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DSSSB PGT Physics Mock Test - 4 - DSSSB TGT/PGT/PRT MCQ


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30 Questions MCQ Test DSSSB PGT Mock Test Series 2024 - DSSSB PGT Physics Mock Test - 4

DSSSB PGT Physics Mock Test - 4 for DSSSB TGT/PGT/PRT 2024 is part of DSSSB PGT Mock Test Series 2024 preparation. The DSSSB PGT Physics Mock Test - 4 questions and answers have been prepared according to the DSSSB TGT/PGT/PRT exam syllabus.The DSSSB PGT Physics Mock Test - 4 MCQs are made for DSSSB TGT/PGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for DSSSB PGT Physics Mock Test - 4 below.
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DSSSB PGT Physics Mock Test - 4 - Question 1

Unit for a fundamental physical quantity is:

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 1

Unit is the reference used as the standard measurement of a physical quantity.

  • The unit in which the fundamental quantities are measured are called fundamental unit.
  • Units used to measure derived quantities are called derived units.
DSSSB PGT Physics Mock Test - 4 - Question 2

The angular speed of a wheel of radius 0.50 m moving with the speed of 20 m/s is:

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 2

Radius r = 0.5 m
Speed, v = 20 m/s
We know,
v = r ω
where, 
ω = angular velocity
20 = 0.5 x ω
ω = 20/0.5 = 40 rad/sec

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DSSSB PGT Physics Mock Test - 4 - Question 3

A solid sphere is rotating in free space. If the radius of the sphere is increased keeping mass same, which one of the following will not be affected ? 

[AIEEE 2004]

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 3

In free space, neither acceleration due to gravity for external torque act on the rotating solid sphere. Therefore, taking the same mass of sphere if the radius is increased then a moment of inertia, rotational kinetic energy and angular velocity will change but according to the law of conservation of momentum, angular momentum will not change.
In free space, neither acceleration due to gravity for external torque act on the rotating solid sphere. Therefore, taking the same mass of sphere if the radius is increased then a moment of inertia, rotational kinetic energy and angular velocity will change but according to the law of conservation of momentum, angular momentum will not change.

DSSSB PGT Physics Mock Test - 4 - Question 4

If the radius of the earth be increased by a factor of 5, by what factor its density be changed to keep the value of g the same ?

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 4

The acceleration due to gravity on surface of earth is
g=GM​/ R2
 
g=GρV​/R2
where, G is the gravitational constant, M  is mass of earth, R  is radius of earth, ρ is the density and V is the volume of earth.
∴g=Gρ(4/3)​πR3​/ R2
 
∴g=(4/3)​GρπR
⇒g∝ρR
since, all other quantities are constant.
Hence, if the radius of the earth be increased by a factor of 5, density will decrease by 51​  to keep the value of g the same.

DSSSB PGT Physics Mock Test - 4 - Question 5

Escape velocity is:

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 5

Escape velocity is the minimum velocity with which the body has to be projected vertically upwards from the surface of the earth so that it crosses the gravitational field of earth and never returns back on its own.

DSSSB PGT Physics Mock Test - 4 - Question 6

In constructing a large mobile, an artist hangs an aluminum sphere of mass 6.0 kg from a vertical steel wire 0.50 m long and 2.5 × 10−3 cm2in cross-sectional area. On the bottom of the sphere he attaches a similar steel wire, from which he hangs a brass cube of mass 10.0 kg. Compute the elongation.

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 6

Hence 1.6 mm upper, 1.0 mm lower is correct.

DSSSB PGT Physics Mock Test - 4 - Question 7

Angle of contact of water proofing agent are generally

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 7

When a liquid surface meets a solid surface the angle (φ) between the two surfaces is important. In fact a surface will be wetted by water if the angle of contact is less than 90o, and so waterproofing is designed to produce an angle of contact that is greater than 90o.

DSSSB PGT Physics Mock Test - 4 - Question 8

Hot coffee in a thermos flask is shaken vigorously, considering it as a system which of the statement is not true?

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 8

No, heat is not transferred as the flask is insulated from the surroundings ∴dQ=0

DSSSB PGT Physics Mock Test - 4 - Question 9

Three vessels of equal capacity have gases at the same temperature and pressure. The first vessel contains neon (monatomic), the second contains chlorine (diatomic), and the third contains uranium hexafluoride (polyatomic). The number of molecules

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 9

Explanation:Avogadro's law states that, "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules".

DSSSB PGT Physics Mock Test - 4 - Question 10

One mole of an ideal monatomic gas is at an initial temperature of 300 K. The gas undergoes an isovolumetric process, acquiring 500 J of energy by heat. It then undergoes an isobaric process, losing this same amount of energy by heat. Determine the new temperature of the gas

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 10

Explanation:

for monoatomic  gas CV = 1.5R, CP =  2.5R

At const volume, 

Q = 500 J

Q=nCVΔT

500=1×1.5×8.31(T1−300)

T1=340K

At const pressure Q = 500 J

Q=nCPΔT

500=1×2.5×8.31(340−T2)

T2=316K

 

DSSSB PGT Physics Mock Test - 4 - Question 11

A uniform semicircular cylinder of radius R and mass m is displaced through a small angle
θ from its equilibrium position. It rolls without slipping during oscillations. The time period
of small oscillation is

 

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 11

Restoring torque is τ = mg ( O ' P ) = − I0 α

In the figure, θ is very small 

DSSSB PGT Physics Mock Test - 4 - Question 12

In Young's double slit experiment, the distance of the n-th dark fringe from the centre is _

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 12

This is a direct result from NCERT. In Young's double slit experiment, the distance of the nth dark fringe from the centre is 

DSSSB PGT Physics Mock Test - 4 - Question 13

Electric potential is a -

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 13

Electric potential is a pure Scalar quantity, The reason is as follows.
The Electric Potential is defined as the amount of work-done per unit positive charge to bring from infinity to that point under the influence of the primary charge only.
U=W/q
And work done is defined as the dot product of force and displacement which is a scalar quantity.
W=F.S
Thus Electric potential is a scalar quantity.

DSSSB PGT Physics Mock Test - 4 - Question 14

If the electric field is given by 26i – k. Calculate the electric flux through a surface of area 20 units lying in x-y plane.

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 14

► Electric field (E) = 26i - k
► A = 20k
Electric flux = electric field.area
= E.A
= (26i - k)*(20k)
= (26*0 -1)*20
= -20 units

DSSSB PGT Physics Mock Test - 4 - Question 15

Figure shows three resistor configurations R1, R2 and R3 connected to 3V battery. If the power dissipated by the configuration R1, R2 and R3, is P1, P2 and P3, respectively, then –

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 15

We know that 
P=We know that 
P=V2/R
For constant value of potential difference (V) we have
For constant value of potential difference (V) we have

This is a case of balanced Wheatstone bridge R1 = 1Ω Case (ii)

Clearly the equivalent resistance (R2) will be less than 1Ω.
Case (iii)

Since, R2 < R1 < R3

∴ P2 > P1 > P3

 

DSSSB PGT Physics Mock Test - 4 - Question 16

During an experiment with a metre bridge, the galvanometer shows a null point when the jockey is pressed at 40.0 cm using a standard resistance of 90 Ω, as shown in the figure.  The least count of the scale used in the metre bridge is 1mm. The unknown resistance is

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 16

In case of a meter bridge

For finding the value of R

For finding the value of ΔR

Therefore, R = (60 ± 0.25)Ω

DSSSB PGT Physics Mock Test - 4 - Question 17

Aluminum is a diamagnetic material.

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 17

No, aluminum is a paramagnetic material. Paramagnetic materials are those, which when placed in a magnetic field are feebly magnetized in the direction of the magnetizing field, i.e. it is feebly attracted by a magnet.

DSSSB PGT Physics Mock Test - 4 - Question 18

Eddy currents have negative effects. Because they produce:

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 18
  • When a conductive material is subjected to a time-varying magnetic flux, eddy currents are generated in the conductor.
  • These eddy currents circulate inside the conductor generating a magnetic field of opposite polarity as the applied magnetic field. The interaction of the two magnetic fields causes a force that resists the change in magnetic flux.
  • However, due to the internal resistance of the conductive material, the eddy currents will be dissipated into heat and the force will die out. As the eddy currents are dissipated, energy is removed from the system, thus producing a damping effect.
DSSSB PGT Physics Mock Test - 4 - Question 19

In a series RCL circuit at resonance the applied ac voltage is 220 V. The potential drop across the inductance is 110V, what is the potential drop across the capacitor?​

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 19

At resonance, the potential drop across the capacitance is equal and opposite to that of inductance i.e. 110V.

DSSSB PGT Physics Mock Test - 4 - Question 20

Acceptor circuit is

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 20

The series resonance circuit is known as an acceptor circuit. The impedance of the acceptor circuit is minimum but the voltage can be magnified.
The Acceptor circuit provides the maximum response to currents at its resonant frequency.
Series resonance circuit is known as acceptor circuit because the impedance at the resonance is at its minimum so as to accept the current easily such that the frequency of the accepted current is equal to the resonant frequency.
 

DSSSB PGT Physics Mock Test - 4 - Question 21

The objective of a telescope has a focal length of 1.2 m. It is used to view a 10.0 m tall tower 2 km away. What is the height of the image of the tower formed by the objective?

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 21

α (Radian)=10/2000=1/200rad
α=h/F=h/1.2
h= α x 1.2
h=(1/200) x1.2 cm
=6mm

DSSSB PGT Physics Mock Test - 4 - Question 22

A photon is

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 22

A particle representing a quantum of light or other electromagnetic radiation. A photon carries energy proportional to the radiation frequency but has zero rest mass.

DSSSB PGT Physics Mock Test - 4 - Question 23

Suppose you are given a chance to repeat the alpha-particle scattering experiment using a thin sheet of solid hydrogen in place of the gold foil. (Hydrogen is a solid at temperatures below 14 K.) What results do you expect?

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 23

In the alpha-particle scattering experiment, if a thin sheet of solid hydrogen is used in place of a gold foil, then the scattering angle would not be large enough. This is because the mass of hydrogen (1.67×10−27) is less than the mass of incident α−particles (6.64×10−27). Thus, the mass of the scattering particle is more than the target nucleus (hydrogen). As a result, the α−particles would not bounce back if solid hydrogen is used in the α−particle scattering experiment.

DSSSB PGT Physics Mock Test - 4 - Question 24

At a given time there are 25% undecayed nuclei in a sample. After 10 seconds number of undecayed nuclei reduces to 12.5%. Then mean life of the nuclei will be about

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 24

Half-life of radioactive sample, i.e., the time in which the number of undecayed nuclei becomes half (T) is 10 s.
Mean life, τ=T/loge​2=10s/0.693=1.443×10=14.43s ≈ 15s

DSSSB PGT Physics Mock Test - 4 - Question 25

In an unbiased p-n junction, holes diffuse from the p-region to n-region because

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 25

The diffusion of charge carriers across a junction takes place from the region of higher concentration to the region of lower concentration. In this case, the p-region has greater concentration of holes than the n-region. Hence, in an unbiased p-n junction, holes diffuse from the p-region to the n-region.

DSSSB PGT Physics Mock Test - 4 - Question 26

A transistor is used in the common-emitter mode as an amplifier. Then

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 26

When a transistor is used in the common emitter mode as an amplifier, the base-emitter junction acts as input junction and collector-emitter junction acts as output junction. The input junction is made forward biased by applying forward voltage and output junction is made reverse biased by applying reverse voltage. The input signal is connected in series with the voltage applied to forward bias the base-emitter junction.

DSSSB PGT Physics Mock Test - 4 - Question 27

Water is flowing on the blades of a turbine at a rate of 100 kg-s-1 from a certain spring. If the height of the spring be 100 m, then power transferred to the turbine will be

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 27
Work done = Force X Distance. 

From the question :

Force = 100 X 10 = 1000N

Distance = 100m

Work done = 100 X 1000 = 100000Joules 

Power = Work done /Time 

The time = 1 second. 

Power = 100000/1 = 100000 Watts 

= 100kW

DSSSB PGT Physics Mock Test - 4 - Question 28

Two blocks are placed on a wedge with coefficients of friction being different for two blocks. Choose the correct option (friction is not sufficient to prevent the motion).

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 28

Idea The normal reaction between the blocks will be non-zero only if the initial acceleration of block m2 is more than block m1.
Then, only the block m2 will push block m1 and normal reaction will develop and it is possible only when μ2< μ1 The normal reaction between the blocks will not depend on the masses mand m2.


So, there is no relative motion between the blocks, so normal reaction between them is zero.
TEST Edge Both are identical planes, if m does not slip then M will?

M will also not slip because in this case motion of block will depend only on (l not on mass of the block.

DSSSB PGT Physics Mock Test - 4 - Question 29

Four capacitors of each of capacity 3μF are connected as shown in the adjoining figure. The ratio of equivalent capacitance between A and B and between A and C will be

Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 29



DSSSB PGT Physics Mock Test - 4 - Question 30
The de-Broglie wavelength associated with proton changes by 0.25% if its momentum is changed by P₀. The initial momentum was
Detailed Solution for DSSSB PGT Physics Mock Test - 4 - Question 30
Use the formula lamba=h/p you will see that they are inversely related, so if you reduce wavelength by 0.25% then momentum reduces by 1 unit. So that implies Initial momentum is 401Po
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