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Test: Angular Momentum - NEET MCQ


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10 Questions MCQ Test Physics Class 11 - Test: Angular Momentum

Test: Angular Momentum for NEET 2024 is part of Physics Class 11 preparation. The Test: Angular Momentum questions and answers have been prepared according to the NEET exam syllabus.The Test: Angular Momentum MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Angular Momentum below.
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Test: Angular Momentum - Question 1

A person standing on a rotating platform with his hands lowered outstretches his arms. The angular momentum of the person

Detailed Solution for Test: Angular Momentum - Question 1

Yes because there is absence of any external force or torque so angular momentum will remain constant
here outstretching the hands means internal forces are working.. so moment of inertia increases in this case and to make angular momentum constant when angular velocity decreases.

Test: Angular Momentum - Question 2

The mass of an electron is  9 x 10-31 kg. It revolves around the nucleus of an atom in a circular orbit of radius 4.5 Å, with a speed of  8 x 105m/s. The angular momentum of electron is

Detailed Solution for Test: Angular Momentum - Question 2

M=9x10-31Kg,r=4.5x10-10
V=8x105m/s
L=mvr
  =9x10-31 x 4.5 x 10-10 x 8 x 10= 3.24 x 10-34 kgm2s-1

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Test: Angular Momentum - Question 3

The earth rotates about an axis passing through its north and south poles with a period of one day. If it is struck by meteorites, then

Detailed Solution for Test: Angular Momentum - Question 3

Because angular momentum remains constant as the moment of inertia is increasing here so the angular velocity will decrease.

Test: Angular Momentum - Question 4

Relation between torque and angular momentum is similar to the relation between

Detailed Solution for Test: Angular Momentum - Question 4

Torque is the rate of change of angular momentum. Force in linear motion corresponds to torque in rotary motion. Thus, just as Newton’s second law can be written as F = dP/dt (F for linear motion), it can be written as T = dL/dt for rotary motion.

Test: Angular Momentum - Question 5

The dimensions of angular momentum are

Detailed Solution for Test: Angular Momentum - Question 5

We know that angular momentum,
L = r x P
Thus its dimension is [r][P] = ML2T-1.

Test: Angular Momentum - Question 6

An earth satellite is moving around the earth in a circular orbit. In such case, what is conserved?

Detailed Solution for Test: Angular Momentum - Question 6

An earth satellite is moving in a circular motion due to change in the direction of velocity. Its angular momentum about centre is conserved as there is no external force acting on the system.

Test: Angular Momentum - Question 7

A uniform circular disc of radius 50 cm at rest is free to turn about an axis which is perpendicular to its plane and passes through its centre. It is subjected  to a torque which produces a constant angular acceleration of 2.0 rad/sec2. It's net acceleration in m/s2 at the end of 2.0 s is a approximately.

Detailed Solution for Test: Angular Momentum - Question 7

A uniform circular disc of radius 50 cm at rest is free to turn about an axis having perpendicular to its plane and passes through its centre. This situation can be shown by the figure given below:

Therefore,

Angular acceleration = α = 2 rad/s2

Angular speed, ω = αt = 4 rad/s

Centripetal acceleration, ac = ω2r

42 x 0.5

=16 x 0.5

= 8m/s2

Linear acceleration at the end of 2 s is,

at = αt = 2 x 0.5 = 1 m/s2

Therefore, the net acceleration at the end of 2.0 sec is given by 

Test: Angular Momentum - Question 8

 kgm2s-1 is the unit of

Detailed Solution for Test: Angular Momentum - Question 8

L = Iw
L is the angular momentum, I is the MOI and w is the rotational velocity.
[I] = [ML2T0], [w] = [M0L0T-1]
[L] = [MLT-1]

Test: Angular Momentum - Question 9

Angular momentum is equal to____.(All the symbols used have their usual meanings)

Detailed Solution for Test: Angular Momentum - Question 9

Angular momentum is equal to L = Iω. It is the formula.

Test: Angular Momentum - Question 10

In case of a projectile, the angular momentum is minimum

Detailed Solution for Test: Angular Momentum - Question 10

At the starting point of the projectile, the perpendicular distance from the point of rotation is zero as it's on the ground itself. Since one factor of the product is zero, the angular momentum at the starting point will be zero too.
 

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