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BDL MT Electronics Mock Test - 2 - Electronics and Communication Engineering (ECE) MCQ


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30 Questions MCQ Test BDL MT Electronics Mock Test Series 2025 - BDL MT Electronics Mock Test - 2

BDL MT Electronics Mock Test - 2 for Electronics and Communication Engineering (ECE) 2025 is part of BDL MT Electronics Mock Test Series 2025 preparation. The BDL MT Electronics Mock Test - 2 questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The BDL MT Electronics Mock Test - 2 MCQs are made for Electronics and Communication Engineering (ECE) 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for BDL MT Electronics Mock Test - 2 below.
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BDL MT Electronics Mock Test - 2 - Question 1

Match the Lists:

The correct matching order is:

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 1

High electron mobility transistor:

  • The High Electron Mobility Transistor is a form of Field Effect Transistor (FET) that uses a junction between two materials with different bandgaps (i.e. a heterojunction) as the channel.
  • The most common material used is aluminum gallium arsenide (AlGaAS) and gallium arsenide (GaAs)
  • Gallium Arsenide (GaAs) is generally used because it provides high-level basic electron mobility.
  • HEMT is used in microwave circuits as it provides low noise and high gain.
  • HEMT has a high gain at microwave frequencies because the charge carriers are almost exclusively the majority carriers. Minority carriers are not significantly involved.

Accelerometer chip:
These are devices that convert acceleration into electrical signals.
MEM's devices:
Micro-electromechanical devices involve the conversion of mechanical energy into electrical energy and vice-versa.
Optoelectronic devices:

  • Optoelectronics deals with the science and technology of electronic devices which involves interaction with light.
  • Optoelectronic devices include LED which involves the emission of light when current is passed through a forward bias LED.
BDL MT Electronics Mock Test - 2 - Question 2

Consider the following statements regarding an FET :

  1. its operation depends upon the flow of majority carriers only.
  2. It has a high input resistance.
  3. It is suitable for high frequency.
  4. Its operation depends upon the flow of both majority and minority carriers.

Which of the above statements are correct ?

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 2

FET:
1. As the input circuit of FET is reverse biased, FET exhibits a much higher input impedance ( in the order of 100 MΩ) and lower output impedance and there will be a high degree of isolation between input and output.
2. The FET (field – effect transistor) is a majority carrier (current flows due to majority carrier i.e. electron for N-type FET and hole for p-type FET) device. It is also called a unipolar transistor
3. They are also considered low–power consumption configuration with a good frequency range and minimal size and weight. FET is a voltage control device.

Explanation
FETs are majority-charge-carrier devices, in which the current is carried predominantly by majority carriers. So statement 1 is correct and statement 4 is incorrect.
In FET gate source is reverse biased so its input impedance is high. Due to high input impedance in FET gate current is zero. So statement 2 is correct.
Now, For FETs

Cgs = gate to source capacitance
Cgd = gate to drain capacitance
FET has low transconductance (gm) in comparison to BJT that’s why FET is not suitable for high frequency. So statement 3) is incorrect.
In summary → FET → low value of gm → fT
At high-frequency f > fT then FET will not provide amplification.

IMPORTANT POINTS ABOUT FET:

  1. The field-effect transistor (FET) is a type of transistor that uses an electric field to control the flow of current.
  2. FETs are also known as unipolar transistors since they involve single-carrier-type operations.
  3. FET has better thermal stability than a BJT.
  4. FET is less noisy.
  5. No minority carrier in FET.
  6. FET offers a large Bandwidth but small gain.
  7. FET is a voltage-controlled device.
BDL MT Electronics Mock Test - 2 - Question 3

The power absorbed in 5 ohm resistor in the circuit shown below is _____.

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 3

The current flowing through 5Ω resistance is

I = 50/5 = 10 A 

Applying KVL in loop (1) we get

KVL is violated
It is not possible to find the power

BDL MT Electronics Mock Test - 2 - Question 4

For a bode magnitude and phase plot the resonant frequency (ωp) is given by where ωn = natural frequency of oscillation and ξ = damping ratio.

The slope of magnitude curve at ω = ωp is ________.

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 4

The bode magnitude plot is shown

At resonant frequency, (ωp), magnitude is maximum and hence slope is 0.

BDL MT Electronics Mock Test - 2 - Question 5

If (110)x = (132)4, then x =

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 5

Concept:
Another number system to Decimal

In each and every representation of numbers with different bases, the maximum value in a number system with the base ‘r’ is r – 1. Since numbers vary from 0 to r – 1.
To convert any number which is in the different base to decimal number system we use binary-weighted representation.
Eg: let the number be ( abc⋯ ⋯ yz)r
Now to convert the above number into the decimal number system
a × rn-1 + b × rn-2 + ⋯ ⋯ + y × r1 + z × r0
If we convert all numbers into decimal then we can perform normal addition and subtraction etc.

Application:
Given:
(110)x = (132)4,
The decimal equivalent of this number will be:
1 x x2 + 1 x x1 + 0 x x0 = 1 x 42 + 3 x 4 + 2 x 40
x2 + x + 0 = 16 + 12 + 2
x2 + x - 30 = 0
On solving this quadratic equation we'll get:
x = 5, -6
Base can't be a negative so;
x = 5

BDL MT Electronics Mock Test - 2 - Question 6

Which of the following circuit has its output dependent only upon the present input?

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 6

Combinational Logic circuits are circuits for which the present output depends only on the present input, i.e. there is no memory element to store the past output.

A combinational circuit can have ‘n’ number of inputs and ‘m’ number of outputs as shown:

Combinational circuits are:

  • Multiplexer/Demultiplexer
  • Encoder/Decoder
  • Adders
  • Subtractors
  • Code Converters

Important Point:

In a sequential circuit, the output depends on both the present and the past values. The circuit diagram is as shown:

Examples of sequential circuits:

  • Shift Registers
  • Flip flops
  • Counters
BDL MT Electronics Mock Test - 2 - Question 7

What is the final output of the three T-flip-flops in cascade provided the input to T-flip-flop is 100 Hz signal?

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 7

Concept:
If we pass the input signal to a single T-flip flop, we will get half of the frequency at the output.


Similarly, when we pass the input signal into an n-bit flip flop counter, the output frequency (fout) will be:

Application:
Given Input frequency f = 100 Hz

fout = 12.5 Hz

BDL MT Electronics Mock Test - 2 - Question 8

The resolution of a D/A converter is approximately 0.4% of it's full scale range. It is

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 8

Resolution is the smallest change in the analog output for a change in digital input, also referred to as step size
Resolution =
Given:

⇒ 2N - 1 = 1000/4 = 250
⇒ 2N = 251
N ≈ 8

BDL MT Electronics Mock Test - 2 - Question 9

JFET is considered as a voltage-controlled device because ______

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 9

JEET is considered as a voltage-controlled device because the drain current is controlled by the gate voltage.
Explanation:

JFET:

  • It is affiliated as a junction field-effect transistor
  • The types of JFET are n-channel FET and p-channel FET
  • A p-type material is added to the n-type substrate in n-channel FET, whereas an n-type material is added to the p-type substrate in p-channel FET.

  • JFET is a three-terminal device and since gate voltage controls the drain current, JFET is called a voltage-controlled device.
  • JFET’s have only a depletion mode of operation.
  • When there is no potential applied between gate and source terminals and a potential VDD is applied between drain and source, then a current I0 flows from drain to source terminals at its maximum as the channel width is more.
  • When the voltage applied between gate and source terminal VGG is reverse biased, this decreases the depletion width, thus the layers grow and the cross-section of the channel decreases and hence the drain current ID also decreases.
  • Thus drain current in JFET is controlled by changing the channel width.
  • Gate source p-n junction is always reverse biased because if it is forward then all the channel current will flow to the Gate and not to the source, ultimately damaging JFET.
BDL MT Electronics Mock Test - 2 - Question 10

Which of the following options about tunnel diodes is INCORRECT?

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 10

Tunnel Diode:

  • Symbol:

  • It is a highly doped PN Junction diode, used for low voltage high-frequency switching applications.
  • It works on the tunneling principle.
  • It has a high charge carrier velocity.
  • When compared to a normal p-n junction diode, the tunnel diode has a narrow depletion width.
  • In normal forward-biased operation, it exhibits the “Negative resistance region” as shown:

  • The negative differential resistance in their operation, allows them to be used as oscillators, amplifiers, and switching circuits.
  • Their low capacitance allows them to function at microwave frequencies.
  • Microwave frequencies range between 109 Hz (1 GHz) to 1000 GHz
  • Tunnel diodes are not good rectifiers, as they have relatively high leakage current when reverse biased.
BDL MT Electronics Mock Test - 2 - Question 11

In an amplifier with the negative feedback, bandwidth is _________ and voltage gain is _________.

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 11

The feedback amplification factor is given by A f = A/1 + Aβ
where A is open-loop gain and βA is loop gain.
As feedback increases the gain decreases thereby bandwidth increases.
The negative feedback in amplifiers causes

  1. reduced the voltage gain and increases the stability in gain
  2. increases the bandwidth by the factor (1 + Aβ) to maintain constant gain-bandwidth product
  3. Reduces the distortion and noise in the amplifier
  4. but the signal to noise ratio is not affected
BDL MT Electronics Mock Test - 2 - Question 12

A Darlington emitter follower circuit is sometimes used in the output stage of TTL gate to _____.

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 12

Explanation:
1. A Darlington pair configuration has high input impedance and low output impedance.
2. Thus it is used as a buffer circuit for impedance matching with the circuits that require high input impedance at the input.
3. In addition to providing high input impedance, the Darlington pair also provides high current gain
Hence a Darlington emitter follower circuit is sometimes used in the output stage of the TTL gate to increase speed.
Note:
Darlington Pair: CC – CC

  • A Darlington pair is a two-transistor circuit with the emitter of one transistor is connected to the base of other transistors, while both collector terminals are connected to the common terminal
  • It has a high current gain β; (equal to the product of the current gain of individual transistors) and is useful in applications where current amplification or switching is required.
  • It also has high input impedance and low output impedance.
  • The current gain of a Darlington pair in common emitter configuration is approximate β2

The symbolic diagram of the Darlington pair is shown below

BDL MT Electronics Mock Test - 2 - Question 13

For an AM signal, the bandwidth is 6 kHz and the highest frequency component present is 600 kHz. The carrier frequency used for this AM signal is

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 13

The frequency spectrum of an Amplitude Modulated wave is given by:

Bandwidth in AM = 2fm = 6 kHz
fm = 3 kHz
Upper sideband = fc + fm = 600 kHz
∴ The carrier frequency is:
fc = 600 – fm = 600 - 3 kHz
fc = 597 kHz

BDL MT Electronics Mock Test - 2 - Question 14

In a digital communication system employing Frequency Shift Keying (FSK), the 0 and 1 bit are represented by sine waves of 10 kHz and 25 kHz respectively. These waveforms will be orthogonal for a bit interval of

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 14

Derivation:
Given, In FSK modulation, let f1, f2 be frequencies for bit ‘0’
s (t) = A sin (2πf1t)
For bit ‘1’
s (t) = A sin (2πf2t)
Let Tb be bit duration
For both waveforms to be orthogonal,

It is possible if both 2π(f1 - f2)Tb and 2π(f1 + f2)Tb are integral multiplies of π(i.e. = nπ), i.e.

Application:
Given, f1 = 10 kHz and f2 = 25 kHz
15 kHz = n/tb and 35 kHz = m/tb
It is possible for 1/tb = 5kHZ , with minimum m and n value, i.e.
i.e. Tb = 200 μs. (minimum value)

BDL MT Electronics Mock Test - 2 - Question 15

The following program states at location 0100 H.


The content of accumulator when the program counter reaches 0109 H is

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 15

HL contains 0107 H and continents of 0107H is 20 H.
Thus after execution of SUB the data of A is 20 H – 20 H = 0.

BDL MT Electronics Mock Test - 2 - Question 16

The ALE line of an 8085 microprocessor is used to

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 16

ALE: (Address Latch Enable):

  • It is an active high output signal.
  • It indicates that the bits on AD7 - AD0 are address bits
  • This signal is used to latch the lower order address from the multiplexed bus and generate a separate set of eight address lines A7 – A0
  • It is provided by the microprocessor to latch the address into the 8282 / 8283 address latch.
  • It is a high pulse active during T1 of any machine cycle. The T1 state is sufficient enough to latch the address on the multiplexed AD0 - AD15 lines.
  • Whenever the processor sends a valid address on the multiplexed lines it also makes the ALE High.
  • ALE is never floated.
  • ALE is used to demultiplexed/multiplexed data buses and address buses.

Note:
The 8085 microprocessor signals can be classified in various groups, namely:

  1. address bus,
  2. data bus
  3. control bus
  4.  status signals,
  5. externally initiated signals
  6. acknowledgement, power and frequency,
  7. serial I/O signals.
BDL MT Electronics Mock Test - 2 - Question 17
If calls arrive at a telephone exchange such that the time of arrival of any call is independent of the time of arrival of earlier or future calls, the probability distribution function of the total number of calls in a fixed time interval will be
Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 17

Concept:

Poisson distribution is applied when the number of trials is very large and the probability of success is small.

Calculation:

Let's say we have an event E such that the success of the event is “Ringing a call at a time t0” and failure is “Not ringing a call at time t0”.

Since the total number of success or failure of the event is unknown. Therefore, we can say that the event is a random variable.

1 hour = 3600 sec = 3600000 msec = 3.6 × 109 μsec

The event can occur a large number of times for any given time interval and the probability of success is very less.

This property corresponds to Poisson distribution.
BDL MT Electronics Mock Test - 2 - Question 18

Set of equations:
4x + 2y + z + 3w = 0
6x + 3y + 4z + 7w = 0
2x + y + w = 0
Determine whether the following set of equations have

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 18

Explanation:
The following set of equations can be written in the matrix form
AX = 0

Where,

Performing row operations,
R2 → R2 -(3/2)R1
R3 → R3 -(R1/2)

R3 → R3 -(R2/5)

∴ Rank (A) = 2, which is less than the number of variables.
∴ The solution is consistent and there are infinite numbers of non-trivial solutions.

BDL MT Electronics Mock Test - 2 - Question 19

The value of c in Mean Value Theorem for the function f (x) = x (x - 4), x ϵ [1, 4] is

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 19

Concept:
If real valued function f (x)
(i) is continuous in [a, b]
(ii) is differentiable on (a, b)
(iii) f'(c) =  [f (b) - f(a)]/(b - a)
Calculation:
(i) is continuous in [a, b]
(ii) is differentiable on (a, b)
f (x) = x (x - 4)
f (a) = f (1) = 1 (1 - 4) = 1 (-3) = -3
f (b) = f (4) = 4 (4 - 4) = 4 0 = 0
f'(c) = [f (b) - f (a)]/(b - a) = [0- (-3)]/(4 - 1) = 3/3 = 1
As per the mean value theorem statement, there is a point c ∈ (1, 4) such that f'(c) = [f (b) – f (a)]/ (b – a), i.e. f'(c) = 1.
2c - 4 = 1

2c = 1 + 4

c = 5/2

BDL MT Electronics Mock Test - 2 - Question 20

The length and breadth of a room is 16 m and 12 m respectively. If the total area of the four walls of the room is 784 m2, then what is the height of the room?

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 20

Given:

The length and breadth of a room is 16 m and 12 m respectively

The area of four walls = 784 m2

Formula used:

Area of four walls = 2(L + B) × H

Where,

L = Length of the room

B = Breadth of the room

And, H = Height of the room

Calculation:

According to the formula, we have

{2(16 + 12) × H} = 784 m2

⇒ 2 × 28 × H = 784

⇒ H = (784/56)

⇒ 14 m

∴ The height of the room is 14 m

Other Related Points

In a room, the area of two walls consists of length and height, and the other two wall's area consists of breadth and height.

BDL MT Electronics Mock Test - 2 - Question 21

A started a business with Rs. 15000, after two months B joined the business with Rs. 12000 and after two months of B the third person C joined the business with Rs. 10000. The total profit share after 1 year is Rs. 5700. What is the profit share of A?

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 21

Shortcut TrickP ∝ I
P ∝ T
Now,
P ∝ (I × T)

⇒ Profit = 9 ∶ 6 ∶ 4
Total profit = Rs. 5700
⇒ 19 units ≡ Rs. 5700
⇒ 1 unit ≡ Rs. 300
For A,
⇒ 9 units ≡ Rs. 2700
∴ The profit share of A is Rs. 2700.Alternate Method
Given:
Investment of A = Rs. 15000, Time = 12 months
Investment of B = Rs. 12000, Time = 10 months
Investment of C = Rs. 10000, Time = 8 months
Concept used:
1) P ∝ I
2) P ∝ T
Where, P = Profit, I = Investment, T = Time
Calculation:
Investment of A × Time ∶ Investment of B × Time ∶ Investment of C × Time
⇒ (15000 × 12) ∶ (12000 × 10) ∶ (10000 × 8)
⇒ (15 × 12) ∶ (12 × 10) ∶ (10 × 8)
⇒ 9 ∶ 6 ∶ 4
The ratio of the profit is directly proportional to the multiplication of investment to time.
⇒ PA ∶ PB ∶ Pc = 9 ∶ 6 ∶ 4
The total profit after 1 year = Rs. 5700
⇒ 9k + 6k + 4k ≡ Rs. 5700
⇒ 19k ≡ Rs. 5700
⇒ k ≡ Rs. 300
For 'A'
⇒ 9k ≡ Rs. 2700
∴ The profit share of A is Rs. 2700.
Important Point
The ratio of the profit is directly proportional to the multiplication of investment to time.

BDL MT Electronics Mock Test - 2 - Question 22

20 litres of a mixture contains milk and water in the ratio 3 : 1.Then the amount of milk to be added to the mixture so as to have milk and water in ratio 4 : 1

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 22

Calculation:

In 20 litres of mixture

Quantity of milk

⇒ (3/4) × 20 = 15 litres

Quantity of water

⇒ (1/4) × 20 = 5 litres

Let the amount of milk to be added is x litres

⇒ 15 + x = 20

⇒ x = 5 litres.

∴ The answer is 5 litres.

BDL MT Electronics Mock Test - 2 - Question 23
If the selling price is doubled, the profit gets tripled. Find the profit % ?
Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 23

Given:

Selling price is doubled then profit is tripled

Formula used:

Profit = SP - CP

Profit % = (Profit/Cost Price) × 100

Calculation:

Let the selling price be x and cost price be y

Initially Profit (P) = x - y

If the selling price is doubled profit will be tripled

2x - y = 3P

⇒ 2x - y = 3(x - y)

⇒ 2x - y = 3x - 3y

⇒ x = 2y

Profit % = (Profit/Cost Price) × 100

Profit % = [(x - y)/y] × 100

Profit % = [(2y - y)/y)] × 100

Profit % = 100%

∴ Profit percentage will be 100%

BDL MT Electronics Mock Test - 2 - Question 24

Select the most appropriate Antonym of the given word.
Anxious

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 24

The correct answer is 'Carefree'.
Explanation

  • ​The word Anxious(adjective) means- "worried and nervous". 
    • E.g: I saw my sister's anxious face at the window.
  • The antonyms of the given word Anxious are- 'Carefree', 'confident', 'sure', 'self-assured', 'controlled, etc.
  • From the antonyms of the given word, we can say that the word 'Carefree' is the opposite in meaning.
  • The word Carefree(adjective) means- "having no problems or not being worried about anything". 
    • E.g: I remember my carefree student days.
  • ​Hence, the correct option is Option 1).
  • Let's have a look at the meaning of other given options:
    • Active(adjective)- "busy with a particular activity". 
    • Taste(noun)- "the flavor of something, or the ability of a person or animal to recognize different flavors". 
    • Rise(verb)- "to move upwards". 

Other Related Points

  • The synonyms of the given word Anxious are- 'Agitating', 'distressful', 'tense', 'nervous, etc.
  • Example of 'Anxious' in a sentence:
    • The drought has made farmers anxious about the harvest.
BDL MT Electronics Mock Test - 2 - Question 25

Which of the following words most appropriately fits the blank labelled as (5)?

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 25

Here the correct answer is too.
Explanation

  • 'Too' is an adverb meaning to a higher degree than is desirable, permissible, or possible; excessively.
  • Too - besides, also.
  • For Examples:-
    • Sell the house and furniture too.
    • He was driving too fast.
  • In the 4th line of the passage, the Delhi police also deployed three companies of paramilitary force at the border of UP and Haryana.
  • Therefore, 'too' will be used.
BDL MT Electronics Mock Test - 2 - Question 26

Which of the following words most appropriately fits the blank labelled as (3)?

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 26

Here the correct answer is Across.
Explanation

  • 'Across' will be used after roads because across is a preposition meaning from one side to other of something with clear boundaries.
  • For Examples:-
    • Across a road.
    • Across a bridge.
  • 'Through' will not be used because it is used to indicate the movement from one end to the other.
    • For Example - They ran swiftly through the woods.
  • In the above given passage in the 3rd line, the movement is across a state which has clear boundaries.
  • Therefore, 'across' will be used.
BDL MT Electronics Mock Test - 2 - Question 27

Which of the following words most appropriately fits the blank labelled as (2)?

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 27

Here the correct answer is Breaking through.
Explanation

  • 'Break through' is a phrasal verb meaning make or force a way through a barrier.
    • For Example - The crowd tried to break through the gates.
  • Here, in the 1st line the farmers along with the leaders of Bhartiya Kisan Union made a way through the two barriers on NH-44 on Wednesday.

Thus, the correct phrasal verb for the blank is 'Breaking through'.

BDL MT Electronics Mock Test - 2 - Question 28

Select the most appropriate option to substitute the underlined segment in the given sentence. If there is no need to substitute it, select No substitution required.

No sooner had I eaten the pizza, then I started feeling sick.

Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 28

The correct answer is- 'than'.

Explanation

  • No sooner than: is used to show that one thing happens immediately after another thing.
  • It is often used with the past perfect.
  • It is followed by 'than'.
    • Example: We had no sooner started cooking than there was a power cut.
  • When 'no sooner' is used in the front position, we invert the order of the auxiliary verb and subject.
    • Example: No sooner had they stepped out of the house than it started to rain.
  • From the above explanation, it is clear that 'than' should come in place of 'then' in the given sentence.
  • Hence, option 3 is the correct answer.

The correct sentence is: No sooner had I eaten the pizza than I started feeling sick.

BDL MT Electronics Mock Test - 2 - Question 29
There are five friends-Satish, Kishore, Mohan, Anil, and Rajesh. Mohan is the tallest. Satish is shorter than Kishore but taller than Rajesh. Anil is a little shorter than Kishore but a little taller than Satish. Who is taller than Rajesh but shorter than Anil?
Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 29

Five friends: Satish, Kishore, Mohan, Anil and Rajesh.

1) Satish is shorter than Kishore but taller than Rajesh.

Kishore > Satish > Rajesh

2) Anil is a little shorter than Kishore but a little taller than Satish.

Kishore > Anil > Satish

3) Mohan is the tallest.

Combining all these statements;

Mohan > Kishore > Anil > Satish > Rajesh

So, Satish is taller than Rajesh but shorter than Anil.

Hence, "Satish" is the correct answer.

BDL MT Electronics Mock Test - 2 - Question 30

If the given words are arranged in the reverse dictionary order then which word will be second from the bottom end in the sequence?

  1. Navigation
  2. Necklace
  3. Necklet
  4. Navigate
Detailed Solution for BDL MT Electronics Mock Test - 2 - Question 30

Arranging the given words according to the English dictionary order :
4. Navigate
1. Navigation
2. Necklace
3. Necklet

The reverse order will be :
3. Necklet
2. Necklace
1. Navigation
4. Navigate
Navigation is the second word from the bottom end.
Hence, "Navigation" is the correct answer.

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