Chemistry Exam  >  Chemistry Tests  >  Inorganic Chemistry  >  Test: Hybridisation & Shapes of Molecules - Chemistry MCQ

Test: Hybridisation & Shapes of Molecules - Chemistry MCQ


Test Description

10 Questions MCQ Test Inorganic Chemistry - Test: Hybridisation & Shapes of Molecules

Test: Hybridisation & Shapes of Molecules for Chemistry 2024 is part of Inorganic Chemistry preparation. The Test: Hybridisation & Shapes of Molecules questions and answers have been prepared according to the Chemistry exam syllabus.The Test: Hybridisation & Shapes of Molecules MCQs are made for Chemistry 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Hybridisation & Shapes of Molecules below.
Solutions of Test: Hybridisation & Shapes of Molecules questions in English are available as part of our Inorganic Chemistry for Chemistry & Test: Hybridisation & Shapes of Molecules solutions in Hindi for Inorganic Chemistry course. Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free. Attempt Test: Hybridisation & Shapes of Molecules | 10 questions in 12 minutes | Mock test for Chemistry preparation | Free important questions MCQ to study Inorganic Chemistry for Chemistry Exam | Download free PDF with solutions
Test: Hybridisation & Shapes of Molecules - Question 1

Which of the following statement is true regarding hybrid orbitals?

Detailed Solution for Test: Hybridisation & Shapes of Molecules - Question 1

The true statements of the incorrect ones are the number of orbitals formed after the hybridization is equal to the number of orbitals before hybridization, the hybrid orbitals have equal energy and the hybridization indicates geometry.

Test: Hybridisation & Shapes of Molecules - Question 2

What is the geometry of PCl5 molecule?

Detailed Solution for Test: Hybridisation & Shapes of Molecules - Question 2

As the PCl5 molecule undergoes sp3d hybridization, it posses the geometry the trigonal bipyramidal. In the shape, the central atom is Phosphorous and the atoms at the five corners are Chlorine.

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Hybridisation & Shapes of Molecules - Question 3

What do you think is the number of sigma bonds in an ethene molecule?

Detailed Solution for Test: Hybridisation & Shapes of Molecules - Question 3

The formula of ethene molecule is C2H4. There is one sigma bond between two carbon atoms and 2 sigma bonds between each of the carbon and the hydrogens. So in total, it’s five (one pi-bond is present between the 2 carbon atoms).

Test: Hybridisation & Shapes of Molecules - Question 4

What type of hybridization does a BCl3 molecule undergo?

Detailed Solution for Test: Hybridisation & Shapes of Molecules - Question 4

In the BCl3 molecule, one s-orbital and two p-orbitals intermix and form three equivalent hybrid orbits. Therefore it undergoes sp2 hybridization and forms trigonal planar shape, like B in the center and Cl in the 3 corners.

Test: Hybridisation & Shapes of Molecules - Question 5

The phenomenon of forming completely new atomic orbitals by intermixing them is known as ___________

Detailed Solution for Test: Hybridisation & Shapes of Molecules - Question 5

The exact meaning of hybridization is the intermixing of different orbitals in order to form a new set of equivalent orbitals otherwise known as hybridized orbitals. These hybrid orbitals are used in bond formation.

Test: Hybridisation & Shapes of Molecules - Question 6

Mention the types of orbitals that undergo hybridization in order to get octahedral geometry?

Detailed Solution for Test: Hybridisation & Shapes of Molecules - Question 6

Octahedral geometry is possible when the atomic orbitals under undergoing sp3d2 or d2sp3 hydration only. So it involves one s-orbital, three p-orbitals, and two d-orbitals. An example of this is SF6.

Test: Hybridisation & Shapes of Molecules - Question 7

What is the bond angle of H-C-H in methane molecule?

Detailed Solution for Test: Hybridisation & Shapes of Molecules - Question 7

The molecule of methane i.e. CH4 had undergone sp3 hybridization (1 s-orbital and 3 p-orbitals combine to give 4 sp3 orbitals). It exhibits tetrahedral geometry. In tetrahedral geometry, the angle between the bonds of corner atoms and the central atom is 109.5°.

Test: Hybridisation & Shapes of Molecules - Question 8

The orbitals that are resulted from sp hybridization have _______% s-character and ________% p-character.

Detailed Solution for Test: Hybridisation & Shapes of Molecules - Question 8

When one s-orbital and p-orbital undergo hybridization, 2 sp orbitals are formed. One sp-orbital has 50% s-character and 50% p-character. They possess linear geometry and it’s also called diagonal hybridization.

Test: Hybridisation & Shapes of Molecules - Question 9

Who introduced the concept of hybridization?

Detailed Solution for Test: Hybridisation & Shapes of Molecules - Question 9

In order to explain the bonding and shapes of every polyatomic atomic molecule like methane, carbon tetrachloride, water, boron trifluoride, etc, Pauling put-forth the concept of hybridization.

Test: Hybridisation & Shapes of Molecules - Question 10

The orbitals formed after hybridization have equal energy.

Detailed Solution for Test: Hybridisation & Shapes of Molecules - Question 10

The hybridization is the intermixing of different orbitals in order to form a new set of equivalent orbitals otherwise known as hybrid orbitals. All the hybrid orbitals those have undergone the same hybridization have the same amount of energy.

48 videos|92 docs|41 tests
Information about Test: Hybridisation & Shapes of Molecules Page
In this test you can find the Exam questions for Test: Hybridisation & Shapes of Molecules solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Hybridisation & Shapes of Molecules, EduRev gives you an ample number of Online tests for practice
48 videos|92 docs|41 tests
Download as PDF