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SSA Chandigarh TGT Math Mock Test -8 - SSA Chandigarh MCQ


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30 Questions MCQ Test SSA Chandigarh TGT Mock Test Series 2025 - SSA Chandigarh TGT Math Mock Test -8

SSA Chandigarh TGT Math Mock Test -8 for SSA Chandigarh 2024 is part of SSA Chandigarh TGT Mock Test Series 2025 preparation. The SSA Chandigarh TGT Math Mock Test -8 questions and answers have been prepared according to the SSA Chandigarh exam syllabus.The SSA Chandigarh TGT Math Mock Test -8 MCQs are made for SSA Chandigarh 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for SSA Chandigarh TGT Math Mock Test -8 below.
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SSA Chandigarh TGT Math Mock Test -8 - Question 1

A can do a piece of work in 20 days and B can do the same work in 30 days. In how many days can both finish the whole work working together?

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 1


Hence, Option B is correct.

SSA Chandigarh TGT Math Mock Test -8 - Question 2

Which of the following are the states of a five state process model?
(i) Running
(ii) Ready
(iii) New
(iv) Exit
(v) Destroy

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 2
States of a Five-State Process Model:


The five-state process model is a common model used in operating systems to represent the different states a process can be in. The states include:
1. Running: This state represents the process that is currently being executed by the CPU.
2. Ready: This state represents the process that is waiting to be assigned to a CPU for execution. It is in main memory and is eligible for execution.
3. New: This state represents the newly created process that has not yet been admitted to the pool of executable processes.
4. Exit: This state represents the process that has finished execution and has been terminated.
5. Destroy: This state represents the process that has been removed from the system and its resources have been deallocated.
Answer:


Based on the given options, the correct answer is C: i, ii, iii, and iv only. The states included in this answer are Running, Ready, New, and Exit. The Destroy state is not included in the answer.
Note: Option C provides the correct states of the five-state process model.
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SSA Chandigarh TGT Math Mock Test -8 - Question 3

PCB stands for

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 3
PCB stands for Process Control Block.
The Process Control Block (PCB) is a data structure used by operating systems to manage processes. It contains all the necessary information about a process that the operating system needs to manage and control the execution of the process.
The PCB includes the following information:
1. Process ID (PID): A unique identifier assigned to each process by the operating system.
2. Process State: Indicates the current state of the process, such as running, ready, waiting, or terminated.
3. Program Counter: Stores the address of the next instruction to be executed by the process.
4. CPU Registers: Contains the values of the CPU registers being used by the process, such as the accumulator, stack pointer, and program status word.
5. Memory Management Information: Includes information about the memory allocated to the process, such as base and limit registers, page tables, and segment tables.
6. Scheduling Information: Contains data related to process scheduling, such as priority, time slice, and waiting time.
7. I/O Status Information: Stores the status of I/O operations initiated by the process, such as the list of open files and their file descriptors.
8. Parent Process ID: Stores the PID of the parent process that created the current process.
9. Child Process ID: Stores the PID of the child process created by the current process, if any.
The PCB plays a crucial role in process management:
- Context Switching: When the operating system switches from one process to another, it saves the context of the currently running process in its PCB and restores the context of the next process from its PCB.
- Process Scheduling: The PCB contains scheduling information that helps the operating system determine the priority and order in which processes should be executed.
- Process Communication: The PCB can be used to facilitate process communication by providing information about shared resources, inter-process communication channels, and synchronization mechanisms.
- Resource Management: The PCB includes information about the resources allocated to the process, such as memory, files, and I/O devices, which helps the operating system manage and track resource usage.
In conclusion, the Process Control Block (PCB) is a data structure used by operating systems to manage and control processes. It contains essential information about a process, including its state, CPU registers, memory management details, and scheduling information. The PCB plays a crucial role in process management, including context switching, process scheduling, process communication, and resource management.
SSA Chandigarh TGT Math Mock Test -8 - Question 4

With the round robin CPU scheduling in a time-shared system, ______.

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 4
Explanation:
The round robin CPU scheduling algorithm is a time-sharing system where each process is executed for a fixed time slice called a time quantum. Once the time quantum expires, the CPU is preempted and the next process in the queue is executed. This process continues until all processes have been executed.
Now, let's analyze the statements given in the question:
A: Using very large time slice degenerates into first come first serve algorithm
- When a large time slice is used, each process is allowed to run for a longer duration before being preempted.
- This essentially means that the CPU is allocated to each process in a sequential manner, following the order in which they arrived.
- Therefore, using a large time slice in round robin scheduling effectively degenerates into the first come first serve algorithm.
B: Using extremely small time slices improves performance
- Using extremely small time slices can lead to a high overhead due to the frequent context switches between processes.
- Context switching involves saving the current state of a process and loading the state of the next process, which incurs additional time.
- This overhead can degrade the overall system performance, especially when the number of processes is large.
C: Using extremely small time slices degenerates into last in first out algorithm
- This statement is not accurate. Using extremely small time slices does not lead to a last in first out algorithm.
- In round robin scheduling, the order of execution is based on the arrival time of the processes, not the order in which they were added to the queue.
D: Using medium-sized time slices leads to shortest request time first algorithm
- This statement is also not accurate. The round robin scheduling algorithm does not prioritize processes based on their request time.
- Instead, it ensures that each process gets an equal share of the CPU's time by using a fixed time slice.
Therefore, the correct answer is:
A: Using very large time slice degenerates into first come first serve algorithm
SSA Chandigarh TGT Math Mock Test -8 - Question 5

What is the term used when you press and hold the left mouse key and move the mouse around the slide?

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 5
Term used when you press and hold the left mouse key and move the mouse around the slide:

  • Dragging: This is the correct term used when you press and hold the left mouse key and move the mouse around the slide. It refers to the action of moving an object or selecting multiple objects by holding down the mouse button and moving the cursor.

  • Highlighting: This term is not applicable in this context. Highlighting usually refers to the action of selecting text or a portion of text by changing its background color.

  • Selecting: This term is also not specifically used to describe the action of pressing and holding the left mouse key and moving the mouse around the slide. Selecting typically refers to choosing or picking something from a list or group of items.

  • Both (b) and (c): This option is incorrect because the correct term for pressing and holding the left mouse key and moving the mouse around the slide is only dragging. The term "selecting" is not accurate in this context.


Therefore, the correct term used when you press and hold the left mouse key and move the mouse around the slide is dragging.
SSA Chandigarh TGT Math Mock Test -8 - Question 6

The board of directors ___________ anxious.

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 6

Explanation:

The correct answer is B: have been.

- When referring to the board of directors, it is considered a collective noun.
- In American English, a collective noun is typically treated as singular, while in British English, it can be treated as both singular and plural.
- In this case, the use of "have been" indicates that the board of directors is being treated as plural, which is acceptable in British English.
- Option A (are) would be correct if the sentence was in the present tense, but the given sentence is in the present perfect tense, therefore "have been" is the appropriate choice.
- Option C (has been) would be correct if the board of directors was being treated as singular, but the sentence is in the present perfect tense, and "have been" is the appropriate choice for a plural subject.
- Option D (were) would be correct if the sentence was in the past tense, but the given sentence is in the present perfect tense, therefore "have been" is the appropriate choice.

SSA Chandigarh TGT Math Mock Test -8 - Question 7

Who was the first Indian male to receive the Bharat Ratna, India's highest civilian award?

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 7

The Correct Answer is "C.V. Raman"

C.V. Raman was awarded the Bharat Ratna in 1954, the same year the award was established. He was one of the most prominent scientists in India, noted for his work in the field of light scattering. This work led to his discovery of the phenomenon, now called "Raman scattering," which earned him the Nobel Prize in Physics in 1930. He was the first Asian and first non-white person to receive any Nobel Prize in the sciences.

Alongside C.V. Raman, the first recipients of the Bharat Ratna in 1954 were politician C. Rajagopalachari and philosopher Sarvepalli Radhakrishnan.

SSA Chandigarh TGT Math Mock Test -8 - Question 8

Learning means to gain:

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 8

Learning is a process where we live, talk with others, learn new things which means we are interacting with others, and learning different skills like sitting, walking, eating, etc. We gain knowledge of what we are not aware of and also learn various skills that help us in the future.
Hence, the correct answer is "All of the above".

SSA Chandigarh TGT Math Mock Test -8 - Question 9

Child development mainly focuses on:

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 9

Child development focuses on human beings. Mainly, psychologists wanted to know how humans grow and change every year by emotion, social growth, how they learn, how their minds work, etc.
Hence, the correct answer is "Humans".

SSA Chandigarh TGT Math Mock Test -8 - Question 10

Right to Education Act-2009 is in implementation for children of which age group? 

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 10
  • The RTE Act was enacted in 2009 and came into effect in 2010.
  • It guarantees the right of every child in the age group of 6 to 14 years to free and compulsory education in a neighborhood school.
  • The Act also provides for a number of other safeguards, such as the prohibition of corporal punishment and the right to education for children with disabilities.

Hence, it can be concluded that Option (1) is the correct answer.

SSA Chandigarh TGT Math Mock Test -8 - Question 11

Sequencing in development is constant but the speed is different in: 

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 11
  • In child development, sequencing refers to the consistent order in which certain developmental milestones or abilities are typically acquired. While the sequencing of development tends to follow a predictable pattern, the speed at which children reach these milestones can vary between individuals.
  • Individual action refers to the actions and behaviors of an individual child. Each child develops at their own pace, influenced by factors such as genetics, environment, and individual characteristics. Some children may reach developmental milestones earlier or later than average, and the rate of development can vary across different areas, such as cognitive, motor, social, or emotional development.

The correct option among the given choices is Individual action.

SSA Chandigarh TGT Math Mock Test -8 - Question 12
उत्थान' का निम्न में से कौन सा सही विलोम शब्द है?
Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 12

'उत्थान' का विलोम शब्द पतन है।

उत्थान का विलोम पतन होता है।

  • उत्थान का अर्थ - उठना
  • पतन का अर्थ - गिरना

Key Pointsअन्य विकल्प -

  • पातन का अर्थ होता है - नीचे ढकेलने की क्रिया या भाव
  • पाटन का अर्थ होता है - छेदने की क्रिया
  • पतान का कुछ अर्थ नहीं होता है।

Additional Informationविलोम के उदाहरण -

  • मूक - वाचाल
  • सम्पन्न - विपन्न
  • सम्मुख - विमुख
  • मितव्ययी - अपव्ययी
  • स्मरण - विस्मरण
  • नीरस - सरस
  • पक्ष - प्रतिपक्ष
  • ज्योति - तम
  • अथ - इति
SSA Chandigarh TGT Math Mock Test -8 - Question 13

The area of the region bounded between the line x=9 and the parabola y2=16x is​

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 13

Correct Answer : a

Explanation : Equation of the parabola is

y2 = 16x .... (i)

Required area =2∫(0 to 9) ydx

[by symmetry about x-axis]

= 2∫(0 to 9) 4(x)1/2 dx

= 8∫(0 to 9) (x)1/2 dx

​= 8[(x3/2)/(3/2)](0 to 9)

​= 16/3[x3/2](0 to 9)

= 144 sq unit.

SSA Chandigarh TGT Math Mock Test -8 - Question 14

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 14

 

SSA Chandigarh TGT Math Mock Test -8 - Question 15

If P (A) = 0.8, P (B) = 0.5 and P(B|A) = 0.4, find P(A ∩ B) 

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 15

We have ,
P (A) = 0.8, P (B) = 0.5 and P(B|A) = 0.4

SSA Chandigarh TGT Math Mock Test -8 - Question 16

The asymptotes of the hyperbola xy–3x–2y = 0 are

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 16

xy - 3x - 2y + λ = 0.
Then abc + 2fgh − af2 − bg2 − ch2 = 0
⇒ 3/2 − λ/4 = 0
⇒ λ = 6
∴ Equation of asymptotes is xy-3x-2y+6=0
⇒ (x-2)(y-3)=0
⇒x - 2 = 0 and y - 3 = 0

SSA Chandigarh TGT Math Mock Test -8 - Question 17

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 17

SSA Chandigarh TGT Math Mock Test -8 - Question 18

Integrate 

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 18

∫(2+tan x)2dx
= ∫(4 + tan2 x + 4tan x)dx
= ∫4 dx + ∫tan2 x dx + 4∫tan x dx
= 4x + ∫(sec2 x - 1)dx + 4(log|sec x|)
= 4x + tanx - x + 4(log|sec x|)
3x + tanx + 4(log|sec x|) + c

SSA Chandigarh TGT Math Mock Test -8 - Question 19

What is the element in the 2nd row and 1st column of a 2 x 2 Matrix A = [ aij], such that a = (i + 3) (j – 1)​?

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 19

Rows are represented by i
Columns are represented by j
... a = (i+3)(j-1)
i = 2 , j = 1    (given)
a21 = (2+3)(1-1) = 0
so, a21 = 0

SSA Chandigarh TGT Math Mock Test -8 - Question 20

If y = – sin2x. Find the values of x at which the tangents drawn to the graph of this function is parallel to the x- axis.

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 20

SSA Chandigarh TGT Math Mock Test -8 - Question 21

The value of  cos 7π/12

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 21

cos(7π/12)
= cos(3π/12 + 4π/12)
= cos(π/4 + π/3)
Use trig identity: cos (a + b) = cos a.cos b - sin a.sin b
cosa = cos(π/4) = √2/2;
cosb = cos(π/3) = 1/2
sina = sin(π/4) = √2/2;
sina = sin(π/3) = √3/2
cos(7π/12) = cos(π/4 + π/3)
=> (√2/2)(1/2) − (√2/2)(√3/2) 
= (√2 − √6)/4
= √2(1 - √3)/2√2√2
= (1 - √3)/2√2

SSA Chandigarh TGT Math Mock Test -8 - Question 22

In fig., AB || CD, ∠a is equal to:

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 22

CD || AB (Given)
Produce RQ to meet AB in S
∠CRS = ∠PSR (at. int. ∠s)
But ∠CRS = 55°
∴ ∠PSR = 55°
Now in QSP
∠QSP + ∠QPS + ∠PQS = 180°
55° + 38° + ∠SQP = 180°
∴ ∠SQP = 180° – 93° = 87°
But angle a and ∠PQS are linear
∠a = 180° – 87°
∠a = 93°

SSA Chandigarh TGT Math Mock Test -8 - Question 23

The locus of a variable point whose distance from the point (2, 0) is 2/3 times its distance from the line x = 9/2 is

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 23

SSA Chandigarh TGT Math Mock Test -8 - Question 24

The stone projected vertically upwards moves under the action of gravity alone and its motion is described by x = 49 t – 4.9 t2 . It is at a maximum height when

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 24

SSA Chandigarh TGT Math Mock Test -8 - Question 25

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 25


SSA Chandigarh TGT Math Mock Test -8 - Question 26

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 26

√x / √(16+√x) - 4

= (√x * √(16+√x) + 4) / ( √(16+√x) - 4) * (√(16+√x) + 4)

= (√x * √(16+√x) + 4) / 16+√x - 16

= √(16+√x) + 4

now at lim x->0

= √16 + 4 = 8

SSA Chandigarh TGT Math Mock Test -8 - Question 27

An oil company has two depots A and B with capacities of 7000 L and 4000 L respectively. The company is to supply oil to three petrol pumps, D, E and F whose requirements are 4500L, 3000L and 3500L respectively. The distances (in km) between the depots and the petrol pumps is given in the following table:

Assuming that the transportation cost of 10 litres of oil is Re 1 per km, how should the delivery be scheduled in order that the transportation cost is minimum?What is the minimum cost?

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 27

Here objective function is : Z = 3x + y + 39500 , subject to constraints : : x + y ≤ 7000, x ≤ 4500, x + y ≥ 3500, , y ≤ 3000x , x,y ≥ 0

Here Z = 4400 is minimum.i.e. . From A: 500, 3000 and 3500 litres; From B: 4000, 0, 0 litres to D, E and F respectively; Minimum cost = Rs 4400 .

SSA Chandigarh TGT Math Mock Test -8 - Question 28

A coin is tossed three times, if E : at least two heads , F : at most two heads. Find P(E|F)

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 28


SSA Chandigarh TGT Math Mock Test -8 - Question 29

The area enclosed by the parabola y2 = 2x and its tangents through the point (-2 , 0) is

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 29


SSA Chandigarh TGT Math Mock Test -8 - Question 30

The angle of elevation of the top of a tower from a distance 100 m from its foot is 60°. The height of the tower is :

Detailed Solution for SSA Chandigarh TGT Math Mock Test -8 - Question 30

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