Indian Navy Tradesman Mate Mock Test - 3 - Indian Navy Tradesman Mate MCQ

(7 x 3) = 21 and (9 x 3) = 27

and (4 x 9) = 36 and (2 x 9) = 18

Therefore (9 x 6) = 54 and (4 x 6) = 24.

(16 + 13) = (14 + 15)

and (28 + 12) = (10 + 30)

Therefore (29 + 16) = (15 + 30).

(3 x 4) + 3 = 15

and (7 x 5) + 3 = 38

Therefore (3 x 5) + 3 = 18.

(15 - 12) + (10 - 9) = 4

(28 - 12) + (16 - 20) = 12

Similarly, (23 -11) + (15- 16) = 11.

As 2012 was a leap year, so the number of days in each month from 23rd January, 2011 to 31st July, 2013 is given as follows.
Since 2011 is not a leap year = 365 - 22 = 343 days
Number of days in 2012 = 366 days (leap year)
Number of days in 2013:
January = 31 days
February = 28 days
March = 31 days
April = 30 days
May = 31 days
June = 30 days
July = 31 days
Total number of days in 2013 = 212
Therefore, total number of days from 23rd January, 2011 to 31st July, 2013 = 343 + 366 + 212 = 921

The time duration from 10 a.m. on Friday to 2 p.m. on the following Monday is 76 hours.
The clock gains 1 minute per hour.
∴ Time gained in 76 hours = 76 minutes = 1 hour 16 minutes
∴ Time shown by the second clock will be 3:16 p.m.

He returned after 8 o'clock but before 9 o'clock, at such a time when both the minute hand and the hour hand were found to be coinciding.
In a simple way, we need to calculate the time when the angle between the minute hand and the hour hand is zero.
Angle between the minute hand and the hour hand at 8 o'clock = 8 × 30 = 240°
We can reduce the difference of 5.5 degree in 1 min,
Required time = 8 hrs + 240 × 2 ÷ 11

In 1 hour, the first clock turns 62 minutes and the second 56 minutes. This implies that for every 56 minutes of the second clock, the first clock gains 6 minutes.
'The second clock shows 10 p.m.' means that it runs for 14 hours.
In this time, the first clock gains = 90 minutes.
So, the time will be 11:30 p.m.

To be together between 9 and 10 o'clock, the minute hand has to gain 45 minute spaces.
55 minute space is gained in 60 minutes.
45 minute space will be gained in 
At 49minutes past 9, the hands of the clock will be together.

According to given information:

Statements: M ≤ N = O ; M ≤ P ; O < Q

Combining the statement: P > M ≤ N = O < Q

Here, P is greater than or equal to M which is less than or equal to N equal to O which is less than Q.

Conclusions:

I.  Q > N → True (In the given statement, P > M ≤ N = O < Q ,It clearly mentioned Q is greater than O which is equal to N .So, Q is greater than N too. Thus, the conclusion I is true).

II. M ≥ O → False (In the given statement, M ≤ N = O, It is clearly mentioned that M is less than or equal to N which is equal to O. So, M can never be greater than O. Thus, conclusion II is a false).

Hence, "Option b" is the correct answer.

The given statement is: J = K ≥ L > X ≥ Y ;  J ≥ P ; P ≥ Z 

Combining the statement: Z < P < J = K ≥ L > X ≥ Y 

Here, Z is smaller than or equal to P which is Smaller than or equal to J which is equal to K which is greater than or equal to L which is greater than X and X is greater than or equal to Y.

Conclusions:

I: J < L → False (as J = K ≥ L gives as J = K and K ≥ L which implies that J ≥ L and J cannot be less than L . Thus, Conclusion I is false.).

II:  P ≤ Y → False (as Z < P < J = K ≥ L > X ≥ Y  → clear relationship between P and Y cannot be determined. Thus, Conclusion II is false.)

Hence, the "Option c" is the correct answer.

According to given information:

Statements: S = R ≥ Q ≤ P ; N ≤ P ; M < N

Combine the statement: S = R ≥ Q ≤ P  ≥ N > M

Here, S is equal to R which is greater than or equal to Q which is less than or equal to P which is greater than or equal to N which is greater than M.

Conclusions:

I. M < S → False (As S = R ≥ Q ≤ P ; N ≤ P ; M < N → there is no direct relation between M and S. So, conclusion I is false)

II. M ≥ S → False (As S = R ≥ Q ≤ P ; N ≤ P ; M < N → there is no direct relation between M and S. So, conclusion II is false)

Here, both conclusions I and II form a complementary pair as both have the same element i.e. M and S and all the three symbols (<, =, >) are present between M and S.

Hence, Either I or II follows.

Hence, "Option d" is the correct answer.

Given: A > B, B > C and C > D

After combining the operators,

we get: A > B > C > D

Now, checking the options:

Option A: A > D → True (As, A > B > C > D gives A > D)

Option B: A > C → True (As, A > B > C > D gives A > C)

Option C: D > A → False (As, A > B > C > D gives A > D)

Option D: B > D → True (As, A > B > C > D gives B > D)

So, Option C, D > A is definitely wrong.

Hence, the correct answer is "Option c".

As the result of Race is Fatigue similarly the result of Fast is Hunger.

As opposite meaning of peace is chaos similarly opposite meaning of creation is destruction.

As Tiger is found in Forest similarly Otter is found in the water.

As magnet has poles similarly battery has terminals.

A Priest wears cassock (a full-length garment worn by certain Christian clergy, members of church choirs, and others having an office or role in a church.) while Graduate wears gown.

The man in the photograph is the daughter of the only son of Lata's grandfather i.e., the girl is the daughter of Lata's father. Hence, the girl is the sister of Lata.

Because the sex of O is not known.

Given: D is the brother of B.

From statement 1, we can detect that D is son of C (son of D is the grandson of C).

From statement 2, we can detect that B is 'Female' (sister of D).

Therefore, B is daughter of C.

M x N → M is the mother of N

N % S → N is the wife of S

and S + T → is the father of T.

Hence, M is the maternal grandmother of T.

The man in the photo is the son of the sister of Bajpai. Hence, Bajpai is the maternal uncle of the man in the photograph.

TOUR → 1234
CLEAR → 56784
SPARE → 90847

Common alphabets in the three words are: 
(i) R coded with the number 4 in each word.
(ii) E coded with the number 7 in each word.
(iii) A coded with the number 8 in each word. 

It is clear from here that each alphabet represents a particular number/code.

Using the codes for the letter from given words.
C A R E will become 5 8 4 7

2*3*5*7*11*13*17 = 510510

4x + 40 = 5(x + 4) → x = 20 (average after 4 innings).

Hence, new average = 20 + 4 = 24.

Since, we have to find the minimum percentage, it can be possible that no one has failed in both the subjects.

Let x kg of oil is used for eating purpose, daily, then
   ► (x + 11) x 50 = + 15 x 45
   ► x = 25
∴ Total quantity of oil = (25 + 11) x 50 = 1800
∴ Required number of days = 1800 / 25 = 72