Bihar PGT/TGT/PRT Exam  >  Bihar PGT/TGT/PRT Tests  >  Bihar PGT Exam Mock Test Series 2024  >  Bihar PGT Mathematics Mock Test - 2 - Bihar PGT/TGT/PRT MCQ

Bihar PGT Mathematics Mock Test - 2 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test Bihar PGT Exam Mock Test Series 2024 - Bihar PGT Mathematics Mock Test - 2

Bihar PGT Mathematics Mock Test - 2 for Bihar PGT/TGT/PRT 2024 is part of Bihar PGT Exam Mock Test Series 2024 preparation. The Bihar PGT Mathematics Mock Test - 2 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar PGT Mathematics Mock Test - 2 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar PGT Mathematics Mock Test - 2 below.
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Bihar PGT Mathematics Mock Test - 2 - Question 1

In the given questions, fill in the blanks with the appropriate words from the alternatives provided.

Q.  _________ contraction is a characteristic of certain groups of skeletal muscle.

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 1

The sentence indicates the contraction of skeletal muscles. Rhythmic contraction would mean a strong, regular pattern of movement or sound, while nonmetrical, arrhythmic, and unrhythmic mean the opposite.
In the above sentence, Rhythmic contraction suits the meaning of the sentence. Thus, option 4 is the correct answer.

Bihar PGT Mathematics Mock Test - 2 - Question 2

क्षीर का तद्भव  शब्द चुनें।

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 2

क्षीर का तद्भव खीर है।

ऐसे शब्द जो संस्कृत से हिंदी में आने पर उनका रूप बदल गया। जैसे - आग, खीर, छत आदि।

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Bihar PGT Mathematics Mock Test - 2 - Question 3

मानव शब्द में प्रत्यय है-

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 3

जो शब्दांश शब्दों के अंत में विशेषता या परिवर्तन ला देते हैं, वे प्रत्यय कहलाते हैं।

जैसे: मानव में अव प्रत्यय है।

Bihar PGT Mathematics Mock Test - 2 - Question 4

सही युग्म पहचानिए-

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 4

दुबला-पतला - लड़का युग्म में लिंग की शुद्धता है।

अन्य शुद्ध युग्म:-

टोपी - काली 

सुनहरा - पत्ता

उड़ती हुई - चिड़िया

Bihar PGT Mathematics Mock Test - 2 - Question 5

Study the following carefully and answer the given question.

Which region denotes singers, who are directors but not actors?

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 5

From the diagram given below:

The shaded part represents the singers, who are directors but not actors.

Hence, the correct answer is "7".

Bihar PGT Mathematics Mock Test - 2 - Question 6

What is the foundation of any democracy?

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 6

The Rule of Law is the essential foundation of democracy. 

  • The Constitution says that the government shall not deny to any person in India equality before the law or the equal protection of the laws.
  • It means that the laws apply in the same manner to all, regardless of a person’s status. This is called the rule of law.
  • Rule of law is the foundation of any democracy. It means that no person is above the law.
  • There cannot be any distinction between a political leader, government official and an ordinary citizen.
  • Every citizen, from the Prime Minister to a small farmer in a remote village, is subjected to the same laws.
  • No person can legally claim any special treatment or privilege just because he or she happens to be an important person. 
    • For example, a few years ago a former Prime Minister of the country faced a court case on charges of cheating.
    • The court finally declared that he was not guilty. But as long as the case continued, he had to go to the court, give evidence and file papers, just like any other citizen.
Bihar PGT Mathematics Mock Test - 2 - Question 7

Among the following, the one with the highest mass is:

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 7

Concept:

  • The laws dealing with ideal gases naturally called ideal gas laws, and the laws determined in the seventeenth century by Boyle's observational work and in the eighteenth century by Charles.
  • The Boyles Law states that the gas pressure is inversely proportional to the gas volume for a given mass of gas stored at a constant temperature.
  • Charles Law states that the gas volume is directly proportional to the gas temperature for a given fixed mass of gas stored at a constant pressure. 
  • An ideal gas is a gas that follows the equation:

PV = nRT at all temperatures and pressure, where P = Pressure of the ideal gas. V = Volume of the ideal gas n = Amount of ideal gas measured in terms of moles 

R = Universal gas constant T = Temperature

Mole Concept -

  •  The quantity one mole of a substance signifies 6.022 × 1023 number of particles of that substance which may be atoms, molecules, or ions.
  • The quantity is a universal constant like Dozen, Gross, etc., and is known as Avogadro number, denoted by NA. after the scientist Amedeo Avogadro.
  • Examples- In one mole of H2, there are 6.022 × 1023 molecules of hydrogen, and the number of atoms is 2 × 6.022 × 1023, as one molecule of hydrogen contains two-atom each.
  • The mass of one mole of a substance is called its Molar Mass (M) or Atomic mass expressed in grams.
  • The volume occupied by a mole of gas is 22.4 L at NTP, called its Molar Volume.
  • The no. of moles (n) is calculated as =

The number of particles / Avogadro’s number.

To summarise, we can say, 

Calculation:

  • The molar mass of 1 mole of H2SO4 is =

2 × 1 + 32 + 4 × 16 = 98g

  • The molar mass of 1 mole of Silver, Ag is its molecular mass 108g.
  • The molar mass of CO2 is = 12 + 2× 16 = 44g.
  • 44g of CO2 means one mole.
  • 1 mole of Oxygen weighs 16 + 16 = 32g.
  • Hence, the highest mass is of 1 mole of Ag.
Bihar PGT Mathematics Mock Test - 2 - Question 8

If 'MANIPUR' is written as 'NBOJQVS', how can 'PATTERN' be written in that code?

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 8

The logic followed is:

Given code: "MANIPUR is written as NBOJQVS

Similarly,

Thus "PATTERN will be written as "QBUUFSO".

Hence, the correct answer is "QBUUFSO". 

Bihar PGT Mathematics Mock Test - 2 - Question 9

Arrange the following events of the French Revolution in chronological order and choose the right answer :

(a) Fall of Bastille

(b) Formation of National Assembly

(c) Establishment of the French Republic

(d) ​Declaration of the Rights of man

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 9

The correct answer is b, a, d, c.

Key Points

  • French Revolution:
    • The French Revolution was a mass movement that shook France and had a far-reaching impact on the world.
    • It was Lasting from 1789 to 1799, it is regarded as one of the most important events in world history.
    • The Revolution began with the rebellion of the Third Estate, which comprised a large majority of the population but was neglected.
    • The representatives of the Third Estate took the Tennis Court Oath on June 20, 1789 pledging not to separate until they had given France a constitution.
    • This was followed by the Storming of the Bastille and the Women’s March on Versailles, incidents through which the Revolution gathered momentum.
    • The execution of King Louis XVI and his wife Marie Antoinette resulted in the Revolution entering its most bloody stage known as the Reign of Terror.
    • A coup, led by Napoleon Bonaparte in 1799 brought an end to the French Revolution with the establishment of a Consulate and later an Empire.
    • Major events and their date of the french revolution:
    • Formation of National Assembly- 13 June 1789
    • Fall of Bastille- 15 July 1789
    • Declaration of the Rights of Man- 26 August 1789
    • Establishment of the French Republic-  21 September 1792

Additional Information

  •  Other major events of the French Revolution and their dates:
Bihar PGT Mathematics Mock Test - 2 - Question 10
Scurvy is caused by the deficiency of which vitamin?
Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 10

The correct answer is Vitamin C.

Important Points

  • Scurvy is a nutritional disorder of humankind.
    • Scurvy is caused by the deficiency of Vitamin C
    • Ascorbic acid is the chemical name of vitamin C.
    • Vitamin C is the first artificially synthesized vitamin.
    • Vitamin C is essential for the healing of wounds, repair, and maintenance of cartilage, bone, and teeth.
    • Vitamin C deteriorated through cooking and canning of food.

Additional Information 

  • Xerophthalmia and night blindness are the deficiency diseases of Vitamin A.
  • Rickets is the deficiency diseases of Vitamin D.
  • Hemorrhage is the deficiency diseases of Vitamin K.
Bihar PGT Mathematics Mock Test - 2 - Question 11

In which hemisphere does India lie?

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 11

The correct answer is option 2 i.e. Northern and Eastern.

  • Any circle drawn around the globe divides the Earth into two equal halves called hemispheres.
  • There are generally considered to be four hemispheres: Northern, Southern, Eastern, and Western.
  • India's main land extends between latitudes 8°4'N and 37°6'N and longitudes 68°7'E and 97°25'E.
  • India is located lattitudinally in the Northern hemisphere, the half of earth that is north of the Equator (0°). 
  • India is located longitudinally in the Eastern hemisphere, the half of earth that is east of the Prime Meridian or the Greenwich Line (0°).

                         

Bihar PGT Mathematics Mock Test - 2 - Question 12

Choose the similar figure in the options.

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 12

The pattern followed is:
Given series:

1. There is a rotation of 90º clockwise in next each step.
2. One similar figure is added next to each step.
The figure which will come next is,

Hence, the correct answer is "Option 3".

Bihar PGT Mathematics Mock Test - 2 - Question 13

Identify the odd one out from the following

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 13

Option C is not a trigonometric identity.

Bihar PGT Mathematics Mock Test - 2 - Question 14

Skew lines are lines in different planes which are

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 14

By definition : The Skew lines are lines in different planes which are neither parallel nor intersecting .

Bihar PGT Mathematics Mock Test - 2 - Question 15

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 15

Since g(x) = |x| is a continuous function and   so f is continuous function. In particular f is continuous at a = 1 and x = 4) f is clearly not differentiable at x = 4) Since g(x) = |x| is not differentiable at x = 0. Now

Bihar PGT Mathematics Mock Test - 2 - Question 16


Then the value of x is ____

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 16


= x+10 = 3x+4
= x = 3

Bihar PGT Mathematics Mock Test - 2 - Question 17

If the rth term in the expansion of  contains x4, then r =

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 17

Bihar PGT Mathematics Mock Test - 2 - Question 18

If z1 = 2 + i, z2 = 1 + 3i, then Re ( z1 - z2) =

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 18

The numbers in the questions are not very clear.
z1 = 2 + i
z2 = 1+3i
z1 – z2 = (2 – 1) + i (1 – 3)
= 1 – 2i

Bihar PGT Mathematics Mock Test - 2 - Question 19

The G.M. of 5 and 8 is

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 19

The geometric mean of two numbers, say x, and y is the square root of their product x * y.
 Mean = [x * y]1/2
= [5 * 8]1/2
= [40]1/2
= 2(10)1/2

Bihar PGT Mathematics Mock Test - 2 - Question 20

The area bounded by the curves y2 = 4x and y = x is equal to

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 20

The two curves y2 = 4x and y = x meet where x2 = 4x i.e ..where x = 0 or x = 4 . Moreover , the parabola lies above the line y = x between x = 0 and x = 4 . Hence , the required are is :

Bihar PGT Mathematics Mock Test - 2 - Question 21

Let f : R → R be a function defined by f(x) = Min {x + 1, |x| + 1}. Then which of the following is true ?

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 21

f(x) = Min {x + 1,∣x∣ + 1}
x = 0 ⇒ ∣x∣ = x
f(x) = min {x + 1,x + 1}
= x + 1
x < 0,∣x∣ = −x
f(x) = min {x + 1,−x + 1}
−x + 1> x + 1
x < 0
⇒x < 0, f(x) = x + 1
x > 0,f (x) = x + 1
⇒ f(x) = x + 1 for all x
∴f(x) is differential everywhere (continuous and constant slope)

Bihar PGT Mathematics Mock Test - 2 - Question 22

If distance between the directrices be thrice the distance between the foci, then eccentricity of ellipse is

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 22

Distance between the directrices is 2a/e
Distance between the foci is 2ae
Given: 2a/e = 3∗2ae
Or,e2 = 1/3
∴ e=1/√3

Bihar PGT Mathematics Mock Test - 2 - Question 23

Domain of f (x) 

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 23

Domain of sin -1x is [-1,1]

Bihar PGT Mathematics Mock Test - 2 - Question 24

A line meets the coordinate axes in A and B, and a circle is circumscribing triangle AOB where O is the origin. If m, n are the distances of the tangents to this circle at the origin from the points A and B respectively, then the diameter of the circle is

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 24

Since AB is the diameter of the circle. 
From figure, 
Also equation of the circle is 

equation of tangent to this circle at (0, 0) is ax + by = 0 ……(1)
∴ m = length of perpendicular from


and n = length of perpendicular from 


Hence (D) is the correct answer.

Bihar PGT Mathematics Mock Test - 2 - Question 25

The point on the straight line x + y = 2, which is nearest to the circle x2 + y2 –10x + 2y + 22 = 0

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 25

Shortest distance between 2 curves occurs along the common normal. Let required point be (t, 2 -t). Normal at this will be y –(2 –t) = (x –t), it should passes through centre of circle so –1 –2 + t = 5 –t ⇒ t = 4, so point can be (4, -2).

Bihar PGT Mathematics Mock Test - 2 - Question 26

Sum of the series S = 12 – 22 + 32 – 42 + ..... – 20022 + 20032 is

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 26

S=12−22+32−42+......−20022+20032

Bihar PGT Mathematics Mock Test - 2 - Question 27

The order of the equation 

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 27

2

Bihar PGT Mathematics Mock Test - 2 - Question 28

L et f : (– 1, 1) → B , be a function defined by  then f is both one - one and onto when B is the interval

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 28



Clearly, range of f (x) 

For f to be onto, codomain = range
∴ Co-domain of function 

Bihar PGT Mathematics Mock Test - 2 - Question 29

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 29

Bihar PGT Mathematics Mock Test - 2 - Question 30

If the harmonic mean between the roots of (5 + √2)x2 - bx + (8 + 2√5) = 0 is 4, then the value of b is

Detailed Solution for Bihar PGT Mathematics Mock Test - 2 - Question 30


given that harmonic mean between the roots of the 
given equation is 4.

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