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QUESTION: 1

The mean of five numbers is 28. If one of the numbers is excluded, the mean gets reduced by 2. The excluded number is

Solution:

Mean of 5 nos.= 28

Therefore, sum of the 5 nos. = 28 * 5 = 140

The the no. exclude by 'x'.

New sum of 4 nos.= 140 - x

New mean = 28- 2 = 26

Therefore, (140 - x ) / 4 = 26

=> 140 - x = 104

=> x = 36

QUESTION: 2

If the mean of the following data is 18.75, then the value of p is

Solution:

QUESTION: 3

The mean of the following data is: 45, 35, 20, 15, 25, 40

Solution:

QUESTION: 4

The mean of 5 observations x, x + 2, x + 4, x + 6 and x + 8 is 11, then the value of x is:

Solution:

(x + x + 2 + x + 4 + x + 6 + x + 8) / 5 = 11

5x + 20 = 55

5x = 35 ⇒ x = 7

QUESTION: 5

The mean of a data set with 12 observations is calculated as 19.25. If one more value is included in the data, then for the new data with 13 observations, mean becomes 20. Value of this 13th observation is

Solution:

Suppose be all twelevth terms = x

Mean = Terms / Observation

19 . 25 = x / 12

x = 19.25 × 12

x = 231 .00

Now let thirteenth term will be y

Mean = 20

So, 20 = x + y / 13

20 = 231 + y / 13

20 × 13 = 231 + x

260 = 231 + x

260 - 231 = x

29 = x

QUESTION: 6

The mean of first ten even natural numbers is

Solution:

QUESTION: 7

A batsman in his 12^{th} innings makes a score of 63 runs and thereby increases his average score by 2. His average score after 12^{th} innings is

Solution:

QUESTION: 8

Which measure of central tendency takes in account all the data?

Solution:

QUESTION: 9

The mean () of a frequency distribution is 45. If the value of = 20 then the value of is:

Solution:

QUESTION: 10

The mean of a data set with 12 observations is calculated as 19.25. If one more value is included in the data, then for the new data with 13 observations, mean becomes 20. The value of this 13^{th} observation is

Solution:

QUESTION: 11

In the following distribution, if the mean of the distribution is 86 then the value of p is

Solution:

QUESTION: 12

The mean of 1, 2, 3, 4 …n is given by

Solution:

⇒ We have the sequence, 1,2,3.......n

⇒ This is an AP, with the initial term a=1 and the common difference d=1.

∴ The sum of n terms of an AP is given by,

→ Arithmetic mean of n numbers a1,a2,a3,a4,...an is given by the formula

QUESTION: 13

The arithmetic mean of the following data is

Solution:

QUESTION: 14

The mean of the marks obtained by 7 students in a group is 226. If the marks obtained by six of them are 340, 180, 260, 56, 275, 307, then the marks obtained by the seventh student are

Solution:

QUESTION: 15

The mean of 15 numbers is 25. If each number is multiplied by 4, mean of the new numbers is

Solution:

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