UP PGT Chemistry Mock Test - 8 - UPTET MCQ

The correct answer is Option B.
If liquids A and B form an ideal solution, the enthalpy of mixing is zero.
For ideal solution ΔV_mixing = 0, ΔH_mixing = 0. The Gibbs free energy is always negative and becomes more negative as the temperature is increased.

The correct answer is Option D
Fe³⁺
Coagulation power is directly proportional to the magnitude of charge on the ion.
 

When chlorine gas reacts with hot and concentrate NaOH solution, it disproportionates into Chloride (Cl^-) and Chlorate (ClO₃^-) ions.

For 4f orbital electrons, n = 4

                       s p d f

l = 3 (because 0 1 2 3 )

m = +3, +2, +1, 0, –1, –2, –3

s = ±1/2.

Lead does affect the kidney and CNS but its first target is RBC and through that onlt it travels inside the body to CNS and kidneys.

Constant Temperature means isotherm.

Group 15 doping on group 14 element forms n type semiconductor due to excess electrons.

Conductivity is high due to [H⁺]

H₂O₂ is an oxidizing agent in 1st reaction and Reducing agent in 2nd reaction.

x²  +  10^–4 x – 2 × 10^–8 = 0
x = 10^–4
[OH–] = x + 10^–4
= 2 × 10^–4

Born Haber cycle involves

B is an alcohol formed by the attack of Grignard's reagent on acetone. Hence, alcohol must have the skeleton


Also, R is C₇H₁₁ with two degree of unsaturation it must be cyclohexenyl methyl not cyclohexyl methyl.

From ΔT, of cane sugar, K, can be determined. 

For NaCI solution,

The complex [CO(NH₃)₅NO₂]CI₂  produces three ions in aqueous solution.

[Co(NH₃)₅NO₂]CI₂ → [Co(NH₃)₅NO₂]⁺ + 2Cl^-
The aqueous solution on treatment with an excess of AgNO₃ gives two moles of AgCI because we have 2 moles of Cl^- ion in aqueous solution.
Linkage isomers

[Co(NH₃)₅NO₂]CI₂ and [Co(NH₃)₅(ONO)]CI₂
The nitrite ligand is bound through oxygen (—ONO)in red form. The nitrite ligand is bound through nitrogen (—NO₂) in yellow form.

Bredig's arc method is a method of preparation of the colidal solution of metals such as silver, gold, platinum etc. Copper sol is not prepared using Bredig's arc method.

S_N1 reaction proceeds via carbocation intermediate which is being indicated here by two transition states and a small trough between reactant and product. Also the second transition state must be below first transition state in S_N1 reaction

Covalent solid doesnot conduct electricity in molten and solid state.

 NH4HS (s)  ⇋ NH3 (g) + H2S (g)
Initial    1                   -               -
At eqm     1-x                 x+0.02     x
Kc = [NH₃][H₂S]   (Since NH4HS is solid, we ignore it.)
1.8×10-4    = (x+0.02)(x)
x2+0.02x-1.8×10-4 = 0
Applying quadratic formula; x = -0.02+√{(0.02)2-4×1.8×10-4}
= 0.033-0.020/2 = 0.0065
Therefore, concn of NH₃ at equilibrium = x+0.020 = 0.0265
concn of H2S at equilibrium = x = 0.0065
So, option b is correct

Eutrophication is the process in which nutrient enriched water bodies support a dense plant population, which kills animal life.

As shown in the above mechanism 1-butene and 2-butene cannot be formed by this free radical. release of 1 hydrogen radical gives 2-methyl propene as disproportionated product.

Hence, the correct option is C.

(c) Close packing in two-dimensions can be Type I A A A ...... ty p e The second row may be ^ placed in contact with the first one such that the spheres of A the second row are exactly . above those of the first row.
The spheres of the two rows A are aligned horizontally as well as vertically. In this arrangement, each sphere is in contact with four of its neighbours.
Thus, its coordination number = 4 and is called square close packing in two-dimensions.
Atom A (•) is in contact with four others.

Type II ABAB... type The second row may be placed above the first in a staggered manner such that its spheres fit in the depressions of the first row.
First row arrangement: A type Second row arrangement: 8 type Third row arrangement: A type and so on There is less free space and packing is more efficient than the square close packing. Each sphere is in contact with six of its neighbours and coordination number = 6 in two-dimensions. It is called two dimensional hexagonal close-packing. Voids formed in this case are triangular in shape. If the apex of the triangles downward in the first row, it is upward in the second row.

The negative electron gain enthalpy of fluorine is less than that of chlorine. It is due to small size of fluorine atom. As a result, there are strong interelectronic repulsions in the relatively small 2p orbitals of fluorine and thus, the incoming electron does not experience much attraction.

(D)
When all particle along are body diagonal one removed, these 2 X atoms from corner are removed, one Y particle removed & 2 Z particle removed.
 
Hence new arrangement, X particle = 
Hence formula =  

The correct answer is option C

Ce exist in the oxidation state other than +3 .

(a) B - Boron has +1 and +3 oxidation state.

(b) Al - Aluminium has +1,+2 and +3 oxidation state.

(c) Ce - Cerium has +3 and +4 oxidation state.

(d) Ga - Gallium has +1 and +3 oxidation state.

Cerium (Ce) have [Xe] 4f²6s² electronic configuration.