Bihar PGT/TGT/PRT Exam  >  Bihar PGT/TGT/PRT Tests  >  Bihar TGT Exam Mock Test Series 2024  >  BPSC TGT Math & Science Mock Test - 7 - Bihar PGT/TGT/PRT MCQ

BPSC TGT Math & Science Mock Test - 7 - Bihar PGT/TGT/PRT MCQ


Test Description

30 Questions MCQ Test Bihar TGT Exam Mock Test Series 2024 - BPSC TGT Math & Science Mock Test - 7

BPSC TGT Math & Science Mock Test - 7 for Bihar PGT/TGT/PRT 2024 is part of Bihar TGT Exam Mock Test Series 2024 preparation. The BPSC TGT Math & Science Mock Test - 7 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The BPSC TGT Math & Science Mock Test - 7 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for BPSC TGT Math & Science Mock Test - 7 below.
Solutions of BPSC TGT Math & Science Mock Test - 7 questions in English are available as part of our Bihar TGT Exam Mock Test Series 2024 for Bihar PGT/TGT/PRT & BPSC TGT Math & Science Mock Test - 7 solutions in Hindi for Bihar TGT Exam Mock Test Series 2024 course. Download more important topics, notes, lectures and mock test series for Bihar PGT/TGT/PRT Exam by signing up for free. Attempt BPSC TGT Math & Science Mock Test - 7 | 150 questions in 150 minutes | Mock test for Bihar PGT/TGT/PRT preparation | Free important questions MCQ to study Bihar TGT Exam Mock Test Series 2024 for Bihar PGT/TGT/PRT Exam | Download free PDF with solutions
BPSC TGT Math & Science Mock Test - 7 - Question 1

Read the following sentence and choose the correct options below.

Get some sweets _____ coffee for me.

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 1

‘And’ is used to tell more.

BPSC TGT Math & Science Mock Test - 7 - Question 2

Direction: Choose the correct possessive pronoun.

Q. The house belongs to Rachit. It is _________.

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 2

It is his house because it belongs to Rachit (boy).

1 Crore+ students have signed up on EduRev. Have you? Download the App
BPSC TGT Math & Science Mock Test - 7 - Question 3

निम्नलिखित प्रश्न में, चार विकल्पों में से, उस विकल्प का चयन करें जो विलोम शब्द का सबसे अच्छा विकल्प है I

मूक

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 3

सही उत्तर वाचाल है।

Key Points

  • 'मूक' का विलोम शब्द वाचाल है।
  • मूक का अर्थ- गूँगा, मूक वाणी।
  • वाचाल का अर्थ- वाक्पटु।

अन्य विकल्प -

  • बड़ा - छोटा
  • घृणा - प्रेम
  • अचर - चर
BPSC TGT Math & Science Mock Test - 7 - Question 4
निम्नलिखित में से एक 'दूध' का पर्यायवाची शब्द है
Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 4

पीयूष शब्द दूध का पर्यायवाची है।

Key Points

पीयूष

  • पुल्लिंग
    • अमृत, सुधा।

दूध का पर्यायवाची शब्द-

  • दुग्ध, गोरस, क्षीर, दोहज, पय, पीयूष, स्तन्य।
Additional Information

पीयूष के पर्यायवाची-

  • अमिय, अमी, अमृत, सुधा, सोम
  • आबेहयात, देवान्न, देवाहार, जीवनोदक।

जल के पर्यायवाची-

  • वारि, पानी, नीर, सलिल, तोय, उदक
  • अंबु, जीवन, पय, अमृत, मेघपुष्प।

घृत का पर्यायवाची-

  • घी, अमृत, नवनीत।

हलाहल का पर्यायवाची

  • गरल, कालकूट, माहुर, विष, जहर
BPSC TGT Math & Science Mock Test - 7 - Question 5
निम्नलिखित में से कौन सा शब्द पुल्लिंग है ?
Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 5

'बचपन' शब्द पुल्लिंग है। अन्य विकल्प असंगत है। अतः सही उत्तर 'बचपन' होगा।
जैसे - उसका बचपन बीत गया
बातचीत, बनावट और बरसात ये तीनो स्त्रीलिंग के उदाहरण है।

Key Points

BPSC TGT Math & Science Mock Test - 7 - Question 6
इनमें से समष्टि का विलोम शब्द क्या है?
Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 6

सही उत्तर है - ‘व्यष्टि’।

  • समष्टि का विलोम व्यष्टि होगा।
  • समष्टि का अर्थ : सामूहिकता।
  • व्यष्टि का अर्थ : समष्टि का सदस्य या व्यक्ति।

Key Pointsअन्य विकल्प:

  • अस्ति का विलोम : नास्ति
  • विशिष्ट का विलोम : साधारण
  • अशिष्ट का विलोम : शिष्ट

Additional Information

  • किसी शब्द का विलोम शब्द उस शब्द के अर्थ से उल्टा या विपरीत अर्थ वाला होता है।

विलोम शब्द के उदाहरण:-

  • कृतज्ञ - कृतघ्न
  • तुच्छ - महान्
  • प्रगतिशील - प्रतिगामी
  • देव - दानव
BPSC TGT Math & Science Mock Test - 7 - Question 7
दिए गए शब्द का विलोम शब्द ज्ञात कीजिए।
​सामिष
Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 7

उपर्युक्त विकल्पों में से विकल्प 4 ‘निरामिषसही उत्तर है। अन्य विकल्प असंगत हैं।

Key Points

  • 'सामिष' का सही विलोम शब्द 'निरामिष' है।
  • सामिष​ और आमिष का अर्थ – मांस से युक्त।
  • निरामिष​ का अर्थ – मांसरहित। (जो माँस नही खाता)

अन्य विकल्प -

Additional Information

BPSC TGT Math & Science Mock Test - 7 - Question 8
पानी न बरसता तो धान सूख जाता'- यह किस तरह का वाक्य है-
Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 8

'पानी न बरसता तो धान सूख जाता'- यह 'संकेतवाचक वाक्य' है।Key Points

  • संकेतवाचक वाक्य - जिन वाक्यों से संकेत का बोध होता है।
  • उदाहरण - अगर वर्षा होती तो फसल भी अच्छी होती।

Additional Informationअर्थ के आधार पर वाक्य के आठ भेद है।

BPSC TGT Math & Science Mock Test - 7 - Question 9

Direction: Study the following question carefully and choose the right answer.

In a certain code, RAIN is written as 8$%6 and MORE is written as 7#8@. How is REMAIN written in that code?

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 9


Thus, the code for REMAIN is 8@7$%6.
Hence, option D is correct.

BPSC TGT Math & Science Mock Test - 7 - Question 10

The average of 31 numbers is 57. The average of the first 10 numbers is 50 and that of the last 20 numbers is 61. What is the 11th number?

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 10

Last 20 number = 12th to 31st
So remaining is 11th number.
So the answer = 31 × 57 – 10 × 50 – 20 × 61 = 47
Hence, Option D is correct.

BPSC TGT Math & Science Mock Test - 7 - Question 11

A tap can fill a tank of 400 liters in 1 hour. In how many hours can the pipe fill a tank of 1800 liters?

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 11


Hence, Option B is correct.

BPSC TGT Math & Science Mock Test - 7 - Question 12

A ratio equivalent to 3 : 7 is:

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 12

A ratio equivalent to 3 : 7 is:
To find a ratio equivalent to 3 : 7, we need to find a pair of numbers that have the same ratio when simplified. Let's try the options:

(i) 3 : 9 → This simplifies to 1 : 3, not the same as 3 : 7
(ii) 6 : 10 → This simplifies to 3 : 5, not the same as 3 : 7
(iii) 9 : 21 → This simplifies to 3 : 7, which is the same as 3 : 7, so the answer is (iii).

BPSC TGT Math & Science Mock Test - 7 - Question 13

Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

BLOCKED : YOLXPVW :: ? : OZFMXS

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 13

BPSC TGT Math & Science Mock Test - 7 - Question 14

Find the average of 6, 0.06, 66.66, 60.60, 600.60 and 6000?

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 14


Hence, Option B is correct.

BPSC TGT Math & Science Mock Test - 7 - Question 15

On which number of term does 78 falls in the A.P. 3, 8, 13, 18, … is 78?

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 15

Given, 3, 8, 13, 18, … is the AP.
a = 3
d = a(2) – a(1) = 8 − 3 = 5
Let a(n) term be 78.
a(n) = a + (n − 1) x d
78 = 3 + (n − 1) x 5
75 = (n − 1) x 5
(n − 1) = 15
n = 16

BPSC TGT Math & Science Mock Test - 7 - Question 16

34.95 + 240.016 + 23.98 = ?

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 16

BPSC TGT Math & Science Mock Test - 7 - Question 17

If the length, breadth and height of a hall are 20 meters, 10 meters, 20 meters respectively, what is the diagonal of the hall?

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 17

Diagonal of a room = √(l2 + b2 + h2)
So the answer = √(202 + 102 + 202) = √900 = 30 meters
Hence, Option B is correct.

BPSC TGT Math & Science Mock Test - 7 - Question 18

A wooden block weighs 10 N in air and 6 N in water. What is the buoyant force acting on the block?

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 18

The buoyant force is equal to the weight of the fluid displaced by the object. In this case, the block weighs 10 N in air and 6 N in water, indicating that it loses 4 N of weight in water. Therefore, the buoyant force is 6 N, equal to the weight lost in water.

BPSC TGT Math & Science Mock Test - 7 - Question 19
Which city is the capital of Australia?
Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 19
The correct answer is Option D: Canberra. Canberra is the capital of Australia. Be cautious not to confuse it with other cities like Lahore, Mumbai, or Karachi, which are capitals of different countries.
BPSC TGT Math & Science Mock Test - 7 - Question 20

If the sum of the zeroes of the cubic polynomial 4x3−kx2−8x−12 is -3/4  then the value of ‘k’ is

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 20

Let α,β,γ are the zeroes of the given polynomial. Given: α+β+γ = (-3/4)

BPSC TGT Math & Science Mock Test - 7 - Question 21

The line x = 3 is

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 21
Line x=3 has special form - it is not from the same family of lines in the form y=mx+b.

Slope is not defined for a line x=3 because it represents vertical line.

Remember the definition of slope. In common words, it is the value that tells us how much is line increasing/decreasing as we move from left to right on the graph. That is why horizontal lines have zero slope - no increase nor decrease on horizontal line.

Now, imagine vertical line. In only 1 point it increases in infinity. Thus, we cannot use any real value of m to describe this behaviour.
BPSC TGT Math & Science Mock Test - 7 - Question 22

In the given figure, the value of x which makes POQ a straight line is :

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 22

For POQ=straight line →∠ POQ=180o

2x+30+4x=180

6x+30=180

6x=150

x=25o.

BPSC TGT Math & Science Mock Test - 7 - Question 23

If α,β are the zeros of x2 + px + 1 and γ,δ be those of x2 + qx + 1, then the value of (α–γ) (β–γ) (α+δ) (β+δ) = 

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 23

Alpha(a) and beta(b) are roots of x^2 + px + 1

This implies that sum of roots= a+b = -p/1=-p

And the product of roots = ab = 1/1=1

Similarly ,

Gamma(c) and delta(d) are roots of x^2 + qx + 1

So c+d=-q and cd =1.

The above results can be obtained once we know that any quadratic equation has two roots and hence can be written as (x-p)(x-q)=0 where a and b are the roots .

So x^2 -(p+q)x + pq =0

Comparing this with the general form of quadratic equation :ax^2 + bx + c= 0 we get

Sum of the roots =p+q= -b/a

And product of the roots = pq = c/a}
 

RHS=(a-c)(b-c)(a+d)(b+d)

=(c^2-ac-bc +ab)(d^2 +bd +ad + ab)

We know ab=1

So RHS= (c^2-ac-bc +1)(d^2 +bd +ad + 1)

= (c^2)(d^2) +(a+b)c^2(d) + c^2 -(d^2)c(a+b) -(a+b)^2(cd) -(a+b)c + d^2 + bd + ad + 1

= 1 + ac+bc + c^2 - da-db - (a^2 + b^2 + 2(1)) -ac -bc + bd + ad +1

Cancelling off all the common terms,

We get c^2 +d^2-a^2-b^2

= c^2+d^2-a^2-b^2
=c^2 -a^2 + d^2 -b^2 + 2(1) -2(1){ ab=cd =1}
=c^2 + d^2 + 2cd - a^2 - b^2 - 2ab
LHS=(c+d)^2-(a+b)^2
Therefore,
But we know -p= a+b and -q = c+d
LHS= q^2-p^2

BPSC TGT Math & Science Mock Test - 7 - Question 24

If the polynomial 3x2 – x3 – 3x + 5 is divided by another polynomial x – 1 – x2, the remainder comes out to be 3, then quotient polynomial is –

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 24

Let's assume the quotient polynomial as ax + b.

Now, (x - 1 - x^2)(ax + b) + 3 = 3x^2 - x^3 - 3x + 5

ax^3 + bx^2 + ax^2 - ax^2 - bx - a + 3 = -x^3 + 3x^2 - 3x + 5

ax^3 + (b - 1)x^2 + (a - b)x + (3 - a) = -x^3 + 3x^2 - 3x + 5

Equating the coefficients of the same degree terms on both sides, we get:

For x^3: a = -1 For x^2: b - 1 = 3 => b = 4 For x: a - b = -3 => a - 4 = -3 => a = 1 For constant: 3 - a = 5 => a = -2

Therefore, the quotient polynomial is x + 4.

Hence, the quotient polynomial is x + 4.

BPSC TGT Math & Science Mock Test - 7 - Question 25

The difference of a rational and an irrational number is always

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 25

The difference of a rational and an irrational number is always an irrational number.

BPSC TGT Math & Science Mock Test - 7 - Question 26

On a morning walk, three persons step off together and their steps measure 40 cm, 42 cm and 45 cm, respectively. What is the minimum distance each should walk so that each can cover the same distance in complete steps?

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 26

We need to find the L.C.M of 40, 42 and 45 cm to get the required minimum distance.
40 = 2×2×2×5
42 = 2×3×7
45 = 3×3×5
L.C.M. = 2×3×5×2×2×3×7 = 2520

BPSC TGT Math & Science Mock Test - 7 - Question 27

In the figure, ABCD is a rhombus, whose diagonals meet at 0. Find the values of x and y. 

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 27

Since diagonals of a rhombus bisect each other at right angle .

∴ In △AOB , we have 

∠OAB + ∠x + 90° = 180° 

∠x = 180° -  90° - 35° [∵ ∠OAB = 35°]

= 55° 

Also, ∠DAO = ∠BAO = 35°  

∴ ∠y + ∠DAO + ∠BAO + ∠x = 180°  

⇒ ∠y + 35° + 35° + 55° =  180°  

⇒ ∠y = 180° - 125° = 55°

Hence the values of x and y are x =  55°, y =  55°.    

BPSC TGT Math & Science Mock Test - 7 - Question 28

A number is selected at random from the numbers 7, 3, 9, 7, 9, 5, 7, 9, 9, 5. The probability that the selected number is their average is

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 28

Average of given numbers
Number of outcomes = 3
Number of total outcomes = 10
∴ Required Probability = 3/10

BPSC TGT Math & Science Mock Test - 7 - Question 29

Which of the following is false:

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 29

H.C.F.(p,q,r)× L.C.M.(p,q,r) ≠ p×q×r. This condition is only applied on HCF and LCM of two numbers.

BPSC TGT Math & Science Mock Test - 7 - Question 30

What is current I in the circuit as shown in figure?​

Detailed Solution for BPSC TGT Math & Science Mock Test - 7 - Question 30

Three 2Ω resistors are in series. Their total resistance =6Ω. Now it is in parallel with 2Ω resistor, so total resistance,
1/R​=1/2+1/6​=3+1/6​=4/6=2/3
R=3/2​
∴I=RV​=3/(3/2)​=3×2​/3=2A

View more questions
20 tests
Information about BPSC TGT Math & Science Mock Test - 7 Page
In this test you can find the Exam questions for BPSC TGT Math & Science Mock Test - 7 solved & explained in the simplest way possible. Besides giving Questions and answers for BPSC TGT Math & Science Mock Test - 7, EduRev gives you an ample number of Online tests for practice

Top Courses for Bihar PGT/TGT/PRT

Download as PDF

Top Courses for Bihar PGT/TGT/PRT