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Bihar PGT Mathematics Mock Test - 1 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test Bihar PGT Exam Mock Test Series 2024 - Bihar PGT Mathematics Mock Test - 1

Bihar PGT Mathematics Mock Test - 1 for Bihar PGT/TGT/PRT 2024 is part of Bihar PGT Exam Mock Test Series 2024 preparation. The Bihar PGT Mathematics Mock Test - 1 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar PGT Mathematics Mock Test - 1 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar PGT Mathematics Mock Test - 1 below.
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Bihar PGT Mathematics Mock Test - 1 - Question 1

In the following question, an idiomatic expression and its four possible meanings are given. Find out the correct meaning of the idiom.

Q. The project team was working against the clock to get the beta launch done. 

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 1

'Working against the clock' means to do it as fast as possible and try to finish it before a certain time.
Option 4 is hence the correct option.
Example- The students worked against the clock to get their final presentation ready before the committee.

Bihar PGT Mathematics Mock Test - 1 - Question 2

In the following question, four words are given out of which one word is incorrectly spelt. Find the incorrectly spelt word.

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 2

The correct answer is Option 4. The correct spelling is ‘embarrassment’

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Bihar PGT Mathematics Mock Test - 1 - Question 3

In the following question, out of the four alternatives, select the alternative which is the best substitute for the phrase.In the following question, out of the four alternatives, select the alternative which is the best substitute for the phrase.

Q. A person who does not believe in the existence of God.

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 3

Atheist' is a person who strongly disbelieves in the existence of God. Option 3 is thus the correct answer.
All other alternatives have no relation to the given phrase. Stubborn stands for a person who is adamant, bogus is something that is not to be taken seriously and devout is a person who believes in God strongly.

Bihar PGT Mathematics Mock Test - 1 - Question 4

In the following question, out of the four alternatives, select the word similar in meaning to the word given.

Slander

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 4

Slander is to work on lines so as to defame the character and image of a person. Thus, defame is the nearest synonym to slander.   
Example- During elections, there is a fest of defamation between politicians.

Bihar PGT Mathematics Mock Test - 1 - Question 5
सही वर्तनी वाला शब्द है:
Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 5

उपर्युक्त विकल्पों में से 'शुद्ध वर्तनी वाला शब्द 'नीरस' है। 

नीरस के पर्यायवाची शब्द हैं - फीका, बेरस, बेजायका, अस्वाद।

Bihar PGT Mathematics Mock Test - 1 - Question 6

A man walks 30 meters towards South, then turning to his right, he walks 30 meters, then turning to his left, he walks 20 meters, again turning to his left, he walks 30 meters. How far is he from his starting point ?

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 6

A man walks 30 meters towards South, then turning to his right, he walks 30 meters, then turning to his left, he walks 20 meters, again turning to his left, he walks 30 meters. The figure are given below -

50 meters far is he from his starting point.

Hence, "50 meters" is the correct answer.

Bihar PGT Mathematics Mock Test - 1 - Question 7

Select the odd letter from the given alternatives

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 7

The logic is :

1) BEH

2) KNR

3) GJM

4) TWZ

Hence, 'KNR' is the odd letter.

Bihar PGT Mathematics Mock Test - 1 - Question 8

Jatin, born on 05 January 1998, is in final year of Engineering of an Integrated course, with an aggregate of 75% till his 7th semester, he does not have any permanent body tattoos.

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 8

Hence. the person will be allowed to appear in the interview.

Bihar PGT Mathematics Mock Test - 1 - Question 9

Select the number which can be placed at the sign of the question mark (?) from the given alternatives.

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 9

The logic follows here is:

In fig 1:

12 = 6 ÷ 2 × 4

12 = 3 × 4 

12 = 12

In fig 2:

80 = 20 ÷ 2 × 8

80 = 10 × 8

80 = 80

Similarly,

63 = ? ÷ 2 × 21

63 / 21 = ? ÷ 2

3 = ? ÷ 2

? = 3 × 2

? = 6

Hence, the correct answer is "6".

Bihar PGT Mathematics Mock Test - 1 - Question 10

The Tropic of Cancer does NOT pass through which of the following state?

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 10

The correct answer is Odisha.

Key Points

  • The Tropic of Cancer is an imaginary line north from the Equator at an angle of 23.50 degrees.
  • Tropic of Cancer passes through 16 countries, 3 continents, and 6 water bodies.
  • It passes through 8 Indian states.

Additional Information

Bihar PGT Mathematics Mock Test - 1 - Question 11
Five years ago, father's age was 5 times that of his son and after 3 years he will be 3 times as old as his son. Find the present age of son.
Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 11

Given:

Five years ago, father's age was 5 times that of his son

After 3 years father will be 3 times as old as his son

Calculation:

Let the present age of son be x years 

Present age of father be y years 

According to the question,

Five years ago, father's age was 5 times that of his son

(y - 5) = 5 (x - 5)

⇒ y - 5 = 5x - 25 

⇒ y - 5x + 20 = 0     ---- (i)

After 3 years father will be 3 times as old as his son

(y + 3) = 3(x + 3)

⇒ y + 3 = 3x + 9

⇒ y - 3x - 6 = 0      ---- (ii)

Solving equation (i) and (ii) we get,

x = 13

∴ Present age of son is 13 years

Bihar PGT Mathematics Mock Test - 1 - Question 12
Who is the custodian of the Indian Constitution?
Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 12

The correct answer is The Supreme Court.

Key Points 

  • The Supreme Court of India is called the custodian of the Constitution in India.
  • The highest court in India, the Supreme Court is considered as the guardian of the Constitution.
  • The conflicts or quarrels of jurisdiction between the central government and the state governments or between the legislature and the executive are decided by the court.
  • It upholds and uplifts the rule of law and also ensures and protects citizens’ rights and liberties as given in the Constitution.
  • Therefore, the Supreme Court is also known as the Guardian of the Constitution.​

Additional Information 

  • The Indian constitution provides for a provision of the Supreme Court under Part V (The Union) and Chapter 6 (The Union Judiciary).
  • The Supreme Court of India is the highest judicial court and the final court of appeal under the Constitution of India, the highest constitutional court, with the power of judicial review.
  • India is a federal state and has a single and unified judicial system with a three-tier structure, i.e. Supreme Court, High Courts, and Subordinate Courts.
Bihar PGT Mathematics Mock Test - 1 - Question 13

Excessive consumption of alcoholic drinks causes damage to the

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 13

The correct answer is Liver.

Key Points

  • Excessive consumption of alcoholic drinks causes damage to the Liver.
    • Alcohol is readily absorbed from the digestive tract, and up to 98% is metabolised in the liver.
    • Each liver cell contains three pathways for alcohol metabolism.
    • All of these result in the production of a highly toxic metabolite which can contribute to liver cell damage.
    • With regular alcohol use, the regenerative ability of liver cells may be inhibited and lead to sustained liver damage.
    • Long term heavy alcohol use may lead to fat accumulation in the liver, which may progress to alcoholic hepatitis, or liver cirrhosis.
    • Over time, excessive alcohol use can lead to the development of chronic diseases and other serious problems including -
      • High blood pressure, heart disease, stroke, liver disease, and digestive problems. 

Additional Information

  • Kidney:
    • Healthy kidneys remove wastes and extra fluid from your blood.
    • But when your kidneys fail, wastes and extra fluid can build up in your blood and make you feel sick. 
    • Kidneys can become damaged from a physical injury or a disease like diabetes, high blood pressure, or other disorders.
    • High blood pressure and diabetes are the two most common causes of kidney failure.
    • Kidney failure does not happen overnight.
  • Lungs:
    • Chronic alcohol abuse and heavy drinking can greatly increase the risk of several pulmonary conditions.
      • including lung disease, alcoholic pneumonia, acute lung injury, and acute respiratory distress syndrome.
    • Smokers are more likely than nonsmokers to develop heart disease, stroke, and lung cancer.
      • Smoking can cause lung disease by damaging your airways and the small air sacs (alveoli) found in your lungs.
      • Lung diseases caused by smoking include COPD, which includes emphysema and chronic bronchitis.
  • Heart:
    • Smokers are at greater risk for diseases that affect the heart and blood vessels.
    • Increases in your blood pressure can also be caused by weight gain from excessive drinking.
    • Heavy drinking weakens the heart muscle, which means the heart can't pump blood as efficiently.
      • It's is known as cardiomyopathy and can cause death, usually through heart failure.
Bihar PGT Mathematics Mock Test - 1 - Question 14

Two dice are thrown simultaneously and the sum of the numbers appearing on them is noted. What is the probability that the sum is 12?

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 14

Given:

No of possible outcomes when two dice are thrown simultaneously: 6 × 6 = 36 

(1,1), (1, 2), (1, 3),  (1, 4), (1, 5), (1, 6) 

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) 

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) 

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

Formula used:

Probability = No of favorable outcome ÷ No of total outcomes 

Calculation:

No of outcome with sum 12 (6, 6) = 1

∴ Required probability = 1/36 

Bihar PGT Mathematics Mock Test - 1 - Question 15

Which one of the following places receives the highest rainfall in the world?

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 15

The correct answer is Mawsynram.

Key Points

  • The highest rainfall in India and the world is recorded at Mawsynram village of Meghalaya.
  • It is also known as the land of clouds.
  • Mawsynram is a village located in the East Khasi Hills in the district of Meghalaya state in northeastern India, which is 65 kilometres from Shillong.
  • Mawsynram receives approximately 11,872 millimetres of rain in an average year.
  • The main majority of rains is during the monsoon season.
  • Basically, due to the high altitude, it rarely gets truly hot in Mawsynram.
  • 14,234 mm is the recorded rainfall in the year 2010.
  • According to the Guinness Book of World Records, Mawsynram received 26,000 millimetres (1,000 in) of rainfall in 1985.

Additional Information 

  • The second rainiest place is Cherrapunji, which is also located in Meghalaya.
  • Here the average annual rainfall is around 11,430 mm (450 in) per year.
  • India is a vast country in geographical terms, with various regions experiences very different climatic conditions.
  • This is also reflected in the distribution of rainfall in India. Some regions experience very high rainfall and others receive very scanty rainfall.
  • The difference between the recorded highest and lowest rainfall in India is approximately 1178 cm.

Bihar PGT Mathematics Mock Test - 1 - Question 16

In a triangle ABC if A = π/4 and tanB tanC = K, then K must satisfy. 

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 16

In a ΔABC, we know that
tanA + tanB + tanC = tanA tanB tanC
∴ tanB + tanC = tanA(tanBtanC – 1) 


⇒ tan2 B - (K - 1) tan B + K = 0
For real values of tan B, Disc.
(K – 1)2 – 4K > 0 
K2 – 6K + 1 >

Bihar PGT Mathematics Mock Test - 1 - Question 17

 where [x] is the greatest integer function. The function f (x) is

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 17

Bihar PGT Mathematics Mock Test - 1 - Question 18

sin (n+1)x cos(n+2)x - cos(n+1)x sin(n+2)x =

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 18

sin(n+1)x cos(n+2)x - cos(n+1)x sin(n+2)x
⇒ sin[(n+1)x - (n+2)x] 
As we know that sin(A-B) = sinA cosB - cosA sinB
⇒ sin(n+1-n-2)
sin(-x) 
= -sinx

Bihar PGT Mathematics Mock Test - 1 - Question 19

The function f (x) = x + cos x

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 19

f(x) = x
g(x) = cosx 
D(f) = R
D(g) = R
D(f+g) = D(f) ⋂ D(g)
So , D(f+g) = R
Therefore, given function is defined for real numbers.

Bihar PGT Mathematics Mock Test - 1 - Question 20

If a differentiable function f (x) has a relative minimum at x = 0, then the function y = f (x) + a x + b has a relative minimum at x = 0 for

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 20


And y has a relative minimum at x = 0 if f ‘(0)+a = 0 . a =0.

Bihar PGT Mathematics Mock Test - 1 - Question 21

The function  is

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 21

Solution we know that if f(t) is an odd function the  dt is given integral since   is odd, the given integral is even

Bihar PGT Mathematics Mock Test - 1 - Question 22

 is equal to 

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 22

We have:
limx→0 ln(1+ax)]/x=a
lim x→0 ln(1+ax)/ax=a
and then:
lim x→0 [ln(1+ax)-ln(1+bx)]/x
= a-b

Bihar PGT Mathematics Mock Test - 1 - Question 23

A lady wants to select one cotton saree and one polyster saree from a textile shop. If there are 15 cotton and 13 polyster varieties in that shop, in how many ways can she pick up two sarees?

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 23

The lady can select one cotton saree out of 15 cotton varieties in 15 ways since
any of 15 varieties can be selected. Corresponding to each selection of a cotton saree, she can
choose a polyester saree in 13 ways. Hence the two sarees (one cotton and one polyester), by
multiplication principle of counting, can be selected in 15 x 13= 195 ways

Bihar PGT Mathematics Mock Test - 1 - Question 24

If A = {1, 3, 4} and B = {1, 4, 3, 2} then which of the following is true?

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 24

All the elements in set-A are presented in set-B. So "A" is a subset of "B".

Bihar PGT Mathematics Mock Test - 1 - Question 25

If f : R → R be a differentiable function, such that f (x + 2y) = f (x) + f (2y) + 4xy for all x, y ∈ R then

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 25

f (x + 2y) = f (x) + f (2 y) + 4xy for x, y ∈ R putting x = y = 0, we get f (0) = 0

Bihar PGT Mathematics Mock Test - 1 - Question 26

The shaded region in the given figure is:
 

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 26
  • (A - B) is A but not B which means A excluding the intersection of A and B.
  • Similarly, in the figure, the shaded region is A but not C and B which means A excluding B and C. But if B and C both are excluded from A then the intersection of A, B and C get excluded two times.
  • So, we take B ∪ C to be excluded from A. Therefore the answer is A - (B ∪ C).
Bihar PGT Mathematics Mock Test - 1 - Question 27

For any two non-zero complex numbers z1 and z2 if then the difference of amplitudes of z1 and z2 is      

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 27







Bihar PGT Mathematics Mock Test - 1 - Question 28

If  + ...... up to ∞ =, then  + ..... =

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 28

(1/12 + 1/22 + 1/32 + ........∞) = π2/6
⇒ (1/12 + 1/32 + 1/52 + ........∞) + (1/22 + 1/42 + 1/62 + ........∞) = π2/6
=> (1/12 + 1/32 + 1/52 + ........∞) + 1/22(1/12 + 1/22 + 1/32 + ........∞) = π2/6
=> (1/12 + 1/32 + 1/52 + ........∞) + 1/222/6) = π2/6
=> (1/12 + 1/32 + 1/52 + ........∞) + π2/24 = π2/6
= π2/8

Bihar PGT Mathematics Mock Test - 1 - Question 29

Find the equation of the circle passing through (–2, 14) and concentric with the circle x2 + y2 - 6x - 4y -12 = 0.

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 29

Let the required circle is x2 + y2 - 6x - 4y + k = 0 and it is passing through (-2, 14)

Bihar PGT Mathematics Mock Test - 1 - Question 30

If 2tan−1(cos x) = tan−1(2cosec x) , then x =

Detailed Solution for Bihar PGT Mathematics Mock Test - 1 - Question 30

If 2 tan-1 (cos x) = tan -1(2 cosec x),

2tan-1(cos x) = tan-1 (2 cosec x)

= tan-1(2 cosec x) 

= cot x cosec x = cosec x = x = π/4

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