In similar triangles ABC and DEF, AG and DH are the medians. What is the value of AG/DH given that
If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides. So Also
ΔABGand ΔDEFare also similar triangles , since , so by SAS criterion they are similar.And we know ratios of sides is ⅝ , so AG/DH=5/8
ΔABC ~ ΔPQR . If ar (ΔABC) = 2.25 m2, ar (ΔPQR) = 6.25 m2, PQ = 0.5 m, then length of AB is:
Triangle ABC is similar to triangle DEF and their areas are 64 cm2 and 121 cm2 respectively. If EF = 15.4 cm, then BC = ?
By Similar Triangle Theorem we get,
By taking square roots of both sides,
In ΔDEF and ΔPQR, ∠D = 30°, ∠P = 30°, ∠E = 50°, ∠Q = 50° DE = 7 cm, PQ = 13cm = ?
The ratio of the areas of two similar triangles is equal to the:
Triangle ABC is similar to triangle DEF and their areas are respectively 64 cm2and 121 cm2. If EF = 15.4 cm, then BC =
Two similar triangles ABC and DEF are such that, AB = 5cm, DE = 12cm, then
Two similar triangles ABC and EDF are such that
Which of the following is true?
Sides of two similar triangles are in the ratio 4: 9. What is the ratio of the area of these triangles?
Two similar triangles ABC and DEF are such that . What is the ratio of their corresponding sides?