Test: The Ideal Operational Amplifiers - Electrical Engineering (EE) MCQ

 The minimum no of pins required by dual-op-amp is 8. Each op-amp has 2 input terminals(4 pins) and one output terminal(2 pins). Another 2 pins are required for power.
Similarly, The minimum no of pins required by dual-op-amp is 14: 4*2 + 4*1 + 2 = 14.

An ideal operational amplifier does not has a zero input impedance.

V_c = 0.5(V₁ + V₂) and
V_{d = V2 – V1.}

Output voltage (v_o​) = 4 V,

Input voltage (v_i​) = 2 V.

• v₊​ = v_i ​= 2V, as the non-inverting terminal is directly connected to the input voltage (v_i​).
• The voltage v_at the inverting terminal is determined by the resistive divider formed by 1MΩ and 1 kΩ.

Using the voltage divider rule:

Substitute v_o​ = 4V:

Step 3: Calculate the Gain

From the op-amp equation:

There are three terminals for the operational amplifier.

It is another way to refer to op amps based on its terminal characteristics.

This is the correct mathematical representation.

The minimum no of pins required by dual-op-amp is 8. Each op-amp has 2 input terminals(4 pins) and one output terminal(2 pins). Another 2 pins are required for power.

Only option d does not satisfies the mathematical relation between the given quantities.

 These units are obtained from the definition of the term slew rate.