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UP PGT Physics Mock Test - 5 - UPTET MCQ


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30 Questions MCQ Test UP PGT Mock Test Series 2024 - UP PGT Physics Mock Test - 5

UP PGT Physics Mock Test - 5 for UPTET 2024 is part of UP PGT Mock Test Series 2024 preparation. The UP PGT Physics Mock Test - 5 questions and answers have been prepared according to the UPTET exam syllabus.The UP PGT Physics Mock Test - 5 MCQs are made for UPTET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for UP PGT Physics Mock Test - 5 below.
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UP PGT Physics Mock Test - 5 - Question 1

One mole of an ideal monatomic gas is at an initial temperature of 300 K. The gas undergoes an isovolumetric process, acquiring 500 J of energy by heat. It then undergoes an isobaric process, losing this same amount of energy by heat. Determine the new temperature of the gas

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 1

Explanation:

for monoatomic  gas CV = 1.5R, CP =  2.5R

At const volume, 

Q = 500 J

Q=nCVΔT

500=1×1.5×8.31(T1−300)

T1=340K

At const pressure Q = 500 J

Q=nCPΔT

500=1×2.5×8.31(340−T2)

T2=316K

 

UP PGT Physics Mock Test - 5 - Question 2

A meter rule is supported at its centre. It is balanced by two weights, A and B. If A and B are placed at a distance 20 cm, and 40 cm from the centre of scale, find the weight of B. The weight of A is 50N.

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 2

In balanced condition torque of the both sides must be equal so Fa × Da = Fb × Db
50 × 20 = Fb × 40
Fb = 25 N

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UP PGT Physics Mock Test - 5 - Question 3

If two coils of inductances L1 and L2 are linked such that their mutual inductance is M, then

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 3

M=k√L1L2

here k is cofficient of coupling. Its maximum value is 1 for tight coupling.

UP PGT Physics Mock Test - 5 - Question 4

The no-load current drawn by transformer is usually what percent of the full-load current ?

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 4
  • The no load current is about 2-5% of the full load current and it accounts for the losses in a transformer.
  • These no-load losses include core(iron/fixed) losses, which contains eddy current losses & hysteresis losses and the copper (I2R) losses due to the no Load current.
UP PGT Physics Mock Test - 5 - Question 5

Water is flowing through a pipe under constant pressure. At some place the pipe becomes narrow. The pressure of water at this place:

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 5

We know that the continuity theorem says that if the cross sectional area of the water flow decreases, the speed must increase to maintain the volume of water flown. And according to Bernoulli's principle if the speed of water flow increases , then the pressure must decrease.

UP PGT Physics Mock Test - 5 - Question 6

The energy of the em waves is of the order of 15 keV. To which part of the spectrum does it belong?​

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 6

λ=hc/E​=1240evnm /15×103 ​=0.083 nm
Since the order of wavelength is between 10 nm and .001 nm, it belongs to X-ray. part of the spectrum.

UP PGT Physics Mock Test - 5 - Question 7

In a series LCR what will be phase difference between voltage drop across inductor and capacitor

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 7

Let’s keep this simple and to the point. We know that:
1.in a series circuit the same current flows through each component
2.the voltage across an ideal inductor L is 90˚ ahead of an AC current through it
3.the voltage across an ideal capacitor C is 90˚ behind an AC current through it
So putting these facts together we can conclude that given an AC series current the voltages across any L and C must have a phase difference of 180˚

UP PGT Physics Mock Test - 5 - Question 8

Two wires P and Q of same length and material but radii in the ratio 2 : 1 are suspended from a rigid support. Find the ratio of strain produced in the wires when both are under same force.

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 8

Using Hooke ‘s Law we get

Stress directly proportional to stress = Load/Area=F/pie*r*r

And rp:rq=2:1

When both the wires are under the same stress,strain produced will be the same.
 

When both the wires are under the same stress,strain produced will be the same.

2.when both the wires are loaded by same weight then

Strain p/strain q=(rq)2/(rp)2

UP PGT Physics Mock Test - 5 - Question 9

The unit of impulse is the same as that of :

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 9

The newton second (also newton-second, symbol N s or N.s) is the derived SI unit of impulse. It is dimensionally equivalent to the momentum unit kilogram metre per second (kg.m/s). One newton second corresponds to a one-newton force applied for one second.

UP PGT Physics Mock Test - 5 - Question 10

If an electric dipole is placed in a uniform electric field ______ will act on the dipole.

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 10

Dipole is the combination of two equal but opposite charges, kept at a certain distance. If it is placed in a uniform electric field, both the charges will suffer the same but opposite forces on them. As a result, the net force on the dipole becomes zero, but due to equal and opposite forces acting on two different points, there is a net torque acting on the dipole.

UP PGT Physics Mock Test - 5 - Question 11

The S.I. unit of electric field intensity is:​

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 11

Electric Field Intensity E = F\q

UP PGT Physics Mock Test - 5 - Question 12

The pulley arrangements shown in figure are identical, the mass of the rope being negligible. In case I, the mass m is lifted by attaching a mass 2m to the other end of the rope. In case II, the mass m is lifted by pulling the other end of the rope with a constant downward force, F = 2 mg, where g is acceleration due to gravity. The acceleration of mass m in case I is

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 12

*Multiple options can be correct
UP PGT Physics Mock Test - 5 - Question 13

The figure shows a circular loop of radius a with two long parallel wires (numbered 1 and 2) all in the plane of the paper. The distance of each wire from the centre of the loop is d. The loop and the wire are carrying the same current I.The current in the loop is in the counterclockwise direction if seen from above.

(q) The magnetic fields (B) at P due to the currents in the wires are in opposite directions.

(r) There is no magnetic field at P.

(s) The wires repel each other.

Q.4.When d ≈ a but wires are not touching the loop, it is found that the net magnetic field on the axis of the loop is zero at a height h above the loop. In that case 

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 13

Magnetic field due to current carrying loop = Magnetic field due to straight wires

B = B1cos θ + B2cos θ = 2 B1cos θ

The current is from P to Q in wire 1 and from R to S in wire 2.

UP PGT Physics Mock Test - 5 - Question 14

Nine particles have speeds of 5.00, 8.00, 12.0, 12.0, 12.0, 14.0, 14.0, 17.0, and 20.0 m/s. find the particles’ average speed.

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 14

UP PGT Physics Mock Test - 5 - Question 15

With what angular velocity the earth should spin in order that a body lying at 30° latitude may become weightless [R is radius of earth and g is acceleration due to gravity on the surface of earth]

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 15

g' = acceleration due to gravity at latitude
g = acceleration due to gravity at poles
ω = angular velocity of earth
(θ) = latitude angle
Now,
g' = g - Rω^2 cos^2(θ)
As, g' = 0 (weightless):
g = Rω^2 cos^2(θ)
g = Rω^2 cos^2(30)
g = Rω^2 (3/4)
ω^2 = 4g/3R
ω = √(4g/3R)

UP PGT Physics Mock Test - 5 - Question 16

A toy car with charge q moves on a frictionless horizontal plane surface under the influence of a uniform electric field . Due to the force , its velocity increases from 0 to 6 m s–1 in one second duration. At that instant the direction of the field is
reversed. The car continues to move for two more seconds under the influence of this field. The average velocity and the average speed of the toy car between 0 to 3 seconds are respectively

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 16

Acceleration 


UP PGT Physics Mock Test - 5 - Question 17

According to the Stefan-Boltzmann law of thermal radiation for a perfect radiator, the rate of radiant energy per unit area is proportional to

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 17

The rate of loss of heat by a body is directly proportional to its excess temperature over that of the surroundings provided that this excess is small.

UP PGT Physics Mock Test - 5 - Question 18

What is the natural frequency of an LC oscillator?

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 18

Natural Frequency of an LC Oscillator

- The natural frequency of an LC oscillator is determined by the values of the inductance (L) and capacitance (C) in the circuit.

- The LC oscillator is a type of oscillator circuit that uses a combination of inductors and capacitors to generate oscillations at a specific frequency.

- The natural frequency of an LC oscillator can be calculated using the formula:

f = 1 / (2 * π * √(LC))
 

UP PGT Physics Mock Test - 5 - Question 19

Water drops fall at regular intervals from a tap that is 5m above the ground. The third drop is leaving the tap at the instant the first drop touches the ground. How far above the ground is the second drop at that instant?

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 19

Time taken by first drop to cover 5 cm (u = 0), is: 
h = 1/2 gt2
5 = 1/2 x 10 x t2
t = 1 sec
Hence, the interval is 0.5 sec for each drop.
Now distance fallen by second drop in 0.5 sec
h1 = 1/2 gt2
= 1/2 x 10 x (0.5)2         
= 5 x 0.25 
= 1.25 m
Height above the ground ( of 2nd drop) = 5 - 1.25 = 3.75 m

UP PGT Physics Mock Test - 5 - Question 20

The earth attracts the moon with a gravitational force of 1020 N. Then the moon attracts the earth with the gravitational force of

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 20

Explanation for the Gravitational Force Between the Earth and the Moon

  • According to Newton's Third Law of Motion, every action has an equal and opposite reaction. This law applies to the gravitational forces between two bodies as well.
  • The gravitational force with which the Earth attracts the Moon is equal to the gravitational force with which the Moon attracts the Earth. This is because the forces are action and reaction pairs, as described by Newton's Third Law.
  • Therefore, if the Earth attracts the Moon with a gravitational force of 1020 N, then the Moon attracts the Earth with the same gravitational force of 1020 N.

Hence, the correct answer is b. 1020 N.

UP PGT Physics Mock Test - 5 - Question 21

A charge of 6 mC is located at the origin. The work done in taking a small charge of -2 x 10-9 C from a point P (0, 3 cm, 0) to a Q (0,4 cm, 0) is​

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 21

q=6x10-10 c
Q=-2x10-9c
r1=3x10-2m
r2=4x10-2m
△vQ=w/q
(1/4πεo)-2x10-9/10-2[(1/4)-(1/3)]=W/6x10-3
9x109x2x10-9x6x10-3/12x10-2=W
W=9x10-3x102
W=0.9J

UP PGT Physics Mock Test - 5 - Question 22

7.5 MHz to 12 MHz band corresponds to wavelength band of

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 22

f​1=7.5×106 Hz
f2​=12×106 Hz
λ1​=c/f1​=40 m
λ2​=c/f2​=25 m
 
So, the range is 40m to 25m

UP PGT Physics Mock Test - 5 - Question 23

Identify the expression for horizontal component from the following.

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 23

Horizontal component is a component of Earth’s magnetic field along the horizontal direction in the magnetic meridian. It is denoted by BH. If B is the intensity of Earth’s total magnetic field, then the horizontal component of Earth’s magnetic field is given by:
BH=Bcosδ

UP PGT Physics Mock Test - 5 - Question 24

Find the final temperature of one mole of an ideal gas at an initial temperature to t K.The gas does 9 R joules of work adiabatically. The ratio of specific heats of this gas at constant pressure and at constant volume is 4/3.

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 24

TInitial  = t K
Work, W = 9R
Ratio of specific heats, γ = C/ Cv = 4/3
In an adiabatic process, we have
W = R(TFinal – Tinitial) / (1-γ)
9R = R (TFinal – t) / (1 – 4/3)
TFinal – t = 9 (-1/3) = -3
TFinal  = (t-3) K

UP PGT Physics Mock Test - 5 - Question 25

A block of mass m is on an inclined plane of angle q. The coefficient of friction betwen the block and the plane is m and tan q > m. The block is held stationary by applying a force P parallel to the plane. The direction of force pointing up the plane is taken to the positive. As P is varied from P = mg (sin q _ m cos q ) to Pz = mg (sin q + m cos q), the frictional force f versus P graph will look like              [jee 2010]

                                 

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 25


UP PGT Physics Mock Test - 5 - Question 26

Two simple pendulums of length 1m and 25 m, respectively, are both given small displacements in the same direction at the same instant.If they are in phase after the shorter pendulum has completed n oscillation, n is equal to 

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 26

∴ T ∝ √L , as time period decreases when the length of pendulum decreases, the time period of shorter pendulum (Ts) is smaller than that of longer pendulum (Tl). That means shorter pendulum performs more oscillations in a given time.

  It is given that after n oscillations of shorter pendulum, both are again in phase. So, by this time longer pendulum must have made (n – 1) oscillations. 

So, the two pendulum shall be in the same phase for the first time when the shorter pendulum has 
completed 5/4  oscillation  

UP PGT Physics Mock Test - 5 - Question 27

A negligibly small current is passed through a wire of length 15 m and uniform cross-section 6.0×10-7 m2. The measured resistance of the wire is 5.0 W. The resistivity of the material is

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 27

Length of the wire, l =15 m
Area of cross-section of the wire, a = 6.0 × 10−7 m2
Resistance of the material of the wire, R = 5.0 Ω
Resistivity of the material of the wire = ρ
Resistance is related with the resistivity as,
ρ=RA/l
=5.0×6×10−7/15
=0.2×10−6Ωm

UP PGT Physics Mock Test - 5 - Question 28

In the expression, what is the significance of negative sign?

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 28

The negative sign signifies that the induced emf always opposes any change in the magnetic flux.

UP PGT Physics Mock Test - 5 - Question 29

A rubber ball with water, having a small hole in its bottom is used as the bob of a simple pendulum. The time-period of such a pendulum:

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 29

When rubber ball completely filled with water its centre of gravity will be at its centre, as water will fall through hole its COG will shift towards lower side leading to increase in length of pendulum and thus T, when very small amount of water will be left in rubber ball its COG will again shifts upward causing decrease in length and thus T, and finally when rubber ball becomes empty its COG will be at its centre and T will remains same as earlier.

UP PGT Physics Mock Test - 5 - Question 30

How does electric field strength change with distance from a short dipole?

Detailed Solution for UP PGT Physics Mock Test - 5 - Question 30

Electric Field Intensity due to a short dipole is given by

E = K2P/r^3

where K is the proportionality constant

P is the electric dipole moment

So electric field intensity is inversely proportional to r^3

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