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Chandigarh TGT Science - Non Medical Mock Test - 9 - SSA Chandigarh MCQ


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30 Questions MCQ Test SSA Chandigarh TGT Mock Test Series 2025 - Chandigarh TGT Science - Non Medical Mock Test - 9

Chandigarh TGT Science - Non Medical Mock Test - 9 for SSA Chandigarh 2024 is part of SSA Chandigarh TGT Mock Test Series 2025 preparation. The Chandigarh TGT Science - Non Medical Mock Test - 9 questions and answers have been prepared according to the SSA Chandigarh exam syllabus.The Chandigarh TGT Science - Non Medical Mock Test - 9 MCQs are made for SSA Chandigarh 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Chandigarh TGT Science - Non Medical Mock Test - 9 below.
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Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 1

The ratio of 1 hour to 300 seconds is:

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 1

The ratio of 1 hour to 300 seconds is:

  • To compare time, we should convert both times to the same unit. Let's convert 1 hour to seconds (since 1 hour = 3600 seconds).
  • 1 hour = 1 × 3600 seconds = 3600 seconds
  • Now we have 3600 seconds to 300 seconds. The ratio is  3600 : 300.
  • To simplify, divide both by their greatest common divisor, which is 300.
  • So, the ratio is 12 : 1, which corresponds to option (b).
Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 2

How many hosts can successfully send data simultaneously on the Ethernet?

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 2
Number of Hosts That Can Successfully Send Data Simultaneously on Ethernet
There are certain limitations to the number of hosts that can successfully send data simultaneously on Ethernet. The answer to this question is:
Answer: B. 2
Explanation:
Ethernet is a widely used technology for local area networks (LANs) and it uses a shared medium for communication. The number of hosts that can send data simultaneously on Ethernet is limited due to the following reasons:
1. Collision Domain: In Ethernet, all devices connected to the same network segment share the same collision domain. A collision occurs when two or more devices transmit data at the same time, resulting in data corruption. To avoid collisions, Ethernet uses a carrier sense multiple access with collision detection (CSMA/CD) mechanism. This means that only one device can successfully transmit data at a time, while others must wait for their turn.
2. Half-Duplex Mode: Ethernet operates in either half-duplex or full-duplex mode. In half-duplex mode, a device can either transmit or receive data at a given time, but not both simultaneously. Therefore, only two hosts can communicate at the same time - one sending and the other receiving.
3. Bandwidth Sharing: Ethernet shares the available bandwidth among all the connected devices. If multiple hosts try to transmit data simultaneously, the available bandwidth gets divided, resulting in lower throughput for each host. To ensure efficient data transmission, it is recommended to limit the number of hosts sending data simultaneously.
In summary, due to the collision domain, half-duplex mode, and bandwidth sharing, Ethernet allows only two hosts to successfully send data simultaneously.
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Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 3

Print chart is

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 3
Print Chart:

  • A: Refers to a printed chart.

  • B: Indicates a chart that is filled in by an analyst while formatting a report.

  • C: Describes a chart that is prepared by users.

  • D: States that the chart is printed by a computer.


The correct answer is B, as it specifically mentions that the chart is filled in by an analyst while formatting a report. Let's further explain each option:
A: A printed chart: This option refers to a chart that has been physically printed, but it does not specify who prepares or fills in the chart.
B: One which is filled in by an analyst while formatting a report: This option explicitly states that the chart is filled in by an analyst during the process of formatting a report. This suggests that the chart is part of the report and is completed by an analyst with the necessary data.
C: Prepared by users: This option indicates that the chart is prepared by users, but it does not mention who these users are or how the chart is used in the context of a report or formatting.
D: Printed by computer: This option suggests that the chart is printed by a computer, but it does not provide any information about who creates or fills in the chart.
In conclusion, the correct option is B as it clearly specifies that the chart is filled in by an analyst while formatting a report.
Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 4

What plaything was invented by Joe McVicker in 1956?

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 4
The stuff was originally intended to be wallpaper cleaner! (I used to eat this as a child)
Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 5
ਸਾਹ ਸੁੱਕਣਾ ਮੁਹਾਵਰੇ ਦਾ ਅਰਥ ਦੱਸੋ-
Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 5

ਬਹੁਤ ਡਰ ਜਾਣਾ

  • ਸਾਹ ਸੁੱਕਣਾ- (ਡਰ ਜਾਣਾ) ਸ਼ੇਰ ਨੂੰ ਸਾਹਮਣੇ ਦੇਖ ਕੇ ਮੇਰਾ ਸਾਹ ਸੁੱਕ ਗਿਆ।
  • ਜਦੋਂ ਹੀ ਮਾਂ ਨੂੰ ਪਤਾ ਲੱਗਾ ਕਿ ਭਰਾ ਦੀ ਪੋਸਟਿੰਗ ਕਾਰਗਿੱਲ ਵਿਚ ਹੋ ਗਈ ਹੈ ਤਾਂ ਉਨ੍ਹਾਂ ਦਾ ਸਾਹ ਸੁੱਕ ਗਿਆ।
  • ਹਾਰ ਜਾਣਾ- (ਈਨ ਮੰਨਣਾ) ਭਾਰਤੀ ਜਵਾਨਾਂ ਦੀ ਲਲਕਾਰ ਸੁਣਦੇ ਹੀ ਪਾਕਿਸਤਾਨੀ ਜਵਾਨਾਂ ਨੇ ਈਨ ਮੰਨ ਲਈ।
  • ਬੇਪਤੀ ਕਰਨੀ (ਬੇਜ਼ਤੀ ਕਰਨਾ) ਮਕਾਨ ਮਾਲਿਕ ਵੱਲੋਂ ਕਰਾਇਆ ਸਮੇਂ ਤੇ ਨਾ ਦੇਣ ਕਰਕੇ ਉਸ ਨੇ ਪੂਰੇ ਮੁਹੱਲੇ ਸਾਮ੍ਹਣੇ ਸੁਰਜੀਤ ਦੀ ਬੇਪਤੀ ਕੀਤੀ।
  • ਗ਼ੁਲਾਮੀ ਕਰਨੀ- (ਹਰ ਹੁਕਮ ਸਿਰ ਝੁਕਾ ਕੇ ਮੰਨਣਾ) ਜਦੋਂ ਦੇਸ਼ ਅੰਗਰੇਜ਼ਾ ਦਾ ਕਬਜ਼ਾ ਭਾਰਤ ਤੇ ਸੀ ਤਾਂ ਦੇਸ਼ ਦੇ ਲੋਕਾਂ ਨੂੰ ਨਾ ਚਾਹੁੰਦੇ ਹੋਏ ਵੀ ਉਨਾਂ ਦੀ ਗ਼ੁਲਾਮੀ ਕਰਨੀ ਪੈਂਦੀ ਸੀ।
Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 6

ਊਠ ਦੇ ਗਲ ____ ਅਖਾਣ ਪੂਰੀ ਕਰੋ :

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 7

ਹੇਠ ਲਿਖੇ ਵਾਕ ਵਿੱਚੋ ਸਬੰਧਮਾਨ ਚੁਣੋ 
ਰਾਹੁਲ ਨੇ ਸ਼ਰਾਬ ਪੀਤੀ 

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 7

ਸਹੀ ਜਵਾਬ , ਸ਼ਰਾਬ ਇਥੇ ਇਕ ਸਬੰਧਮਾਨ ਹੈ 

  • ਸਬੰਧਕ :- : ਜਿਹੜਾ ਸ਼ਬਦ ਕਿਸੇ ਨਾਂਵ ਜਾਂ ਪੜਨਾਂਵ ਦੇ ਪਿਛੇ ਆ ਕੇ ਉਸ ਦਾ ਸੰਬੰਧ ਵਾਕ ਦੇ ਬਾਕੀ ਹਿੱਸੇ/ ਸ਼ਬਦਾਂ ਨਾਲ ਜ਼ੋੜੇ ਉਸਨੂੰ ਸੰਬੰਧਕ ਆਖਦੇ ਹਨ |
  • ਸਬੰਧੀ ਅਤੇ ਸਬੰਧਮਾਨ :- ਸਬੰਧਕ ਤੋਂ ਪਹਿਲਾ ਲੱਗਣ ਵਾਲੇ ਸ਼ਬਦ ਨੂੰ ਸਬੰਧੀ ਅਤੇ ਬਾਅਦ ਵਿਚ ਲੱਗਣ ਵਾਲੇ ਸ਼ਬਦ ਨੂੰ ਸਬੰਧਮਾਨ ਕਿਹਾਂ ਜਾਂਦਾ ਹੈ। ਜਿਵੇ , ਰਾਹੁਲ ਨੇ ਸ਼ਰਾਬ ਪੀਤੀ  ਵਾਕ ਵਿੱਚ "ਨੇ " ਸਬੰਧਕ ਹੈ ਤੇ  "ਰਾਹੁਲ ਸਬੰਧੀ ਤੇ "ਸ਼ਰਾਬਸਬੰਧਮਾਨ ਹੈ। 
Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 8

Choose the word which is different from the rest.

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 8

Answer: C

Explanation:
The word that is different from the rest is Scallop (C). The reasons are as follows:
- Oyster (A), Clam (B), and Mussel (D) are all bivalve mollusks, meaning they have a shell that is divided into two hinged parts. On the other hand, Scallop (C) is also a bivalve mollusk, but it has some unique features that set it apart.
- Scallop's unique features:
- Scallops have a distinct shell shape, which is rounder and flatter compared to the other three.
- Scallops have an ability to swim by opening and closing their shells rapidly, which is not a common feature among the other three mollusks.
- The adductor muscle of the scallop, the part that is commonly consumed, is larger and more developed than in oysters, clams, or mussels, making it a more popular choice for culinary dishes.
These differences make Scallop (C) the word that stands out from the rest.All except Scallop, live in shells.

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 9

The wavelength of X-rays is of the order of:

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 9

X-ray wavelength is in range of 10−11m to 10−8m

So option C is correct.

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 10

Ten million electrons pass from point P to point Q in one micro second. The current and its direction is

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 10

Here,number of electron,
n = 10000000 = 107
Total charge on ten million electrons is
Q = ne [where e = 1.6 × 10−19C]
=10× 1.6 × 10−19C = 1.6 × 10−12C
Time taken by ten million electrons to pass from point P to point Q is
t = 1μs = 10−6s
The current
I = 
Since the direction of the current is always opposite to the direction of flow of electrons. Therefore due to flow of electrons from point P to point Q the current will flow from point Q to point P.

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 11

No force is exerted by magnetic field on a stationary

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 11

Electric dipole at rest can be considered as charge particles at rest. hence, no magnetic field is applied on it.

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 12

A convex lens forms a real image of an object on a screen; the magnification of the image being 3/2. The object and the screen are kept fixed and the lens is moved through a distance of 16 cm when a sharp image is again formed on the screen; the magnification now being 2/3. What is the focal length of the lens?

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 12

3/2=v/u…...1
2/3=(v-16)/(u+16)......2
from these equation
we get v=48, u=32
so now f=(vxu)/(v+u)=96/5=19.2
The correct answer is option B.

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 13

What is the maximum current that can be drawn from a cell of emf E and internal resistance r connected to an external resistance R?

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 13

as the maximum current that can be drawn from a cell is for R =0 therefore, it is I = E/r.

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 14

Electromagnetic Spectrum is

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 14

The orderly distribution of electromagnetic radiations according to their wavelength or frequency as called the electromagnetic spectrum. Radio waves are electromagnetic waves of the frequency range from few Hz to 106 Hz.

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 15

The frequency (v) of charged particle, moving at right angles to the magnetic field is independent of

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 15

Frequency (v) = qB/2πm.
Frequency is independent of radius of trajectory of particle and speed of particle.
 

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 16

We have a right angled isosceles prism, Its refractive index is 1.5. If we incident a ray normally on one of the two perpendicular surfaces, which of the following phenomenon will take place?​

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 16

Critical angle will be, sin−1(1/1.5) = 41.8. The angle of incidence inside the prism will be 45. Since it is more than critical angle, the light ray will be internally reflected.

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 17

In a current carrying conductor varying electric field generates

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 17

In a current-carrying conductor, by varying the electric current, the magnetic field is generated. The direction of the magnetic field generated will be perpendicular to the conductor.
The direction of the magnetic field can be determined as wrapping the right-hand fingers around the wire and the direction of the current is indicated by the thumb.
Ampere’s law is used for determining the magnetic field of a long conductor:
B=μ0I/2πr
Where,

  • I is the current in Amperes

  • r is the radial distance in metres

  • B is the magnetic field in Tesla

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 18

The inverse of conductivity is called:

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 18

The correct answer is option D
Electrical resistivity (also called specific electrical resistance or volume resistivity) and its inverse, electrical conductivity, is a fundamental property of a material that quantifies how strongly it resists or conducts electric current. ... The SI unit of electrical resistivity is the ohm-meter (Ω⋅m).
 

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 19

Which of the following configurations represents a noble gas?

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 19

The outermost shell configuration of the element shows 8 electrons hence it is a noble gas.

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 20

On hydrolysis maltose gives:

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 20

Maltose can be produced from starch by hydrolysis in the presence of the enzyme diastase. It can be broken down into two glucose molecules by hydrolysis. In living organisms, the enzyme maltase can achieve this very rapidly. In the laboratory, heating with a strong acid for several minutes will produce the same result.

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 21

Alpha helix is found in

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 21

The alpha helix (α-helix) is a common motif in the secondary structure of proteins and is a right hand-helix conformation in which every backbone N−H group hydrogen bonds to the backbone C=O. group of the amino acid located three or four residues earlier along the protein sequence.

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 22

Which of the following reactions defines ΔfH° ?

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 22

For ∆H formation we have to look for following:
1. formation of "1 mole" of substance.
2. from "stable" constituting elements.

In first option 1 mole of Co2 should be formed from C(graphite) for enthalpy of formation to be defined.
In third option 2 moles of NH3 is formed instead of 1 mole. So incorrect.
In fourth option Co2 is not formed from constituent elements I.e C(gr) and O2(g) so it is not enthalpy of formation.

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 23

Which of the following is a characteristic property of both mixtures and compounds?

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 23

Mixture and a compound both follow the law of conservation of mass so their weight equals to the sum of mass of their components.

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 24

The function f (x) = x– 2 x is increasing in the interval

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 24

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 25

The solution of cos 4x = cos 2x

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 25

cos 4x = cos 2x

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 26

In a box containing 100 Ipods, 10 are defective. The probability that out of a sample of 5 Ipods, exactly 1 is defective is:

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 26

r = 1, n = 5
p = 10/100  = 1/10,
q = 1 - p
q = 1 - 1/10   = 9/10
= nCr (p)r (q)(n - r)
Exactly one is defective = 5C1 (1/10)1 (9/10)(5 - 1)
= 5C1 (1/10) (9/10)4
= (1/2) (9/10)4

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 27

The feasible solution of a L.P.P. belongs to​

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 27

As per the definition of LPP:
Linear Programming Problem is one that is concerned with finding the optimal value of a linear function of several variables, subject to the conditions that the variables are non-negative and satisfy a set of linear inequalities.
Since the variables (x & y) are non-negative, the feasible solution of a LPP belongs to the 1st quadrant only.

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 28

The function f(x) = ax, 0 < a < 1 is​

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 28

 f(x) = ax
Taking log bth the sides, log f(x) = xloga
f’(x)/ax = loga
f’(x) = ax loga   {ax > 0 for all x implies R, 
for loga e<a<1 that implies loga < 0}
Therefore, f’(x) < 0, for all x implies R
f(x) is a decreasing function.

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 29

The non zero value of ‘a’ for which the lines 2x – y + 3z + 4 = 0 = ax + y – z + 2 and x – 3y + z = 0 = x + 2y + z + 1 are co-planar is

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 29

2x - y +3z + 4 = 0
x - 3y + z = 0
x + 2y + z + 1 = 0
x = 12/5
y = -1/5
z= -3
this point also satisfied by
ax - y + z + 2 = 0
a(12 / 5) - (-1/5) + (-3) = 0
⇒ 12a/5 + 1/5 -3 = 0
a= -2

Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 30

If tan 2A = cot (A – 18°), then the value of A is

Detailed Solution for Chandigarh TGT Science - Non Medical Mock Test - 9 - Question 30

 

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