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MPPGCL JE Electrical Mock Test - 7 - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test MPPGCL JE Electrical Mock Test Series 2025 - MPPGCL JE Electrical Mock Test - 7

MPPGCL JE Electrical Mock Test - 7 for Electrical Engineering (EE) 2024 is part of MPPGCL JE Electrical Mock Test Series 2025 preparation. The MPPGCL JE Electrical Mock Test - 7 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The MPPGCL JE Electrical Mock Test - 7 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MPPGCL JE Electrical Mock Test - 7 below.
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MPPGCL JE Electrical Mock Test - 7 - Question 1

Find the number which is common to all three figures.

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 1

In the question, We have to find the common to all three figures which is shown below-

Here, The highlighted area is common to all shapes.

Hence, Option (3) is correct.

MPPGCL JE Electrical Mock Test - 7 - Question 2

Direction: Study the following information carefully and answer the given questions besides.

Eight person A, B, C, D, E, F, G and H sit around the circular table facing towards the centre but not necessarily in the same order.
G sits opposite to B. One person sits between A and C, who sits second to the right of H. Both G and B do not sit immediate left of H. D sits second to the left of B. A doesn’t sit beside D. E doesn’t face C.
What is the position of G with respect to C?

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 2

From the common explanation, we get the position of G is 3rd to the right of C.

Hence, Option B is correct.

Common Explanation:

References:

One person sits between A and C, who sits second to the right of H.

G sits opposite to B.

Both G and B do not sit immediate left of H.

Inferences:

From the above reference, we get two different cases:

References:

D sits second to the left of B.

A doesn’t sit beside D.

E doesn’t face C.

Inferences:

From the above reference, case 1 will be eliminated because A doesn’t sit beside of D.

So, the final arrangement:

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MPPGCL JE Electrical Mock Test - 7 - Question 3

P is 6 km west from point Q. Point R is 4 km north to point Q. S is 12 km south from point R. Now point S in which direction and how far from point P?

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 3

As per the given information;

Distance between S and P = √(PQ2 + QS2)
SP = √(62 + 82)
SP = √(36 + 64)
SP = √100
SP = 10 km
Hence, S is 10 km in South-East with respect to P.

MPPGCL JE Electrical Mock Test - 7 - Question 4

DirectionsIn questions given below out of four alternatives, choose the one which can be substituted for the given word/sentence.

Q. Leave or remove from a place considered dangerous.

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 4

One word substitution is Evacuate.

Evade: escape or avoid (someone or something), especially by guile or trickery.

Evacuate: remove (someone) from a place of danger to a safer place.

Avoid: keep away from or stop oneself from doing (something).

Exterminate: destroy completely.

MPPGCL JE Electrical Mock Test - 7 - Question 5

How many seats are reserved in Lok Sabha for the Scheduled Tribes?

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 5

B is the correct option.Some seats are reserved in Lok Sabha for the members of the Schedule Castes and Scheduled Tribes. As per the order issued by the Delimitation Commission in 2008 , 412 are general, 84 seats are reserved for Scheduled Castes and “47 seats” for the Scheduled Tribes.

MPPGCL JE Electrical Mock Test - 7 - Question 6

Eight friends- P, Q, R, S, T, U, V and W are sitting around a circular table but not necessarily in the same order. All of them are facing the center. Who is facing V?

Statement I: V is sitting to the immediate left of W. R is sitting 2nd to the left of S.
Statement II: Q is sitting 2nd to the left of T. T is facing P. The number of friends sitting between P and Q is same as the number of friends sitting between P and W.

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 6

From statement I alone, we don’t get the answer.

From statement II alone, Q is sitting 2nd to the left of T. T is facing P. The number of friends sitting between P and Q is same as the number of friends sitting between P and W.


From statement II alone, we don’t get the answer.

Combining both statement I and II, we get,


From statements I and II together, we don’t get the answer.

Hence, option ‘D’ is correct.

MPPGCL JE Electrical Mock Test - 7 - Question 7

What happens to the conductivity of semi-conductors when temperature increases?

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 7

The electrical conductivity of a semiconductor increases with increase in temperature because with increase in temperature the electrons overcome the energy barrier between the valence band and the conduction band easily.

MPPGCL JE Electrical Mock Test - 7 - Question 8

A 1 mA meter movement with an internal resistance of 100Ω  is to be converted into (0 – 100) mA. To achieve this, value of shunt resistance Rsh is given by

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 8

MPPGCL JE Electrical Mock Test - 7 - Question 9

The curie temperature of iron is-

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 9
Curie point, also called Curie Temperature, temperature at which certain magnetic materials undergo a sharp change in their magnetic properties. In the case of rocks and minerals, remanent magnetism appears below the Curie point—about 550 °C (1,060 °F) for the common magnetic mineral magnetite.
MPPGCL JE Electrical Mock Test - 7 - Question 10

Armature reaction in a D.C. motor is increased.

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 10
In the armature, an electromotive force is created by the relative motion of the armature and the field. When the machine is used as a motor, this EMF opposes the armature current, and the armature converts electrical power to mechanical power in the form of torque, and transfers it via the shaft. When the machine is used as a generator, the armature EMF drives the armature current, and the shaft's movement is converted to electrical power. In an induction generator, these distinctions are blurred, since the generated power is drawn from the stator, which would normally be considered the field.

A growler is used to check the armature for shorts, opens and grounds.

MPPGCL JE Electrical Mock Test - 7 - Question 11

The range of horse power of diesel locomotive is______.

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 11
Hence, the correct option is (B)
MPPGCL JE Electrical Mock Test - 7 - Question 12

As per recommendation of ISI the maximum number of points of lights, fans, socket and that can be connected in one sub-circuit is____

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 12
Hence, the correct option is (B)
MPPGCL JE Electrical Mock Test - 7 - Question 13

The skin effect does not depend on-

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 13
Impedance of round wire[edit] The internal impedance of round wire is given by 5:40.

The internal impedance is complex and may be interpreted as a resistance in series with an inductance. The inductance accounts for energy stored in the magnetic field inside the wire. It has a maximum value of H/m at zero frequency and goes to zero as the frequency increases. The zero-frequency internal inductance is independent of the radius of the round wire.

The internal inductance of round wire vs. the ratio of skin depth to radius. The inductance asymptotically approaches (μ / 8 π ) H/m for large skin depth. The internal inductance is associated with the magnetic field inside the wire. As skin depth becomes small, the inductance goes linearly to zero.

Hence, the correct option is (D)

MPPGCL JE Electrical Mock Test - 7 - Question 14

Kilowatt-hour(kWh) is a unit of?

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 14
Power is the energy per unit time. That is, P = Et.

If the unit of power in kW and the unit of time is an hour, then the unit of energy = unit of power × unit of time = kWh.

Hence, the correct option is (B).

MPPGCL JE Electrical Mock Test - 7 - Question 15

After the starting winding is disconnected from the circuit the motor continues to run only on the-

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 15
A single-phase motor cannot create a rotating magnetic field. It will just standstill and oscillate. To see this disconnect the start winding and you will see the motor will not startup. If you twist the motor shaft with your fingers it will run in whichever direction you twist. To self-start a single-phase motor one must create a rotating magnetic field on the stator. Two windings are used and the difference in impedance creates a phase delay in the magnetic fields produced by each winding allowing the motor to start.

Hence, the correct option is (B)

MPPGCL JE Electrical Mock Test - 7 - Question 16

The yoke of a DC. Machine is made of-

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 16
To provide a low reluctance path, it must be made up of some magnetic material. It is prepared by using cast iron because it is cheapest. For large machines rolled steel, cast steel, silicon steel is used which provides high permeability i.e. low reluctance, and gives good mechanical strength.

Hence, the correct option is (D)

MPPGCL JE Electrical Mock Test - 7 - Question 17

If I be the current, C the capacitance, and V the potential differences, then I/CV will have the unit of-

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 17
I/GV = 1/RG which is reciprocal of the time constant in steady-state analysis of the network which in turn gives frequency.

Hence, the correct option is (D)

MPPGCL JE Electrical Mock Test - 7 - Question 18

...........motor is most suitable for push and pull action

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 18
A cumulative compound motor has a fairly constant speed and good starting torque. Such motors are used where series characteristics are required and the load is likely to be removed totally. These motors are used in driving machines which are subject to the sudden application of heavy loads; they are used in rolling mills, punching and shearing machines, mine-hoists etc.

Hence, the correct option is (D)

MPPGCL JE Electrical Mock Test - 7 - Question 19

For the circuit shown in figure, when . When Vs = 200V. what will be the value of I?

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 19

Net current,

{{chart?cht=tx chl=\(I=I}}

MPPGCL JE Electrical Mock Test - 7 - Question 20

A short circuit test on a transformer gives ___________.

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 20

From the short circuit test of the Transformer we will find out full load copper loss and equivalent circuit parameter & voltage regulation.
From full load copper loss we can find out copper losses at any fraction of load by using the following formula.
Wcu at x% full load = x2 [Wcu full load]

MPPGCL JE Electrical Mock Test - 7 - Question 21

A 0 – 200 V voltmeter has guaranteed accuracy of 2% at full scale. Find the % error if the measured value is 144 V

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 21

Maximum error = 2% of 240 = (200)×(2/100)= 4 V
% error when measured 100V = 4×(100/144)=2.78 %

MPPGCL JE Electrical Mock Test - 7 - Question 22

Inductance of moving iron instrument is given as  If the control spring torque is  then find deflection in rad for a current of 3 A –

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 22

MPPGCL JE Electrical Mock Test - 7 - Question 23

Power consumed in the given circuit is-

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 23

power consumed in the circuit, P

MPPGCL JE Electrical Mock Test - 7 - Question 24

An over-excited 3-phase synchronous motor can be used to

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 24

An over-excited 3-phase synchronous motor is not only used as a motor to supply the needed mechanical power but also acts as a power factor correction device.But generally prefered for power factor correction.

MPPGCL JE Electrical Mock Test - 7 - Question 25

What is rotor copper loss of a 3-phase, 550volt, 50hz, 6-poles induction motor developing 4.1kW at the shaft with mechanical loss of 750W at 970rpm?

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 25
Rotor copper loss = gross mechanical power output.

Gross mechanical power output = shaft power + mechanical losses

= 4.1×103+750

= 4850

Here slip =

Slip s =

= 0.03

Rotor copper loss =

= 150W

Hence, the correct option is (B).

MPPGCL JE Electrical Mock Test - 7 - Question 26

Three 3μ F capacitors are in series. A 6 capacitor is in parallel with this series arrangement. The equivalent capacitance of this combination is-

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 26

Cab = (1e)μ F = 7μ F

MPPGCL JE Electrical Mock Test - 7 - Question 27

Phasor diagram of load voltage (V), current in pressure coil ((IP)), and current in the current coil ((IC)) is shown in the figure when an electrodynamic wattmeter is used to measure power. The reading of the wattmeter will be proportional to-.

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 27
P = V cosβ.IC cosψ

P = V IC cosβ cosψ

Pα cosβ cosψ

MPPGCL JE Electrical Mock Test - 7 - Question 28

For n-type semiconductor, the doping material is-

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 28
For n-type semiconductors, the doping material is pentavalent.
MPPGCL JE Electrical Mock Test - 7 - Question 29

The Req for the circuit shown in figure is

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 29

Equivalent of 6 ohm 3 ohm in parallel = 6x3/9= 2 ohm
This 2 ohm again in series with 2 ohm resistor = 2+2 =4 ohm
Equivalent of 1 ohm & 5 ohm series = 1+5 = 6 ohm
Now 6 ohm & 4 ohm in parallel so its equivalent = 6x4/10 =2.4
Hence Req of the network = 4+2.4 +8 = 14.4

MPPGCL JE Electrical Mock Test - 7 - Question 30

A workshop is consuming 500 kW at 0.707 p.f. lagging. A synchronous motor is connected to improve the p.f. to 0.95 lagging. If the synchronous motor takes 100 kW, p.f. of the motor is

Detailed Solution for MPPGCL JE Electrical Mock Test - 7 - Question 30

p.f. of synchronous motor,

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