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NVS PGT Mathematics Mock Test - 7 - NVS TGT/PGT MCQ


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30 Questions MCQ Test NVS PGT Mock Test Series 2025 - NVS PGT Mathematics Mock Test - 7

NVS PGT Mathematics Mock Test - 7 for NVS TGT/PGT 2024 is part of NVS PGT Mock Test Series 2025 preparation. The NVS PGT Mathematics Mock Test - 7 questions and answers have been prepared according to the NVS TGT/PGT exam syllabus.The NVS PGT Mathematics Mock Test - 7 MCQs are made for NVS TGT/PGT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for NVS PGT Mathematics Mock Test - 7 below.
Solutions of NVS PGT Mathematics Mock Test - 7 questions in English are available as part of our NVS PGT Mock Test Series 2025 for NVS TGT/PGT & NVS PGT Mathematics Mock Test - 7 solutions in Hindi for NVS PGT Mock Test Series 2025 course. Download more important topics, notes, lectures and mock test series for NVS TGT/PGT Exam by signing up for free. Attempt NVS PGT Mathematics Mock Test - 7 | 150 questions in 180 minutes | Mock test for NVS TGT/PGT preparation | Free important questions MCQ to study NVS PGT Mock Test Series 2025 for NVS TGT/PGT Exam | Download free PDF with solutions
NVS PGT Mathematics Mock Test - 7 - Question 1

Who started the Sufi sect in India?

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 1

The correct answer is Khwaja Moinuddin Chishti.

Key Points

  • Khwaja Moinuddin Chishti came to India in 1192 CE and afterwards, he started the Sufi sect in India.
  • After visiting many places in India, he settled permanently in Ajmer.
  • The tomb of Khwaja Moinuddin Chishti in Ajmer is known as Ajmer Sharif’.
  • His disciples or devotees recall him by the names of ‘Khwaja Sahib’ or ‘Garib Nawaz’.
  • Chishti sect considers music as the important source of displaying love for God. 

Thus, we can conclude that the Sufi sect was started by Khwaja Moinuddin Chishti.

Additional Information

  • Baba Farid was a Sunni Muslim and was one of the founding fathers of the Chishti Sufi order.
  • Shaikh Nuruddin, also known as Nund Rishi was a Kashmiri Sufi saint, mystic, poet and Islamic preacher. Nund Reshi was among the founders of the Rishi order, a Sufi tradition of the region.
  • Amir Khusro was an Indo-Persian Sufi singer, musician, poet and scholar who lived under the Delhi Sultanate. He was an iconic figure in the cultural history of the Indian subcontinent.
NVS PGT Mathematics Mock Test - 7 - Question 2

The capital of _________ is Kohima.

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 2

The correct answer is Nagaland.

  • Kohima is the capital of Nagaland.

Key Points

  • In 1963, the State of Nagaland was formed by taking the Naga Hills and Tuensang area out of the state of Assam.
  • Nagaland shares its International border with Myanmar.
  • Nagaland shares its borders with Arunachal Pradesh, Manipur, and Assam.
  • Neiphiu Rio is the current Chief Minister of the state.

Additional Information

  • Gangtok is the capital of Sikkim.
  • Shillong is the capital of Meghalaya.
  • Agartala is the capital of Tripura.
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NVS PGT Mathematics Mock Test - 7 - Question 3

Select the Venn diagram that best represents the relationship between the following classes.

Crockery, Plate, Bowl

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 3

The Venn diagram that best represents the relationship between Crockery, Plate, and Bowl is shown below:

Bowl and Plate are name of Crockery items.

Hence, ‘option 3’ is the correct answer.

NVS PGT Mathematics Mock Test - 7 - Question 4

From the given alternatives, select the word which CANNOT be formed using the letters of the given word.

SKATEBOARD

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 4

1) DARKEST – SKATEBOARD (Can be formed)

2) ABROAD – SKATEBOARD (Can be formed)

3) STRIKE – SKATEBOARD (Cannot be formed because I is missing)

4) BEAST – SKATEBOARD (Can be formed)

Hence, the correct answer is “STRIKE”.

NVS PGT Mathematics Mock Test - 7 - Question 5
The average of 40 numbers is calculated as 25. But later, it is found that 3 numbers 23, 25, and 41 are mistakenly written as 32, 52, and 15 respectively. Find the correct average of numbers.
Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 5

GIVEN:

The average of 40 numbers = 25

CONCEPT:

Basic Average concept.

FORMULA USED:

Average = Sum of all numbers/Total numbers

CALCULATION:

Sum of numbers = 40 × 25 = 1000

23, 25 and 41 are mistakenly written as 32, 52 and 15 respectively.

⇒ Change in sum = (23 + 25 + 41) – (32 + 52 + 15)

= 89 – 99

= -10

Actual sum of numbers will be 10 less.

⇒ Sum of numbers = 1000 – 10 = 990

∴ Correct average = 990/40 = 24.75

NVS PGT Mathematics Mock Test - 7 - Question 6

Manav born on 03 December 1999, is in final year of Engineering of a Regular Course, with an aggregate of 75% till his 5th semester, he has permanent body tattoo on his inner face of forearm.

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 6

Hence, the person does not satisfy all the conditions.

NVS PGT Mathematics Mock Test - 7 - Question 7

Select the number which can be placed at the sign of the question mark (?) from the given alternatives.

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 7

The logic follows here is:

Middle number = square root of first number + third number.

Row-wise operation :

(25, 41, 36)

middle number = 41

= √25 + 36

= 5 + 36

= 41

(49, 45, 38)

middle number = 45

= √49 + 38

= 7 + 38

= 45

Similarly

(36, ?, 62)

middle number = ?

= √36 + 62

= 6 + 62

= 68

Hence, the correct answer is "68"

Additional Information

The most common pattern asked in exams are based on:

  • It could be the sum of two numbers divided by a constant
  • It could be the average of numbers.
  • It could be in the form of alphabets, where alphabets are increased by constant or increased by the square of numbers or increased by prime numbers.
  • It could be the difference of product of two diametrically opposite numbers.
  • It could be the difference in the sum of adjacent numbers.
  • The difference of the numbers could be in the patterns 1± 1, 2± 1,  and so on.
  • The difference of the numbers could be in the patterns 1± 1, 2± 1, and so on.
  • Numbers could be 12, 22, 32, and so on or 13, 23, 33, and so on.
  • The difference could be prime numbers or the difference could be the square of prime numbers.
  • The difference could be in the form of N± N or N± N.
  • The difference could be in the form of ×N + N or ×2 + 1, ×2 + 2, ×2 + 3, and so on.
  • The difference could be in the form of ×2 ± 1 alternatively.
  • Numbers could be ×1, ×2, ×3, and so on. 
NVS PGT Mathematics Mock Test - 7 - Question 8

Which answer figure will complete the pattern in the question figure?

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 8

NVS PGT Mathematics Mock Test - 7 - Question 9

Which of the following is/are the parts of an e-mail address?

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 9

Example of e-mail address is

NVS PGT Mathematics Mock Test - 7 - Question 10

Which of the following is not a method used for exposition?

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 10

NVS PGT Mathematics Mock Test - 7 - Question 11

Students will respect the teacher the most, if he/she

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 11

Students will respect the teacher the most, if he/she is sincere. The teacher must be able to reflect sincerity in her attitude and behaviour. She could do this by showing concern and care for students. These positive interpersonal behaviours, where teachers spend time talking to students about their personal or social issues, promote a sense of belonging and strengthen the bond between the teacher and the students.

NVS PGT Mathematics Mock Test - 7 - Question 12

tan (sin−1x) is equal to

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 12

NVS PGT Mathematics Mock Test - 7 - Question 13

An object is moving on the circle of radius 7 cm in clockwise direction with a speed of 10 cm/s. find the angle in radians covered by it in 10 sec when it starts at 0 degree.

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 13


NVS PGT Mathematics Mock Test - 7 - Question 14

If f(x) = x2 and g(x) = cosx, which of the following is true?

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 14

if f(x) is an odd function

So, f(−x)=−f(x)

F(−x)=cos(f(−x))

=cos(−f(x))

=cos(f(x))

=F(x)

So cos(f(x)) is an even function

So, f(x) and g(x) is an even function

NVS PGT Mathematics Mock Test - 7 - Question 15

The domain of the function  

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 15

NVS PGT Mathematics Mock Test - 7 - Question 16

If cos x = tan y, cos y = tan z, cos z = tan x then the value of sin x is

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 16





NVS PGT Mathematics Mock Test - 7 - Question 17

 The centre and radius of the circle x2 + y2 + 4x – 6y = 5 is:

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 17

x2+y2+4x-6y=5
Circle Equation
(x-a)2+(y-b)2=r2 is the circle equation with a radius r, centered at (a,b)
Rewrite x2+y24x-6y=5 in the form of circle standard circle equation
(x-(-2))2+(y-3)2=(3√2)2
Therefore the circle properties are:

(a,b) = (-2,3), r = 3√2

NVS PGT Mathematics Mock Test - 7 - Question 18

The number of arrangements of n different things taken r at a time which include a particular thing is

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 18

Total Permutations of n different things taken r at a time when a particular item is always included in the arrangement is : r * (n-1 p r-1).

NVS PGT Mathematics Mock Test - 7 - Question 19

Let f(x) = ( x + 1)2 – 1,x > –1

Statement -1 : The set {x : f(x) = f –1(x) = {0, –1}

Statement-2 : f is a bijection.

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 19

Given that f (x)  = (x + 1)2 –1,  x > –1 Clearly Df = [–, ∞) but co-demain is not given.
Therefore  f (x) need not be necessarily onto.
But if f (x) is onto then as f (x) is one one also, (x + 1) being something +ve, f–1(x) will exist where (x + 1)2 –1 = y

∴ The statement-1 is correct but statement-2 is false.

NVS PGT Mathematics Mock Test - 7 - Question 20

Six boys and six girls sit in a row at random. Then the probability that six girls sit together is

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 20

Let n (s) = total number of ways of seating (permutations) 6 boys and 6 girls
i.e. 12 people = 12P12 = 12!
Let E: six girls sit together.
Then they become one unit
∴ No. of units is 6 boys + 1 unit of girls = 7 units
∴ n (E) = No. of ways in which six girls can sit together is = 7!, 6!
(Here 6! is the number of ways in which the six girls can sit among themselves)

NVS PGT Mathematics Mock Test - 7 - Question 21

Let U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, A = {1, 2, 5}, B = {6, 7}. Then A ∩ B’ is:

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 21

The correct answer is a) A

  • B' gives us all the elements in U other than 6 and 7 i.e., B' = {1, 2, 3, 4, 5, 8, 9, 10}
  • The intersection of this set with A will be the common elements in both of these (A and B') i.e., = {1, 2, 5} which is set A itself.
NVS PGT Mathematics Mock Test - 7 - Question 22

If tn denotes nth term of the series 2 + 3 + 6 + 11 + 18 + ..... then t50

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 22

(2+0) + (2+12) + (2+22) + (2 32)+...
∴ tn = 2+(n-1)2

NVS PGT Mathematics Mock Test - 7 - Question 23

1 + sec 200 = cot x0.cot y0 then x+y may be

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 23



NVS PGT Mathematics Mock Test - 7 - Question 24

The area bounded by the parabolas y = (x+1)2 and y = (x−1)2 and the line y = (1/4) is equal to

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 24

Required area :

NVS PGT Mathematics Mock Test - 7 - Question 25

If a, b are the roots of x2 + px + 1 = 0, and c, d are the roots of x2 + qx + 1 = 0, then the value of E = (a - c)(b - c)(a+ d)(b+ d) is    

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 25

We have x2 + px + 1 = (x – a)(x – b)
Thus, E = (c – a)(c – b)(-d - a)(-d - b)
= (c2 + pc + 1)[(-d2) - pd + 1] = (c2 + pc + 1)(d2 - pd + 1)       [∴ a + b = -p]
But c2 + qc + 1 = 0 and d2 + qd + 1 = 0
∴ E = (-qc + pc)(-qd - pd) = cd(q - p)(q + p) = cd(q2 - p2) = q2 - p2 [∴ cd = 1]

NVS PGT Mathematics Mock Test - 7 - Question 26

What is the 10th A.M between 2 and 57 if 10 A.M s are inserted between these numbers?

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 26

an = 57, a = 2, n = 12
an = a + (n-1)d
=> 57 = 2 + (12 - 1)d
=> 55 = 11d
d = 5
T10 = a + 10d
=> 2 + 10(5) 
= 52

NVS PGT Mathematics Mock Test - 7 - Question 27

In the following question, a sentence has been given in Active/Passive Voice. Out of the four alternatives suggested, select the one which best expresses the same sentence in Passive/Active Voice.

I have seen him.

Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 27

Rule- The object in the active voice becomes the subject in the passive voice and the subject in the active voice becomes the object in the passive voice.This is valid in both ways (Active to passive and vice-versa). Further, the verb is changed to the past participle form

NVS PGT Mathematics Mock Test - 7 - Question 28
संज्ञा या विशेषण से बनने वाली क्रिया को कहते हैं:
Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 28

संज्ञा या विशेषण से बनने वाली क्रिया को 'नाम धातु' कहते हैअन्य सभी विकल्प गलत है।

Key Points

Additional Information

विशेष:

NVS PGT Mathematics Mock Test - 7 - Question 29
मालिक नौकर से काम करवाता है।” वाक्य से क्रिया के किस भेद का पता चलता है?
Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 29

"मालिक नौकर से काम करवाता है।” वाक्य में प्रेरणार्थक क्रिया है

  • जिस क्रिया से ज्ञान हो कि कर्ता स्वयं कार्य को न करके किसी अन्य को कार्य करने की प्रेरणा देता है वह प्रेरणार्थक क्रिया कहलाती है।
  • जैसे - माता पिता अपने बच्चो के कार्य करवाते है।

Hint

प्रेरणार्थक क्रिया के उदाहरण

  • वह सबसे चालान भरवाता है.
  • महेश बच्चों को रुलाता है.
  • गीता बच्चों को हिंदी पढ़ाती है.
  • सुरेश आज नौकर से गाड़ी धुलवाना
  • आज तुम विजय से चाय बनवाना

Key Pointsअन्य विकल्प

NVS PGT Mathematics Mock Test - 7 - Question 30
निम्नलिखित में से ‘द्विकर्मक क्रिया’ वाले वाक्य का चयन कीजिए -
Detailed Solution for NVS PGT Mathematics Mock Test - 7 - Question 30

दिए गए विकल्पों में से विकल्प 1 "मैं किशोर को खाना खिलाती हूँ।" सही है।

Key Points

  • "मैं किशोर को खाना खिलाती हूँ।" ‘द्विकर्मक क्रिया’ वाले वाक्य है।
  • जिस क्रिया के उपयोग से दो कामों के पूरे होने का पता चलता है उसे द्विकर्मक क्रिया कहते हैं।
    • जैसे:- दुकानदार ने ग्राहक को पुस्तक दी। इस वाक्य में दी क्रिया का फल दो कर्मों पर पढ़ता है, इसलिए इस वाक्य में द्विकर्मक क्रिया है।
      • दिए गए वाक्यों में केवल "मैं किशोर को खाना खिलाती हूँ।" में द्विकर्मक क्रिया है।

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