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Quantitative Aptitude - Test 11


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25 Questions MCQ Test SSC CGL Tier 1 Mock Test Series | Quantitative Aptitude - Test 11

Quantitative Aptitude - Test 11 for SSC CGL 2022 is part of SSC CGL Tier 1 Mock Test Series preparation. The Quantitative Aptitude - Test 11 questions and answers have been prepared according to the SSC CGL exam syllabus.The Quantitative Aptitude - Test 11 MCQs are made for SSC CGL 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Quantitative Aptitude - Test 11 below.
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Quantitative Aptitude - Test 11 - Question 1

An employer reduces the number of employees in the ratio 8 : 5 and increases their wages in the ratio 7 : 9. As a result, the overall wages bill is

Detailed Solution for Quantitative Aptitude - Test 11 - Question 1

Let's say employees were change from 8x to 5x and wage per employee is changed from 7y to 9y
Hence total wage is changed from 56xy to 45xy or in a ratio of 56 : 45

Quantitative Aptitude - Test 11 - Question 2

The ratio of ages of father and son is 7 : 2. Five years ago the product of their ages was 150. What is the age of the father?

Detailed Solution for Quantitative Aptitude - Test 11 - Question 2

Let father's age = 7x years and son's age = 2x years

According to ques, => (7x − 5)(2x − 5) = 150

=> 14x2 − 35x − 10x + 25 − 150 = 0

=> 14x2 − 45x − 125 = 0

=> 14x2 − 70x + 25x − 125 = 0

=> 14x(x − 5) + 25(x − 5) = 0

=> (x − 5)(14x + 25) = 0

Since, age can't be negative, thus x = 5

∴ Father's age = 7 × 5 = 35 years

=> Ans - (C)

Quantitative Aptitude - Test 11 - Question 3

The sum of the ages of husband and wife at present is 56. Ten years ago the product of their ages was 320. What is the age of the husband and the wife?

Detailed Solution for Quantitative Aptitude - Test 11 - Question 3

Let husband's age = xx years

=> Wife's age = (56 − x) years

According to ques, (x − 10)(56 − x − 10) = 320

=> (x − 10)(46 − x) = 320

=> 46x − x2 − 460 + 10x = 320

=> x2 − 56x + 780 = 0

=> x2 − 30x − 26x + 780 = 0

=> x(x − 30) − 26(x − 30) = 0

=> (x − 30)(x − 26) = 0

=> x = 30, 26

∴ Ages of the husband and the wife = 30 and 26 years.

Quantitative Aptitude - Test 11 - Question 4

Ronald and Elan are working on an Assignment. Ronald takes 6 hours to type 32 pages on a computer, while Elan takes 5 hours to type 40 pages. How much time will they take working together on two different computers to type an assignment of 110 pages?

Detailed Solution for Quantitative Aptitude - Test 11 - Question 4

Ronald takes 6 hours to type 32 pages

no.of pages typed by ronald per hour = 32/6 = 16/3

 Elan takes 5 hours to type 40 pages

no.of pages typed by elan per hour = 40/5 = 8

in 1hr, both can type 8 + 16/3 pages = 40/3

time taken by both to type 110 pages = 110/(40/3) = 33/4 = 8hrs 15mins    (∵ 1/4 hr = 15mins)

so the answer is option C.

Quantitative Aptitude - Test 11 - Question 5

The ratio of present ages of Ramya and Saurabh is 8 : 7. After 10 years the ratio of their ages will be 12 : 11. What is Ramya's present age?

Detailed Solution for Quantitative Aptitude - Test 11 - Question 5

Let Ramya's present age = 8x years and Saurabh's present age = 7x years

According to ques,

=> 88x + 110 = 84x + 120

=> 88x - 84x = 120 - 110 = 10

=> x = 10/4 ​= 2.5

∴ Ramya's age = 8 × 2.5 = 20 years

=> Ans - (A)

Quantitative Aptitude - Test 11 - Question 6

If a + 1/a + 2 = 0, then the value of

Detailed Solution for Quantitative Aptitude - Test 11 - Question 6

It is given that 
it is possible only when a = -1
hence a + 2 = 1
and so

Quantitative Aptitude - Test 11 - Question 7

If 5x + 9y = 5 and 125x3 + 729y3 = 120 then the value of the product of x and y is

Detailed Solution for Quantitative Aptitude - Test 11 - Question 7

Expression: 5x + 9y = 5

Cubing both sides, we get:

=> (5x + 9y)3 = 125

=> 125x3 + 729y3 + 135xy(5x + 9y) = 125

=> 125x3 + 729y3 + 135xy ∗ 5 = 125

Since, 125x3 + 729y3 = 120

Quantitative Aptitude - Test 11 - Question 8

The value of

Detailed Solution for Quantitative Aptitude - Test 11 - Question 8


 

on squaring both sides

x2 − x − 6 = 0

x = 3 , x = -2

here -2 will be rejected as square root can not give negative value and hence x = 3

Quantitative Aptitude - Test 11 - Question 9

If x = 2 + √3 , then the value,

Detailed Solution for Quantitative Aptitude - Test 11 - Question 9

x = 2 + √3​

1/x ​= 2 − √3​

so the answer is option B.

Quantitative Aptitude - Test 11 - Question 10

If m - 5n = 2, then the value of (m3 − 125n3 - 30 mn) is

Detailed Solution for Quantitative Aptitude - Test 11 - Question 10

Using the formula, (x − y)3 = x3 − y3 − 3xy(x − y)

=> (m − 5n)3 = m3 − 125n3 − 15mn(m − 5n)

=> 23 = m3 − 125n3 − 15mn ∗ 2

=> m3 − 125n3 − 30mn = 8

Quantitative Aptitude - Test 11 - Question 11

Which of the following statement (s) is / are TRUE?

Detailed Solution for Quantitative Aptitude - Test 11 - Question 11


L.H.S. = 26 + 2.6 + 0.26 = 28.86 ≠ R.H.S.

Thus, only II is correct.

=> Ans - (B)

Quantitative Aptitude - Test 11 - Question 12

The 4th term of an arithmetic progression is 15, 15th term is -29, find the 10th term?

Detailed Solution for Quantitative Aptitude - Test 11 - Question 12

The nth term of an A.P. = a + (n - 1)d, where 'a' is the first term, 'n' is the number of terms and 'd' is the common difference.

4th term, A4 = a + (4 - 1)d = 15

=> a + 3d = 15 -----------------(i)

Similarly, 15th term, A15 = a + 14d = -29 ------------------(ii)

Subtracting equation (i) from (ii), we get :

=> (14d - 3d) = -29 - 15

=> d = -44/11 ​= −4

Substituting it in equation (i), => a - 12 = 15

=> a = 15 + 12 = 27

∴ 10th term, A10 = a + (10 - 1)d

= 27 + (9× − 4) = 27 − 36 = −9

=> Ans - (D)

Quantitative Aptitude - Test 11 - Question 13

If 4x = 7√1024​, then what is the value of X?

Detailed Solution for Quantitative Aptitude - Test 11 - Question 13

 

Expression: 4x = 7√1024

=> Ans - (A)

Quantitative Aptitude - Test 11 - Question 14

What is the simplified value of

Detailed Solution for Quantitative Aptitude - Test 11 - Question 14

Expression:

=> Ans - (B)

Quantitative Aptitude - Test 11 - Question 15

What is the value of

Detailed Solution for Quantitative Aptitude - Test 11 - Question 15

Expression: 

= 8 + 13 + 6 + 15 = 42

=> Ans - (C)

Quantitative Aptitude - Test 11 - Question 16

If the cost price of 15 articles is equal to the selling price of 12 articles, find gain %

Detailed Solution for Quantitative Aptitude - Test 11 - Question 16

Let's say cost price of 15 articles is xx
cost price of 12 articles will be = 12x​/15
selling price of 15 articles is = x
gain = 3x​/15

Quantitative Aptitude - Test 11 - Question 17

A man bought an article listed at Rs. 1500 with a discount of 20% offered on the list price. What additional discount must be offered to man to bring the net price to Rs. 1,104?

Detailed Solution for Quantitative Aptitude - Test 11 - Question 17

After having 20% discount price will be =
So for net price of 1104 discount should be 1200 - 1104 = 96

Quantitative Aptitude - Test 11 - Question 18

A is 50% as efficient as B. C does half of the work done by A and B together. If C alone does the work in 20 days, then A, B and C together can do the work in

Detailed Solution for Quantitative Aptitude - Test 11 - Question 18

C does 1/20​ amount of work in a day.
And A + B do twice of work as much done by C or A + B = 2C or 2/20​.
So A + B + C together will do amount of work in a day.
And complete work will be done in 20/3​ days.

Quantitative Aptitude - Test 11 - Question 19

A man sold 20 apples for Rs. 1000 and gained 20%. How many apples did he buy for Rs. 1000?

Detailed Solution for Quantitative Aptitude - Test 11 - Question 19

Selling price of 20 apples = 1000
gain = 20% 
Cost price of 20 will be = 
So on cost price of 1000 amount of apples will be 

Quantitative Aptitude - Test 11 - Question 20

A grain dealer cheats to the extent of 10% while buying as well as selling by using false weights. His total profit percentage is:

Detailed Solution for Quantitative Aptitude - Test 11 - Question 20

Let the retailer buys 110 gram in Rs 100 because of 10 % cheating 

so cost price = 1 gram = Rs 100/110 = Rs 0.909

and retailer sells 90 gram in Rs 100 

and hence selling price = Rs 100/90 = Rs 1.111

Quantitative Aptitude - Test 11 - Question 21

What is the equation of the line whose y­intercept is ­3/4 and making an angle of 45° with the positive x-­axis?

Detailed Solution for Quantitative Aptitude - Test 11 - Question 21

Slope of line making an angle of 45° with the positive x­-axis = tan(45°)

=> Slope, m = 1

y-intercept, c = 3/43​

Equation of line having slope mm and y intercept cc is: y = mx + c

=> y = x + 43​

=> 4y = 4x + 3

=> 4x − 4y = −3

=> Ans - (B)

Quantitative Aptitude - Test 11 - Question 22

In what ratio is the segment joining (-1, -12) and (3, 4) divided by the x-axis?

Detailed Solution for Quantitative Aptitude - Test 11 - Question 22

Using section formula, the coordinates of point that divides line joining A = (x1​, y1​) and B = (x2​, y2​) in the ratio a : b

Let the ratio in which the segment joining (-1,-12) and (3,4) divided by the x-axis = k : 1

Since, the line segment is divided by x-axis, thus y-coordinate of the point will be zero, let the point of intersection = (x, 0)

Now, point P (x, 0) divides (-1, -12) and (3, 4) in ratio = k : 1

=> 4k - 12 = 0

=> k = 12​/4 = 3

∴ Required ratio = 3 : 1

=> Ans - (C)

Quantitative Aptitude - Test 11 - Question 23

Find equation of the perpendicular bisector of segment joining the points (2, -5) and (0, 7)?

Detailed Solution for Quantitative Aptitude - Test 11 - Question 23

Let line l perpendicularly bisects line joining  A(2, -5) and B(0, 7) at C, thus C is the mid point of AB.

=> Coordinates of C = 

Now, slope of AB 

Let slope of line l = m

Product of slopes of two perpendicular lines = -1

=> m × −6 = −1

=> m = 1/61

Equation of a line passing through point (x1​, y1​) and having slope mm is (y − y1​) = m(x − x1​)

∴ Equation of line l

=> (y - 1) = 1/6​(x − 1)

=> 6y - 6 = x - 1

=> x - 6y = 1 - 6 = -5

=> Ans - (C)

Quantitative Aptitude - Test 11 - Question 24

Find k, if the line 2x - ­3y = 11 is perpendicular to the line 3x + ky = ­4?

Detailed Solution for Quantitative Aptitude - Test 11 - Question 24

Slope of line 2x - ­3y = 11 is
= 2/3
Slope of line 3x + ky = ­4 is −3​/k

Also, product of slopes of two perpendicular lines is -1

=> k = −2 × −1 = 2

=> Ans - (D)

Quantitative Aptitude - Test 11 - Question 25

The point P(-4, 1) divides the segment joining the points (x, 0) and (0, y) in the ratio 3 : 2. Find x and y?

Detailed Solution for Quantitative Aptitude - Test 11 - Question 25

Using section formula, the coordinates of point that divides line joining A = (x1​, y1​) and B = (x2​, y2​) in the ratio a : b

Now, point P (-4, 1) divides (x, 0) and (0, y) in ratio = 3 : 2

=> 3y = 5 => y = 5/3

=> Ans - (A)

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