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JEE Exam  >  JEE Tests  >  Mathematics (Maths) Class 12  >  Test: Area Between Two Curves - JEE MCQ

Test: Area Between Two Curves - JEE MCQ


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10 Questions MCQ Test Mathematics (Maths) Class 12 - Test: Area Between Two Curves

Test: Area Between Two Curves for JEE 2024 is part of Mathematics (Maths) Class 12 preparation. The Test: Area Between Two Curves questions and answers have been prepared according to the JEE exam syllabus.The Test: Area Between Two Curves MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Area Between Two Curves below.
Solutions of Test: Area Between Two Curves questions in English are available as part of our Mathematics (Maths) Class 12 for JEE & Test: Area Between Two Curves solutions in Hindi for Mathematics (Maths) Class 12 course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Test: Area Between Two Curves | 10 questions in 10 minutes | Mock test for JEE preparation | Free important questions MCQ to study Mathematics (Maths) Class 12 for JEE Exam | Download free PDF with solutions
Test: Area Between Two Curves - Question 1
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The area between the curves y = x2 and y = x3 is:​

Detailed Solution for Test: Area Between Two Curves - Question 1

y = x2 and y = x3 
To find point of intersections :
x2 = x3
x2(x-1) = 0
So, x = 0,1
POI are (0,0) & (1,1)

= [x3/3 – x4/4]x=1   - [x3/3 – x4/4]x=0
= (1/3 – 1/4) – (0)
= 1/12 sq units

Test: Area Between Two Curves - Question 2
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The area bounded by the curve y2 = 16x , x = 1, x = 3 and X-axis is: 

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Test: Area Between Two Curves - Question 3
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The shaded area is equal to:

​

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Test: Area Between Two Curves - Question 4
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The curves x2 + y2=16 and y2 = 6x intersects at​
Detailed Solution for Test: Area Between Two Curves - Question 4

x2 + y2=16 and y2 = 6x 
So, to figure out the P.O.I
x2 + 6x = 16
x2 + 6x – 16 = 0
(x+8) (x-2) = 0
x = -8, 2
For x = -8
y = (6*(-8))1/2 
= (-48)1/2 
No real value for y
For x = 2
y = (6*2)1/2 
= (12)1/2 
= 2*(3)1/2 
So, P.O.I is (2 , 2*(3)1/2 )    

Test: Area Between Two Curves - Question 5
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Find the area of region bounded by curve ​
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Test: Area Between Two Curves - Question 6
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The area of the region bounded by y = x2 – 2x and y = 4 – x2 is.​
Detailed Solution for Test: Area Between Two Curves - Question 6

To find area between y = x2 – 2x and y = 4 – x2,
We need to find POI.
x2 – 2x = 4 – x2
2x2 - 2x – 4 = 0
x2 – x – 2 = 0
(x-2)(x+1) = 0
x = -1, 2


= [(-2x3)/3 + x2 + 4x]x=2 - [(-2x3)/3 + x2 + 4x]x= -1
= -16/3 + 4 + 8 – (2/3 + 1 - 4)
= 9 sq units

Test: Area Between Two Curves - Question 7
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The shaded area enclosed between the parabolas with equations y = 1 + 10x – 2x2and y = 1 + 5x – x2 is equal to:
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Test: Area Between Two Curves - Question 8
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The area of the smaller region lying above the x-axis and included between the circle x2 + y2 = 2x and the parabola y2 = x.
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= π/4 – 2/3

Test: Area Between Two Curves - Question 9
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The area bounded by the curves f(x) = x2 + 1 and g(x) = x – 1 on the interval [1,3] is:​
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Test: Area Between Two Curves - Question 10
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The area shaded in the given figure can be calculated by which of the following definite integral?
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