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This mock test of RS Aggarwal Test: Introduction To Trigonometry for Class 10 helps you for every Class 10 entrance exam.
This contains 15 Multiple Choice Questions for Class 10 RS Aggarwal Test: Introduction To Trigonometry (mcq) to study with solutions a complete question bank.
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QUESTION: 1

The value of

Solution:

QUESTION: 2

If ΔABC is right angled at C, then the value of cos (A + B) is

Solution:

Δ ABC is right angled at C, A + B + C = 180°

∴ A + B = 180° - 90° = 90° (∵ ∠C = 90°)

cos (A + B) = cos 90° = 0

QUESTION: 3

If cos A + cos^{2} A = 1, then sin^{2} A + sin^{4} A is

Solution:

QUESTION: 4

If cos (α + β) = 0, then sin (α - β) can be reduced to

Solution:

cos (a + β) = 0 = cos 90°

⇒ α + β = 90°

sin (α - β) = sin (α - β + β - β)

= sin (α + β - 2β)

= sin (90° - 2β) = cos 2β

QUESTION: 5

The value of

Solution:

QUESTION: 6

(1 + tanθ + secθ) (1 + cotθ - cosecθ) is equal to

Solution:

QUESTION: 7

If cos 9α = sin α and 9α < 90°, then the value of tan 5α is

Solution:

QUESTION: 8

sin (45° + θ) - cos (45° - θ) is equal to

Solution:

sin (45° + θ) - cos (45° - θ)

= sin {90° - (45° - θ)} - cos (45° - θ)

= cos (45° - θ) - cos (45° - θ) = 0

QUESTION: 9

If sin A = 1/2, then the value of cot A is

Solution:

QUESTION: 10

tan A =

Solution:

QUESTION: 11

Given that sin θ = a/b, then cos θ is equal to

Solution:

QUESTION: 12

If cosec A - cot A = 4/5, then cosec A =

Solution:

cosec A - cot A = 4/5 ........(i)

Also cosec^{2} A - cot^{2} A = 1

⇒ (cosec A - cot A) (cosec A - cot A) = 1

⇒ cosec A + cot A = 4/5 ......(ii)

From (i) and (ii), cosec A = 41/40

QUESTION: 13

The value of (tanl° tan2° tan3°... tan89°) is

Solution:

QUESTION: 14

If sin x + cosec x = 2, then sin^{19}x + cosec^{20} x =

Solution:

sin x + cosec x = 2

QUESTION: 15

The value of the expression is

Solution:

We know that sin 60 =√3/2 and cos 30 = √3/2.

Therefore , Sin 60/cos 30= (√3/2)/(√3/2) = 1

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