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Bihar STET Paper 1 Mathematics Mock Test - 5 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test Bihar STET Mock Test Series 2024 - Bihar STET Paper 1 Mathematics Mock Test - 5

Bihar STET Paper 1 Mathematics Mock Test - 5 for Bihar PGT/TGT/PRT 2024 is part of Bihar STET Mock Test Series 2024 preparation. The Bihar STET Paper 1 Mathematics Mock Test - 5 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar STET Paper 1 Mathematics Mock Test - 5 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar STET Paper 1 Mathematics Mock Test - 5 below.
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Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 1

Direction: Child labour refers to any work or activity that deprives children of their childhood. It is a violation of children's rights. This can harm them mentally or physically. It also exposes them to hazardous situations or stop them from going to school. Naman got data on number of child labours (in million) in different country that is given below.

Q. Name the countries having more than 4 million child labour?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 1
India and Bangladesh having more than 4 million child labour.
Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 2

Directions: In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Mark the correct choice as:

Assertion: If the product of the zeroes of the quadratic polynomial x2+3x+5k is -10 then value of k is -2.
Reason: Sum of zeroes of a quadratic polynomial ax2+bx+c is -b/a

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 2

Both the assertion and the reason are true, but the reason provided is related to the sum of the zeroes, not their product. The correct explanation involves the formula for the product of the zeroes of a quadratic polynomial, c/a, which would lead to 5k/−10, hence determining the value of k.

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Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 3

If the bisector of the exterior vertical angle of a triangle is parallel to the base, then it is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 3
∠CAE is the external vertical angle and AD is its bisector.

∴ ∠CAD = ∠DAE  .... (i)

As, AD || BC

∴ ∠CAD = ∠ACB  .... (ii)  (alternate angle)

and ∠DAE = ∠ABC  ....(iii)  (corresponding angle)

From (i), (ii) and (iii),

∠ABC = ∠ACB

∴ AC = AB  (opposite sides to equal angles)

Hence, ΔABC is isosceles.
Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 4

If (α + β) = 90°, then the value of  

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 4


Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 5

Factorise : 8a3+ b3 + 12a2b + 6a b2

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 5

8a3 + b3+ 12a2b + 6ab2
8a3 + b3+ 12a2b + 6ab2
= (2a)3 + (b)3 + 3(2a)(b) (2a + b)
= (2a + b)3 | Using Identity VI
= (2a + b)(2a + b)(2a + b)

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 6

The given figures show two congruent circles with centre O and O’. Arc AXB subtends an angle of 75o at the centre and arc A’YB’ subtends an angle of 25o at the centre O’. Then, the ratio of arcs AXB to A ‘YB’ is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 6

Because the circles are congruent, therefore their radius are same

Length of arc AXB = [θ/(360°)] × 2πr = [(75°)/(360°)] × 2πr

Length of arc A’YB’ = [θ/(360°)] × 2πr = [(25°)/(360°)] × 2πr

Required Ratio = ([(75°)/(360°)] × 2πr) : ([(25°)/(360°)] × 2πr) = 3 : 1

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 7

If the graph of a polynomial intersects the x – axis at three points, then the number of zeroes =

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 7

If the graph of a polynomial intersects the x-axis at three points, then the number of zeroes are 3 because number of zeroes of the polynomial are the number of the coordinates of the points where its graph intersects the x-axis.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 8

The angle which is equal to 8 times its complement is :

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 8
Complement angle of 80 degree is 10 degree (90-80), which gives 80 degree when multlipied by 8.
Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 9

In the figure, O and O' are centres of two circles intersecting at B aand C. ACD is a straight line, find x.

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 9

In the figure, two circle with centers O and O' intersect each other at B and C.

ACD is a line, ∠AOB=130

Arc AB subtends ∠AOB at the centre O and ∠ACB at the remaining part of the circle.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 10

Divide 16 into two parts such that twice the square of the larger part exceeds the square of the smaller part by 164.​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 10

Let x and (16 - x) are two parts of 16 where (16 - x) is longer and x is smaller .
A/C to question,
2 × square of longer = square of smaller + 164
⇒ 2 × (16 - x)² = x² + 164
⇒ 2 × (256 + x² - 32x ) = x² + 164
⇒ 512 + 2x² - 64x = x² + 164
⇒ x² - 64x + 512 - 164 = 0
⇒ x² - 64x + 348 = 0
⇒x² - 58x - 6x + 348 = 0
⇒ x(x - 58) - 6(x - 58) = 0
⇒(x - 6)(x - 58) = 0
⇒ x = 6 and 58

But x ≠ 58 because x < 16
so, x = 6 and 16 - x = 10

Hence, answer is 6 and 10.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 11

Direction: In the following questions, a statement of Assertion is given followed by a corresponding statement of Reason just below it. Of the statements, mark the correct answer as

Assertion : Given a circle of radius r and with centre O. A point P lies in a plane such that OP > r then point P lies on the exterior of the circle.

Reason : The region between an arc and the two radii, joining the centre of the end points of the arc, is called a sector.

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 11
A sector is region which lies between an arc and two radii joining the extremities of the arc and the centre.

The shaded region denotes the sector of a circle. The unshaded part is also a sector.

Notice that it is enclosed by two radii and an arc.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 12

If bisectors of ∠A and ∠B of a quadrilateral ABCD intersect each other at P, of ∠B and ∠C at Q, of ∠C and ∠D at R and of ∠D and ∠A at S, then PQRS is a

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 12

To show: ∠PSR + ∠PQR = 180°
∠SPQ + ∠SRQ = 180°

In △DSA,

∠DAS + ∠ADS + ∠DSA = 180° (angle sum property)

+ ∠ SA = 180° (since RD and AP are bisectors of ∠D and ∠A)

∠DSA = 180°
∠PSR = 180°−

(∵ ∠DSA = ∠PSR are vertically opposite angles)

Similarly,

∠PQR = 180°− 


Adding (i) and (ii), we get, ∠PSR + ∠PQR = 180°
=360° − 1/2 ​× (∠A + ∠B + ∠C + ∠D)
 

=360°− 1/2​ × 360° = 180° ∴ ∠PSR + ∠PQR = 180°

In quadrilateral PQRS,

∠SPQ + ∠SRQ + ∠PSR + ∠PQR = 360°
=> ∠SPQ + ∠SRQ + 180° = 360°
=> ∠SPQ + ∠SRQ = 180°

Hence, showed that opposite angles of PQRS are supplementary.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 13

Read the following text and answer the following question on the basis of the same:

Authority wants to construct a slide in a city park for children. The slide was to be constructed for children below the age of 12 years. Authority prefers the top of the slide at a height of 4 m above the ground and inclined at an angle of 30° to the ground.

Q. The distance of AB is :

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 13

We have,

∠B = 30° and AC = 4 m

sinθ=p/h or perpendicular/hypotenuse [perpendicular = side directly in front of θ ]

Then, sin 30° = AC / AB

⇒ 1 / 2 = 4 / AB

⇒ AB = 8 m.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 14

The nature of the roots of the equation x2 – 5x + 7 = 0 is –

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 14

Given equation is x2-5x+7=0
We have discriminant as b2-4ac=(-5)2-4*1*7= -3
And x = , Since we do not have any real number which is a root of a negative number, the roots are not real.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 15

From an A.P. 5 consecutive terms are required to be written. The central term out of the five terms is given as 5 and it’s informed that the common difference of the A.P. is 4. Write the 5 terms in the correct sequence.​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 15

AP is:  a,a+d,a+2d,a+3d,a+4d
Middle term is a+2d=5
d=4
a+2d=5
a+2*4=5
a=5-8= -3
a+d= -3+4=1
a+3d= -3+3*4=-3+12=9
a+4d= -3+4*4= -3+16=13
So the terms are : -3,1,5,9,13

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 16

a2 + b2 is equal to​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 16

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 17

In the given figure, AB = EF, BC = DE, AB ⊥ BD and EF ⊥ CE. Which of the following criterion is true for ΔABD ≅ ΔEFC?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 17

In triangle ABD and FEC:
► AB = FE ( given )
► ∠FEC = ∠ABD ( 90degree)
► BC = DE
CD is common part coming in both triangles.
► BC + CD = CD + DE
► BD = CE
Therefore, triangle ABD is congruent to triangle FEC by SAS rule of congruence.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 18

The largest number which divides 70 and 125, leaving remainders 5 and 8 respectively, is      

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 18

 Since, 5 and 8 are the remainders of 70 and 125, respectively. Thus, after subtracting these remainders from the numbers, we have the numbers 65 = (70-5),
117 = (125 – 8), which is divisible by the required number.
Now, required number = HCF of 65,117                                     [for the largest number]
For this, 117 = 65 × 1 + 52 [∵ dividend = divisior × quotient + remainder]
⇒ 65 = 52 × 1 + 13
⇒ 52 = 13 × 4 + 0
∴ HCF = 13 
Hence, 13 is the largest number which divides 70 and 125, leaving remainders 5 and 8.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 19

The number of zeros of a cubic polynomial is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 19

A polynomial of degree 3 is called a cubic polynomial. 

For example, x3−1, 4a− 100a+ a − 6, and m2n + mn2 are all cubic polynomials with atmost 3 zeroes (having degree 3).

Hence, the polynomial having atmost 3 zero is a cubic polynomial.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 20
Generally speaking, teaching aptitude implies –
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 20

Teaching aptitude refers to have a deep interest in transferring knowledge and making students learn specific skills by giving primacy to their needs and experiences.

Key Points

Generally speaking, teaching implies:

  • keen desire to teach.
  • dedication towards teaching.
  • possessing an ability to teach.
  • interest in the teaching work orientation.
  • specific ability and potentiality in teaching profession.
  • intrinsic motivation towards the teaching-learning process.

Hence, it could be concluded that all options are true in the context of teaching aptitude.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 21

A teacher needs to ensure that all the learners in her class feel accepted and valued. To do this, the teacher should

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 21

A teacher needs to ensure that all the learners in her class feel accepted and valued. To do this, the teacher should get to know the social and cultural backgrounds of her students, and encourage diverse opinions in the class. The teachers must encourage students to research and share information about their ethnic background as a means of fostering a trusting relationship with fellow classmates. She should analyze and celebrate differences in traditions, beliefs, and social behaviors. This makes students realize that their beliefs and traditions constitute a culture as well, which is a necessary breakthrough in the development of a truly culturally responsive classroom.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 22

While making a lesson plan, Mrs Sharma should always decide upon:
a. The needs of learners
b. Evaluation process
c. Personal interaction with learners

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 22

Lesson planning should be based on both, the needs of the learners and the process for evaluation to be followed. The content should be presented in such a way that it fulfils the student's academic needs. The process of the evaluation must be decided beforehand, so that the teacher understands how much learning has taken place. Different kinds of evaluation processes could be used, depending upon the learning objectives.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 23

How does NEP 2020 address the issue of early dropouts from school?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 23

NEP 2020 proposes mandatory school attendance for all students until the age of 16 to reduce early dropouts.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 24

According to NEP 2020, what is the role of school counselors?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 24

NEP 2020 recognizes the role of school counselors in providing mental health support to students.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 25
The highest production and largest reserves of manganese ore lies in the state
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 25

The correct answer is Odisha.

Key Points

  • India is the world's fifth-largest producer of manganese after China, Gabon, South Africa, and Australia.
  • Manganese is not found as a free element in nature. It is usually found in combination with iron.
  • The most important manganese ore is pyrolusite.
  • Manganese is primarily used in the iron and steel industry.
  • It is the essential raw material for manufacturing steel alloys.
  • 6 kilograms of manganese ore is required for manufacturing one tonne of steel.
  • State-wise reserves of Manganese:
    • Odisha (44%),
    • Karnataka (22%),
    • Madhya Pradesh (13%), etc.
Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 26

Which country is the host of ‘Asia-Pacific Leaders’ Conclave on Malaria Elimination’?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 26

The ‘Asia-Pacific Leaders’ Conclave on Malaria Elimination’ will be organized in New Delhi by the Union Ministry of Health and Family Welfare in partnership with the Asia Pacific Leaders Malaria Alliance (APLMA) as a precursor to World Malaria Day.
Its goal is to reaffirm political commitment to achieve malaria elimination by 2030.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 27

Recently, the naval forces of which three countries launched a joint exercise near the Gulf of Oman?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 27

The naval forces of China, Iran, and Russia recently launched a joint exercise called the “Maritime Security Belt-2024” near the Gulf of Oman. The exercise, which began on March 11 and lasted until 15, is the fifth common military exercise between the three countries in recent years. The exercise aims to safeguard regional maritime security and strengthen maritime cooperation. The exercise is organized in three phases: harbor, sea, and summarize. The exercise focuses on anti-piracy and search and rescue training courses, and includes the participation of Russian warships and aviation.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 28

Directions: Answer the following question by selecting the most appropriate option.
When did Supreme Court of India ordered Ministry of Environment and Forest to establish a special division to develop a green belt around Taj Mahal?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 28

In 1994, Supreme Court of India ordered Ministry of Environment and Forest to establish a special division to develop a green belt around Taj Mahal.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 29

In a certain code language, 518 means 'Evening is good', 714 means 'Star is beautiful', 834 means 'Evening was beautiful'. Find the code for 'was'.

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 29

The above information can be summarized below diagram,

Therefore, the code for “was” will be “3”. 

Hence, option 4 is the correct answer.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 30
If x + y + 1 = 0, then x3 + y3 - 3xy = ?
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 30

Given:

x + y + 1 = 0

Concept Used:

(a + b )3 = a3 + b3 + 3ab (a + b)

Calculations:

x + y + 1 = 0

⇒ x + y = -1

Cubing on both sides we get

(x + y)3 = ( -1 )3

⇒ x3 + y3 + 3xy( x + y ) = -1

⇒ x3 + y3 + 3xy ( -1) = -1

∵ x + y = -1

⇒ x3 + y3 - 3xy = -1

∴ required value = -1

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