If f(x) = (x2 -4)÷(x-2) for x<2, f(x)=4 for x=2 and f(x)=2 for x>2, then f(x) at x = 2 is
f(x) = when x o 0, then f(x) is
If = i, then which of the following is correct?
is equal to
If f(x) = x for 0 ≤ x 1/2, f(x) = 1 for x = 1-x for 1/2<x<1 then at x =1/2 the function is
e-1/x[1+e1/x]-1 is
If f(x)=9x÷(x+2) for x<1, f(1)=3, f(x)=(x+3)x-1 for x>1, then in the interval (-3,3) the function is
Function f(x) = K.x-1 for x < 2
= x-k for x ≥ 2
is continuous at x = 2
The value of 'k' is __________.
Evaluate
Evaluate
The points of discontinuity of the function, F(x) = are
Find limn→∞(2n-1)2n (2n+1)-1 21-n
Find limn→∞[4n2 + 6n +2] ÷ 4n2
Find limn→∞[xn.(n+1)] ÷ [nx n+1 ]
Find limn→∞[n(n+2)] ÷ (n+1)2
Find limn→∞(n3 +a )[(n+1)3a]-1 (2n+1 +a ) (2n +a)-1
Find limn→∞(n2 +1)[(n+1)2 +1]-1 5n+1 5-n
Find limn→∞nn(n+1)-n-1 ÷ n-1
Find limn→∞2n-1 (10 +n) (9+n)-1 2-n
Find limn→∞(1+n-1)[1+2n)-1]-1
Find limn→∞[nn. (n+1)!] ÷ [n! (n+1)n+1]
Find limn→∞[(n+1)n+1. n-n-1 -(n+1).n-1]-n
3x2+2x-1 is continuous
Find limn→∞nn (1+n)-n
Find limn→∞[n!3n+1] ÷[3n(n+1)!]
The value of the limit when x tends to zero of the expression (1+n)1/n is
The value of the limit when x tends to zero of the expression (1+n)1/n is
The value of the limit when x tends to zero of the expression [(1+x)n-1] ]
The value of the limit when x tends to 2 of the expression (x-2)-1-(x2-3x+2)-1 is
The value of the limit when x tends to zero of the expression (ex-1)/x is
The value of the limit when n tends to infinity of the expression 2-n(n2+5n+6)[(n+4)(n+5)]-1 is
The value of the limit when x tends to zero of the expression (1+n)1/n is
Find limn→∞[n1/2 + (n+1)1/2]-1 ÷ n-1/2
The value of the limit when x tends to zero of the expression [(a+x2)1/2
Find limn→∞ (2n-2)(2n+1)-1
Find limn→∞ [(n3 +1)1/2 - n 3/2] ÷ n3/2
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