we get,

Input: hold 71 open 59 equal 81 13 shift count 68 kitten 46

Step I: 19 hold 71 open 59 equal 13 shift 68 kitten 46 count

Step II: 18 19 hold open 59 13 shift 68 kitten 46 count equal

Step III: 87 18 19 open 59 13 shift kitten 46 count equal hold

Step IV: 96 87 18 19 open 13 shift 46 count equal hold kitten

Step V: 65 96 87 18 19 13 shift count equal hold kitten open

Step VI: 32 65 96 87 18 19 count equal hold kitten open shiftstep III, ‘28’ interchanges its position with ‘kitten’ and ‘59’ also interchanges its position with ‘equal’, we get,

Step III: 87 18 kitten open equal 13 shift 19 46 count 59 hold

Then ‘19’ is to the immediate left of ‘46’.

a) Words are arranged in ascending dictionary order, from the right end one at a time in each step.

b) The largest number is reversed and one is added to it and then placed at the left end one at a time in each step, moving the previously placed number towards right.

So the given input can be analyzed as follows,

Applying the same rule on the given input we get,

Input: hold 71 open 59 equal 81 13 shift count 68 kitten 46

Step I: 19 hold 71 open 59 equal 13 shift 68 kitten 46 count

Step II: 18 19 hold open 59 13 shift 68 kitten 46 count equal

Step III: 87 18 19 open 59 13 shift kitten 46 count equal hold

Step IV: 96 87 18 19 open 13 shift 46 count equal hold kitten

Step V: 65 96 87 18 19 13 shift count equal hold kitten open

Step VI: 32 65 96 87 18 19 count equal hold kitten open shift

Clearly ‘13’ comes exactly between ‘59’ and ‘shift’ in step II of the given input.

a) Words are arranged in ascending dictionary order, from the right end one at a time in each step.

b) The largest number is reversed and one is added to it and then placed at the left end one at a time in each step, moving the previously placed number towards right.

So the given input can be analyzed as follows,

Applying the same rule on the given input we get,

Input: hold 71 open 59 equal 81 13 shift count 68 kitten 46

Step I: 19 hold 71 open 59 equal 13 shift 68 kitten 46 count

Step II: 18 19 hold open 59 13 shift 68 kitten 46 count equal

Step III: 87 18 19 open 59 13 shift kitten 46 count equal hold

Step IV: 96 87 18 19 open 13 shift 46 count equal hold kitten

Step V: 65 96 87 18 19 13 shift count equal hold kitten open

Step VI: 32 65 96 87 18 19 count equal hold kitten open shift

Step VI is the last step of the above arrangement as the intended arrangement is obtained.

Now if in the last step, ‘1’ is added to each of the odd numbers and ‘2’ is subtracted from each of the even numbers, we get,

Last Step: 30 66 94 88 16 20 count equal hold kitten open shift

Then multiple of ‘4’ are 88,20 and 16, thus answer is three.

a) Words are arranged in ascending dictionary order, from the right end one at a time in each step.

b) The largest number is reversed and one is added to it and then placed at the left end one at a time in each step, moving the previously placed number towards right.

So the given input can be analyzed as follows,

Applying the same rule on the given input we get,

Input: hold 71 open 59 equal 81 13 shift count 68 kitten 46

Step I: 19 hold 71 open 59 equal 13 shift 68 kitten 46 count

Step II: 18 19 hold open 59 13 shift 68 kitten 46 count equal

Step III: 87 18 19 open 59 13 shift kitten 46 count equal hold

Step IV: 96 87 18 19 open 13 shift 46 count equal hold kitten

Step V: 65 96 87 18 19 13 shift count equal hold kitten open

Step VI: 32 65 96 87 18 19 count equal hold kitten open shift

Eighth element from the right end in step IV is ‘open’ and third to its right is ‘46’.

a) Words are arranged in ascending dictionary order, from the right end one at a time in each step.

b) The largest number is reversed and one is added to it and then placed at the left end one at a time in each step, moving the previously placed number towards right.

So the given input can be analyzed as follows,

Applying the same rule on the given input we get,

Input: hold 71 open 59 equal 81 13 shift count 68 kitten 46

Step I: 19 hold 71 open 59 equal 13 shift 68 kitten 46 count

Step II: 18 19 hold open 59 13 shift 68 kitten 46 count equal

Step III: 87 18 19 open 59 13 shift kitten 46 count equal hold

Step IV: 96 87 18 19 open 13 shift 46 count equal hold kitten

Step V: 65 96 87 18 19 13 shift count equal hold kitten open

Step VI: 32 65 96 87 18 19 count equal hold kitten open shiftInput: hold 71 open 59 equal 81 13 shift count 68 kitten 46

Step I: 28 hold 71 open 59 equal 13 shift 68 kitten 46 count

Step II: 18 28 hold open 59 13 shift 68 kitten 46 count equal

Step III: 87 18 28 open 59 13 shift kitten 46 count equal hold

Step IV: 96 87 18 28 open 13 shift 46 count equal hold kitten

Step V: 65 96 87 18 28 13 shift count equal hold kitten open

Step VI: 32 65 96 87 18 28 count equal hold kitten open shift

Step VI is the last step of the above arrangement as the intended arrangement is obtained.

The third and the ninth element in the second last step of the given input from the left end are, ‘87’ and ‘equal’.

For number: The place value(as per the alphabetical series) of the opposite letter of the first letter of the word.

For symbol: If the number of letters in the word is odd then coded as ‘@’ and the number of letters in the word is even then coded as ‘%’.

For letter: if the number of letters in the word is even then take the next letter (as per the alphabetical series) of the last letter of the word, whereas if the number of letters in the word is odd then take the previous letter(as per the alphabetical series) of the last letter of the word.

Based on the above given information we have:

For number: The place value(as per the alphabetical series) of the opposite letter of the first letter of the word.

For symbol: If the number of letters in the word is odd then coded as ‘@’ and the number of letters in the word is even then coded as ‘%’.

For letter: if the number of letters in the word is even then take the next letter (as per the alphabetical series) of the last letter of the word, whereas if the number of letters in the word is odd then take the previous letter(as per the alphabetical series) of the last letter of the word.

Based on the above given information we have:

For number: The place value(as per the alphabetical series) of the opposite letter of the first letter of the word.

For symbol: If the number of letters in the word is odd then coded as ‘@’ and the number of letters in the word is even then coded as ‘%’.

For letter: if the number of letters in the word is even then take the next letter (as per the alphabetical series) of the last letter of the word, whereas if the number of letters in the word is odd then take the previous letter(as per the alphabetical series) of the last letter of the word.

Based on the above given information we have:

For number: The place value(as per the alphabetical series) of the opposite letter of the first letter of the word.

For symbol: If the number of letters in the word is odd then coded as ‘@’ and the number of letters in the word is even then coded as ‘%’.

For letter: if the number of letters in the word is even then take the next letter (as per the alphabetical series) of the last letter of the word, whereas if the number of letters in the word is odd then take the previous letter(as per the alphabetical series) of the last letter of the word.

Based on the above given information we have:

So, this entire code language is based on only 2 symbols % and #, i.e. 0 and 1.

Logic:

On observation, we notice that starting from the rightmost digit, each digit is multiplied with corresponding power of 2, starting with 2⁰, and then all these terms are added to obtain the number in the decimal system.

[The rightmost term is multiplied with 2⁰, the second term from right is multiplied with 2¹, the third term from right is multiplied with 2² and so on..]

Resultant of the given expression is: 39 × 5 + 114 × 2 - 125 = 298

Now, we need to convert 298 into the given code language.

298 = 256 + 32 + 8 + 2

∴ 298 ⇒ 100101010

Converting 0s and 1s to %s and #s respectively, we get

298 = #%%#%#%#%

So, the resultant of the expression "39 × 5 + 114 × 2 − 125" will be coded as ‘#%%#%#%#%'.

So, this entire code language is based on only 2 symbols % and #, i.e. 0 and 1.

Logic:

On observation, we notice that starting from the rightmost digit, each digit is multiplied with corresponding power of 2, starting with 2⁰, and then all these terms are added to obtain the number in the decimal system.

[The rightmost term is multiplied with 2⁰, the second term from right is multiplied with 2¹, the third term from right is multiplied with 2² and so on..]

Based on this logic,

‘###%#’ ↔ 11101

'##%%' ↔ 1100

'#%#' ↔ 101

The resultant of the expression is: 29 ÷ 2 × 12 + 6 × 5 = 204

Now, we need to convert 204 into the given code language.

204 = 128 + 64 + 8 + 4

Converting 0s and 1s to %s and #s respectively, we get

204 = ##%%##%%

So, the resultant of the expression "###%# ÷ #% × ##%% + ##% × #%#" is ##%%##%%.

So, this entire code language is based on only 2 symbols % and #, i.e. 0 and 1.

Logic:

On observation, we notice that starting from the rightmost digit, each digit is multiplied with corresponding power of 2, starting with 2⁰, and then all these terms are added to obtain the number in the decimal system.

[The rightmost term is multiplied with 2⁰, the second term from right is multiplied with 2¹, the third term from right is multiplied with 2² and so on..]

Based on this logic,

‘###%#’ ↔ 11101

Square of 27 is 729.

Now, we need to convert 729 into the given code language.

729 = 512 + 128 + 64 + 16 + 8 + 1

∴ 729 ⇒ 1011011001

Converting 0s and 1s to %s and #s respectively, we get

729 = #%##%##%%#

So, the square of "##%##" is "#%##%##%%#".

We have:

• P is the father-in-law of Q, who is the mother of V.
• S is the sister-in-law of V and vice-versa. V is not married person.

That means, S must be married to V’s brother.

Based on the above given information we have:

Again, we have:

• P’s wife sits fourth to the left of S, who sits third from the left end.
• Only one person sits between S and U but both are not facing in the same direction.

That means, in case (1) U sits second to the right of S, in case (2) U sits second to the left of S.

• P and U sit together.
• None of the married couples are sitting together.

That means, in case (1) P sits immediate right of U, in case (2) P sits immediate left of U.

Based on the above given information we have:

Again, we have:

• S’s husband sits third to the right of P.
• None of the male members sit at the extreme ends.

That means, in case (1) S’s husband sits second to the left of S, in case (2) S’s husband sits to the right of S.

But no male member sits at the end, thus case (2) is not valid.

• U is the only daughter of T.
• T sits third to the right of W and both are facing in the same direction.
• W is the father of R, who is a married member of the family.

That means, in case (1) W sits immediate left of S

Based on the above given information we have:

Case (2) is not valid as no male member sits at the end.

Again, we have:

• R sits immediate right of W’s daughter.

Since, either both or none of the parents are alive.

Since, Q is the daughter-in-law of P, and thus, only possible daughter of W is V.

• The persons sitting adjacent to T are facing in the opposite direction to each other.
• Q and R are not facing in the same direction.

Based on the above given information we have:

We have:

• P is the father-in-law of Q, who is the mother of V.
• S is the sister-in-law of V and vice-versa. V is not married person.

That means, S must be married to V’s brother.

Based on the above given information we have:

Again, we have:

• P’s wife sits fourth to the left of S, who sits third from the left end.
• Only one person sits between S and U but both are not facing in the same direction.

That means, in case (1) U sits second to the right of S, in case (2) U sits second to the left of S.

• P and U sit together.
• None of the married couples are sitting together.

That means, in case (1) P sits immediate right of U, in case (2) P sits immediate left of U.

Based on the above given information we have:

Again, we have:

• S’s husband sits third to the right of P.
• None of the male members sit at the extreme ends.

That means, in case (1) S’s husband sits second to the left of S, in case (2) S’s husband sits to the right of S.

But no male member sits at the end, thus case (2) is not valid.

• U is the only daughter of T.
• T sits third to the right of W and both are facing in the same direction.
• W is the father of R, who is a married member of the family.

That means, in case (1) W sits immediate left of S

Based on the above given information we have:

Case (2) is not valid as no male member sits at the end.

Again, we have:

• R sits immediate right of W’s daughter.

Since, either both or none of the parents are alive.

Since, Q is the daughter-in-law of P, and thus, only possible daughter of W is V.

• The persons sitting adjacent to T are facing in the opposite direction to each other.
• Q and R are not facing in the same direction.

Based on the above given information we have:

We have:

• P is the father-in-law of Q, who is the mother of V.
• S is the sister-in-law of V and vice-versa. V is not married person.

That means, S must be married to V’s brother.

Based on the above given information we have:

Again, we have:

• P’s wife sits fourth to the left of S, who sits third from the left end.
• Only one person sits between S and U but both are not facing in the same direction.

That means, in case (1) U sits second to the right of S, in case (2) U sits second to the left of S.

• P and U sit together.
• None of the married couples are sitting together.

That means, in case (1) P sits immediate right of U, in case (2) P sits immediate left of U.

Based on the above given information we have:

Again, we have:

• S’s husband sits third to the right of P.
• None of the male members sit at the extreme ends.

That means, in case (1) S’s husband sits second to the left of S, in case (2) S’s husband sits to the right of S.

But no male member sits at the end, thus case (2) is not valid.

• U is the only daughter of T.
• T sits third to the right of W and both are facing in the same direction.
• W is the father of R, who is a married member of the family.

That means, in case (1) W sits immediate left of S

Based on the above given information we have:

Case (2) is not valid as no male member sits at the end.

Again, we have:

• R sits immediate right of W’s daughter.

Since, either both or none of the parents are alive.

Since, Q is the daughter-in-law of P, and thus, only possible daughter of W is V.

• The persons sitting adjacent to T are facing in the opposite direction to each other.
• Q and R are not facing in the same direction.

Based on the above given information we have:

We have:

• P is the father-in-law of Q, who is the mother of V.
• S is the sister-in-law of V and vice-versa. V is not married person.

That means, S must be married to V’s brother.

Based on the above given information we have:

Again, we have:

• P’s wife sits fourth to the left of S, who sits third from the left end.
• Only one person sits between S and U but both are not facing in the same direction.

That means, in case (1) U sits second to the right of S, in case (2) U sits second to the left of S.

• P and U sit together.
• None of the married couples are sitting together.

That means, in case (1) P sits immediate right of U, in case (2) P sits immediate left of U.

Based on the above given information we have:

Again, we have:

• S’s husband sits third to the right of P.
• None of the male members sit at the extreme ends.

That means, in case (1) S’s husband sits second to the left of S, in case (2) S’s husband sits to the right of S.

But no male member sits at the end, thus case (2) is not valid.

• U is the only daughter of T.
• T sits third to the right of W and both are facing in the same direction.
• W is the father of R, who is a married member of the family.

That means, in case (1) W sits immediate left of S

Based on the above given information we have:

Case (2) is not valid as no male member sits at the end.

Again, we have:

• R sits immediate right of W’s daughter.

Since, either both or none of the parents are alive.

Since, Q is the daughter-in-law of P, and thus, only possible daughter of W is V.

• The persons sitting adjacent to T are facing in the opposite direction to each other.
• Q and R are not facing in the same direction.

Based on the above given information we have:

1) Hari starts the seminar at 1 pm.

2) The one who ends the seminar at 11 pm was Priya.

3) Priya conducts seminars on taxation.

4) Mona is third one to conduct seminar.

5) Suman conducts seminar immediate before Mona.

6)The one who takes seminar on chemistry has at 3 pm.

7) Only one seminar take place between Chemistry and Economics.

8) Priya conducts seminar immediate after Amit who conducts seminar in economics.

9) Amit does not conduct seminar after 6 pm.

10) Only 3 persons have seminar between Arts and Economics. (There are 2 possibilities in

here as shown)

11) There are 4 seminars between physics and biology.(There are 2 possibilities in case 1 here as shown)

12)The seminar on Biology and economics was conducted after 4 pm.

13) There are 4 seminars conducted between 2 mathematics seminars.

14) Mathematics is conducted after 3 pm. (This eliminates case 1b and case 2)

15) The seminar on history is conducted by Riya.

16) There are three seminar between Dhruva and Riya.

All the options match the name of the persons and the seminar conducted by them except in option (E).

So, Mona - History does not belong to the group.

1) Hari starts the seminar at 1 pm.

2) The one who ends the seminar at 11 pm was Priya.

3) Priya conducts seminars on taxation.

4) Mona is third one to conduct seminar.

5) Suman conducts seminar immediate before Mona.

6)The one who takes seminar on chemistry has at 3 pm.

7) Only one seminar take place between Chemistry and Economics.

8) Priya conducts seminar immediate after Amit who conducts seminar in economics.

9) Amit does not conduct seminar after 6 pm.

10) Only 3 persons have seminar between Arts and Economics. (There are 2 possibilities in

here as shown)

11) There are 4 seminars between physics and biology.(There are 2 possibilities in case 1 here as shown)

12)The seminar on Biology and economics was conducted after 4 pm.

13) There are 4 seminars conducted between 2 mathematics seminars.

14) Mathematics is conducted after 3 pm. (This eliminates case 1b and case 2)

15) The seminar on history is conducted by Riya.

16) There are three seminar between Dhruva and Riya.

Jay conducts seminar at 7 pm.

1) Hari starts the seminar at 1 pm.

2) The one who ends the seminar at 11 pm was Priya.

3) Priya conducts seminars on taxation.

4) Mona is third one to conduct seminar.

5) Suman conducts seminar immediate before Mona.

6)The one who takes seminar on chemistry has at 3 pm.

7) Only one seminar take place between Chemistry and Economics.

8) Priya conducts seminar immediate after Amit who conducts seminar in economics.

9) Amit does not conduct seminar after 6 pm.

10) Only 3 persons have seminar between Arts and Economics. (There are 2 possibilities in

here as shown)

11) There are 4 seminars between physics and biology.(There are 2 possibilities in case 1 here as shown)

12)The seminar on Biology and economics was conducted after 4 pm.

13) There are 4 seminars conducted between 2 mathematics seminars.

14) Mathematics is conducted after 3 pm. (This eliminates case 1b and case 2)

15) The seminar on history is conducted by Riya.

16) There are three seminar between Dhruva and Riya.

So, Priya conducts seminar just before the one who conducts seminar on Biology.

1) Hari starts the seminar at 1 pm.

2) The one who ends the seminar at 11 pm was Priya.

3) Priya conducts seminars on taxation.

4) Mona is third one to conduct seminar.

5) Suman conducts seminar immediate before Mona.

6)The one who takes seminar on chemistry has at 3 pm.

7) Only one seminar take place between Chemistry and Economics.

8) Priya conducts seminar immediate after Amit who conducts seminar in economics.

9) Amit does not conduct seminar after 6 pm.

10) Only 3 persons have seminar between Arts and Economics. (There are 2 possibilities in

here as shown)

11) There are 4 seminars between physics and biology.(There are 2 possibilities in case 1 here as shown)

12)The seminar on Biology and economics was conducted after 4 pm.

13) There are 4 seminars conducted between 2 mathematics seminars.

14) Mathematics is conducted after 3 pm. (This eliminates case 1b and case 2)

15) The seminar on history is conducted by Riya.

16) There are three seminar between Dhruva and Riya.

So, Hari conducts seminar on Arts.

1) Hari starts the seminar at 1 pm.

2) The one who ends the seminar at 11 pm was Priya.

3) Priya conducts seminars on taxation.

4) Mona is third one to conduct seminar.

5) Suman conducts seminar immediate before Mona.

6)The one who takes seminar on chemistry has at 3 pm.

7) Only one seminar take place between Chemistry and Economics.

8) Priya conducts seminar immediate after Amit who conducts seminar in economics.

9) Amit does not conduct seminar after 6 pm.

10) Only 3 persons have seminar between Arts and Economics. (There are 2 possibilities in

here as shown)

11) There are 4 seminars between physics and biology.(There are 2 possibilities in case 1 here as shown)

12)The seminar on Biology and economics was conducted after 4 pm.

13) There are 4 seminars conducted between 2 mathematics seminars.

14) Mathematics is conducted after 3 pm. (This eliminates case 1b and case 2)

15) The seminar on history is conducted by Riya.

16) There are three seminar between Dhruva and Riya.

So, Amit conducts seminar at 5pm is true statement.