Bihar STET Paper 2 Chemistry Mock Test - 1 - Bihar PGT/TGT/PRT MCQ

In A one and more different types of ligands are present.

Molarity is temperature dependent. In the formula of molarity, you have L of solution. Volume is temperature-dependent. It varies with changing temperature. Because of this, molarity changes if the temp changes. 

• Ionic solids or compounds are formed by the transfer of electrons from one atom to another atom.
• Hence there is always the formation of anion and cation due to opposite charges electrostatic force of attraction formed between them which holds them together.

Therefore, the correct answer is B. 

Depression in freezing point is a colligative property but freezing point is not a colligative property.

∆H_Vap = 30kJ/mol and ∆S = 75 J/K
∆G = ∆H - T∆S
At eqm, ∆G = 0
Therefore, ∆H = T∆S
Or T = 30×10³/75 = 400 K

conc. of N₂O₄ = 4.8 × 10^–2 mol/lit
NO₂ = 1.2 × 10^–2 mol/lit

The correct answer is Option C.

Lyophobic colloid is a colloidal dispersion whereby the dispersed phase is solvent hating .i.e little interaction between the dispersed phase and the continuous phase. Lyophobic colloidal particles are not readily solvated because the continuous phase prefers to interact with one another rather than be involved in solvating the dispersed particles. 
Casein (a milk protein), a lyophobic colloid present in milk acts as an emulsifying agent as it forms a protective layer around fat molecules dispersed in water. It is found in milk as a suspension of particles called "casein micelles" which show only limited resemblance with surfactant-type micelle in a sense that the hydrophilic parts reside at the surface and they are spherical.
 

∆H = (B.E)_reactant - (B.E)_product
117.36 = 716.682 + 2(278.805) - ∆H_2C=S
∆H _2C=S = 1156.932
∆H_C=S = 1156.932/2 = 578.74 kJ mol^-1

A slightly weaker base (NaHCO₃) is used in the second step S_N2 reaction otherwise oxirane formation would be preferred.

because of presence of lp of electron on head of oxygen atom the bond angle in water deviates from standard bond angle of 109.8⁰ . bond angle in water is 104.5⁰

The symbol represents enthalpy of combustion which is always exothermic. For exothermic rxn delta H is always -ve. 

Si,P,C,N

Electronegativity increases along a period and decreases down the group.Nitrogen is expected to have maximum electronegativity.

 (a) van’t Hoff factor (i) = [1 + (n - 1)α] where, n = number of ions from one mole of solute

α = degree of ionisation/association 

Maximum oxidation number of Cl = + 7

Thus, species with + 7 oxidation number can be reduced but not oxidised.

Soda ash is Na₂CO₃.

Molecularity is defined as the number of molecules, atoms, or radicals that must collide simultaneously in order for the reaction to take place. It is always a natural number and cannot be negative.

In solid state, N₂O₅ exists as nitronium nitrate 
In   nitrogen is sp and in  , nitrogen is sp².

(d) Depression in freezing poin t is a colligative property.

Thus, (i) -> (r) (ii) -+ (p) (iii) -4 (s) (iv) -> (q)

Ferromagnetic substance get permanently magnetised in applied Magnetic Field.

To complete octet, N shares 2 electrons and oxygen shares 3 electrons.

Thus, (a) is correct.

To have confidence that a test is valid, and thus the inferences we make based on the test scores are valid, three kinds of validity evidence are:

Construct- It is the extent to which the content of the test matches the instructional objectives.

Criterion- It is the extent to which scores on the test are in agreement with or predict an external criterion.

Content- It is the extent to which an assessment corresponds to other variables, as predicted by some rationale or theory.

Tape recorder can be used as a teaching aid by primary class teachers to teach the sounds of birds and animals to the students, make them learn rhymes, or make them hear important historical speeches.

The triarchic theory of intelligence is also called the three forms of intelligence. Based on this theory, research on human intelligence take a more cognitive approach. 
Sternberg explained only three types of intelligence: Componential or analytical sub theory, Experiential or creative sub theory, and Contextual or practical sub theory. 
Hence, the correct answer is, 'Social.'

Key Points 

• The curricular and pedagogical structure and the curricular framework for school education will therefore be guided by a 5 + 3 + 3 + 4 design, consisting of the stages:
  • Foundational (3 years of preschool + Grades 1-2):- The Foundational Stage will consist of play/activity-based learning. It will also include a focus on good behavior, courtesy, ethics, personal and public hygiene/cleanliness, teamwork, cooperation, etc. 
  • Preparatory (Grades 3- 5):-  The Preparatory Stage will transition gradually from play-based learning to more formal but interactive classroom learning, with the introduction of some (light) textbooks, in order to lay a solid groundwork across subjects, including reading, writing, speaking, physical education, art, languages, science, and mathematics.
  • Middle (Grades 6-8):- The Middle Stage will see the introduction of subject teachers for learning/discussion of the more abstract concepts in each subject that students will be ready for at this stage, across the sciences, mathematics, arts, social sciences, and humanities.
  • High school (Grades 9-12 in two phases, i.e. 9 and 10 in the first and 11 and 12 in the second) stages respectively, with an option of exiting at Class 10 and re-entering in the next phase:- The High School (or Secondary) Stage will comprise of four years of multidisciplinary study, building on the subject-oriented pedagogical and curricular style of the Middle Stage, but with greater depth, greater critical thinking, greater attention to life aspirations, and greater flexibility and student choice.

Thus, it is concluded that Primary classes (Classes I to V) will consist of  Preparatory and  Foundational Stages according to NEP, 2020.

Let AB be the building and the man is standing at A.

When the car is 200m away from the building, the angle of depression is 60°

tan 60° = BD/AB = √3

⇒ 200/AB = √3

⇒ AB = 115.47 m

⇒ tan30° =BC/AB = x/115.47 = 1/√3

⇒ x = 66.67

Now, the car travels distance CD in 8 seconds

 CD = BD – BC = 200 – 66.67 = 133.33 m

 Speed = 133.33/8 = 16.67 m/s