EPFO Assistant Mains Mock Test - 3 - Bank Exams MCQ

Persons: P, Q, R, S, T, U, V and W (5 males, 3 females)
Colleges: IITB, IITD, IITKGP, BITS, IITR, IITM, IISc and IITK
Cities: Mumbai, Delhi, Shimla, Kolkata, Hyderabad, Chennai, Bhopal and Jaipur

1. T studies in IITM and is from Mumbai.
2. Q is from IITR and his sister R is from IITKGP and is from Shimla.
   So, Q is a male and R is a female.
3. S is from BITS and her friend is from IITB.
   So, S is a female.
4. U is from Chennai and is not from IISc or IITK.
5. W is from Bhopal.
6. P is not from Jaipur.
   
7. No male belongs from Bhopal and Delhi.
   So, W is a female, all else are male.
   Also, S is from Delhi as she is only female left.
   

8. The one who belongs to Hyderabad is from IITB.
   Only college left for U is now IITD. So, U is from IITD.
   Only cities left: Jaipur, Kolkata, Hyderabad

9. The one who is from IITK is not from Jaipur nor Kolkata.
   So, W from Bhopal is from IITK.
   

10. The one who applied for IISc is neither from Kolkata nor Bhopal.
    So, V is from Jaipur and IISc.
    So, P is from IITB and Hyderabad and Q is from Kolkata.
    

Hence, P is S’s friend is from IITB.

Persons: P, Q, R, S, T, U, V and W (5 males, 3 females)
Colleges: IITB, IITD, IITKGP, BITS, IITR, IITM, IISc and IITK
Cities: Mumbai, Delhi, Shimla, Kolkata, Hyderabad, Chennai, Bhopal and Jaipur

1. T studies in IITM and is from Mumbai.
2. Q is from IITR and his sister R is from IITKGP and is from Shimla.
   So, Q is a male and R is a female.
3. S is from BITS and her friend is from IITB.
   So, S is a female.
4. U is from Chennai and is not from IISc or IITK.
5. W is from Bhopal.
6. P is not from Jaipur.
   
7. No male belongs from Bhopal and Delhi.
   So, W is a female, all else are male.
   Also, S is from Delhi as she is only female left.
   

8. The one who belongs to Hyderabad is from IITB.
   Only college left for U is now IITD. So, U is from IITD.
   Only cities left: Jaipur, Kolkata, Hyderabad

9. The one who is from IITK is not from Jaipur nor Kolkata.
   So, W from Bhopal is from IITK.
   

10. The one who applied for IISc is neither from Kolkata nor Bhopal.
    So, V is from Jaipur and IISc.
    So, P is from IITB and Hyderabad and Q is from Kolkata.
    

Hence, W is a female student of IITK.

Persons: P, Q, R, S, T, U, V and W (5 males, 3 females)
Colleges: IITB, IITD, IITKGP, BITS, IITR, IITM, IISc and IITK
Cities: Mumbai, Delhi, Shimla, Kolkata, Hyderabad, Chennai, Bhopal and Jaipur

1. T studies in IITM and is from Mumbai.
2. Q is from IITR and his sister R is from IITKGP and is from Shimla.
   So, Q is a male and R is a female.
3. S is from BITS and her friend is from IITB.
   So, S is a female.
4. U is from Chennai and is not from IISc or IITK.
5. W is from Bhopal.
6. P is not from Jaipur.
   
7. No male belongs from Bhopal and Delhi.
   So, W is a female, all else are male.
   Also, S is from Delhi as she is only female left.
   

8. The one who belongs to Hyderabad is from IITB.
   Only college left for U is now IITD. So, U is from IITD.
   Only cities left: Jaipur, Kolkata, Hyderabad

9. The one who is from IITK is not from Jaipur nor Kolkata.
   So, W from Bhopal is from IITK.
   

10. The one who applied for IISc is neither from Kolkata nor Bhopal.
    So, V is from Jaipur and IISc.
    So, P is from IITB and Hyderabad and Q is from Kolkata.
    

Hence, Q is from Kolkata.

Members: P, Q, R and S
Let us first decode the given symbols and then draw a family tree.


Expression P – Q * R – S means that,
P is the mother of Q. Q is the sister of R. R is the mother of S.
The diagram is as follows:

Hence, Q is the Aunt of S.

Members: P, Q, R and S
Let us first decode the given symbols and then draw a family tree.


Expression: U ÷ V – W * D means that,
U is the father of V. V is the mother of W. W is the sister of D.
                
Thus, W is granddaughter of U.

Given: 
Ten people are sitting in two parallel rows having five people each in such a way that there is an equal distance between adjacent persons.
Row-1: Ajay, Vidyanand, Vishnu, Uday and Anil are seated and all of them are facing south.
Row-2: Praveen, Arpit, Sagar, Ashu and Munna are seated and all of them are facing north.
1) Munna sits third to the right of Arpit.
2) Praveen sits second to the left of Munna.
3) The person facing Praveen sits on the immediate right of Vidyanand.

4) Neither Vidyanand nor Ajay faces Ashu.
5) Ajay is not an immediate neighbour of Vidyanand.
(Therefore Sagar will sit in leftover place.)
6) Only two people sit between Ajay and Vishnu.

7) Only one person sits between Vidyanand and Uday.
(Therefore case – 2 will get eliminated here)
(Therefore Anil will sit in leftover place)

Above arrangement will be final arrangement.
Hence, Vishnu sits to the immediate right of Uday is only true statement.

Given: 
Ten people are sitting in two parallel rows having five people each in such a way that there is an equal distance between adjacent persons.
Row-1: Ajay, Vidyanand, Vishnu, Uday and Anil are seated and all of them are facing south.
Row-2: Praveen, Arpit, Sagar, Ashu and Munna are seated and all of them are facing north.
1) Munna sits third to the right of Arpit.
2) Praveen sits second to the left of Munna.
3) The person facing Praveen sits on the immediate right of Vidyanand.

4) Neither Vidyanand nor Ajay faces Ashu.
5) Ajay is not an immediate neighbour of Vidyanand.
(Therefore Sagar will sit in leftover place.)
6) Only two people sit between Ajay and Vishnu.

7) Only one person sits between Vidyanand and Uday.
(Therefore case – 2 will get eliminated here)
(Therefore Anil will sit in leftover place)

Above arrangement will be the final arrangement.
Hence, Munna is seated to the immediate left of Ashu.

Given statements: S = T ≤ C; G = C; A > P; G ≤ H = P
On combining: S = T ≤ C = G ≤ H = P < A
Conclusions:
I. C ≤ H → True (as C = G ≤ H → C ≤ H)
II. T > P → False (as T ≤ C = G ≤ H = P → T ≤ P)
III. A > S → True (as S = T ≤ C = G ≤ H = P < A → A > S)
IV. G < S → False (as S = T ≤ C = G → S ≤ G)
Therefore, only conclusion I and III are true.

Given statements: X > Y; Y > N = D; D ≥ B = O; P < O
On combining: X > Y > N = D ≥ B = O > P
Conclusions:
I. Y ≤ P → False (as Y > N = D ≥ B = O > P → Y > P)
II. X < D → False (as X > Y > N = D → X > D)
III. O > D → False (as D ≥ B = O → D ≥ O)
IV. P < N → True (as N = D ≥ B = O > P → P < N)
Therefore, only conclusion IV is true.

Given table:

According to the given conditions,

Here, only 1st rule applies. As per 1st rule, a number is immediately preceded by a number and immediately succeeded by a symbol. So, the symbols are to be coded as ‘y’.
Therefore, *0{7+65^1 will be coded as yIyfywYyy.

Given table:

According to the given conditions,

Here, only 3rd rule applies. As per 3rd rule, there are no odd numbers. So, the codes of the second and last element have to be interchanged.
Therefore, 8)646+2 will be coded as JUwRwPG.

Statement I. Nidhi’s mother is the sister of Payal’s father.

Since the gender of Nidhi is not known and there is no information about Payal's grandmother.
Statement II. Payal is the daughter of Nidhi’s grandmother’s only son.

Since the gender of Nidhi is not known, we cannot determine the relationship between Nidhi and Payal's grandmother.
On combining statement I and II we get:

Since the gender of Nidhi is not known, we cannot determine the relationship between Nidhi and Payal's grandmother.
Hence, the data even in both statements I and II together are not sufficient to answer the question.

Given that: Eight members A, B, C, D, E, F, G and H are sitting around a circular table facing outward.
Statement I: A is to the immediate right of E, who is third to the right of B.

This gives no information about the position of G or the person sitting third to the right of G. Therefore, statement I alone is not sufficient.
Statement II: G is fourth to the right of H, who is third to the left of A.

This gives no information about the person sitting third to the right of G. Therefore, statement II is not sufficient.
Statement III: H is not an immediate neighbor of G.
Either A, B, C, D, E or F can be sitting third to the right of G. Therefore, this statement is also not sufficient.
Combining I and II

It is clear that B sits third to the right of G. Therefore, statement I and II are sufficient.
Combining I and III

There is no surety where is the position of H and G. Therefore, I and III are not sufficient.
Combining II and III

There is no information about the person sitting third to the right of G. Therefore, statement II and III are not sufficient.
Hence, both statement I and II together are sufficient.

Given:
People: A, B, C, D, E, F, G, H
Movies: Redline, Zero, Meego, Hero, OK, Schindler’s list, Karma, Green Mile
1) H faces outward and likes Green Mile.
2) B, facing outwards, sits opposite to H and likes Meego.
3) C sits to the immediate left of B and faces inwards.

4) F, facing inwards and A, facing outwards sit adjacent to H.
There will be 2 cases.

5) E sits adjacent to F and likes OK.
6) Person to 2^nd right of F likes Schindler’s List.
7) D likes Zero, faces inwards and sits opposite to person who likes OK.

8) The person to the left of D likes Hero.
Hence, case (2) gets eliminated.
9) Person opposite to Hero liker likes Karma.
 
Clearly, G likes Schindler’s list.

Given:
People: A, B, C, D, E, F, G, H
Movies: Redline, Zero, Meego, Hero, OK, Schindler’s list, Karma, Green Mile
1) H faces outward and likes Green Mile.
2) B, facing outwards, sits opposite to H and likes Meego.
3) C sits to the immediate left of B and faces inwards.

4) F, facing inwards and A, facing outwards sit adjacent to H.
There will be 2 cases.

5) E sits adjacent to F and likes OK.
6) Person to 2^nd right of F likes Schindler’s List.
7) D likes Zero, faces inwards and sits opposite to person who likes OK.

8) The person to the left of D likes Hero.
Hence, case (2) gets eliminated.
9) Person opposite to Hero liker likes Karma.
 
Since E’s direction is not known, it can’t be determined.

The correct answer is option 2. Both A and R are correct and R is NOT the correct explanation of A. Here, the reason is not the correct explanation of the given assertion. If both the sentences are read, it will be clear that they do not relate to each other. In (A), frogs and toads undergo hibernation because they are cold blooded animals so they cannot adjust their body temperature. In (R), it says trees slow down their metabolism and undergo dormancy which is true but is not the reason behind frogs and toads undergoing hibernation. Thus both the statements are correct but the reason does not hold true for the assertion.

Simran should inform her boss about her interests and let the boss decide what the next course of action must be taken. She should not take matter in her own hands nor should she be silent about her desires. Hence, option 2 is the right choice.

Based on the statement that the vegetable prices are increasing, no conclusions can be made about the reason behind the price rise. It doesn’t necessarily be that they aren’t eaten often. It might change due to other factors which require further conclusions which shouldn’t be made. Hence conclusion I don't follow, and according to conclusion II, we cannot assume that shop owners will be benefited. Anything about the sales and profit of the shop owners is not mentioned in the statement so, further conclusions apart from the statement cannot be done.

From careful analysis of the given input,

1. In step 1, word which appears first in dictionary is placed at extreme left position and highest number is placed in extreme right position. In the given input, word 'have’ occurs first in the dictionary and hence it is placed in the leftmost position in step 1. 99 being the highest among the given numbers are placed in the rightmost position.
2. In step 2, word which is observed in second place in dictionary is placed at extreme left and second highest number is placed at extreme right. In the given input, word which occurs second after 'have’ in dictionary is ’luck’. So, ’luck’ is placed in leftmost position. 78 being the second highest are placed to the rightmost.
3. Same procedure is applied to the given input and the below sequence is obtained:

‘alt’ being first word in dictionary is placed in leftmost and 87 being largest number is placed to rightmost.
Input: soap 28 have 18 99 48 luck nice 78 ramp

• Step 1: alt 48 late Zebra 15 82 Yak can vase 33 54 87
• Step 2: can alt 48 late Zebra 15 Yak vase 33 54 87 82
• Step 3: late can alt 48 Zebra 15 Yak vase 33 87 82 54
• Step 4: vase late can alt Zebra 15 Yak 33 87 82 54 48
• Step 5: Yak vase late can alt Zebra 15 87 82 54 48 33
• Step 6: Zebra Yak vase late can alt 87 82 54 48 33 15

From the above series we can conclude that step 4 matches the series given in the question.

From careful analysis of the given input,

1. In step 1, word which appears first in dictionary is placed at extreme left position and highest number is placed in extreme right position. In the given input, word 'have’ occurs first in the dictionary and hence it is placed in the leftmost position in step 1. 99 being the highest among the given numbers are placed in the rightmost position.
2. In step 2, word which is observed in second place in dictionary is placed at extreme left and second highest number is placed at extreme right. In the given input, word which occurs second after 'have’ in dictionary is 'luck’. So, 'luck’ is placed in leftmost position. 78 being the second highest are placed to the rightmost.
3. Same procedure is applied to the given input and the below sequence is obtained:

‘alt’ being first word in dictionary is placed in leftmost and 87 being largest number is placed to rightmost.
Input: soap 28 have 18 99 48 luck nice 78 ramp

• Step 1: alt 48 late Zebra 15 82 Yak can vase 33 54 87
• Step 2: can alt 48 late Zebra 15 Yak vase 33 54 87 82

Counting the words from leftmost, the eight word is 'vase’.
Hence answer is 3.

B lives in a flat, immediately left to the vacant flat. D lives on a second floor and in a flat 2^nd to the right of flat in which B lives.

For both the vacant flats, flat number is same as that of its floor number.
G lives in a flat which is to the immediate left of vacant flat. Flat number of G is same as that of A.

Floor numbers of C and F are same. So, C and F should live on floor number 1.
Case 1: -

Flat numbers of C and E are different.
So, case 2 becomes invalid.
Final arrangement will be: -

Vacant flats are on the floor number 2 and floor number 3.

B lives in a flat, immediately left to the vacant flat. D lives on a second floor and in a flat 2^nd to the right of flat in which B lives.

For both the vacant flats, flat number is same as that of its floor number.
G lives in a flat which is to the immediate left of vacant flat. Flat number of G is same as that of A.

Floor numbers of C and F are same. So, C and F should live on floor number 1.
Case 1: -

Flat numbers of C and E are different.
So, case 2 becomes invalid.
Final arrangement will be: -

Flat number and floor number of A is 2 and 1 respectively.
Flat number and floor number of D is 3 and 2 respectively.
Flat number and floor number of G is 2 and 3 respectively.
Sum for A = 3
Sum for D = 5
Sum for G = 5
Maximum possible sum = 3 + 3 = 6
But, 3rd flat on 3rd floor is vacant.
So, it is maximum for G and D.

• Q was to the immediate right of T and was 2nd to the left of S
• Q and R were seated at a gap of 2
  
• R was neighbouring U
  
• S was not standing neighbouring P and P was not at either of the extreme ends. Thus, case 1 and 2 become invalid.
• Thus, the arrangement is as follows:
  
• P travelled for 30m towards the South and stopped at point X such that the shortest distance between him and U became 34m and also the shortest distance between him and V became 50m
  

Using the Pythagoras theorem:
PU² = 34²-30²
Pu = 16
Similarly, PV = 40m
Thus, distance between U and V = (16+40) = 56m

• Q was to the immediate right of T and was 2nd to the left of S
• Q and R were seated at a gap of 2
  
• R was neighbouring U
  
• S was not standing neighbouring P and P was not at either of the extreme ends. Thus, case 1 and 2 become invalid.
• Thus, the arrangement is as follows:
  
• P travelled for 30m towards the South and stopped at point X such that the shortest distance between him and U became 34m and also the shortest distance between him and V became 50m
  

S was seated at the extreme right, hence nobody was to his right

• Q was to the immediate right of T and was 2nd to the left of S
• Q and R were seated at a gap of 2
  
• R was neighbouring U
  
• S was not standing neighbouring P and P was not at either of the extreme ends. Thus, case 1 and 2 become invalid.
• Thus, the arrangement is as follows:
  
• P travelled for 30m towards the South and stopped at point X such that the shortest distance between him and U became 34m and also the shortest distance between him and V became 50m
  

T was exactly in the middle of the row.

Panther's cage was opposite to the empty cage which faced North

• Tiger's cage was 2nd to the left of the elephant's cage
• Monkey was in an even numbered cage
• Sum of the cage numbers of monkey and leopard was equal to the cage number of tiger.

Monkey's cage number can only be 2 or 4, as the sum of monkey's and leopard's cage is equal to tiger's cage. Tiger is 2^nd to the left of elephant's cage, thus, tigers cage can be 5 or 6 only.
Case 1:

Case 2:

Case 3:

Case 4:

• Elephant was opposite to the lion's neighbour, thus, only case 1 is valid.
• Elephant was not opposite to the monkey's cage

Thus, the final arrangement is as follows:

The bear was in cage number 7

Panther's cage was opposite to the empty cage which faced North

• Tiger's cage was 2nd to the left of the elephant's cage
• Monkey was in an even numbered cage
• Sum of the cage numbers of monkey and leopard was equal to the cage number of tiger.

Monkey's cage number can only be 2 or 4, as the sum of monkey's and leopard's cage is equal to tiger's cage. Tiger is 2^nd to the left of elephant's cage, thus, tigers cage can be 5 or 6 only.
Case 1:

Case 2:

Case 3:

Case 4:

• Elephant was opposite to the lion's neighbour, thus, only case 1 is valid.
• Elephant was not opposite to the monkey's cage

Thus, the final arrangement is as follows:

Apart from elephant others were in cage facing the south.

• Number of villages electrified after village B was thrice as that the number of villages that were electrified after village A
• A and F were electrified at a gap of 2 villages
• B and D were electrified consecutively
  
  
  
  

• Number of villages electrified after village I was twice as that of the number of villages electrified before D, thus, 1st arrangement becomes invalid

Case 1:

• C was electrified in March, thus, case 1 becomes invalid.
• J was electrified on 23rd
• G was electrified just before E but neither of them was the last or the first to be electrified

Case 2:

Invalid as C cannot be placed in this case
Case 2a:


Invalid as C cannot be placed in this case
Thus, the final case is as follows:

H was electrified 2^nd last.

• Number of villages electrified after village B was thrice as that the number of villages that were electrified after village A
• A and F were electrified at a gap of 2 villages
• B and D were electrified consecutively
  
  
  
  

• Number of villages electrified after village I was twice as that of the number of villages electrified before D, thus, 1st arrangement becomes invalid

Case 1:

• C was electrified in March, thus, case 1 becomes invalid.
• J was electrified on 23rd
• G was electrified just before E but neither of them was the last or the first to be electrified

Case 2:

Invalid as C cannot be placed in this case
Case 2a:


Invalid as C cannot be placed in this case
Thus, the final case is as follows:

H and F were electrified consecutively.

• Number of villages electrified after village B was thrice as that the number of villages that were electrified after village A
• A and F were electrified at a gap of 2 villages
• B and D were electrified consecutively
  
  
  
  

• Number of villages electrified after village I was twice as that of the number of villages electrified before D, thus, 1st arrangement becomes invalid

Case 1:

• C was electrified in March, thus, case 1 becomes invalid.
• J was electrified on 23rd
• G was electrified just before E but neither of them was the last or the first to be electrified

Case 2:

Invalid as C cannot be placed in this case
Case 2a:


Invalid as C cannot be placed in this case
Thus, the final case is as follows:

E was electrified on 23^rd February