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BPSC TGT Math & Science Mock Test - 3 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test Bihar TGT Exam Mock Test Series 2024 - BPSC TGT Math & Science Mock Test - 3

BPSC TGT Math & Science Mock Test - 3 for Bihar PGT/TGT/PRT 2024 is part of Bihar TGT Exam Mock Test Series 2024 preparation. The BPSC TGT Math & Science Mock Test - 3 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The BPSC TGT Math & Science Mock Test - 3 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for BPSC TGT Math & Science Mock Test - 3 below.
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BPSC TGT Math & Science Mock Test - 3 - Question 1

Which of these is a preposition to indicate closeness?

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 1
Towards indicates direction, at indicates a place and beneath indicates the position.
BPSC TGT Math & Science Mock Test - 3 - Question 2

Fill in the blanks with the correct preposition.

The cat always sleeps ____ my bed.

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 2
Answer: A. under Explanation: The correct preposition to use in this sentence is "under." This is because the preposition "under" is used to describe something that is beneath or below something else. In this case, the cat is sleeping beneath the bed. Here's a breakdown of the other prepositions and why they are not appropriate in this context: - B. above: This preposition indicates that something is higher or at a higher level than something else. In this case, it does not make sense for the cat to sleep above the bed. - C. between: This preposition is used when something is in the middle of two other things. It does not fit the context of the cat sleeping in relation to the bed. - D. over: Similar to "above," this preposition implies that something is on top of or covering something else. It does not accurately describe the cat's position in relation to the bed. So, the correct sentence is: "The cat always sleeps under my bed."
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BPSC TGT Math & Science Mock Test - 3 - Question 3

Direction: Choose the correct pronoun to fill in the blanks.
Q. Please don’t talk about _____________.

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 3

'Her' is the pronoun because it is singular. The other pronouns do not match the sentence.

BPSC TGT Math & Science Mock Test - 3 - Question 4

दिए गए शब्द युग्म का सही अर्थ ज्ञात कीजिए।

सर्व-शर्व

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 4

सही उत्तर है - "सभी-शैव" lKey Points

  • सर्व का अर्थ है - सभी l
  • शर्व का अर्थ है - शैव l
  • इसलिए यह सही उत्तर है l

अन्य विकल्पों का विश्लेषण:-

  • शव शब्द का अर्थ है - मृतक का शरीर, लाश l
  • सही का अर्थ है - ठीक l
  • शाकाहारी का अर्थ है - वह जो बस वनस्पति खाता है l
  • इन तीनों शब्द जोड़ों में एक- एक शब्द का अलग अर्थ है, इसलिए यह तीनों प्रश्न में दिए गए शब्द- युग्म के सही अर्थ को नहीं बताते l

Additional Information

  • सर्व-शर्व यह दोनों श्रुतिसम भिन्नार्थक शब्दों के उदाहरण है जो सुनने में एक जैसे लगते हैं, और वर्तनी में भी कुछ सामान ही होते हैं, लेकिन इनके अर्थ बिल्कुल अलग-अलग होते हैं l
  • ऐसे कुछ शब्दों के उदाहरण:-
  • चर्म- चमड़ा
    • चरम- अत्यधिक
  • हय- घोड़ा
    • हिय- हृदय
  • श्रवण- सुनना, कान
    • श्रमण- बौद्ध संन्यासी
BPSC TGT Math & Science Mock Test - 3 - Question 5
निम्नांकित में 'विस्मयादिबोधक शब्द' का उदाहरण है -
Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 5

सही उत्तर "शाबाश" है।

  • दिए गए विकल्पों में, 'शाबाश' शब्द 'विस्मयादिबोधक' अव्यय है।
  • दिए गए जिन शब्दों से शोक, विस्मय, घृणा, आश्चर्य आदि भाव व्यक्त हों, उन्हें विस्मयादि बोधक अव्यय कहा जाता है।
  • जैसे - (शाबाश!) तुमने बहुत अच्छा कार्य किया।
  • इस वाक्य में आश्चर्य के भाव प्रकट हों रहा है और साथ ही इस वाक्य में विस्मयादिबोधक (!) चिह्न का प्रयोग हुआ है इसलिए यहां विस्मयसूचक अव्यय है।

Key Points

अन्य विकल्पों का विश्लेषण:

Additional Information

  • वे शब्द जिनमे लिंग, कारक, वचन, पुरुष आदि के कारण कोई विकार/ परिवर्तन उत्पन्न नहीं होता है, अव्यय शब्द कहलाते है।
  • जैसे – आज, कब, इधर, किन्तु आदि।
  • अव्यय के पांच भेद हैं
BPSC TGT Math & Science Mock Test - 3 - Question 6
“पुत्री का विवाह करके अजय के माता-पिता आज गंगा नहा लिए”। रेखांकित मुहावरे का अर्थ है-
Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 6

दिए गए विकल्पों में से सही उत्तर विकल्प 1 'कार्य से निवृत्त होना’ है। अन्य विकल्प इसके गलत उत्तर हैं।

Key Points

  • मुहावरा- गंगा नहाना
  • अर्थ - ​कार्य से निवृत्त होना
  • वाक्य - हर कोई अपना काम करके गंगा नहाने की चाह रखता है।
  • अन्य विकल्प अनुचित हैं।


अन्य विकल्प:


Additional Information

  • मुहावरा का शाब्दिक अर्थ ‘अभ्यास’ है।
  • मुहावरा शब्द अरबी भाषा का शब्द है।
  • हिन्दी में ऐसे वाक्यांशों को मुहावरा कहा जाता है, जो अपने साधारण अर्थ को छोड़कर विशेष अर्थ को व्यक्त करते हैं।
BPSC TGT Math & Science Mock Test - 3 - Question 7

Directions: Study the following question carefully and choose the right answer.

If ACELDNRA stands for CALENDAR, what does LEGIBIEL stands for?

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 7

Assign numbers to letter and move them like given word.

Similarly;
Arrange the given word like the bold value of CALENDAR;

Hence, option B is correct.

BPSC TGT Math & Science Mock Test - 3 - Question 8

In a big garden 40% of the trees are mango trees. The number of mango trees is 80% of the number of guava trees. The rest of the trees are Jambolan trees. If the number of Jambolan trees is 40, what is the total number of trees in the garden?

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 8

Total Mango trees = 40%

Remaining trees = (100 – 40 – 50)% = 10%

Hence, Option B is correct.

BPSC TGT Math & Science Mock Test - 3 - Question 9

Direction: In a family, there are seven members P, Q, R, S, T, U, and V are a married couple. P being the male member. S is the only son of R, who is the brother of P. T is the sister of S. Q is the daughter-in-law of U, whose husband has died.

Q. How is U related to P?

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 9

P is male member and married to Q.
P is husband and Q is wife.
R is brother of P.
S is the son of R.
T, who is the sister of S will be daughter of R.
Q is the daughter-in-law of U, whose husband has died means U is the mother of P.

BPSC TGT Math & Science Mock Test - 3 - Question 10

If a pipe can fill 75% of a tank in 33 minutes, in how many minutes can it fill 95% of the tank?

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 10


Hence, Option C is correct.

BPSC TGT Math & Science Mock Test - 3 - Question 11

Does 210 falls in the AP: 21, 42, 63, 84…? If yes, then on which term?

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 11

AP: 21, 42, 63, 84, …
a = 21
d = 42 – 21 = 21
a(n) = 210
a + (n – 1) x d = 210
21 + (n – 1) x (21) = 210
21 + 21 x n – 21 = 210
21 x n = 210
n = 10

BPSC TGT Math & Science Mock Test - 3 - Question 12

How many rotations of a wheel with a 21 m radius are required to cover a distance of 6.60 km?

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 12

Perimeter of the wheel

Hence, Option B is correct.

BPSC TGT Math & Science Mock Test - 3 - Question 13

The horizontal distance between two towers is 140 m. The angles of depression of the first tower, when seen from the top of the second tower is 30°. If the height of the first tower is 60 m. Find the height of the second tower.

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 13

The second tower is smaller than the first tower so let the height of the first tower is h So a part of it is equal to 60m so the remaining height is h-60 m
Tan 30=perpendicular/base

BPSC TGT Math & Science Mock Test - 3 - Question 14

The common difference of the A.P whose Sn = 3n2+ 2n is

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 14


Thus, initial term of the A.P. is 5 and the common difference is 6.

BPSC TGT Math & Science Mock Test - 3 - Question 15

In the adjoining figure, the bisectors of ∠CBD and ∠BCE meet at the point O. If ∠BAC = 700, then ∠BOC is equal to :-

 

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 15



If the outer bisectors of the angle B and angle C meet at a point O outer side of the triangle, then ∠BOC = 90° - ∠A/2 = 90° - 70°/2 = 55°

BPSC TGT Math & Science Mock Test - 3 - Question 16

Which of the following quadratic expression can be expressed as a product of real linear factors?

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 16


Thus, it can be expressed as product of linear factors.

BPSC TGT Math & Science Mock Test - 3 - Question 17

What are the chances that no two boys are sitting together for a photograph if there are 5 girls and 2 boys? 

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 17

BPSC TGT Math & Science Mock Test - 3 - Question 18

DIRECTION : In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Mark the correct choice as:

Assertion : If a ball is in the shape of a sphere has a surface area of 221.76cm2 , then its diameter is 8.4 cm.

Reason : If the radius of the sphere be r , then surface area, S = 4p r2 , i.e.

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 18
Given, surface area of sphere = 221.76cm2

We know, surface area of sphere = 4πr2

⇒ 4(π)r2 = 221.76

⇒ r2 = 7/22​ × 221.76 × 1/4 ​= 7 × (10.08) × 1/4 ​

⇒ r = 4.2cm

Then, diameter equals 2r = 2 × 4.2 = 8.4 cm, which is true and reason is also correct.

Moreover reason is the correct explanation of assertion.

BPSC TGT Math & Science Mock Test - 3 - Question 19

In △AOC and △XYZ, ∠A =∠X, AO = YZ, AC = XY, then by which congruence rule △AOC ≅ △XYZ

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 19

To determine the congruence rule for ΔAOC and ΔXYZ:


  • Given: ∠A = ∠X

  • AO = YZ (one pair of corresponding sides)

  • AC = XY (another pair of corresponding sides)

  • Two pairs of sides and the included angle are equal

  •  

Therefore, by the SAS (Side-Angle-Side) congruence rule, ΔAOC ≅ ΔXYZ.

BPSC TGT Math & Science Mock Test - 3 - Question 20

A park is in the form of a rectangle 120m by 90 m. At the centre of the park there is a circular lawn as shown in the figure. If the area of the park excluding the lawn is 2950 m2, then the radius of the circular lawn will be 

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 20

ANSWER :- b

Solution :- Area of rec. park=(120×90)m²=10800m²

Area of rec. park excluding lawn=2950m²

Area of circular lawn=(10800 - 2950)m²

=7850m²

Let the radius be = r

7850/3.14 = 3.14r²/3.14

→2500 = r²

→√2500 = √r²

→50 = r

→r = 50

Radius = 50m

BPSC TGT Math & Science Mock Test - 3 - Question 21

The mean of 1, 2, 3, 4 …n is given by

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 21

⇒   We have the sequence, 1,2,3.......n
⇒   This is an AP, with the initial term a=1 and the common difference d=1.
∴   The sum of n terms of an AP is given by,


→   Arithmetic mean of n numbers a1​,a2​,a3​,a4​,...an​ is given by the formula

BPSC TGT Math & Science Mock Test - 3 - Question 22

A tree in each year grows 4cm less than it grew in previous year. If it grew 1 metre in the first year, in how many years will it have ceased growing and what will be its height then,​

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 22

One metre = 100 cm, a = 100 cm

since every year it grows 4 cm less than it did the preceding year, d = -4

Thus, it is an AP, with initial term a = 100 and d = -4

The tree will stop its growth, when nth term of the series is 0.

Nth term = a + (n - 1)d

0 = 100 + (n - 1)(-4)

0 = 100 - 4n + 4

0 = 104 -4n

4n = 104

n = 104/4

n = 26 years

BPSC TGT Math & Science Mock Test - 3 - Question 23

What is the order of magnitude of the resistance of a dry human body?

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 23

Human body has different resistances, when dry, resistance is 100,000 ohms. When wet because of sweat or water, resistance is only 1,000 ohms.

BPSC TGT Math & Science Mock Test - 3 - Question 24

 Which of the following relations are not correct?

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 24

The correct answer is Option B 
 
k =G*l/A      (Since, G = 1/R)
   = l/AR 
Therefore, kR = l/A 
So, l/A = kR not k/R

BPSC TGT Math & Science Mock Test - 3 - Question 25

The amino acid which are synthesized in the body are known as:

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 25

Nonessential amino acids can be synthesized in the body, whereas essential amino acids must be obtained in the diet. Cells in the body can provide the carbon skeleton of the nonessential amino acids.

BPSC TGT Math & Science Mock Test - 3 - Question 26

Reduction is defined in terms of

I. electronation and hydrogenation
II. deelectronation and gain of oxygen
III. increase in oxidation number
IV. decrease in oxidation number

Select the correct terms

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 26

Gain of hydrogen , electron and decrease in oxidation number is reduction

BPSC TGT Math & Science Mock Test - 3 - Question 27
How does the pH of a salt formed by a weak acid and a strong base compare to 7?
Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 27
When a weak acid and a strong base combine to form a salt, the resulting compound will be basic with a pH greater than 7. The presence of a strong base in the compound contributes to its alkalinity, causing the pH to rise above the neutral value of 7.
BPSC TGT Math & Science Mock Test - 3 - Question 28

A resistance of 50Ω is registered when two electrodes are suspended into a beaker containing a dilute solution of a strong electrolyte such that exactly half of the them are submerged into solution. If the solution is diluted by adding pure water (negligible conductivity) so as to just completely submerge the electrodes, the new resistance offered by the solution would be

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 28

the k is halved while the A is doubled. Hence R remain 50 Ω.

BPSC TGT Math & Science Mock Test - 3 - Question 29

Select the incorrect statement.

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 29

Weight of body depends on diet and habits. If somebody is not eating he will definitely lose weight as the body fat will be used for production of energy once glycogen reserve finishes.

BPSC TGT Math & Science Mock Test - 3 - Question 30

Which of the following contributed to the success of Mendel :-

Detailed Solution for BPSC TGT Math & Science Mock Test - 3 - Question 30
Contributions to the success of Mendel:
1. His knowledge of biology:
- Mendel's background in biology allowed him to understand the basic principles of inheritance and genetics.
- He was knowledgeable about the reproductive processes of plants, which allowed him to perform experiments and make accurate observations.
2. Qualitative analysis of data:
- Mendel meticulously collected and analyzed data from his experiments.
- He focused on qualitative traits, such as flower color or seed texture, rather than just counting the number of offspring.
- This approach allowed him to identify distinct patterns of inheritance and formulate his laws of genetics.
3. Observation of distinct inherited traits:
- Mendel chose to study traits that were easily distinguishable and occurred in distinct forms, such as tall vs. short plants or yellow vs. green peas.
- By selecting traits with clear-cut variations, he was able to easily track their inheritance patterns and make accurate predictions.
4. Consideration of one character at a time:
- Instead of studying multiple traits simultaneously, Mendel focused on one trait, such as flower color, in each experiment.
- This allowed him to establish clear and consistent patterns of inheritance for each trait and avoid confusion or overlap between different traits.
In conclusion, Mendel's success can be attributed to his knowledge of biology, his qualitative analysis of data, his observation of distinct inherited traits, and his consideration of one character at a time. These factors enabled him to make significant discoveries in the field of genetics and lay the foundation for modern understanding of inheritance.
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