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Test: Elimination Method - Class 10 MCQ


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10 Questions MCQ Test Mathematics (Maths) Class 10 - Test: Elimination Method

Test: Elimination Method for Class 10 2024 is part of Mathematics (Maths) Class 10 preparation. The Test: Elimination Method questions and answers have been prepared according to the Class 10 exam syllabus.The Test: Elimination Method MCQs are made for Class 10 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Elimination Method below.
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Test: Elimination Method - Question 1

The values of x and y which satisfy the equations: 47x + 31y = 63 and 31x + 47y = 15 are ____________​

Detailed Solution for Test: Elimination Method - Question 1

Given pair of linear equations:

47x+31y = 63  ---(1)

31x+47y = 15  ---(2)

multiply equation (1) by 31 and equation (2) by 47

substract (2) from (1) we get

(961 - 2209)y = 63x31 - 15x47

-1248 y = 1953 - 705

-1248 y = 1248

Therefore, y = -1.

Substitute y = -1 in equation (1) we get

47x = 94

So, x = 2.
Hence, The values of x and y are 2, -1.

Test: Elimination Method - Question 2

 If x + 2y = 5 & x – 2y = 7, then the value of x & y is: -

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Test: Elimination Method - Question 3

A train overtakes two persons who are walking at the rate of 8 kmph and 12 kmph in the same direction in which the train is going, and passes them completely in 9 and 10 seconds respectively. What is the length of the train?

Test: Elimination Method - Question 4

Adding 1 to the numerator and subtracting 1 from the denominator of a fraction makes it 1. However, if 1 is added only to the denominator of the fraction it becomes ½ . The fraction is______​

Test: Elimination Method - Question 5

In elimination method _____________ is an important condition.​

Detailed Solution for Test: Elimination Method - Question 5

In the elimination method we equate either of the coefficient so that the other is eliminated ,substituting the value of one variable into the other equation and then we are left with the linear equation which is solvable and values of the variables are obtained.

Test: Elimination Method - Question 6

The value of x in mx + ny = c; nx – ny = c + 1 is​

Test: Elimination Method - Question 7

The sum of the digits of a two digit number is 12. The number obtained by reversing its digits exceeds the given number by 18. Then the number is_____

Detailed Solution for Test: Elimination Method - Question 7

Let us assume x and y are the two digits of the number
Therefore, two-digit number is = 10x + y and the reversed number = 10y + x
Given:
x + y = 12
y = 12 – x  (1)
Also given:
10y + x - 10x – y = 18
9y – 9x = 18
y – x = 2    (2)
Substitute the value of y from Equation 1 in Equation 2
12 – x – x = 2
12 – 2x = 2
2x = 10
x = 5
Therefore, y = 12 – x = 12 – 5 = 7
Therefore, the two-digit number is 10x + y = (10*5) + 7 = 57

Test: Elimination Method - Question 8

If x = a, y = b is the solution of the equations x – y = 2 and x + y = 4, then the values of a and b are, respectively.

Detailed Solution for Test: Elimination Method - Question 8

Given, x=a and y=b.
Given equations, x-y=2( assume it as equation 1)
x+y=4( assume it as equation 2)

Equation 1+2,
x-y=2
x+y=4
- - - - - - -
2x=6( y gets cancelled as there is a negative y and a positive y implies y-y=0)
x=6/2
x=3
But x=a implies a=3
substitute a in equation 1 (it can be substituted even in equation 2)
x-y=2
3-y=2
y=3-2
y=1
But y=b implies b=1
Therefore, a=3 and b=1

Test: Elimination Method - Question 9

A lending library has a fixed charge for the first two days and an additional charge for each day thereafter. Sunil paid Rs 28 for a book kept for seven days, while Sohail paid Rs 32 for the book he kept for nine days. Find the charge for each extra day.​

Test: Elimination Method - Question 10

At a closing down sale, a book store was selling 3 books and 5 notebooks for Rs 309 or 6 books and 2 notebooks for Rs 282. How much would one book and 1 notebook cost?​

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