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# RS Aggarwal Test: Introduction To Trigonometry

## 15 Questions MCQ Test Mathematics (Maths) Class 10 | RS Aggarwal Test: Introduction To Trigonometry

Description
This mock test of RS Aggarwal Test: Introduction To Trigonometry for Class 10 helps you for every Class 10 entrance exam. This contains 15 Multiple Choice Questions for Class 10 RS Aggarwal Test: Introduction To Trigonometry (mcq) to study with solutions a complete question bank. The solved questions answers in this RS Aggarwal Test: Introduction To Trigonometry quiz give you a good mix of easy questions and tough questions. Class 10 students definitely take this RS Aggarwal Test: Introduction To Trigonometry exercise for a better result in the exam. You can find other RS Aggarwal Test: Introduction To Trigonometry extra questions, long questions & short questions for Class 10 on EduRev as well by searching above.
QUESTION: 1

Solution:
QUESTION: 2

### If ΔABC is right angled at C, then the value of cos (A + B) is

Solution:

Δ ABC is right angled at C, A + B + C = 180°
∴ A + B = 180° - 90° = 90° (∵ ∠C = 90°)
cos (A + B) = cos 90° = 0

QUESTION: 3

### If cos A + cos2 A = 1, then sin2 A + sin4 A is

Solution:

QUESTION: 4

If cos (α + β) = 0, then sin (α - β) can be reduced to

Solution:

cos (a + β) = 0 = cos 90°
⇒ α + β = 90°
sin (α - β) = sin (α - β + β - β)
= sin (α + β - 2β)
= sin (90° - 2β) = cos 2β

QUESTION: 5

The value of

Solution:
QUESTION: 6

(1 + tanθ + secθ) (1 + cotθ - cosecθ) is equal to

Solution:
QUESTION: 7

If cos 9α = sin α and 9α < 90°, then the value of tan 5α is

Solution:

QUESTION: 8

sin (45° + θ) - cos (45° - θ) is equal to

Solution:

sin (45° + θ) - cos (45° - θ)
= sin {90° - (45° - θ)} - cos (45° - θ)
= cos (45° - θ) - cos (45° - θ) = 0

QUESTION: 9

If sin A = 1/2,  then the value of cot A is

Solution:
QUESTION: 10

tan A =

Solution:

QUESTION: 11

Given that sin θ = a/b, then cos θ is equal to

Solution:
QUESTION: 12

If cosec A - cot A = 4/5, then cosec A =

Solution:

cosec A - cot A = 4/5  ........(i)
Also cosec2 A - cot2 A = 1
⇒ (cosec A - cot A) (cosec A - cot A) = 1

⇒ cosec A + cot A = 4/5   ......(ii)
From (i) and (ii), cosec A = 41/40

QUESTION: 13

The value of (tanl° tan2° tan3°... tan89°) is

Solution:
QUESTION: 14

If sin x + cosec x = 2, then sin19x + cosec20 x =

Solution:

sin x + cosec x = 2

QUESTION: 15

The value of the expression  is

Solution:

We know that sin 60 =√3/2 and cos 30 = √3/2.
Therefore , Sin 60/cos 30= (√3/2)/(√3/2) = 1