Indian Navy Tradesman Mate Mock Test - 6 - Indian Navy Tradesman Mate MCQ

We know that the time difference between India and USA is 9 hours 30 minutes.
India is 9 hours 30 minutes  ahead of USA.
Time in India = 4 hours 15 minutes + 9 hours 30 minutes = 13 hours 45 minutes 
Required time after 18 hrs = 13 hours 45 minutes + 18 hrs = 7 hours 45 minutes 
Hence, it is 7 hours 45 minutes  the next morning. 

Sunday 8 am to next Sunday 8 pm time duration 24 × 7 + 12 = 180 hrs.
In 180 hrs total gain = 10 min 48 s = 648 s
Gain of 5 min = 300 s will be obtained in  

Hence, Sunday 8 am + 83 h 20 min = Wednesday 7 : 20 p.m.

Hands will be at right angle twice every hour except from 2 to 4 and 8 to 10 where hands will be at right angle only thrice instead of four times.
Thus, hands will be at right angle 22 times in 12 hours or 44 times in 24 hrs.

Hands are pointing in opposite directions. It means hands are 180° apart or they are 30 minutes apart.
Required time = (5x + 30) × 12/11 minutes past x

At 5 o'clock, the hands are 25 minute space apart.
To be at right angle, that too between 5:30 and 6:00, the minute hand has to gain (25 + 15) or 40 minute space.
55 minute space is gained in 60 minutes.
40 minute space is gained in 40 ×
Therefore, required time =  

The given statement is: C < A ≤ T = D ≥ O; G ≥ D < S; T ≥ A

Combine the statement: C < A ≤ T = D ≥ O; G ≥ D < S

Conclusions:

I: A ≤ O → False (as A ≤ T = D ≥ O gives; as A ≤ D and D ≥ O → clear relationship between A and O cannot be determined).

II: C < G → True (as C < A ≤ T = D ≥ O; G ≥ D < S gives; as by combinatin C < A ≤ T = D ≤ G so C < G True).

Hence, the correct answer is “Only II”.

Given: A ≤ P = B; C = P; F < B

On combining: A ≤ P = B = C

I. B < A → False as A ≤ B.

II. F = P → False as F < P.

Hence both conclusions are false.

Given:

C < O > K; Z < R < N = C

On Combining:

Z < R < N = C < O > K

Conclusions:

1. R < C → True (as R < N = C)

2. Z > N → False (as Z < R < N; therefore Z < N)

3. O = R → False (as R < N = C < O; therefore R < O)

4. C < K → False (as C < O > K; thus, a clear relation between C and K cannot be established)

Hence, “R < C” is definitely true among the given options.

Given : A + B = C + D

⇒ A - D = C - B ----- (i)

Also, it is given that A + D > B + C ----- (ii)

Subtracting (i) from (ii), we get :

D > B

Therefore, B > D is definitely wrong.

Hence, option 4 is the correct answer.

Statements:

U > H = G ≥ N; E < N > W ≥ O

Conclusion:

I. G > E → True → According to the statement G ≥ N > E

II. H > N → False → According to the statement U > H = G ≥ N

Hence, Option (b) is correct.
Mistake Points:
As from the equation H = G ≥ N.
There is a difference in (≥, >) both the sign.

When H ≥ N means H is greater or equal to N.

When H > N means H is greater than N.

As in conclusion 2, it is said H = G ≥ N from this we cannot say H is greater than N.

Thus conclusion 2 is false.

As Chairman is the highest authority in a conference similarly Editor is in Newspaper.

As safe ans secure have same meaning in the same way protect and guard have same meaning.

As Microphone makes sound louder similarly Microscope makes the object magnified.

As on melting, liquid is formed similarly on freezing solid is formed.

So Option A is correct

So Option B is correct

Some fruits are mangos.
All mangos are guavas.
I + A => I - type of conclusion
"Some fruits are guavas".
Conclusion II is Converse of it.
All mangos are guavas
No guava is a banana.
A + E => E - type of conclusion
"No mango is a banana

So Option B is correct

TEACHING:CHEATING ⇔ 12345678:45231678 

BANKING:? ⇔ 12345678:45231678

Thus, BANKINGS will become KIANBNGS

F - 2 = D
I - 2 = G
R - 2 = P
E - 2 = C
FIRE →DGPC

Similarly,
S - 2 = Q
H - 2 = F
O - 2 = M
T - 2 = R
QFMR → SHOT.

Hence, the last letter of the coded word is R.

A - 1 = Z
W - 1 = V
A - 1 = Z
K - 1 = J
E - 1 = D
AWAKE → ZVZJD

Similarly, 
F - 1 = E
R - 1 = Q
I - 1 = H
E - 1 = D
N - 1 = M
D - 1 = C
FRIEND → EQHDMC

PAINT - 74128
EXCEL - 93596
Since each letter is assigned a unique code in the given words.
Therefore, the code for ACCEPT is 455978.

Write the letters of the given word in reverse order
i.e. LOGIC → CIGOL
Now write the previous letters of the reversed word
i.e. CIGOL → BHFNK

Similarly, 
CLERK → KRELC→ JQDKB

Total Valid votes are = 80% of 7500= 6000
If one has 55% vote then the other has left with 45% votes
Hence, 45% of 6000= 2700

Given:

A and B together can do a piece of work in 50 days.

A is 40% less efficient than B

Concept used:

Total work = Efficiency of the workers × time taken by them

Calculation:

Let the efficiency of B be 5a

So, efficiency of A = 5a × 60%

⇒ 3a

So, total efficiency of them = 8a

Total work = 8a × 50

⇒ 400a

Now,

60% of the work = 400a × 60%

⇒ 240a

Now,

Required time = 240a/3a

⇒ 80 days

∴ A can complete 60% of the work working alone in 80 days.

Solve this question through options.
⇒  For instance, if he travelled at 25 km/h, his original speed would have been 24 km/h.
⇒ The time difference can be seen to be 6 minutes in this case = 60 / 24 – 60 / 25 = 0.1 hrs = 6 mins

Thus, 25 km/h is the correct answer. 

So Option A is correct

Relative speed = Speed of A + Speed of B = 2 + 3 = 5 rounds per hour
(∴ they walk in opposite directions)

⇒ They cross each other 5 times in 1 hour and 2 times in 1/2 hour

∵ Time duration from 8 a.m. to 9.30 a.m. = 1.5 hour

∴ They cross each other 7 times before 9.30 a.m