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Test: CAT Logical Reasoning & Data Interpretation- 1 - CAT MCQ


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20 Questions MCQ Test CAT Mock Test Series 2024 - Test: CAT Logical Reasoning & Data Interpretation- 1

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Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 1

The average age of the female patients who weigh 50 kg or above is approximately

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 1

There are 5 ladies whose weights are 50 or above
There ages are 50,50, 70,60 and 80

Average = 310/5 = 62

*Answer can only contain numeric values
Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 2

What is the absolute difference between the highest possible value and the lowest possible value of (x+y+z+p+q+r+s)? All people have at least one vehicle. All the unknown variables are necessarily natural numbers.


Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 2

For the highest possible value, the individual values must be equal to their maximum possible values.
x = 897 [number of people in the city]
y = 986 [number of people in the city]
z = 1034 [number of people in the city]
p = q = 564 [number of people in the city]
r = s = 1067 [number of people in the city]
x + y + z + p + q + r + s = 6179.
For the lowest possible value, the individual values must be equal to their minimum possible values.
x = 1 [total number of vehicles already exceeds the total number of people]
y = 1 [total number of vehicles already exceeds the total number of people]
z = 1 [total number of vehicles already exceeds the total number of people]
p and q are interdependent. p + q = 87 [If p+q = 87, only then can at least one person own one vehicle, that is, the number of vehicles = number of people]
r and s are interdependent. r + s = 1 + 1 = 2 [total number of vehicles already exceeds the total number of people]
Hence, x + y + z + p + q + r + s = 1 + 1 + 1 + 87 + 2 = 92
Difference = 6179 - 92 = 6087.

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*Answer can only contain numeric values
Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 3

If the total number of bikes in all 5 cities combined is 2816, what is the maximum possible number of people in Chennai who own at least 3 vehicles? It is known that all people in Chennai own at least one vehicle.


Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 3

Bike owners in Chennai = 2816 – 707 – 971 – 432 – 342 = 364.

To own at least 3 vehicles, one can own either 3 or 4 vehicles.

I + II + III + IV = 1034

I + 2 II + 3 III + 4 IV = 1987

The difference has to be adjusted among people owning 2, 3 and 4 vehicles. To maximise the sum of people owning 3 and 4 vehicles, we will try to allocate the maximum possible to 3 and the remaining to 4.

1987 – 1034 = 953

2III + 3IV = 953.

III = 475

IV = 1

But, if we observe the values for Chennai, the number of people having a bike is 364 and the number of people having a private jet is 24. Hence, even if we consider that people who own a bike also own a 4-wheeler and a scooter(but not a private jet) and people who own a private jet also own a 4-wheeler and a scooter(but not a bike), we won’t be able to reach the above numbers. We would be able to achieve a maximum value of 24 + 364 = 388.
Let us verify if we can represent the above condition in a 4-set Venn Diagram.

Now, we need to arrange the remaining people who own a 4-wheeler and those who own a scooter.

I + II + III + IV = 1034

IV = 0, because we have already assigned all people who own a Private jet and a bike into III.

III = 388.

I + II = 1034 – 388 = 646

I + 2II + 3III + 4IV = 1987

I + 2II + 3 X 388 = 1987

I + 2II = 823

II = 823 – 646 = 177

I = 469

Hence, we get the following Venn Diagram:

Hence, maximum people who own 3 vehicles = 388.

Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 4

In Bengaluru, the number of people who own zero vehicles is zero, the number of people who own 2 vehicles is 163, the number of people who own 3 vehicles is 36 and the number of people who own all 4 vehicles is more than the number of people who own 3 vehicles, what is the maximum value that y can take?

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 4

I + II + III + IV = 986
I + 2 II + 3 III + 4 IV = 1265 + y
Subtracting the first from the second,
II + 2 III + 3 IV = 279 + y
163 + 72 + 3 IV = 279 + y
y = 3 IV - 44
Now, IV > III, so , IV > 36
But IV <= 57
For maximum y, we have to put maximum IV,
y = 3 x 57 - 44 = 171 - 44 = 127

Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 5

If it is given that all unknowns are equal to 150, what is the maximum number of people in all 5 cities combined who owns exactly 4 vehicles? Also, every person in all of the 5 cities owns at least one vehicle.

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 5

In the following table, I represents people who own only one vehicle, II represents people who own two vehicles, III represents people who own three vehicles and IV represents people who own four vehicles.

We have to calculate the additional value for every city.
Then we try to allocate the maximum to IV for each city. If for a city, this value is more than any particular vehicle value, we take that value.
Hence sum =  326

*Answer can only contain numeric values
Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 6

What is the difference between number of people owning vehicle in hyderabad and number of people owning vehicle in bengaluru?


Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 6

Thus, in Hyderabad, the excess value is 152. We will try to allot maximum to IV, and automatically we will get the maximum I value.
152 = 3 x 50 + 2 x 1
Hence, 50 people own 4 vehicles and 1 person owns 3 vehicles.
Number of people left with 1 vehicle = 897 - 51 = 846
In Bengaluru, the excess value is 429.
But a maximum of 57 people can own all 4 vehicles. We will try to allocate the rest among III.
429 = 3 X 57 + 2 X 129
But 129 people cannot own 3 vehicles, because people owning a scooter is 150, and 57 + 129 exceeds this value.
Hence, the maximum number of people who can own 3 vehicles = 150 - 57 = 93.
Hence we are left with... 429 - 3 x 57 - 2 x 93 = 72
Hence, 57 people own 4 vehicles and 93 people own 3 vehicles, 72 people own 2 vehicles.
Number of people left with 1 vehicle =986 - 57 - 93 - 72 = 764.
Hence, difference = (846 + 764) - (50 + 57)
1503 is the right answer.

*Answer can only contain numeric values
Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 7

At least how many runs were scored by Q in match III? Key in the value.


Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 7

From the given information, we can make the following empty table:

From (ii) and (iii), we get that Q got F grade in match II and match IV.
From (v) and (vi), P got same grade in match II and match III. Now, P could obtain grade B in match II and match III (from (vi)).
Now, in every match, at least one century was scored; thus, R obtained grade A in match II and match IV (from (iv)).
Thus, grade C would be obtained by Q in match I, R in match III and P in match IV (from (iii) and (v)).
Now, remaining rows and columns can be filled giving the final table as follows:

Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 8

If an Indian has invested Rs.93,000 in UK Stock Market in January 2019 then in which month his/her portfolio has declined by maximum percentage in rupee terms?

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 8

From the table, we can see that the % decline in the rupee was maximum in the month of July among the options and also the stock index of UK was lowest in July among the given months so the maximum decline in the portfolio was in July.

*Answer can only contain numeric values
Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 9

What is the average of maximum runs scored by Q in match I and match II? Key in the value upto 2 decimal places.


Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 9

From the given information, we can make the following empty table:

From (ii) and (iii), we get that Q got F grade in match II and match IV.
From (v) and (vi), P got same grade in match II and match III. Now, P could obtain grade B in match II and match III (from (vi)).
Now, in every match, at least one century was scored; thus, R obtained grade A in match II and match IV (from (iv)).
Thus, grade C would be obtained by Q in match I, R in match III and P in match IV (from (iii) and (v)).
Now, remaining rows and columns can be filled giving the final table as follows:

Maximum runs scored by Q in match I = 49
Maximum runs scored by Q in match II = 30
Average of maximum runs scored by Q in match I and match II = (49+30)/2 = 39.5

Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 10

If an Indian has invested Rs. 100,000 in 1st January 2019 till 1st January 2020, then whichoption is best for her?

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 10

The percentage increase in the USA market index is the maximum among the three markets in a year.

Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 11

What is the profit made by Mr. Brown on week 4?

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 11



Total C.P of magazines of Week 1 = 54 × 7.5 + 88 × 8 = 1,109
Total C.P of magazines of Week 2 = 34 × 8 + 88 × 6.75 + 2 × 6.5 = 879
Total C.P of magazines of Week 3 = 72 × 6.5 + 36 × 7.75 = 747
Total C.P of magazines of Week 4 = 84 × 7.75 + 30 × 6 = 831
Total C.P of magazines of Week 5 = 66 × 6 + 42 × 6.52 = 669
Total C.P of magazines of Week 6 = 22 × 6.52 + 82 × 8.50 = 840

Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 12

If a person from USA Invest $1500 in Indian stock market in 1st February then, on which of thefollowing date investment reaches a maximum value in Dollar terms?

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 12

Since on 1st October, the value of the rupee has gotten stronger than its value on 1st February so the investor will be able to draw more dollars for a given amount of rupee and also the Indian stock market has reached the second-highest value among the options given so the value investment is maximum on 1st October in dollars term.

Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 13

For how many magazines that Mr. Brown sold was the profit percentage more than 20%?

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 13



Total C.P of magazines of Week 1 = 54 × 7.5 + 88 × 8 = 1,109
Total C.P of magazines of Week 2 = 34 × 8 + 88 × 6.75 + 2 × 6.5 = 879
Total C.P of magazines of Week 3 = 72 × 6.5 + 36 × 7.75 = 747
Total C.P of magazines of Week 4 = 84 × 7.75 + 30 × 6 = 831
Total C.P of magazines of Week 5 = 66 × 6 + 42 × 6.52 = 669
Total C.P of magazines of Week 6 = 22 × 6.52 + 82 × 8.50 = 840

Thus, the number of magazines with profit > 20% is 410.

Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 14

If a person from India Invest Rs. 108,000 in US stock market in the month of January 2019 then, on which one of the following dates the investment reaches minimum value in rupee terms?

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 14

Among the given options since the dollar got weak the most on 1st May 2019 and also the US market index fell below the value of the index on 1st January so therefore the minimum value reaches was in 1st May 2019.

Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 15

In which of the following weeks did Mr. Brown make the lowest profit?

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 15



Total C.P of magazines of Week 1 = 54 × 7.5 + 88 × 8 = 1,109
Total C.P of magazines of Week 2 = 34 × 8 + 88 × 6.75 + 2 × 6.5 = 879
Total C.P of magazines of Week 3 = 72 × 6.5 + 36 × 7.75 = 747
Total C.P of magazines of Week 4 = 84 × 7.75 + 30 × 6 = 831
Total C.P of magazines of Week 5 = 66 × 6 + 42 × 6.52 = 669
Total C.P of magazines of Week 6 = 22 × 6.52 + 82 × 8.50 = 840

Lowest profit i.e. $138 was made in week 4.

Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 16

How many vehicles were imported in year 2017-18?

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 16

In 2017-18 only the production of commercial vehicles is less than the domestic sales and exports, so only commercial vehicles are imported.
No. of commercial vehicles imported = 954 - 895 = 59

Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 17

What is the average profit per week that Mr. Brown made from week 3 to week 6 (inclusive of both the weeks)?

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 17



Total C.P of magazines of Week 1 = 54 × 7.5 + 88 × 8 = 1,109
Total C.P of magazines of Week 2 = 34 × 8 + 88 × 6.75 + 2 × 6.5 = 879
Total C.P of magazines of Week 3 = 72 × 6.5 + 36 × 7.75 = 747
Total C.P of magazines of Week 4 = 84 × 7.75 + 30 × 6 = 831
Total C.P of magazines of Week 5 = 66 × 6 + 42 × 6.52 = 669
Total C.P of magazines of Week 6 = 22 × 6.52 + 82 × 8.50 = 840

Total profit from week 3 to week 6 is $864.72.
Average for the 4 weeks = $216.18

Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 18

How many two wheelers were in Inventory by the end of 2019 -20?

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 18

The inventory of two-wheelers which was created in 2014-15 is used up in 2015-16. The production of two-wheelers was more than the domestic and sales of two-wheelers therefore,

No. of two-wheelers in inventory by the end of 2019-20 = (19934 - 19930) + (23155 - 23015) + (24500 - 244661) + (21036 - 20938) = 4+140+39+98= 281

Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 19

By what percent is the profit gained in week 1 more/less than that gained in week 2?

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 19



Total C.P of magazines of Week 1 = 54 × 7.5 + 88 × 8 = 1,109
Total C.P of magazines of Week 2 = 34 × 8 + 88 × 6.75 + 2 × 6.5 = 879
Total C.P of magazines of Week 3 = 72 × 6.5 + 36 × 7.75 = 747
Total C.P of magazines of Week 4 = 84 × 7.75 + 30 × 6 = 831
Total C.P of magazines of Week 5 = 66 × 6 + 42 × 6.52 = 669
Total C.P of magazines of Week 6 = 22 × 6.52 + 82 × 8.50 = 840

Difference of profit of week 1 and week 2 = $361 - $240 = $121
Now, 121/361 × 100% = 33.52%

Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 20

In which year import of number of vehicles is highest?

Detailed Solution for Test: CAT Logical Reasoning & Data Interpretation- 1 - Question 20

Total vehicles imported in 2015-16 = (789-787) + (942-934) = 2+8 = 10

Total vehicles imported in 2016-17 = (3807-3802) + (822-810) = 5+12 = 17

Total vehicles imported in 2017-18 = (4037-4020) + (954-895) = 17+59 = 76

Total vehicles imported in 2018-19 = (4053-4028) = 25

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