Test: Ratio And Proportion, Indices, Logarithms - 2


40 Questions MCQ Test Quantitative Aptitude for CA CPT | Test: Ratio And Proportion, Indices, Logarithms - 2


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Attempt Test: Ratio And Proportion, Indices, Logarithms - 2 | 40 questions in 40 minutes | Mock test for CA Foundation preparation | Free important questions MCQ to study Quantitative Aptitude for CA CPT for CA Foundation Exam | Download free PDF with solutions
QUESTION: 1

Division of Rs. 750 into 3 parts in the ratio 4 : 5 : 6 is

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QUESTION: 2

The sum of the ages of 3 persons is 150 years. 10 years ago their ages were in the ratio 7 : 8 : 9. Their present ages are

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QUESTION: 3

The numbers 14, 16, 35, 42 are not in proportion. The fourth term for which they will be in proportion is

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QUESTION: 4

If x/y = z/w, implies y/x = w/z, then the process is called

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QUESTION: 5

If p/q = r/s = p–r/q–s, the process is called

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QUESTION: 6

If a/b = c/d, implies (a+b)/(a–b) = (c+d)/(c–d), the process is called

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QUESTION: 7

If u/v = w/p, then (u–v)/(u+v) = (w–p)/(w+p). The process is called

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QUESTION: 8

12, 16, *, 20 are in proportion. Then * is

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QUESTION: 9

4, *, 9, 13½ are in proportion. Then * is

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QUESTION: 10

The mean proportional between 1.4 gms and 5.6 gms is

Solution:

Let 1.4 gms, x gms and 5.6 gms be in continuous proportion.

(Mean proportional terms)^2 = Product of extremes.

Therefore x^2 = 1.4 x 5.6

therefore x^2 = 7.84

therefore x= 2.8 gms.

QUESTION: 11

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QUESTION: 12

Two numbers are in the ratio 3 : 4; if 6 be added to each terms of the ratio, then the new ratio will be 4 : 5, then the numbers are

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QUESTION: 13

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QUESTION: 14

Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:

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QUESTION: 15

if  then  (b-c)x + (c-a)y+(a-b)z is 

Solution:

Let X=(b+c-a);y=(c+a-b);z=(a+b-c)

=(b-c)(b+c-a)+(c-a)(c+a-b)+(a-b)(a+b-c)

=b^2-c^2-ab+ac+c^2-a^2-bc+ab+a^2-b^2-ac+bc

=0

QUESTION: 16

4x–1/4 is expressed as

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QUESTION: 17

The value of 81/3 is

Solution:
QUESTION: 18

The value of 2 × (32) 1/5 is

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QUESTION: 19

The value of 4/(32)1/5 is

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QUESTION: 20

The value of (8/27)1/3 is

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QUESTION: 21

2½ .4¾ is equal to

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QUESTION: 22

 has simplified value equal to 

Solution:
QUESTION: 23

xa–b × xb–c × xc–a is equal to

Solution:
QUESTION: 24

The value of  is equal to 

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QUESTION: 25

{(33)2 × (42)3 × (53)2} / {(32)3 × (43)2 × (52)3} is

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QUESTION: 26

Which is True ?

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QUESTION: 27

If x1/p = y1/q = z1/r and xyz = 1, then the value of p+q+r is

Solution:
QUESTION: 28

The value of ya–b × yb–c × yc–a × y–a–b is

Solution:
QUESTION: 29

The True option is

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QUESTION: 30

The simplified value of 16x–3y2 × 8–1x3y–2 is

Solution:
QUESTION: 31

The value of (8/27)–1/3 × (32/243)–1/5 is

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QUESTION: 32

The value of {(x+y)2/3 (x–y)3/2/√x+y × √ (x–y)3}6 is

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QUESTION: 33

Simplified value of (125)2/3 × √25 × 3√53 × 51/2 is

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QUESTION: 34

[{(2)1/2 . (4)3/4 . (8)5/6 . (16)7/8 . (32)9/10}4]3/25 is

Solution:
QUESTION: 35

[1–{1–(1–x2)–1}–1]–1/2 is equal to

Solution:

ANSWER :- a

Solution :- [1–{1–(1–x2)–1}–1]–1/2

=[1 - { 1- x2 -1/(1-x2) }-1]-1/2 here we used a-n = 1/an

= [1 - {(-x^2)/(1-x^2)}^-1]^-1/2

= [ 1 - { x^2 /( x^2 -1) }-1]-1/2

= [ 1- (x2-1)/ x2]-1/2

= [ (x2 -x2+1)/ x2]-1/2

= [1/x2]-1/2

= [x2]1/2

= x 2*1/2

= x

QUESTION: 36

Ajay and Raj together have Rs. 1050. On taking Rs. 150 from Ajay, Ajay will have same amount as what Raj had earlier. Find the ratio of amounts with Ajay and Raj initially. 

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QUESTION: 37

If a3–b3 = (a–b) (a2 + ab + b2), then the simplified form of 

Solution:
QUESTION: 38

 Using (a–b)3 = a3–b3–3ab(a–b) tick the correct of these when x = p1/3 – p–1/3

Solution:
QUESTION: 39

On simplification, 1/(1+am–n+am–p) + 1/(1+an–m+an–p) + 1/(1+ap–m+ap–n) is equal to

Solution:
QUESTION: 40

If A:B = 2:3, B:C = 4:5 and C:D = 6:7, then find the value of A:B:C:D

Solution:

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