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HPCL Civil Engineer Mock Test - 3 - HPSC (Haryana) MCQ


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30 Questions MCQ Test HPCL Civil Engineer Mock Test Series 2024 - HPCL Civil Engineer Mock Test - 3

HPCL Civil Engineer Mock Test - 3 for HPSC (Haryana) 2024 is part of HPCL Civil Engineer Mock Test Series 2024 preparation. The HPCL Civil Engineer Mock Test - 3 questions and answers have been prepared according to the HPSC (Haryana) exam syllabus.The HPCL Civil Engineer Mock Test - 3 MCQs are made for HPSC (Haryana) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for HPCL Civil Engineer Mock Test - 3 below.
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HPCL Civil Engineer Mock Test - 3 - Question 1

Directions: Each item in this section consists of a sentence with an underlined word followed by four words/group of words. Select the option that is nearest in meaning to the underlined word and mark your response on the answer sheet accordingly.

The restaurant is known for its sumptuous dishes that delight the taste buds.

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 1

The correct answer is “Appetizing”.

Key Points

  • Sumptuous: lavish or luxurious.(भव्य या विलासी)
    • Example- The sumptuous feast was fit for a king.
  • Appetizing: appealing to the sense of taste.(स्वाद की अनुभूति के लिए आकर्षक)
    • Example- The appetizing aroma of the food made my mouth water.
  • Hence, the option that is similar in meaning to the given word is 'Appetizing'.

Therefore, the correct answer is “option 2”.

Additional Information

  • Unpalatable: not pleasant to the taste.(स्वाद के लिए सुखद नहीं)
  • Bland: lacking flavor or taste.(स्वाद या स्वाद का अभाव)
  • Nutritious: providing the nutrients necessary for growth and health.(विकास और स्वास्थ्य के लिए आवश्यक पोषक तत्व प्रदान करना)
HPCL Civil Engineer Mock Test - 3 - Question 2

Select the most appropriate ANTONYM of the underlined word.

An autoimmune disease is a condition in which your immune system mistakenly attacks your body.

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 2

Here the correct answer is Susceptible.

Key Points

  • The word "immune" refers to having protection or resistance against something, such as diseases or infections. In the given context, it specifically refers to the immune system's ability to defend the body against foreign substances and pathogens.("प्रतिरक्षा")
    • Example sentence: Vaccines help to boost your immune system, making you less susceptible to certain diseases.
  • Among the given options:
  • "Susceptible" means vulnerable or prone to something. In the context of immunity, it is the opposite of being immune. If someone is susceptible to a disease, it means their immune system is not able to provide sufficient protection against it.(अतिसंवेदनशील)
  • "Fragile" means delicate or easily broken. It does not convey the opposite meaning of "immune" in the context of the immune system attacking the body.(कमज़ोर)
  • "Sick" means unwell or having an illness. It is not an antonym of "immune."(बीमार)
  • "Sedentary" means characterized by or involving little physical activity. It does not convey the opposite meaning of "immune."(गतिहीन)
  • Among the options, "susceptible" is the best antonym of "immune" as it denotes the lack of immunity or the ability to resist the attacks of the immune system. In the case of autoimmune diseases, the immune system mistakenly attacks the body, indicating a lack of immunity against one's own cells or tissues.
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HPCL Civil Engineer Mock Test - 3 - Question 3

In a single throwing of a dice, the probability of getting more than 4 is 1/3 then probability of getting 4 or less than 4 will be

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 3

Concept:

A probability is a chance of prediction. The formula of the probability of an event is given by

 

Calculation:

Favorable outcomes of getting 4 or less than 4 = {1, 2, 3, 4} = 4

Total number of outcomes = 6

∴ Probability = 4/6 = 2/3

Hence, the probability of getting 4 or less than 4 is 2/3.

HPCL Civil Engineer Mock Test - 3 - Question 4

Select the correct mirror image of the given figure which will be formed when the mirror is placed on MN as shown below.

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 4

The mirror image of the given figure is:

Hence, the correct answer is "Option ()".

HPCL Civil Engineer Mock Test - 3 - Question 5

Directions: Each item in this section has a sentence with three underlined parts, labelled as (a), (b) and (c). Read each sentence to determine whether there is any error in any underlined part and indicate your response on the Answer Sheet against the corresponding letter, i.e., (a) or (b) or (c). If you find no error, your response should be indicated as (d).

The politicians (a)/ parted ways (b)/ due towards ideological differences. (c)/ No error (d)

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 5

The correct answer is 'C' i.e. this part of the sentence has an error.

Key Points

  • The phrase "due towards" is incorrect. The correct phrase should be "due to".
  • "Due to" is a prepositional phrase that is used to give a reason or cause for something.
  • In the given sentence, "due to" should be used to indicate the cause of the politicians parting ways.
  • Therefore, the correct sentence should read: "The politicians parted ways due to ideological differences."

Hence, the correct answer is option 3.

Correct sentence:

The politicians parted ways due to ideological differences.

Additional Information

  • Option 1 (a): "The politicians" - This part is correct as it correctly identifies the subject of the sentence.
  • Option 2 (b): "parted ways" - This part is also correct as it correctly describes the action taken by the politicians.
  • Option 4 (d): "No error" - This option is incorrect because there is an error in part (c) of the sentence.
HPCL Civil Engineer Mock Test - 3 - Question 6

You are given a question and two statements I and II. You have to decide whether the data provided in the statements are sufficient to answer the question.

On which date of month was Harish born in February 2000?

Statements:

I. Harish was born on an even date of the month.

II. Harish’s birth date was a prime number.

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 6

Statements:

I. Harish was born on an even date of the month → 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28

II. Harish’s birth date was a prime number → 2, 3, 5, 7, 11, 13, 17, 19, 23, 29

But we know that 2 is the smallest even prime number.

According to both statements we can say that on 2nd February 2000 Harish was born.

Hence, Option (1) is correct.

HPCL Civil Engineer Mock Test - 3 - Question 7

A question is given, followed by two statements labelled I and II. Identify which of the statements is/are sufficient to answer the question.

Question:

In a certain code language, "pu ma kas' means 'we eat mangoes'. What is the code of 'mangoes'?

Statements:

I. 'la ti kas' means 'we are graduate'.

II. 'hum tup pu' means 'they eat bananas'.

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 7

Given: "pu ma kas' means 'we eat mangoes'.

Statements:

I. 'la ti kas' means 'we are graduate'.

II. 'hum tup pu' means 'they eat bananas'.

From I and II statements we conclude that both are sufficient to answer the question. So 'ma' is the code of 'mangoes'.

Hence, Statements I and II together are sufficient to answer the question.

HPCL Civil Engineer Mock Test - 3 - Question 8
The sum of three consecutive odd numbers is 20 more than the first number. What is the middle number?
Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 8

Calculation:

Let the three consecutive odd numbers be (x - 2), x, and (x + 2)

Sum = 20 + (x - 2)

Sum = x - 2 + x + x + 2 = 3x

3x = 20 + x - 2

Or, x = 9

∴ The middle number is 9.

HPCL Civil Engineer Mock Test - 3 - Question 9

If and θ is an acute angle, then the value of is:

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 9

Given:

Concept used:

secθ = Hypotenuse/Base, tanθ = perpendicular/base, cosθ = base/hypotenuse

Pythgorus theorem

Hypotenuse2 = Perpendicular2 + Base2

Calculation:

Let Perpendicular = P, Base = B, Hypotenuse = H

⇒ {(H/B) + (P/B)}/{(H/B) - (P/B)} = 5/1

⇒ (H + P)/(H - P) = 5/1

⇒ H + P = 5 ----(1)

⇒ H - P = 1 ----(2)

Solve (1) and (2)

⇒ H = 3, P = 2

Hypotenuse2 = Perpendicular2 + Base2

⇒ Base = √5

⇒ {3 × (√5/3)2 + 1}/{3 × (√5/3)2 - 1}

⇒ (8/3)/(2/3)

⇒ 4

∴ The value is 4.

HPCL Civil Engineer Mock Test - 3 - Question 10
In how many ways 8 girls and 8 boys can sit around a circular table so that no two boys sit together?
Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 10

There are 8 boys and 8 girls.

No two boys can sit together.

Consider one seat as fixed because table is circular. If that fixed position is allotted to a boy then remaining places are filled with boys in 7! Ways.

Now, for 8 girls, there 8! Ways to place in between so that no two boys can sit together.

So, total number of ways = 8! × 7!
HPCL Civil Engineer Mock Test - 3 - Question 11

Choose the word that means the same as the given word.

Edacious

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 11

The correct answer is 2) Gluttonous.

Key Points

  • The word "edacious" means having a voracious or excessively eager appetite, often associated with being gluttonous or excessively hungry.
    (तीव्र या अत्यधिक भूख होना). It describes someone or something that has a strong desire for consuming food.
    • Example: "The edacious eater devoured the entire pizza in minutes, leaving no slice behind."
    • In this example, "edacious" describes the person's insatiable appetite and their quick consumption of the entire pizza.
  • In conclusion, the word that means the same as "edacious" is 2) Gluttonous, as it conveys the idea of having an excessively eager appetite or being inclined towards overeating(अधिक खाने की ओर प्रवृत्त होना).
    • Example: Despite already having a full dinner, Tom couldn't resist indulging in a gluttonous feast of desserts.

Additional Information

  • Now let's examine the other options:
  • Solvent: (अन्‍य पदार्थ को अपने में विलीन करने वाला तरल; विलायक) This option does not have the same meaning as "edacious." "Solvent" refers to being financially stable or able to pay debts, which is unrelated to the concept of being excessively hungry.
    • Example: "Despite the economic downturn, the company remained solvent and was able to pay its employees."
  • Insolvent: (धन की कमी के कारण ऋण चुकाने में असमर्थ; दिवालिया)This option does not have the same meaning as "edacious." "Insolvent" refers to being in a state of financial distress or bankruptcy, which is unrelated to the concept of having a voracious appetite.
    • Example: "Due to mounting debts, the business became insolvent and had to file for bankruptcy."
  • Satiated: (भूख को पूरी तरह शांत करना; तृप्त करना)This option does not have the same meaning as "edacious." "Satiated" means being fully satisfied or no longer hungry or thirsty, which is the opposite of the intense hunger associated with "edacious."
    • Example: "After enjoying a delicious meal, he felt satiated and content."
HPCL Civil Engineer Mock Test - 3 - Question 12
Choose the option that best expresses the meaning of the highlighted idiom/phrase:
If you don't have a place to stay, you can't get a job, and with no job you can't get an apartment. It's a Catch 22 situation.
Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 12

The correct answer is "a situation where one factor depends on another"

Key Points

  • Catch 22 situation is a phrase used to describe a situation in which a person is in a dilemma because two conflicting rules or conditions make it impossible to satisfy both of them at the same time(ऐसी स्थिति जहां एक कारक दूसरे पर निर्भर करता है).
  • This phrase is often used to describe situations in which someone is trapped in a paradoxical situation, and no matter what they do, they cannot find a solution.
  • Example:
    A job applicant must have experience to be hired, but they cannot gain experience without first being hired. This is a classic example of a Catch 22 scenario.
  • Thus, the correct answer is Option 1.

Correct answer: a situation where one factor depends on another"

HPCL Civil Engineer Mock Test - 3 - Question 13

Choose the word that means the same as the given word.

Jarred

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 13

The correct answer is: 'Altercated'.

Key Points

  • The word "jarred" means causing a feeling of unease or discord.(बेचैनी या कलह की भावना पैदा करना)
  • Similarly, "altercated" means to engage in a heated or argumentative dispute or quarrel.(तर्कपूर्ण विवाद या झगड़े में शामिल होना)
    • Example: "The heated debate between the two politicians jarred the atmosphere in the room."
    • In this example, "jarred" describes the tense and uncomfortable impact of the argument.
    • Example: The two neighbors altercated loudly in the middle of the street, drawing the attention of passersby.
  • In summary, the correct answer is "altercated" as it conveys the sense of engaging in a heated dispute or quarrel, which aligns with the meaning of "jarred" in the context of conflict or discord.
HPCL Civil Engineer Mock Test - 3 - Question 14

If 1 is added to each even digit and 2 is subtracted from each odd digit in the numbers given below, then what will be the product of the second digit from the left and third digit from the right in the new number thus formed?

(Left) 56897423 (Right)

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 14

Given number: (Left) 56897423 (Right)

Conditions:

Now, after rearranging the given number as per the given conditions, we get:

New number: (Left) 47986532 (Right)

So, the product of the second digit from the left and the third digit from the right = 7 × 5 = 35

Hence, the correct answer is "Option 3".

HPCL Civil Engineer Mock Test - 3 - Question 15

P. A weir is a hydraulic structure where majority or the entire ponding is achieved by a raised crest and smaller part or nil part by the shutters.

Q. A weir is a hydraulic structure that is made by constructing the width of the channel only.

R. A barrage is a hydraulic structure that is made by creating a choking condition only.

S. A barrage is a hydraulic structure where majority or the entire ponding is achieved by a shutter and smaller part or nil part by the raised crest.

Identify the correct statements in the above.

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 15

Concept:

Weir:

  • If the major part of the entire ponding of water is achieved by the raised crest and a smaller part or nil part of it is achieved by the shutters, then this barrier is known as a weir.

Barrage:

  • If most of the ponding is done by gates and a smaller or nil part of it is done by the raised crest, then the barrier is know as a barrage.
  • It is a structure similar to a weir with the only difference being that the crest is kept at a low level and ponding of water is accomplished mainly by means of gates. During floods these gates can be raised above HFL and thus enable the high flood to pass with minimum afflux.

HPCL Civil Engineer Mock Test - 3 - Question 16

Four concurrent forces are acting at a point O as shown in figure. What would be the component of the resultant force in the X direction?

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 16

Force 400 N acts 60° with x-axis,

so two component of force is,

400cos(60°) acts with horizontal axis and

400 sin(60°) acts with vertical axis

again, Force 300 N acts 60° with x-axis,

so two component of force is,

300cos(60°) acts with horizontal axis and

300 sin(60°) acts with vertical axis

According to force equilibrium,

Resultant force in X-direction

= 300 + 400cos(60°) - 300cos(60°) (→ positive)

Resultant force in X-direction

= 300 + 400 x - 300 x

Resultant force in X-direction

= 300 + 200 - 150

Resultant force in X-direction = 350 N (→)

HPCL Civil Engineer Mock Test - 3 - Question 17

The vertical stress at point P1 due to the point load Q on the ground surface as shown in the figure is σz. According to Bossiness's equation, the vertical stress at point P2 shown in the figure will be

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 17

Concept:

Vertical stress due to concentrated load is given as per Boussinesq’s equation.

where,

σz = Stress magnitude, Q = Vertical point load, r = Radial distance, and z = Vertical distance.

Calculation:

Given:

For Point P1 r = r, z = z

For Point P2 ,

Case 1: For Point P1

r = r, z = z

Case 2: For Point P2

,

σ'z = 4 × σz

HPCL Civil Engineer Mock Test - 3 - Question 18
A vehicle has a wheelbase of 6.5 m. What is the off tracking while negotiating a curved path with a mean radius of 32 m?
Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 18

Concept:

Off-tracking in curve path:

  • It is the term used to describe the difference in path radii between the leading and trailing axle of a vehicle as it maneuvers around a turn.
  • The Geometric design of streets and highways and of parking lots and trucking yards will be affected by the maximum off-tracking of vehicles using those facilities.
  • In some accident investigations, off-tracking is the primary consideration.

Off-tracking while negotiating a curve is

=

where,

n = number of traffic lanes,

l = length of the wheelbase,

R = Radius of the curve(m)

Calculation:

Given l = 6.5 m,

R = 32 m

The off tracking while negotiating a curved path is

=

= = 0.66 m

HPCL Civil Engineer Mock Test - 3 - Question 19

As per IRC : 73-1980, the width of the carriageway for double lanes (with raised curbs) is

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 19

Important Points

  • The lane width of expressways is 3.75 m in plain and rolling terrains and 3.5 m in mountainous terrain, the changeover of lane width from 3.5 to 3.75 m should be effected by a smooth transition of 1 in 60 for a flatter rate.
  • On urban roads without raised kerbs, the lane width may be 3.5 m.
  • The minimum width recommended for the kerbed urban road is 5.5 m to make allowance for stalled vehicles.
  • In local streets of residential areas, the lane width may be decreased to 3.0 m.
HPCL Civil Engineer Mock Test - 3 - Question 20

Consider the following for bending stress induced in a beam:

(i) Directly proportional to modulus of elasticity,

(ii) Inversely proportional to curvature and

(iii) Inversely proportional to radius of curvature

Which one of the following is correct answer?
Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 20

Bending equation states that:

Various terms in above bending equation are:

σ = Bending stress

y = Distance from neutral axis

M = Bending moment

I = Area moment of inertia

E = Modulus of elasticity

R = Radius of curvature

HPCL Civil Engineer Mock Test - 3 - Question 21

Match List - I with List - II and select the correct answer using the codes given below the lists:

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 21

Proctor test:

  • The Proctor compaction test is a laboratory method of experimentally determining the optimal moisture content at which a given soil type will become most dense and achieve its maximum dry density.
  • The graphical relationship of the dry density to moisture content is then plotted to establish the compaction curve.

​Vane test:

  • The laboratory vane shear test for the measurement of shear strength of cohesive soils.
  • It is useful for soils of low shear strength (less than 0.3 kg/cm2) for which triaxial or unconfined tests can not be performed.
  • The test gives the undrained strength of the soil.

Penetration test:

  • The standard penetration test, commonly known as 'SPT', was developed to provide geotechnical engineering properties for foundation design purposes.
  • The test is carried out within a borehole.
  • The results can be used to determine the relative density, bearing capacity, and settlement of granular soil.

Hydrometer test:

  • Measuring the particle size distribution(Grain Size Analysis) of fine-grained soils like clay and silt is best performed using the soil hydrometer test
  • The hydrometer analysis of soil, based on Stokes’ law, calculates the size of soil particles from the speed at which they settle out of suspension from a liquid.
HPCL Civil Engineer Mock Test - 3 - Question 22
In case of continuous slab, the torsion reinforcement provided in an inner corner with all the face side continuous an amount equal to
Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 22

Concept:

  • For a restrained slab, the area of reinforcement in each of the four corner layers shall be three-quarters of the area required for the maximum mid span moment in the slab simply supported on both edges meeting at that corner.
  • If the corner is contained by edges over only one of which the slab is continuous, torsion reinforcement equal to 0.375 or times the area of reinforcement provided the mid-span in the same direction shall be provided.
  • If both edges are continuous, no torsion reinforcement shall be provided.

Additional Information

For Slab:

Minimum reinforcement criteria-

Mild steel- 0.15% of total C/S area

HYSD BARS- 0.12% of total C/S area

Maximum diameter = d should not be greater than 1/8 ( thickness of slab)

For Columns:

Longitudinal reinforcement criteria-

It should not be less than 0.8%
It should not be greater than 6%

For Beams:

Tension Reinforcement criteria-

The minimum area of reinforcement

Maximum area of reinforcement = 0.04bD

HPCL Civil Engineer Mock Test - 3 - Question 23

In case of unequal angle section oriented with longer leg vertical, axis parallel to shorter leg of the angle and passing form centroid of cross-section is______

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 23

In reference to the following figure of an unequal angle section with a longer leg vertical:

  1. U-U axis passes through the centroid of the unequal angle section and it is the major principal axis for a single unequal angle section.
  2. V-V axis passes through the centroid of the unequal angle section and it is the minor principal axis for a single unequal angle section.
  3. The y-Y axis is parallel to the longer leg of an unequal angle section and it also passes through the centroid. This is the minor axis and it is perpendicular to the shorter leg of the unequal angle section.
  4. The z-Z axis is parallel to the shorter leg of an unequal angle section and it also passes through the centroid. This is the major axis and it is perpendicular to the longer leg of the unequal angle section​
HPCL Civil Engineer Mock Test - 3 - Question 24
A catchment area has 4 rain gauges installed, with an annual average rainfall of 110 cm and a standard deviation of 25 cm. If an error of 0.10 is allowed in the estimation of mean rainfall data, the additional number of rain gauges required are
Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 24

Concept:

Optimum number of Rain gauges:

It is the number of Rain gauges required to calculate the average rainfall value with a certain acceptable percentage of error.It is given as,

Where,

e = Allowable error

Cv = Coefficient of variance

Also,

Calculation:

Pm = 110 cm, σ = 25 cm, e = 0.1

Adopting 6 rain gauges, additional number of rain gauges required = 6 – 4 = 2

Important Point:

According to WMO, at least 10% of rain gauges should be of recording type.
HPCL Civil Engineer Mock Test - 3 - Question 25
In case of bundled bars, the code IS 456 : 2000 specifies that the development length of each bar of bundled bars shall be that for the individual bar, increased by ________ percent for two bars in contact.
Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 25

Concept:

Development length:

(i) The calculated tension or compression in any bar at any section shall be developed on each side of the section by an appropriate development length or end anchorage or a combination thereof.

(ii) Development length can be calculated as:

Where, ϕ = Diameter of bar

τbd = Design bond stress = Permissible value of average bond stress

The value of bond stress is increased by 60% for a deformed bar in tension and a further increase of 25% is made for bars in compression.

In case of bundled bars in contact the development length is increased than that for individual bar by

  1. 10% for two bars in contact
  2. 20% for three bars in contact
  3. 33% for four bars in content
HPCL Civil Engineer Mock Test - 3 - Question 26

The amount of residual chlorine left in public water supply for safety against pathogenic bacteria is about:-

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 26
  • Doses of chlorine should be sufficient so as to leave a residue of 0.2 mg/l or 0.2 ppm after 10 min of the contact period.
  • The residue chlorine is tested by the Diethyl-paraphenylene diamine (DPD) test.
  • The higher the residual chlorine levels in the supply, the better and longer the chemical will be able to protect the system from contamination.
  • However, high levels of chlorine make the water smell and give it a bad taste, which will discourage people from drinking it.
  • For normal domestic use, residual chlorine levels at the point where the consumer collects water should be between 0.2 and 0.5 mg/l.
  • The higher level will be close to the disinfection point and the lower level at the far extremities of the supply network.
HPCL Civil Engineer Mock Test - 3 - Question 27

In vacuum flotation unit, the vacuum pressure present in the aerated sewage cause the air bubbles to:

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 27

Vacuum flotation method:

  • It is a water treatment process that clarifies wastewaters (or other waters) by the removal of suspended matter such as oil or solids.
  • The removal is achieved by dissolving air in the water or wastewater under pressure and then releasing the air at atmospheric pressure in a flotation tank basin.
  • The released air forms tiny bubbles which adhere to the suspended matter causing the suspended matter to float to the surface of the water where it may then be removed by a skimming device.
  • Dissolved air flotation is very widely used in treating the industrial wastewater effluents from oil refineries, petrochemical, and chemical plants, natural gas processing plants, paper mills, general water treatment, and similar industrial facilities.
HPCL Civil Engineer Mock Test - 3 - Question 28

On the basis of its function, power plants comes under which type of construction project ?

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 28

The functional outcome of a project, once the construction is completed, is also an important feature of a project. Construction projects according to the type of work being completed, are as follows:

HPCL Civil Engineer Mock Test - 3 - Question 29

Which one of the following is the CORRECT sequence for a train in order to pass over the turnout from the facing direction?

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 29

Concept-

A turnout has three distinct portions,

  • Switch Assembly
  • Lead Assembly
  • Crossing Assembly

  • Curve lead (CL)- This is the distance from the tangent point (T) to the theoretical nose of crossing (TNC) measured along the length of the main track.
  • Switch lead (SL)- This is the distance from the tangent point (T) to the heel of the switch (TL) measured along the length of the main track.
  • Lead of crossing (L)- This is the distance measured along the length of the main track as, Lead of crossing (L) = curve lead (CL) – switch lead (SL)
  • Heel divergence (D)- This is the distance between the mainline and the turnout side at the heel.
  • Correct sequence for a train in order to pass over the turnout from the facing direction is Toe of a switch - Tongue rail - Lead rail - Crossing.
HPCL Civil Engineer Mock Test - 3 - Question 30

The rivets in an eccentrically loaded riveted joint are shown in figure below,

Which rivets will be stressed to maximum?

Detailed Solution for HPCL Civil Engineer Mock Test - 3 - Question 30

Concept:

Eccentric Loading of Riveted Joints:

  • An eccentrically loaded joint is one in which the line of application of load does not pass through centre of gravity (c.g) of rivets.
  • It passes away from c.g axis.
  • This has two effects, primary/direct load and secondary load.

Direct Load:

  • This load acts parallel to the load acting and vertically downwards.
  • The magnitude for the direct load is
  • It is represented by f1.

Secondary load:

  • It acts perpendicular to the line joining the centre of gravity of rivets assembly to individual rivets.
  • The direction of the secondary load is the same as given by external load i.e. the moment produced due to external load is clockwise so the secondary load will also be clockwise.
  • The magnitude for the secondary load is for rivet 1 and similarly for other rivets by changing r2, r3 and r4 in the numerator.

Now, both the load are added vectorially.

Calculation:

Given:

Direct load and secondary load diagram is given above.

The resultant of two forces acting at an angle is given by

Rivets that are farthest from centroid and having least θ will be subjected to maximum stress.

Hence rivets 4 and 6 will experience maximum stress.

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